How to achieve an outer join with existsNode() function
I have a requirement to do an outer join with existsNode() function in my where clause. At present my where clause for join is like below
WHERE A.SOME_ID= “XYZ”
AND existsNode (B.SOMEXML_FEILD , …. ) = 1
AND existsNode (C.SOMEOTHERXML_FEILD , …. ) = 1
In this case if the existsNode fails on B or C, I still want data from A to be selected. How to rewrite this query to achieve that? I kinda want to achieve an outer join
Hi,
is this what you are looking for:
SQL> with t as(select 1 id1,'A' name from dual union all
2 select 2 ,'B' name from dual union all
3 select 3,'C' from dual)
4 ,x as(select 1 id2,xmltype('<a>a</a>') xcol from dual union all
5 select 2 ,xmltype('<b>b</b>') xcol from dual)
6 select *
7 from t,x
8 where t.id1=x.id2(+)
9 and (existsNode(x.xcol,'/a')=1 or x.xcol is null);
ID1 N ID2 XCOL
1 A 1 <a>a</a>
3 C
SQL> spool off;
Similar Messages
-
Hello
I am trying to translate the following Sybase Query to Oracle . I am running the query on a 10gR1 database.
The problem is with the NVL clause on the join I am getting a runtime exception .
Is there a way to re-write this query without breaking the functionality.
SELECT t1.*,
NVL(t2.Branch_name, t3.Branch_name)
FROM table1 t1
LEFT OUTER JOIN
table2 t2
ON (t1.Account_id = t2.Account_id)
LEFT OUTER JOIN
table3 t3
ON (t1.Account_id = t3.Account_id)
LEFT OUTER JOIN
table4 t4
ON (NVL(t2.Branch_Name, t3.Branch_Name) = t4.cost_centre);
ThanksThe original query had a insert statement and it was failing with ORA-01400 even though the select query fetched 0 rows
Insert into Branch_Master
SELECT t1.*,
NVL(t2.Branch_name, t3.Branch_name)
FROM table1 t1
LEFT OUTER JOIN
table2 t2
ON (t1.Account_id = t2.Account_id)
LEFT OUTER JOIN
table3 t3
ON (t1.Account_id = t3.Account_id)
LEFT OUTER JOIN
table4 t4
ON (NVL(t2.Branch_Name, t3.Branch_Name) = t4.cost_centre);
ksedmp: internal or fatal error
ORA-01400: cannot insert NULL into ("<<schema_name>>"."Branch_Master"."BRANCH_NAME")
I have re-written the query using a Inline view . Can you please review and let me know if it is ok
select * from
( SELECT t1.*,
NVL(t2.Branch_name, t3.Branch_name) Branch_name_final
FROM table1 t1
LEFT OUTER JOIN
table2 t2
ON (t1.Account_id = t2.Account_id)
LEFT OUTER JOIN
table3 t3
ON (t1.Account_id = t3.Account_id) ) IV_Temp
LEFT OUTER JOIN Table4 on (IV_temp.Branch_name_final = T4.cost_centre ; -
Outer Join with Where Clause in LTS
HI all,
I have a requirement like this in ANSI SQL:
select p1.product_id, p1.product_name, p2.product_group
from product p1 left outer join product_group p2 on p1.product_id = p2.product_id
and p2.product_group = 'NEW'
In Regular SQL:
select p1.product_id, p1.product_name, p2.product_group
from product p1, product_group p2
WHERE p1.product_id *= p2.product_id and p2.product_group = 'NEW'
In OBIEE, I am using a left outer join between these two in Logical table Source, and also, Gave
p2.product_group = 'NEW' in WHERE clause of LTS.
This doesn't seem to solve purpose.
Do you have any idea how to convert WHERE clause in physical query that OBIEE is generating to something like
product p1 left outer join product_group p2 on p1.product_id = p2.product_id AND p2.product_group = 'NEW'
I am using Version 10.1.3.4.1
Creating an Opaque view would be my last option though.Hello
I have read your post and the responses as well. and I understand that you have issues with the Outer Join with where Clause in LTS.
Try this solution which worked for me (using your example ) -
1. In the Physical Layer created a Complex join between PRODUCT and PRODUCT_GROUP tables and use this join relationship :
PRODUCT.PROD_ID = PRODUCT_GROUP.PROD_ID AND PRODUCT_GROUP.GROUP_NAME = 'MECHANICAL'
2. In the General Tab of PRODUCT table LTS add PRODUCT_GROUP table and select Join Type as Left Outer Join.
3. Check Consistency and make sure there are no errors .
when you run a request you should see the following query generated -
select distinct T26908.PROD_ID as c1,
T26908.PROD_NAME as c2,
T26912.GROUP_NAME as c3
from
PRODUCT T26908 left outer join PRODUCT_GROUP T26912 On T26908.PROD_ID = T26912.PROD_ID and T26912.GROUP_NAME = 'MECHANICAL'
order by c1, c2, c3
Hope this works for you. If it does please mark this response as 'Correct' .
Good Luck. -
How to use left outer joins ,right outer joins and order by clause for belo
Hi,
How to use left outer joins ,right outer joins and order by clause for below XML query.
The query which is red colour returns null then its not displaying any values for columns in that tables. Tried decode, nvl function hasn't worked.
