How I can store Image file in a database

Can any one how i can stored image file in a database and then by using same database how i can show in HTML page...(in a browser)

This is not something that can be answered easily. There is quite alot of code involved....
To get started I suggest you read up on the built-in package 'DBMS_LOB' from Oracle . Most of what you need you should find there.
regards Dave.

Similar Messages

How to insert an image file in Oracle database

hi
can you please tell me how to insert an image file into oracle database????
suppose there is one image file in c:\pictures\rose.jpg. how to insert that file into database? theoretically i know that will be BFILE type but i dont know how to insert that.
will be waiting for your reply........
thanks & regards,
Priyatosh

Hello,
The easiest way to load a blob is to use SQL loader.
This example comes from the utilities guide:
LOAD DATA
INFILE 'sample.dat'
INTO TABLE person_table
FIELDS TERMINATED BY ','
(name CHAR(20),
1 ext_fname FILLER CHAR(40),
2 "RESUME" LOBFILE(ext_fname) TERMINATED BY EOF)
Datafile (sample.dat)
Johny Quest,jqresume.txt,
Speed Racer,'/private/sracer/srresume.txt',
Secondary Datafile (jqresume.txt)
Johny Quest
500 Oracle Parkway
Secondary Datafile (srresume.txt)
Loading LOBs
10-18 Oracle Database Utilities
Speed Racer
400 Oracle Parkway
regards,
Ivo

How to insert a image file into oracle database

hi all
can anyone guide me how to insert a image file into oracle database now
i have created table using
create table imagestore(image blob);
but when inserting i totally lost don't know what to do how to write query to insert image file

Hi I don't have time to explain really, I did have to do this a while ago though so I will post a code snippet. This is using the commons file upload framework.
Firstly you need a multi part form data (if you are using a web page). If you are not using a web page ignore this bit.
out.println("<form name=\"imgFrm\" method=\"post\" enctype=\"multipart/form-data\" action=\"FileUploadServlet?thisPageAction=reloaded\" onSubmit=\"return submitForm();\"><input type=\"FILE\" name=\"imgSource\" size='60' class='smalltext' onKeyPress='return stopUserInput();' onKeyUp='stopUserInput();' onKeyDown='stopUserInput();' onMouseDown='noMouseDown(event);'>");
out.println("   <input type='submit' name='submit' value='Submit' class='smalltext'>");
out.println("</form>"); Import this once you have the jar file:
import org.apache.commons.fileupload.*;Now a method I wrote to upload the file. I am not saying that this is correct, or its the best way to do this. I am just saying it works for me.
private boolean uploadFile(HttpServletRequest request, HttpSession session) throws Exception {
        boolean result = true;
        String fileName = null;
        byte fileData[] = null;
        String fileUploadError = null;
        String imageType = "";
        String error = "";
        DiskFileUpload fb = new DiskFileUpload();
        List fileItems = fb.parseRequest(request);
        Iterator it = fileItems.iterator();
        while(it.hasNext()){
            FileItem fileItem = (FileItem)it.next();
            if (!fileItem.isFormField()) {
                fileName = fileItem.getName();
                fileData = fileItem.get();
                // Get the imageType from the filename extension
                if (fileName != null) {
                    int dotPos = fileName.indexOf('.');
                    if (dotPos >= 0 && dotPos != fileName.length()-1) {
                        imageType = fileName.substring(dotPos+1).toLowerCase();
                        if (imageType.equals("jpg")) {
                            imageType = "jpeg";
        String filePath = request.getParameter("FILE_PATH");
        session.setAttribute("filePath", filePath);
        session.setAttribute("fileData", fileData);
        session.setAttribute("fileName", fileName);
        session.setAttribute("imageType", imageType);
        return result;
     } And now finally the method to actually write the file to the database:
private int writeImageFile(byte[] fileData, String fileName, String imageType, String mode, Integer signatureIDIn, HttpServletRequest request) throws Exception {
        //If the previous code found a file that can be uploaded then
        //save it into the database via a pstmt
        String sql = "";
        UtilDBquery udbq = getUser(request).connectToDatabase();
        Connection con = null;
        int signatureID = 0;
        PreparedStatement pstmt = null;
        try {
            udbq.setUsePreparedStatements(true);
            con = udbq.getPooledConnection();
            con.setAutoCommit(false);
            if((!mode.equals("U")) || (mode.equals("U") && signatureIDIn == 0)) {
                sql = "SELECT SEQ_SIGNATURE_ID.nextval FROM DUAL";
                pstmt = con.prepareStatement(sql);
                ResultSet rs = pstmt.executeQuery();
                while(rs.next()) {
                   signatureID = rs.getInt(1);
                if (fileName != null && imageType != null) {
                    sql = "INSERT INTO T_SIGNATURE (SIGNATURE_ID, SIGNATURE) values (?,?)";
                    InputStream is2 = new ByteArrayInputStream(fileData);
                    pstmt = con.prepareStatement(sql);
                    pstmt.setInt(1, signatureID);
                    pstmt.setBinaryStream(2, is2, (int)(fileData.length));
                    pstmt.executeUpdate();
                    pstmt.close();
                    con.commit();
                    con = null;
            if(mode.equals("U") && signatureIDIn != 0) {
                signatureID = signatureIDIn.intValue();
                if (fileName != null && imageType != null) {
                    sql = "UPDATE T_SIGNATURE SET SIGNATURE = ? WHERE SIGNATURE_ID = ?";
                    InputStream is2 = new ByteArrayInputStream(fileData);
                    pstmt = con.prepareStatement(sql);
                    pstmt.setBinaryStream(1, is2, (int)(fileData.length));
                    pstmt.setInt(2, signatureID);
                    pstmt.executeUpdate();
                    pstmt.close();
                    con.commit();
                    con = null;
        } catch (Exception e) {
            con = null;
            throw new Exception(e.toString());
        return signatureID;
   }

