How must getElementsByTagName work on an xml file with namespaces?

Hello together,
is there any normative document, which specifies
which nodes must be returned by
the org.w3c.dom.Document method
getElementsByTagName when which was
created by a namespace aware dom parser
from an xml file containing namespaces?
In other words:
when you have an xml file:
<someprefix:somenode xmlns:someprefix="http://someuri">
<someprefix:innertag>
<someprefix:mostinnertag>
</someprefix:mostinnertag>
<someprefix:mostinnertag>
</someprefix:mostinnertag>
</someprefix:innertag>
</someprefix>
and you call
document.getElementsByTagName( ... );
1) How many nodes must be returned when giving
"mostinnertag" as parameter?
2) How many nodes when giving "someprefix:mostinnertag" as parameter?
Is it allowed to use the "non namespaceaware"
method and not "getElementsByTagNameNS"?
I know:
a) xerces returns 2 nodes when using
alternative 2 and none with alternative 1
b) oracle xml parser returns 2 nodes when using
alternative 1 and none when using alternative 2
Which implementation is right?
Yours
Stefan

I've got some problems with this methos and xerces too.
Perhaps the two implementations (xerces and oracle) are different. I mean xerces implementation gives you nodes of this name but without namespace and oracles's implementation gives you modes with namespace whose unprefix-name is "mostinnertag".

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I'm a beginner with XML and for the first time i have to read a file with columns.
I have try this code, but the result is always the same: no rows selected.
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screenshot

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t.transform(new DomSource(dXml), new StreamResult(new OutputStreamWriter(osSave)));
finally
osSave.close();
And your Document was now saved.

How to Insert data from an XML file into an Oracle 10g table

Hello,
Please can you help me as I have hit a brick wall with this problem.
We are running version 10g Oracle and we will start receiving XML files with employee data that needs loading into a table, this is the XML file:
<?xml version="1.0"?>
<RECRUITS>
<RECRUIT>
<FIRST_NAME>Gordon</FIRST_NAME>
<LAST_NAME>Brown</LAST_NAME>
<SHORT_NAME>GORDONBROWN</SHORT_NAME>
<APP_NO>00002</APP_NO>
<STATUS>M</STATUS>
<DATE_FROM>21-JUL-2006</DATE_FROM>
<RESOURCE_TYPE>P</RESOURCE_TYPE>
<TITLE>Mr</TITLE>
<DATE_OF_BIRTH>28-DEC-1983</DATE_OF_BIRTH>
<SOCIAL_SEC>AB128456A</SOCIAL_SEC>
<PARTTIME_PCT>1</PARTTIME_PCT>
<SEX>M</SEX>
<ADDRESS_TYPE>1</ADDRESS_TYPE>
<ADDRESS>A HOUSE SOMEWHERE HERE</ADDRESS>
<ZIP_CODE>PE3 LLL</ZIP_CODE>
<PLACE>BOROUGH</PLACE>
<COUNTRY_CODE>UK</COUNTRY_CODE>
<PROVINCE>UK</PROVINCE>
<EMAIL>[email protected]</EMAIL>
</RECRUIT>
(FYI - there may be more than 1 employee in each file so all of the above will be repeated X amount of times)
</RECRUITS>
To make things simple we have created a table which mirrors the XML file completely to load the data into, the SQL i have used is thus:
CREATE TABLE RECRUITMENT
FIRST_NAME VARCHAR2(30),
LAST_NAME VARCHAR2(30),
SHORT_NAME VARCHAR2(30),
APP_NO NUMBER,
STATUS VARCHAR2(1),
DATE_FROM DATE,
RESOURCE_TYPE VARCHAR2(1),
TITLE VARCHAR2(4),
DATE_OF_BIRTH DATE,
SOCIAL_SEC VARCHAR2(9),
PARTTIME_PCT NUMBER,
SEX VARCHAR2(1),
ADDRESS_TYPE VARCHAR2(1),
ADDRESS VARCHAR2(30),
ZIP_CODE VARCHAR2(8),
PLACE VARCHAR2(10),
PROVINCE VARCHAR2(3),
EMAIL VARCHAR2(20)
Every method we try from the numerous documents and so called "user guides" have failed, please can somebody show me the PL/SQL i need to get this files data into the above table?
We need to be able to do this purely through SQL*PLUS as we hope - if we ever get it working manually to create a procuedure that will encapsulate everything so it can be run over and over again.
The XML file is sitting in the XMLDIR and is called REC.XML.
Please help : (