SELECT XMLAGG ( XMLELEMENT( "P", XMLFOREST( P.process_id AS Ppid,
(SELECT XMLAGG( XMLELEMENT( "PI", XMLFOREST( PI.question_id AS PIqid,
PI.process_id AS PIpid,
PI.innertext AS
PItext, PI.itemtype AS PItype,
PI.linkfrom AS PIfrom,
PI.linkto AS PIto,
PI.associated AS PIas,
PI.content_id AS PIc,
PI.exitpoint1_id AS PIe1,
PI.exitpoint2_id AS PIe2,
PI.exitpoint3_id AS PIe3,
PI.followoncall AS PIfoc,
PI.userinput AS PIui,
PI.resolveidentifier AS PIri,
PI.libquestion_idfk AS PIlqid,
PI.isLocked AS PIstls,
PI.PreviousAnswer AS PIPAns,
PI.VisibleToAgent AS PIVAgent,
PI.RetryAttempt AS PIRetry,
PI.Tags AS PITag,
SELECT XMLAGG( XMLELEMENT( "PO", XMLFOREST( PO.option_id AS POoid,
PO.question_id AS POqid,
PO.process_id AS popid,
PO.opt_innertext AS POtext,
PO.opt_linkfrom AS POfrom,
PO.opt_linkto AS POto,
PO.libquestion_idfk AS POlqid,
PO.liboption_idfk AS POloid ) ) )
FROM vw_liveProcessOption_Sim_v6 PO
WHERE PI.question_id = PO.question_id (+)
AND PI.process_id = PO.process_id (+)
) "A" ) ) ) AS "PO"
FROM vw_liveProcessItem_Sim_v6 PI
WHERE P.process_id = PI.process_id
) "A" ) ) ) AS "PI"
FROM liveProcess_ec P
WHERE (P.process_id = 450)
Any help really appreciated.
Thanksuser512743 wrote:
Hi,
Here below is the scripts of tables, insert statements and Required output.
CREATE TABLE VW_LIVEPROCESSOPTION_SIM_v6
( "OPTION_ID" NUMBER,
"QUESTION_ID" NUMBER(10,0),
"PROCESS_ID" NUMBER(10,0),
"OPT_INNERTEXT" VARCHAR2(200 CHAR),
"OPT_LINKFROM" VARCHAR2(20 CHAR),
"OPT_LINKTO" VARCHAR2(20 CHAR),
"LIBQUESTION_IDFK" NUMBER,
"LIBOPTION_IDFK" NUMBER
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,2,450,'Yes',null,'5',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,3,450,'Yes',null,'5',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,5,450,'Yes',null,'6',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,6,450,'Yes',null,'7',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,8,450,'Block All',null,'9',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,9,450,'Yes',null,'10',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,11,450,'Yes',null,'12',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,12,450,'Yes',null,'13',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,14,450,'Yes',null,'16',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,2,450,'No',null,'3',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,3,450,'No',null,'4',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,5,450,'No',null,'8',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,6,450,'No',null,'8',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,8,450,'Standard',null,'11',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,9,450,'No',null,'11',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,11,450,'No',null,'14',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,12,450,'No',null,'14',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,14,450,'No',null,'15',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (3,8,450,'Disabled',null,'12',null,null);
Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (4,8,450,'User Defined',null,'12',null,null);
REATE TABLE "VW_LIVEPROCESSITEM_SIM_v6"
( "QUESTION_ID" NUMBER(10,0),
"PROCESS_ID" NUMBER(10,0),
"INNERTEXT" VARCHAR2(200 CHAR),
"ITEMTYPE" VARCHAR2(50 CHAR),
"LINKFROM" VARCHAR2(500 CHAR),
"LINKTO" VARCHAR2(500 CHAR),
"ASSOCIATED" VARCHAR2(200 CHAR),
"CONTENT_ID" NUMBER,
"EXITPOINT1_ID" NUMBER(10,0),
"EXITPOINT2_ID" NUMBER(10,0),
"EXITPOINT3_ID" NUMBER(10,0),
"RESOLVEIDENTIFIER" VARCHAR2(40 CHAR),
"LIBQUESTION_IDFK" NUMBER(10,0),
"FOLLOWONCALL" NUMBER(1,0),
"USERINPUT" VARCHAR2(200 CHAR),
"ISLOCKED" NUMBER(1,0),
"PREVIOUSANSWER" NUMBER(1,0),
"VISIBLETOAGENT" NUMBER(1,0),
"RETRYATTEMPT" NUMBER(10,0),
"TAGS" VARCHAR2(50 BYTE)
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (1,450,'CBB1015 - Router Firewall Settinngs Process','Title',null,'2',null,null,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (2,450,'Is the customers PC Firewall turned off?','Question','1','2.2,2.1',null,null,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (3,450,'Advise the customer to turn off the PC Firewall in order to continue. Has this been done?','Question','2.2','3.2,3.1',null,278,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (4,450,'Advise the customer the PC Firewall must be switched off before this process????','ExitPoint','3.2',null,null,null,14,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (5,450,'Is