How I can open Image File

I guess it is simple but I do not know how I can in this class open Image file. This code should go instead of the line:
window.setSize(450,300);
Please, help me.
Pan.
class ItemHandler implements ActionListener {
          public void actionPerformed( ActionEvent e )
               for ( int i = 0; i < techItems.length;i++ );
               if (techItems[ i ].isSelected() ){
               window.setSize(450,300);
               break;
               repaint();
     }

The easiest way is to use a JLabel where you have an image. Something like this:
JLabel lbl = new JLabel(new ImageIcon("icon.gif"));
JPanel p = new JPanel();
p.add(lbl);
Klint

How to fetch the image file from oracle database and display it.

hi... i've inserted the image file into the oracle database... now i want to retreive it and want to display it... can anybody help me... pls

not a big deal dude... i fetched the image from database and saved it into my local hard disk.. but when tried to open it,ends up with no preview... dont know what d prob is... any idea... i've inserted the image as bytes n trying to fetch it as binary stream.. is that the problem... here im giving my insertion and retireving code.. jus go through it...
Insertion code:_
* To change this template, choose Tools | Templates
* and open the template in the editor.
package PMS;
import java.io.File;
import java.io.FileInputStream;
import java.sql.Blob;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.SQLException;
public class Browse_java
static Connection con=null;
public static void main(String args[])
try{
System.out.println("(browse.java) just entered in to the class");
con = new PMS.DbConnection().getConnection();
System.out.println("(browse.java) connection string is"+con);
PreparedStatement ps = con.prepareStatement("INSERT INTO img_exp VALUES(?,?)");
System.out.println("(browse.java) prepare statement object is"+ps);
File file =new File("E:/vanabojanalu-/DSC02095.JPG");
FileInputStream fs = new FileInputStream(file);
System.out.println("lenth of file"+file.length());
byte blob[]=new byte[(byte)file.length()];
System.out.println("lenth of file"+blob.length);
fs.read(blob);
ps.setString(1,"E:/vanabojanalu-/DSC02095.JPG");
ps.setBytes(2, blob);
// ps.setBinaryStream(2, fs,(int)file.length());
System.out.println("(browse.java)length of picture is"+fs.available());
int i = ps.executeUpdate();
System.out.println("image inserted successfully"+i);
catch(Exception e)
e.printStackTrace();
finally
try {
con.close();
} catch (SQLException ex) {
ex.printStackTrace();
and Retrieving code is:
* To change this template, choose Tools | Templates
* and open the template in the editor.
package PMS;
import java.beans.Statement;
import java.io.*;
import java.net.*;
import java.sql.*;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import javax.servlet.*;
import javax.servlet.http.*;
import oracle.jdbc.OracleResultSet;
* @author Administrator
public class view_image2 extends HttpServlet {
* Processes requests for both HTTP <code>GET</code> and <code>POST</code> methods.
* @param request servlet request
* @param response servlet response
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("image/jpeg");
//PrintWriter out = response.getWriter();
try
javax.servlet.http.HttpServletResponse res=null;;
int returnValue = 0;
Connection con = null;
PreparedStatement stmt = null;
ResultSet rs = null;
InputStream in = null;
OutputStream os = null;
Blob blob = null;
//String text;
//text=request.getParameter("text");
//Class.forName("com.mysql.jdbc.Driver");
con=new PMS.DbConnection().getConnection();
System.out.println("jus entered the class");
//String query = "SELECT B_IMAGE FROM img_exp where VC_IMG_PATH=?";
//conn.setAutoCommit(false);
PreparedStatement pst = con.prepareStatement("select b_image from img_exp where vc_img_path=?");