Hi, I have got some material for inserting data into oracle table from xml file, this might help you.
Create XML Document Table
create table XML_DOCUMENT_TABLE
FILENAME varchar2(64),
XML_DOCUMENT XMLTYPE
(This will be as per your record details).
Inserting record to Oracle Table
declare
XML_TEXT CLOB := '<smsnotification>
               <messageid> 256427844 </messageid>
          <protocolid> CO0NPS2KHQ </protocolid>
          <notifiedon> 1156123007416 </notifiedon>
          <status> 3PBI: Invalid </status>
<additionalinfo> Customer account not active </additionalinfo>
<carrierid> 1175 </carrierid>
</smsnotification>';
begin
insert into XML_DOCUMENT_TABLE values ('Receipt.xml',XMLTYPE(XML_TEXT));
end;
Select Statement
select extractValue(XML_DOCUMENT,'/smsnotification/messageid') Messageid,
extractValue(XML_DOCUMENT,'/smsnotification/status') Status,
extractValue(XML_DOCUMENT,'/smsnotification/carrierid') CarrierID
from XML_DOCUMENT_TABLE;

How can we get tag of XML file using SAX

Hi ,
I'm parsing one SAX parser , I'have almost done this parsing. i have faced problem for one case, i'e how can we get tag from XML file using SAX parser?
XML file is
<DFProperties>
<AccessType>
<Get/>
</AccessType> <Description>
gdhhd
</Description>
<DFFormat>
<chr/>
</DFFormat>
<Scope>
<Permanent/>
</Scope>
<DFTitle>gsgd</DFTitle>
<DFType>
<MIME>text/plain</MIME>
</DFType>
</DFProperties>
I want out like GET and Permanent... means this one tag which is present inside of another tag.
Handler class like
public void startElement(String namespaceURI, String localName,
               String qName, Attributes atts) throws SAXException {
if(_ACCESSTYPE.equals(localName)){
               accessTypeElement=ACCESSTYPE;
public void characters(char[] ch, int start, int length)
               throws SAXException {
if (_ACCESSTYPE.equals(_accessTypeElement)) {
               String strValue = new String(ch, start, length);
               System.out.println("Accestype-----------------------------> " + strValue);
               //System.out.println(" " + strValue);
public void endElement(String namespaceURI, String localName, String qName)
               throws SAXException {
if (_ACCESSTYPE.equals(localName)) {
               _accessTypeElement = "";
. please any body help me

Hi ,
I have one problem,Please help me.
1. How can I'll identify where exactly my Node is ended,means how how can we find corresponding nodename? in partcular place
<Node> .............starttag1
<NodeName>Test</NodeName>
<Node>................starttag2
<nodeName>test1</NodeName>
</Node>..................endtag2
<Node>.....................starttag3
<NodeName><NodeName>
<Node> .........................starttag4
<NodeName>test4</NodeName>
</Node>.......enddtag4
</Node>...........end tag3
</Node>............endtag1
my code is below
private final String _NODENAME = "NodeName";
private final String _NODE = "Node";
private String _nodeElement = "";
     private String _NodeNameElement = "";
public void startElement(String namespaceURI, String localName,
               String qName, Attributes atts) throws SAXException {
if (_NODENAME.equals(localName)) {
               NodeNameElement = NODENAME;
if(_NODE.equals(localName)){
     System.out.println("start");
     if (_NODENAME.equals(localName)) {
               NodeNameElement = NODENAME;
public void characters(char[] ch, int start, int length)
               throws SAXException {
if (_NODENAME.equals(_NodeNameElement)) {
               String strValue = new String(ch, start, length);
               String sttt=strValue;
               System.out.println("NODENAME: ************* " + strValue);
if(_NODE.equals(_nodeElement)){
               if (_NODENAME.equals(_NodeNameElement)) {
                    String strValue = new String(ch, start, length);
                    String sttt=strValue;
                    System.out.println("nodevalue********** " + strValue);
public void endElement(String namespaceURI, String localName, String qName)
               throws SAXException {
if (_NODENAME.equals(localName)) {
               _NodeNameElement = "";
if(_NODE.equals(localName)){
               System.out.println("NODENAME: %%%%%%%%%");
please help me. How can I figure node ending for particular nodename

How must getElementsByTagName work on an xml file with namespaces?

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