the customer able to access the internet now?','Question','3.1,2.1','5.2,5.1',null,null,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (6,450,'Is the customer having a problem with a specific website?','Question','5.1','6.2,6.1',null,null,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (7,450,'1536: CBB1008 - Browser Setup and Daignostics','SubProcess','6.1',null,'1536-1-0',null,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (8,450,'What is the security level on the CPE Management page?','Question','6.2,5.2','8.4,8.3,8.2,8.1',null,279,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (9,450,'Change the security level to Standard. Does this resolve the customers issue?','Question','8.1','9.2,9.1',null,280,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (10,450,'Issue Resolved','ExitPoint','9.1',null,null,null,1,6,122,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (11,450,'Change the security level to Disabled. Is the customer able to browse the internet?','Question','9.2,8.2','11.2,11.1',null,281,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (12,450,'Change the security level to Standard. Is the customer able to browse the internet now?','Question','11.1,8.3,8.4','12.2,12.1',null,283,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (13,450,'Issue Resolved','ExitPoint','12.1',null,null,null,1,6,123,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (14,450,'Ask the customer to perform a master reset. Does this resolve their issue?','Question','12.2,11.2','14.2,14.1',null,282,null,null,null,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (15,450,'Faulty CPE','ExitPoint','14.2',null,null,null,1,6,124,null,null,null,null,null,null,null,null,null);
Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (16,450,'Issue Resolved','ExitPoint','14.1',null,null,null,1,6,123,null,null,null,null,null,null,null,null,null);
CREATE TABLE "LIVEPROCESS_EC_V"
( "PROCESS_ID" NUMBER(10,0),
"USER_ID" NUMBER(10,0),
"CREATED" TIMESTAMP (6)
Insert into LIVEPROCESS_EC (PROCESS_ID,USER_ID,CREATED) values (450,7460,to_timestamp('21-APR-08 09.34.41.000000000 AM','DD-MON-RR HH.MI.SS.FF AM'));
Required O/P in XML format
<P>
<Ppid>450</Ppid>
<PI>
<PIqid>1</PIqid>
<PIpid>450</PIpid>
<PItext>CBB1015 - Router Firewall Settinngs Process</PItext>
<PItype>Title</PItype>
<PIto>2</PIto>
<PO />
</PI>
<PI>
<PIqid>2</PIqid>
<PIpid>450</PIpid>
<PItext>Is the customers PC Firewall turned off?</PItext>
<PItype>Question</PItype>
<PIfrom>1</PIfrom>
<PIto>2.2,2.1</PIto>
<PO>
<POoid>1</POoid>
<POqid>2</POqid>
<popid>450</popid>
<POtext>Yes</POtext>
<POto>5</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>2</POqid>
<popid>450</popid>
<POtext>No</POtext>
<POto>3</POto>
</PO>
</PI>
<PI>
<PIqid>3</PIqid>
<PIpid>450</PIpid>
<PItext>Advise the customer to turn off the PC Firewall in order to continue. Has this been done?</PItext>
<PItype>Question</PItype>
<PIfrom>2.2</PIfrom>
<PIto>3.2,3.1</PIto>
<PIc>278</PIc>
<PO>
<POoid>1</POoid>
<POqid>3</POqid>
<popid>450</popid>
<POtext>Yes</POtext>
<POto>5</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>3</POqid>
<popid>450</popid>
<POtext>No</POtext>
<POto>4</POto>
</PO>
</PI>
<PI>
<PIqid>4</PIqid>
<PIpid>450</PIpid>
<PItext>Advise the customer the PC Firewall must be switched off before this process????</PItext>
<PItype>ExitPoint</PItype>
<PIfrom>3.2</PIfrom>
<PIe1>14</PIe1>
<PO />
</PI>
<PI>
<PIqid>5</PIqid>
<PIpid>450</PIpid>
<PItext>Is the customer able to access the internet now?</PItext>
<PItype>Question</PItype>
<PIfrom>3.1,2.1</PIfrom>
<PIto>5.2,5.1</PIto>
<PO>
<POoid>1</POoid>
<POqid>5</POqid>
<popid>450</popid>
<POtext>Yes</POtext>
<POto>6</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>5</POqid>
<popid>450</popid>
<POtext>No</POtext>
<POto>8</POto>
</PO>
</PI>
<PI>
<PIqid>6</PIqid>
<PIpid>450</PIpid>
<PItext>Is the customer having a problem with a specific website?</PItext>
<PItype>Question</PItype>
<PIfrom>5.1</PIfrom>
<PIto>6.2,6.1</PIto>
<PO>
<POoid>1</POoid>
<POqid>6</POqid>
<popid>450</popid>
<POtext>Yes</POtext>
<POto>7</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>6</POqid>
<popid>450</popid>
<POtext>No</POtext>
<POto>8</POto>
</PO>
</PI>
<PI>
<PIqid>7</PIqid>
<PIpid>450</PIpid>
<PItext>1536: CBB1008 - Browser Setup and Daignostics</PItext>
<PItype>SubProcess</PItype>
<PIfrom>6.1</PIfrom>
<PIas>1536-1-0</PIas>
<PO />
</PI>
<PI>
<PIqid>8</PIqid>
<PIpid>450</PIpid>