System.out.println("before executing the query");
pst.setString(1,"C:/Documents and Settings/Administrator/Desktop/Leader.jpg");
rs = pst.executeQuery();
//System.out.println("status of result set is"+rs.next());
System.out.println("finished writing the query");
int i=1;
if(rs.next())
System.out.println("in rs") ;
byte[] byte_image=rs.getBytes(1);
// byte blob_byte[]= new byte[(byte)blob.length()];
//System.out.println("length of byte is"+blob_byte);
//String len1 = (Oracle.sql.blob)rs.getString(1);
//System.out.println("value of string is"+len1);
//int len = len1.length();
//byte [] b = new byte[len];
//in = rs.getBinaryStream(1);
int index = in.read(byte_image, 0, byte_image.length);
System.out.println("value of in and index are"+in+" "+index);
FileOutputStream outImej = new FileOutputStream("C://"+i+".JPG");
//FileOutputStream fos = new FileOutputStream (imgFileName);
BufferedOutputStream bos = new BufferedOutputStream (outImej);
//byte [] byte_array = new byte [blob_byte.length]; //assuming 512k size; you can vary
//this size depending upon avlBytes
//int bytes_read = in.read(blob_byte);
bos.write(index);
/*while (index != -1)
outImej.write(blob_byte, 0, index);
index = in.read(blob_byte, 0, blob_byte.length);
//System.out.println("==========================");
//System.out.println(index);
//System.out.println(outImej);
//System.out.println("==========================");
/*ServletOutputStream sout = response.getOutputStream(outImej);
          for(int n = 0; n < blob_byte.length; n++) {
               sout.write(blob_byte[n]);
          sout.flush();
          sout.close();*/
outImej.close();
//i++;
else
returnValue = 1;
catch(Exception e)
System.out.println("SQLEXCEPTION : " +e);
finally {
//out.close();
// <editor-fold defaultstate="collapsed" desc="HttpServlet methods. Click on the + sign on the left to edit the code.">
* Handles the HTTP <code>GET</code> method.
* @param request servlet request
* @param response servlet response
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
* Handles the HTTP <code>POST</code> method.
* @param request servlet request
* @param response servlet response
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
* Returns a short description of the servlet.
public String getServletInfo() {
return "Short description";
// </editor-fold>
}

How do I store images in a jar file to be displayed on a jsp?

Afternoon all,
I have created a java component which accepts some parameters and returns a string. The returned string contains html tags to display a table in a webpage when rendered through a browser.
I want to be able to add this component to any java web project to display my table. The problem is that I want to use images in my table to give the appearance of curved corners.
How do I store images in my component and render to a webpage?
Thanks in advance,
Alex

You won't be able to make the install of this library as simple as the installation of a jar file. You can't access the images directly in the jar.
There are a few approaches you can take:
1 - jar file + resources:
Have the install as being a jar and a "resources" directory which you store all the images in. Thus the images become part of the web application/web site and are accessible. Probably need to allow an entry in web.xml to configure where/what this directory is called.
2 - jar file only:
Provide a servlet to access the images, which will load them from the jar file, using the ClassLoader.getResourceAsStream(). Requires declaration of a servlet in the web.xml file. Won't be as efficient as having the images on disk, but will keep them bundled in the jar file.
you would generate code such as <img src="myImgServlet?img=.....">
Cheers,
evnafets

How to store image files in oracle DB

Hi,
I am new to working with database.
Please let me know how to store image files in Database using insert command.
Thanks,
Ramesh Yakkala.