<PItext>What is the security level on the CPE Management page?</PItext>
<PItype>Question</PItype>
<PIfrom>6.2,5.2</PIfrom>
<PIto>8.4,8.3,8.2,8.1</PIto>
<PIc>279</PIc>
<PO>
<POoid>1</POoid>
<POqid>8</POqid>
<popid>450</popid>
<POtext>Block All</POtext>
<POto>9</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>8</POqid>
<popid>450</popid>
<POtext>Standard</POtext>
<POto>11</POto>
</PO>
<PO>
<POoid>3</POoid>
<POqid>8</POqid>
<popid>450</popid>
<POtext>Disabled</POtext>
<POto>12</POto>
</PO>
<PO>
<POoid>4</POoid>
<POqid>8</POqid>
<popid>450</popid>
<POtext>User Defined</POtext>
<POto>12</POto>
</PO>
</PI>
<PI>
<PIqid>9</PIqid>
<PIpid>450</PIpid>
<PItext>Change the security level to Standard. Does this resolve the customers issue?</PItext>
<PItype>Question</PItype>
<PIfrom>8.1</PIfrom>
<PIto>9.2,9.1</PIto>
<PIc>280</PIc>
<PO>
<POoid>1</POoid>
<POqid>9</POqid>
<popid>450</popid>
<POtext>Yes</POtext>
<POto>10</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>9</POqid>
<popid>450</popid>
<POtext>No</POtext>
<POto>11</POto>
</PO>
</PI>
<PI>
<PIqid>10</PIqid>
<PIpid>450</PIpid>
<PItext>Issue Resolved</PItext>
<PItype>ExitPoint</PItype>
<PIfrom>9.1</PIfrom>
<PIe1>1</PIe1>
<PIe2>6</PIe2>
<PIe3>122</PIe3>
<PO />
</PI>
<PI>
<PIqid>11</PIqid>
<PIpid>450</PIpid>
<PItext>Change the security level to Disabled. Is the customer able to browse the internet?</PItext>
<PItype>Question</PItype>
<PIfrom>9.2,8.2</PIfrom>
<PIto>11.2,11.1</PIto>
<PIc>281</PIc>
<PO>
<POoid>1</POoid>
<POqid>11</POqid>
<popid>450</popid>
<POtext>Yes</POtext>
<POto>12</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>11</POqid>
<popid>450</popid>
<POtext>No</POtext>
<POto>14</POto>
</PO>
</PI>
<PI>
<PIqid>12</PIqid>
<PIpid>450</PIpid>
<PItext>Change the security level to Standard. Is the customer able to browse the internet now?</PItext>
<PItype>Question</PItype>
<PIfrom>11.1,8.3,8.4</PIfrom>
<PIto>12.2,12.1</PIto>
<PIc>283</PIc>
<PO>
<POoid>1</POoid>
<POqid>12</POqid>
<popid>450</popid>
<POtext>Yes</POtext>
<POto>13</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>12</POqid>
<popid>450</popid>
<POtext>No</POtext>
<POto>14</POto>
</PO>
</PI>
<PI>
<PIqid>13</PIqid>
<PIpid>450</PIpid>
<PItext>Issue Resolved</PItext>
<PItype>ExitPoint</PItype>
<PIfrom>12.1</PIfrom>
<PIe1>1</PIe1>
<PIe2>6</PIe2>
<PIe3>123</PIe3>
<PO />
</PI>
<PI>
<PIqid>14</PIqid>
<PIpid>450</PIpid>
<PItext>Ask the customer to perform a master reset. Does this resolve their issue?</PItext>
<PItype>Question</PItype>
<PIfrom>12.2,11.2</PIfrom>
<PIto>14.2,14.1</PIto>
<PIc>282</PIc>
<PO>
<POoid>1</POoid>
<POqid>14</POqid>
<popid>450</popid>
<POtext>Yes</POtext>
<POto>16</POto>
</PO>
<PO>
<POoid>2</POoid>
<POqid>14</POqid>
<popid>450</popid>
<POtext>No</POtext>
<POto>15</POto>
</PO>
</PI>
<PI>
<PIqid>15</PIqid>
<PIpid>450</PIpid>
<PItext>Faulty CPE</PItext>
<PItype>ExitPoint</PItype>
<PIfrom>14.2</PIfrom>
<PIe1>1</PIe1>
<PIe2>6</PIe2>
<PIe3>124</PIe3>
<PO />
</PI>
<PI>
<PIqid>16</PIqid>
<PIpid>450</PIpid>
<PItext>Issue Resolved</PItext>
<PItype>ExitPoint</PItype>
<PIfrom>14.1</PIfrom>
<PIe1>1</PIe1>
<PIe2>6</PIe2>
<PIe3>123</PIe3>
<PO />
</PI>
</P>
Thanks in advance
Edited by: user512743 on Nov 18, 2008 4:46 AM -
I have a very complicated query to construct that requires the use of 'AND', 'OR', and Outer Joins. Oracle's 9i documentation says you can't use an outer join with an 'OR'.
Can you suggest how I may return the correct records under the following conditions. There are 3 tables to join. Table A, Table B, and Table C. Tables A & B join with an = to common fields. The problem is with Table C.
The way the application was designed, it has to track a parent and child relationship. As such, the field to relate may exist in 1 of 2 fields. Let's see if I can draw it out for you.
Table A - Record 1
(ID = 1)
Table B - Record 1
(ID =1 [this relates to Table A.ID]
PID = 12345
CID = 67899
Site = A)
Table C - Record 1
(PID = 12345 [this relates to Table B.PID]
CID = 67899
Site = A)
Table C - Record 2
(PID = 67899 [This relates to Table B.CID]
CID = 12345
Site = A)
Now, I need to relate Table A to Table B where A.ID = B.ID AND
((B.PID = C.PID AND B.CID = C.CID)
OR
(B.CID = C.PID AND B.PID = C.CID))
AND
B.SITE = C.SITE
There may or may NOT be related records in Table C. That's the problem. This is where I need the outer join to get the all the records of the 1st two joins and only those that apply from the last join.
Your help will be greatly appreciated.I'd create two queries, a join from b to c in each of those manners and then UNION ALL the results together.
drop table junk_a;
create table junk_a (
id number );
drop table junk_b;
create table junk_b (
id number,
pid number,
cid number,
site varchar2(80) );
drop table junk_c;
create table junk_c (
pid number,
cid number,
site varchar2(80) );
insert into junk_a values (1);
insert into junk_b values (1, 12345, 67899, 'A');
insert into junk_c values (12345, 67899, 'A');
insert into junk_c values (67899, 12345, 'A');
commit;
SELECT b.*,
c.site AS site_c
FROM junk_b b,
junk_c c
WHERE c.pid(+) = b.pid
AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
c.site AS site_c
FROM junk_b b,
junk_c c
WHERE c.cid(+) = b.pid
AND c.pid(+) = b.cid;
SELECT a.id,
bc.pid,
bc.cid,
bc.site,
bc.site_c
FROM junk_a a,
SELECT b.*,
c.site AS site_c
FROM junk_b b,
junk_c c
WHERE c.pid(+) = b.pid
AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
c.site AS site_c
FROM junk_b b,
junk_c c
WHERE c.cid(+) = b.pid
AND c.pid(+) = b.cid
) bc
WHERE bc.id(+) = a.id; -
I have written the below query, our requirement is, Some employees have "Transport Allowance" but not "Project Allowance". For this, I tried to use OUTER JOIN with this query. But this query takes long time and failed. The following query works fine if the employee has both "Transport Allowance" and "Project Allowance" (without outer join) Now, I also need to retrieve the employees who have "Transport Allowance" but not "Project Allowance". How can I retrieve it?
SELECT DISTINCT papf.employee_number
, peev.screen_entry_value Transport_Allowance
,peev1.screen_entry_value Project_Allowance
FROM apps.per_all_people_f papf
,apps.per_all_assignments_f paaf
,apps.pay_element_types_x petf
,apps.pay_element_types_x petf1
,apps.pay_element_types_x petf2
,apps.pay_element_entries_f peef
,apps.pay_element_entries_f peef1
,apps.pay_element_entries_f peef2
,apps.pay_element_entry_values_x peev
,apps.pay_element_entry_values_x peev1
,apps.pay_element_entry_values_x peev2
,apps.pay_input_values_x pivf
,apps.pay_input_values_x pivf1
,apps.pay_input_values_x pivf2
WHERE
papf.person_id = paaf.person_id
AND paaf.assignment_id = peef.assignment_id
AND paaf.assignment_id = peef1.assignment_id
AND paaf.business_group_id = papf.business_group_id
--Transport Allowance
AND peef.element_entry_id = peev.element_entry_id
AND petf.element_Name = 'Transport Allowance'
AND pivf.element_type_id =petf.element_type_id
AND pivf.name = 'Allowance'
AND peev.input_value_id= pivf.input_value_id
--Project Allowance
AND peef1.element_entry_id = peev1.element_entry_id
AND petf1.element_Name = "Project Allowance'
AND pivf1.element_type_id = petf1.element_type_id
AND pivf1.name = 'Allowance'
AND peev1.input_value_id = pivf1.input_value_id
AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
ORDER BY papf.employee_number
Thanks in advance.I am using sames tables with alias to retrieve the columns values from the same table.
Here is my query.
SELECT DISTINCT papf.employee_number
, peev.screen_entry_value Transport_Allowance
,peev1.screen_entry_value Project_Allowance
FROM apps.per_all_people_f papf
,apps.per_all_assignments_f paaf
,apps.pay_element_types_x petf
,apps.pay_element_types_x petf1
,apps.pay_element_entries_f peef
,apps.pay_element_entries_f peef1
,apps.pay_element_entry_values_x peev
,apps.pay_element_entry_values_x peev1
,apps.pay_input_values_x pivf
,apps.pay_input_values_x pivf1
WHERE
papf.person_id = paaf.person_id
AND paaf.assignment_id = peef.assignment_id
AND paaf.assignment_id = peef1.assignment_id
AND paaf.business_group_id = papf.business_group_id
--Transport Allowance
AND peef.element_entry_id = peev.element_entry_id
AND petf.element_Name = 'Transport Allowance'
AND pivf.element_type_id =petf.element_type_id
AND pivf.name = 'Allowance'
AND peev.input_value_id= pivf.input_value_id
--Project Allowance
AND peef1.element_entry_id = peev1.element_entry_id
AND petf1.element_Name = "Project Allowance'
AND pivf1.element_type_id = petf1.element_type_id
AND pivf1.name = 'Allowance'
AND peev1.input_value_id = pivf1.input_value_id
AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
ORDER BY papf.employee_number
Thanks in advance. -
Outer join with BETWEEN clause
Hi All,
I have 2 tables (A and B) which i need to join. I need all records from table A and matching records from the table B. below is the structure.