Hi,
You need to create a directory object to import these files:
Take a look on the example below:
eg:
CREATE TABLE MY_IMAGE_TABLE (
ID NUMBER,
NAME VARCHAR2(20),
IMAGE BLOB);
CREATE OR REPLACE DIRECTORY IMAGES AS '/tmp';
GRANT READ, WRITE ON DIRECTORY IMAGES TO PUBLIC;
CREATE OR REPLACE PROCEDURE load_file_to_my_table (p_file_name IN MY_IMAGE_TABLE.NAME%TYPE) AS
v_bfile BFILE;
v_blob BLOB;
BEGIN
INSERT INTO MY_IMAGE_TABLE (id, name, image)
VALUES (1, p_file_name, empty_blob())
RETURN doc INTO v_blob;
v_bfile := BFILENAME('IMAGES', p_file_name);
Dbms_Lob.Fileopen(v_bfile, Dbms_Lob.File_Readonly);
Dbms_Lob.Loadfromfile(v_blob, v_bfile, Dbms_Lob.Getlength(v_bfile));
Dbms_Lob.Fileclose(v_bfile);
COMMIT;
END;
SQL> execute load_file_to_my_table('myfhoto.jpg');Cheers

How to insert an image file as blob using JDBC Statement

Hi,
I'm new on java.
I want the code to insert an image file in Oracle database whose data type is blob.
i want to use JDBC statement not the prepared statement.
Please help me out.

user8739226 wrote:
thanks for the solution.
I want to ask one thing
let say i've created a method in a bean in which i'm passing three parameters.
One is tablename as String, Second is Name of tablefields as Object, Third is Values as Object
Like:
public synchronized int insert(String table,Object[] fields, Object[] values)Ah now we're getting somewhere. I was trying to come up with a situation where using a regular Statement over PreparedStatement would be viable and came up with practically nothing.
In the method body i'm accessing the table fields and values and combining them into the insert sql query.
how can i do this using preparedstatment.
how do i come to know here in this bean that this value is int or string or date at runtime to use setInt, setString, setdate or setBlob respectively.That's your problem. Bad design. You want to make some sort of universal insert method that can insert anything anywhere. But it doesn't really make sense, because whenever you're trying to insert something, you know exactly what you want to insert and where. You could use a PreparedStatement at that point (although encapsulate it in its own method). Now you're trying to create your own poorly designed framework over JDBC that doesn't solve problems, only increases them.
Above was the only reason i saw, i was using statement instead of preparedstatment as statement was looking easy in this situation.
please, give me the solution of above using preparedstatment.No, rather you should reconsider your design. What advantage does your insert() method give you over, let's say using a regular PreparedStatement. Granted, you can put your connection opening and other boilerplate code in the method. But if that's your only problem, then your insert method isn't gonna be much use. You could always switch to JPA for example and work with that.

How to link an image file in code view

I can't seem to figure out how to link the image file in code view. It has to be in code view because the image is hidden in Design View so I can't do it in HTML view. Here's the coded section:

                <div id="tab3" class="tabsGeneral">
                  <div class="tabsFeatureImageContainer asyncImgLoad" title="img/index/tabs/tab3/DonateNow-168x112.jpg"></div>
                  <h3 class="tabsHeader">Partner With Us</h3>
                  <p class="tabsDesc">Get involved with all the exciting things God is doing at Provision House. Partner with us to help others find true and lasting freedom from addiction in Christ. <a href="http://provisionhouse.org/giving.html" class="commonLink">Click here</a></p>
It's' the red jpeg image file I want to link to another page in the site and I don't have enough experience to do this.
I am thankful for your help.
Paul

Thanks, Gramps. Here's the page I want to like to from the image:
http://provisionhouse.org/giving.html
Paul
Here's the whole section where the problem exists:

            <div id="tabsContainer">
                <div id="tabsWrapper">
                    
                    <div id="tab1" class="tabsGeneral">
                     <div class="tabsFeatureImageContainer asyncImgLoad" title="img/index/tabs/tab3/WalkingByTheSpirit-168x112.jpg"></div>
                    <h3 class="tabsHeader">Session 5 of the Breaking the Chains Seminar Completed</h3>
                        <p class="tabsDesc">Visit the <a href="videos.html" class="commonLink">Videos page</a> to watch clips of Session 5, <span class="Italic">Walking by the Spirit</span></a></p>
                    </div> 
                    