TABLE A (total rows = 10)
ROW_WID
GL_DATE
LOCATION_CODE
TABLE B (total = 7)
ROW_WID
START_DATE
END_DATE
LOCATION_CODE
Initially, we were asked to join based on location_code. In the table B, some of the LOCATION_CODE are missing, which is present in table A.
We wrote below query
SELECT A.*, B.START_DATE, B.END_DATE
FROM A, B
WHERE A.LOCATION_CODE = B.LOCATION_CODE (+)
This gives 10 records, where 3 records have START_DATE and END_DATE NULL. because of outer join
It gave all records from the A table. It worked fine. Now i need to add one more condition where A.GL_DATE between B.START_DATE and B.END_DATE
If i write this
SELECT A.*, B.START_DATE, B.END_DATE
FROM A, B
WHERE A.LOCATION_CODE = B.LOCATION_CODE (+)
AND A.GL_DATE BETWEEN B.START_DATE and B.END_DATE
This gives me only 7 records. IS IT POSSIBLE TO ADD OUTER JOIN with BETWEEN clause.Hi All,
I'm in a similar situation,
I have a complex query, everything is working fine, except this part (I will simplify everything, removing other stuffs because I need help only on the following condition)
SELECT *
from transaction t, card c
where c.card_id = t.card_id (+)
and t.trn_date between to_date ('01/01/2012','dd/mm/yy') and ('01/01/2013,'dd/mm/yy')
How could i OUTER JOIN the between condition?
I tried with
and t.trn_date between to_date ('01/01/2012','dd/mm/yy') (+) and ('01/01/2013','dd/mm/yy') (+)
but returns a "missing expression" error.
Surely I'm missing some stupid thing about it, could you help me on this? (probably because I'm talking about parameters and I cannot put the outer join on a value)
How can I rewrite the condition in order to satisfy what I'm trying to accomplish?
Thanks in Advance,
Alex
Edited by: 981667 on 14-gen-2013 4.23
Edited by: 981667 on 14-gen-2013 4.24 -
Join columns of outer join with table have no uniqueness cons
Hi! I'm getting noizy error in alert log from time to time:
Join columns of outer join with table <table_name> have no uniqueness constraints
I've collected all the queries (v$sql, all_source) with montioned table, but non of them produces that error if executed.
Any hints how to reproduce this error or where else to search that buggy sql join?
Edited by: user545083 on 25.10.2010 6:21Hi
I think this error is output via an materialized view refresh - check for mviews against the given table which fulfil the issue given in the error text.
Thanks
Paul -
Problem with outer join with filter on join column
Hi,
In physical layer I have one dimension and two facts, and there's an outer join between the facts.
dim_DATE ,
fact_1 ,
fact_2
Joins:
dim_DATE inner join fact_1 on dim_DATE.DATE = fact_1.DATE
fact_1 left outer join fact_2 on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
When I run a report with a date as a filter, OBIEE executes "optimized" physical SQL:
select fact1.X, fact2.Y
from
Fact_1 left outer join on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
where Fact_1.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD' )
and Fact_2.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD')
The filter on Fact_2.DATE effectively replaces outer join with inner.
Is there a way to disable this "optimization", which is actually very good for inner joins, but doesn't allow outer joins?
Thanks in advance,
Alex
Edited by: AM_1 on Aug 11, 2009 8:20 AMIf you want to perform a Fact-based partitioning with OBIEE (two fact with the same dimension), you have to :
* create in your physical layer for each fact table the joins with the dimension
* create in the Business Model layer ONE star schema with ONE logical fact table containing the columns of your two physical fact table
In this way when you choose minimal one column of your fact1 and one column of your fact2, OBIEE will perform two query against each fact table/dimension, join them with an OUTER JOIN and your problem will disappear.
Cheers
Nico -
How Can We Tune the Joins with "OR" Caluse ?
Hi
We've identified one Query in one of Our PL/SQL Stored Procedure which is taking huge time to fetch the records. I have simulated the problem as shown below. The problem Is, How can i tune the Jions with "OR" Clause. i have tried replacing them with Exists Caluse, But the Performance was not much was expected.
CREATE TABLE TEST
(ID NUMBER VDATE DATE );
BEGIN
FOR i IN 1 .. 100000 LOOP
INSERT INTO TEST
VALUES
(i, TO_DATE(TRUNC(DBMS_RANDOM.VALUE(2452641, 2452641 + 364)), 'J'));
IF MOD(i, 1000) = 0 THEN
COMMIT;
END IF;
END LOOP;
END;
CREATE TABLE RTEST1 ( ID NUMBER, VMONTH NUMBER );
INSERT INTO RTEST1
SELECT ID, TO_NUMBER(TO_CHAR(VDATE,'MM'))
FROM TEST ;
CREATE TABLE RTEST2 ( ID NUMBER, VMONTH NUMBER );
INSERT INTO RTEST2
SELECT ID, TO_NUMBER(TO_CHAR(VDATE,'MM'))
FROM TEST;
CREATE INDEX RTEST1_IDX2 ON RTEST1(VMONTH)
CREATE INDEX RTEST2_IDX1 ON RTEST2(VMONTH)
ALTER TABLE RTEST1 ADD CONSTRAINT RTEST1_PK PRIMARY KEY (ID)
ALTER TABLE RTEST2 ADD CONSTRAINT RTEST2_PK PRIMARY KEY (ID)
SELECT A.ID, B.VMONTH
FROM RTEST1 A , RTEST2 B
WHERE A.ID = B.ID
AND ( (A.ID = B.VMONTH) OR ( B.ID = A.VMONTH ) )
BEGIN
DBMS_STATS.gather_table_stats(ownname => 'PHASE30DEV',tabname => 'RTEST1');
DBMS_STATS.gather_table_stats(ownname => 'PHASE30DEV',tabname => 'RTEST2');
DBMS_STATS.gather_index_stats(ownname => 'PHASE30DEV',indname => 'RTEST1_IDX1');
DBMS_STATS.gather_index_stats(ownname => 'PHASE30DEV',indname => 'RTEST2_IDX2');
DBMS_STATS.gather_index_stats(ownname => 'PHASE30DEV',indname => 'RTEST1_IDX2');
DBMS_STATS.gather_index_stats(ownname => 'PHASE30DEV',indname => 'RTEST2_IDX1');
END; Pls suggest !!!!!!! How can I tune the Joins with "OR" Clause.
Regards
RJI don't like it, but you could use a hint:
SQL>r
1 SELECT A.ID, B.VMONTH
2 FROM RTEST1 A , RTEST2 B
3 WHERE A.ID = B.ID
4* AND ( (A.ID = B.VMONTH) OR ( B.ID = A.VMONTH ) )
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=94 Card=2 Bytes=28)
1 0 TABLE ACCESS (BY INDEX ROWID) OF 'RTEST2' (Cost=94 Card=1 Bytes=7)
2 1 NESTED LOOPS (Cost=94 Card=2 Bytes=28)
3 2 TABLE ACCESS (FULL) OF 'RTEST1' (Cost=20 Card=100000 Bytes=700000)
4 2 BITMAP CONVERSION (TO ROWIDS)
5 4 BITMAP AND
6 5 BITMAP CONVERSION (FROM ROWIDS)
7 6 INDEX (RANGE SCAN) OF 'RTEST2_PK' (UNIQUE)
8 5 BITMAP OR
9 8 BITMAP CONVERSION (FROM ROWIDS)
10 9 INDEX (RANGE SCAN) OF 'RTEST2_IDX1' (NON-UNIQUE)
11 8 BITMAP CONVERSION (FROM ROWIDS)
12 11 INDEX (RANGE SCAN) OF 'RTEST2_PK' (UNIQUE)
Statistics
0 recursive calls
0 db block gets
300332 consistent gets
0 physical reads
0 redo size
252 bytes sent via SQL*Net to client
235 bytes received via SQL*Net from client
2 SQL*Net roundtrips to/from client
0 sorts (memory)
0 sorts (disk)
2 rows processed
SQL>SELECT /*+ ordered use_hash(b) */ A.ID, B.VMONTH
2 FROM RTEST1 A, RTEST2 B
3 WHERE A.ID = B.ID AND(A.ID = B.VMONTH OR B.ID = A.VMONTH)
4 ;
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=175 Card=2 Bytes=28)
1 0 HASH JOIN (Cost=175 Card=2 Bytes=28)
2 1 TABLE ACCESS (FULL) OF 'RTEST1' (Cost=20 Card=100000 Bytes=700000)
3 1 TABLE ACCESS (FULL) OF 'RTEST2' (Cost=20 Card=100000 Bytes=700000)
Statistics
9 recursive calls
0 db block gets
256 consistent gets
156 physical reads
0 redo size
252 bytes sent via SQL*Net to client
235 bytes received via SQL*Net from client
2 SQL*Net roundtrips to/from client
0 sorts (memory)
0 sorts (disk)
2 rows processed -
Is there a tutorial on how to achieve Black/White photos with color details?
I am newbie with learning photoshop, Is there a tutorial on how to achieve Black/White photos with color details? similiar to this photo?
thanksType exactly that "black white photos with colour details with Photoshop" when searching online and you will find many examples on how to achieve this effect.
Examples:
Photoshop combining color with black and white - A non-destructive method - YouTube
How to Create Color Splash Effect | Adobe Photoshop cs5 - YouTube -
Maximum number of tables that can be outer joined with one table in a query
Hi All,
Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
Thanks,
Srinisrinu2 wrote:
Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
There is no limit to the number of tables you can outer join as long as you join them correctly.