                  <div id="tab2" class="tabsGeneral">
                        <div class="tabsFeatureImageContainer asyncImgLoad" title="img/index/tabs/tab2/FreedomFromAddiction168x112.jpg"></div>
                        <h3 class="tabsHeader">Session 2, Freedom from Addiction</h3>
                        <p class="tabsDesc">Is it possible for the Christian to find true and lasting freedom from addiction? This session explains how all addictions are also sin, and it is sin that Jesus has set us free from. Anticipated release: November, 2011. <span class="commonLink"><a href="curriculum.html">Read about Session 2</a></span>
 
                  </div> 
                    
                    <div id="tab3" class="tabsGeneral">
                    <div class="tabsFeatureImageContainer asyncImgLoad" title="img/index/tabs/tab3/DonateNow-168x112.jpg"></div>
                        <h3 class="tabsHeader">Partner With Us</h3>
                        <p class="tabsDesc">Get involved with all the exciting things God is doing at Provision House. Partner with us to help others find true and lasting freedom from addiction in Christ. <a href="http://provisionhouse.org/giving.html" class="commonLink">Click here</a></span>
                        <div class="tabsThumbsContainer">
                            <a class="tabsThumb imgTipLeftTop" rel="img/index/tabs/tab3/WalkingByTheSpirit-350x250-no text.jpg">
                                <img src="img/index/tabs/tab3/WalkingByTheSpirit-26x26-no text2.jpg" alt="" />
                            <a class="tabsThumb imgTipLeftTop" rel="img/index/tabs/tab3/WalkingByTheSpirit-350x250-no text.jpg">
                                <img src="img/index/tabs/tab3/WalkingByTheSpirit-26x26-no text2.jpg" alt="" />
                            <a class="tabsThumb imgTipLeftTop" rel="img/index/tabs/tab3/WalkingByTheSpirit-350x250-no text.jpg">
                                <img src="img/index/tabs/tab3/WalkingByTheSpirit-26x26-no text2.jpg" alt="" />
                            <a class="tabsThumb imgTipLeftTop" rel="img/index/tabs/tab3/WalkingByTheSpirit-350x250-no text.jpg">
                                <img src="img/index/tabs/tab3/WalkingByTheSpirit-26x26-no text2.jpg" alt="" />
                            <a class="tabsThumb imgTipLeftTop" rel="img/index/tabs/tab3/WalkingByTheSpirit-350x250-no text.jpg"><img src="img/index/tabs/tab3/WalkingByTheSpirit-26x26-no text2.jpg" alt="" />
                            <a class="tabsThumb imgTipLeftTop" rel="img/index/tabs/tab3/WalkingByTheSpirit-350x250-no text.jpg">
                                <img src="img/index/tabs/tab3/WalkingByTheSpirit-26x26-no text2.jpg" alt="" />
                                </span>
                            </a>
                        </div>

                    </div> 
                </div> 
                
                <div id="tabsBtnBar">
                    <div class="tabsBtn">latest news<span class="tabsSource">#tab1</span><span class="tabsSource">#tab1</span>
                </div>
                    <div class="tabsBtn">Current Project
                        <span class="tabsSource">#tab2</span>
                    </div>
                    <div class="tabsBtn">how to help
                        <span class="tabsDefaultTab"></span>
                        <span class="tabsSource">#tab3</span>
                    </div>
                </div> 
            </div>

How I can display images as table data?

Dear project Marvel,
I would like to display images as one of table data, but I do not know how to easily store image data into tables using htmldb and whether I can display the stored images. Does anyone knows how I can store/display images using htmldb? If I cannot do this easily then displaying image (which is stored somewhere else but) just looks like one of columns also fine to me.
Thanks in advance,
Rui

you can show those images inline in your report region if you call our "p" procedure in an image tag. so the example above has you creating a table that you then join to the wwv_flow_files view with a query like...
select htf.anchor('p?n='||f.id, f.filename) name,
f.doc_size, f.mime_type, m.upload
from my_docs m, wwv_flow_files f
where m.filename = f.name
...clicking on the links in the first column would return a page that just showed the associated image. if changed that anchor tag to an image one like so...
select '<img src="p?n=' || f.id ||'>' the_image,
f.doc_size, f.mime_type, m.upload
from my_docs m, wwv_flow_files f
where m.filename = f.name
...your images would then appear inline as opposed to on a separate page.
[Edited by: rmattama on Sep 25, 2003 1:22 PM]
i'm not sure how, but i'd earlier posted an incomplete answer to rui's question. i've fixed some of the above and added this below...
just fixed the html above so it renders correctly in this forum. sorry i didn't see that earlier. also, i'm not sure where the rest of my post went, but rui had also wanted to know what the wwv_flow_files was. that's a view to the table we use to store uploaded BLOBs like images, css's, and stylesheets. since you can only identify one document table in your DAD configuration, we give you this view to allow you access to that doc table that HTML DB owns.
fyi,
raj