SQL> with a as
2 (
3 select 1 id, 2 b_key, 3 c_key from dual union all
4 select 2 id, 1 b_key, 4 c_key from dual union all
5 select 3 id, 3 b_key, 1 c_key from dual union all
6 select 4 id, 4 b_key, 2 c_key from dual
7 ),
8 b as
9 (
10 select 1 id, 1 c_key2 from dual union all
11 select 2 id, 5 c_key2 from dual union all
12 select 3 id, 3 c_key2 from dual union all
13 select 4 id, 2 c_key2 from dual
14 ),
15 c as
16 (
17 select 1 key1, 1 key2, '1-1' dta from dual union all
18 select 1 key1, 2 key2, '1-2' dta from dual union all
19 select 1 key1, 3 key2, '1-3' dta from dual union all
20 select 1 key1, 4 key2, '1-4' dta from dual union all
21 select 2 key1, 1 key2, '2-1' dta from dual union all
22 select 2 key1, 2 key2, '2-2' dta from dual union all
23 select 2 key1, 3 key2, '2-3' dta from dual union all
24 select 2 key1, 4 key2, '2-4' dta from dual union all
25 select 3 key1, 1 key2, '3-1' dta from dual union all
26 select 3 key1, 2 key2, '3-2' dta from dual union all
27 select 3 key1, 3 key2, '3-3' dta from dual union all
28 select 3 key1, 4 key2, '3-4' dta from dual union all
29 select 4 key1, 1 key2, '4-1' dta from dual union all
30 select 4 key1, 2 key2, '4-2' dta from dual union all
31 select 4 key1, 3 key2, '4-3' dta from dual union all
32 select 4 key1, 4 key2, '4-4' dta from dual
33 )
34 select d.a_id, d.b_id, c.key1 as c_key1, c.key2 as c_key3, c.dta
35 from
36 c,
37 (
38 select
39 a.id as a_id, b.id as b_id, a.c_key, b.c_key2
40 from a, b
41 where a.b_key = b.id
42 ) d
43 where d.c_key = c.key1 (+)
44 and d.c_key2 = c.key2 (+);
A_ID B_ID C_KEY1 C_KEY3 DTA
3 3 1 3 1-3
4 4 2 2 2-2
2 1 4 1 4-1
1 2
SQL> -
Outer join With a constant value
Hi all,
In one of query i have found out that the outer join with a constant value like
to_currency(+)='USD'
to_currency is a column name in a table.can any one please explain this outer join condtn.
Thanks in advance
SenthilHallo,
if you write var (+) = constant
var can be equal constant, and also can be null
Compare these 2 queries
select e.* from scott.emp e, scott.dept d
where e.deptno = d.deptno(+)
and d.deptno(+) = 10EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7369 SMITH CLERK 7902 17-Dez-1980 800 20
7499 ALLEN SALESMAN 7698 20-Feb-1981 1600 300 30
7521 WARD SALESMAN 7698 22-Feb-1981 1250 500 30
7566 JONES MANAGER 7839 2-Apr-1981 2975 20
7654 MARTIN SALESMAN 7698 28-Sep-1981 1250 1400 30
7698 BLAKE MANAGER 7839 1-Mai-1981 2850 30
7782 CLARK MANAGER 7839 9-Jun-1981 2450 10
7788 SCOTT ANALYST 7566 19-Apr-1987 3000 20
7839 KING PRESIDENT 17-Nov-1981 5000 10
7844 TURNER SALESMAN 7698 8-Sep-1981 1500 0 30
7876 ADAMS CLERK 7788 23-Mai-1987 1100 20
7900 JAMES CLERK 7698 3-Dez-1981 950 30
7902 FORD ANALYST 7566 3-Dez-1981 3000 20
7934 MILLER CLERK 7782 23-Jan-1982 1300 10
select e.* from scott.emp e, scott.dept d
where e.deptno = d.deptno(+)
and d.deptno = 10 EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7782 CLARK MANAGER 7839 9-Jun-1981 2450 10
7839 KING PRESIDENT 17-Nov-1981 5000 10
7934 MILLER CLERK 7782 23-Jan-1982 1300 10
As you can see, this (+) is very important
Regards
Dmytro -
Outer join with effective date in peoplesoft query
Hi,
I'm trying to join two tables using outer join. Both tables are effective dated:
Dept_Tbl: dept_id, status, effdt
Tips_Tbl: dept_id, tips_id, effdt
Not all records in Dept_Tbl are in Tips_Tbl. I need to get all active depts and their most recent tips_id if they have one.
select a.dept_id, b.tips_id
from dept_tbl a, tips_tbl b
where a.status = 'Active'
and a.effdt =
(select max(a_ed.effdt) from dept_tbl a_ed
where a.dept_id = a_ed.dept_id
and a_ed.effdt <= SYSDATE)
and b.dept_id(+) = a.dept_id
and b.effdt =
(select max(b_ed.effdt) from tips_tbl b_ed
where b.dept_id = b_ed.dept_id
and b.tips_id = b_ed.tips_id
and b_ed.effdt <= SYSDATE)
The query only returns records that are in both tables.
Is there a way for outer join to work with effective dates?
Thanks in advance,
RegHere is an example of one solution. Note the use of NVL on both sides of the equal sign since both sides could be NULL in the case of the outer join
with dept_tbl as (select 1 dept_id, SYSDATE effdt FROM DUAL),
tips_tbl as (select 1 dept_id, NULL effdt FROM DUAL)
select a.effdt
from dept_tbl a,
tips_tbl b
where b.dept_id(+) = a.dept_id
and NVL(b.effdt, SYSDATE) = NVL((select max(b_ed.effdt)
from tips_tbl b_ed
where b.dept_id = b_ed.dept_id
and b_ed.effdt <= SYSDATE), SYSDATE);
EFFDT
5/7/2007 3:25:00 PM -
How to tack print out use with Query ?
Hi
I have to tack purchase order print out (print details- PO date, BP code, name, item name, Quantity and Amount . System Print Layout means from Purchase Order layout designer) use with Query
How to tack print out use with Query (system print layout means from Purchase Order layout designer) ?
Regards
Aravind MHi
I have to take purchase order print out and I created 3 templates for that purchase order in layout designer (Because as per the MIS requirement I created 3 templates, its cover more information). I have to take print out 3 templates at a time. So i try to take print use with Query.
Regards
Aravind M
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