How to update an image file into existing file

how to update an image file into existing file

Hi,
So, i assume you want to change one picture. On Stage, i have edgeAnimate (an image), and
1) i am using the div tag.
So: sym.$("edgeAnimate").css("background-image", "url(images/myImage.png)" ); will change my picture.
Link: CSS properties.
More CSS:
sym.$("edgeAnimate").css( { "background-image": "url(images/myImage.png)", "background-size": "100% 100%", "background-repeat": "no-repeat", "cursor": "pointer" } );
Using a path variable:
var myPath = "images/myImage.png";
sym.$("edgeAnimate").css( { "background-image": "url("+myPath+")", "background-size":"100% 100%", "background-repeat":"no-repeat", "cursor": "pointer" } );
2) i am using the img tag.
I can add a class using Edge Animate user interface.
I choose one class name: "newImage".
So: sym.$(".newImage").css("background-image", "url(images/myImage.png)" ); will change my picture.
Note: I assumed you don’t need to preload your picture.

I need to convert PDF file to Word Document, so it can be edited. But the recognizing text options do not have the language that I need. How I can convert the file in the desired of me language?

I need to convert PDF file to Word Document, so it can be edited. But the recognizing text options do not have the language that I need. How I can convert the file in the desired of me language?

The application Acrobat provides no language translation capability.
If you localize the language for OS, MS Office applications, Acrobat, etc to the desired language try again.
Alternative: transfer a copy of content into a web based translation service (Bing or Google provides a free service).
Transfer the output into a word processing program that is localized to the appropriate language.
Do cleanup.
Be well...

Hello Anybody, I have a question. Can any of you please suggest me how to make an xml file from the database table with all the rows? Note:- I am having the XSD Schema file and the resulted XML file should be in that XSD format only.

Hello Anybody, I have a question. Can any of you please suggest me how to make an xml file from the database table with all the records?
Note:- I am having the XSD Schema file and the resulted XML file should be in that XSD format only.

The Oracle documentation has a good overview of the options available
Generating XML Data from the Database
Without knowing your version, I just picked 11.2, so you made need to look for that chapter in the documentation for your version to find applicable information.
You can also find some information in XML DB FAQ

Does anyone know how i can view PDF files using Galaxy Note 2?

Does anyone know how i can view PDF files using Galaxy Note 2?
This is what i have been doing;
I click on the file i wish to view (via a portal)
this file goes to notification widget (i drag down screen)
notification/message says download complete
i click on notification/message
nows it says complete action using (here i only have 2 icon options 1= DB Text Editor 2 = HTML Viewer)
I have installed Adobe Reader.

Can you confirm if the downloaded file is a pdf file, that is it ends with .pdf?

Hi! I have a library of around 1000 songs on my iTunes, I recently synced my phone and all was lost, my partner has the same songs on hers with a different sign in, but not backed up anywhere, any suggestion on how I can store her tunes in my account ???

Hi! I have a library of around 1000 songs on my iTunes, I recently synced my phone and all was lost, my partner has the same songs on hers with a different sign in, but not backed up anywhere, any suggestion on how I can store her tunes in my account ??? Then sync them to mine? When I sign her phone into her account I get a message warning that if I sync the dogs on her phone will be replaced by the ones in the library! But as there are no songs there I'm reluctant to continue!!! Please help this non techi guy.!!!!!

Hello Solid Buck,
Thank you so much for providing the details about the duplicate song issue you are experiencing. It sounds like you would like to remove the duplicate songs that will not play on your iPhone, but when you connect it to iTunes, iTunes only shows you one copy of the song on your iPhone.
In this situation, I recommend deleting the individual songs that do not play directly from your iPhone. I found the steps to do this on page 61 of the iPhone User Guide (http://manuals.info.apple.com/en_US/iphone_user_guide.pdf):
Delete a song from iPhone: In Songs, swipe the song, then tap Delete.
Thank you for using Apple Support Communities.
Best,
Sheila M.

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