How to achieve Interval partition by Weekly ?

Hi All,
How to use interval partition by weekly wise?
please share some examples.

after the above link read http://asktom.oracle.com/pls/apex/f?p=100:11:0::::P11_QUESTION_ID:549370300346187664

Similar Messages

Oracle 11g interval partitioning - meaningfull partition-names

Hello,
On 11g, when creating interval partitions, the partitions get automatically created just fine. Very nice feature. But is it possible to supply meaningfull names to them?
Now they get names SYS_nnn, but I would like to name them for instance SALES_2007.
Here is one example on how to use interval partitioning:
http://download.oracle.com/docs/cd/B28359_01/server.111/b32024/part_admin.htm#BAJHFFBE
And here is the syntax guide:
http://download.oracle.com/docs/cd/B28359_01/server.111/b28286/statements_7002.htm#sthref7644
I don't see how to accomplish meaningfull names (automatically!). Do you?

No I don't think it is possible. This is what is written in Oracle documentation..
http://download.oracle.com/docs/cd/B28359_01/server.111/b32024/partition.htm#CACHFHHF
>
The range partitioning key value determines the high value of the range partitions, which is called the transition point, and the database creates interval partitions for data beyond that transition point.
>

How to index a column in an interval partitioned table

Hi -
I see that domain indexes are not allowed on a table which has interval partitioning on it.
Given this limitation, is there any way to improve performance on wildcard searches (like '%condition%';) on a VARCHAR(2) column in a table which has interval partitioning?
Or are we SOL if we want to do this?
Thanks for any advice or experience in this area.
LJ

There's no real good way to make non-domain-indexed text queries fast. If there was, the Text forum wouldn't be the lively place it is today!
But SOL? No, I wouldn't call you SOL... There are always ways to do stuff, just depends on how important it is to you, how much space/time/maintenance you're willing to do to make things work.
For example, create a non-interval-partitioned materialized view of your target table/column and use a domain index on that.
What constraints or options do you have (or think you have) in order to make this work?

How to search data dictionary for interval partitions?

Oracle 11.2.0.3
When I query DBA_PART_TABLES.PARTITIONING_TYPE it says 'range'. I want to be able to differential an interval from other range based partitions in the data dictionary?
used this example. shows 'range'
http://www.rittmanmead.com/2008/09/investigating-oracle-11g-interval-partitioning/
Oracle Docs list 'SYSTEM' as a partitioning_type which I thought would be intervals.
ALL_PART_TABLES
[code]
1   CREATE TABLE interval_sales
2          ( prod_id        NUMBER(6)
3          , cust_id        NUMBER
4          , time_id        DATE
5          , channel_id     CHAR(1)
6          , promo_id       NUMBER(6)
7          , quantity_sold NUMBER(3)
8          , amount_sold    NUMBER(10,2)
9          )
10       PARTITION BY RANGE (time_id)
11       INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
12         ( PARTITION p0 VALUES LESS THAN (TO_DATE('1-1-2005', 'DD-MM-YYYY')),
13           PARTITION p1 VALUES LESS THAN (TO_DATE('1-1-2006', 'DD-MM-YYYY')),
14           PARTITION p2 VALUES LESS THAN (TO_DATE('1-7-2006', 'DD-MM-YYYY')),
15*          PARTITION p3 VALUES LESS THAN (TO_DATE('1-1-2007', 'DD-MM-YYYY')) )
SQL>/
Table created.
Elapsed: 00:00:00.01
SQL> select partitioning_type from user_part_tables where table_name = 'INTERVAL_SALES';
PARTITION
RANGE
[/code]

CREATE TABLE junk1
   ( id         NUMBER )
   PARTITION BY RANGE (id)
   INTERVAL(5)
     ( PARTITION p0 VALUES LESS THAN (5),
       PARTITION p1 VALUES LESS THAN (10),
       PARTITION p2 VALUES LESS THAN (15),
       PARTITION p3 VALUES LESS THAN (20) )
CREATE TABLE junk2
   ( id         NUMBER )
   PARTITION BY RANGE (id)
     ( PARTITION p0 VALUES LESS THAN (5),
       PARTITION p1 VALUES LESS THAN (10),
       PARTITION p2 VALUES LESS THAN (15),
       PARTITION p3 VALUES LESS THAN (20) )
select owner, table_name, partitioning_type, interval
from dba_part_tables
where table_name in ('JUNK1', 'JUNK2')
OWNER                          TABLE_NAME                     PARTITIONING_TYPE INTERVAL
GREGS                          JUNK1                          RANGE             5
GREGS                          JUNK2                          RANGE
2 rows selected.

Interval partitioning. How to choose partition name

Hi all,
Is there any wat to choose partition name when new partitions are created?
I mean insted of "SYS_P101" something like CUSTOMRES_P_256 where 256 is the new value that caused the creation of the partition.
The reason is that before running a long process I need to gather statistics on the partition based on that number
Thanks in advance,

You can rename a partition with your preferred naming convention:
alter table CUSTOMER rename partition SYS_P101 to CUSTOMRES_P_256;But first you need to know the name of the partition. One thing I have used in cases when an interval partition has not been created yet is to insert a record with the new partition key value so that the interval partition is created, then get the partition name and then roll back the insert. This way you know the partition name in advance of any data loading.
You can of course query dba_tab_partitions and look at the high_value column to select the correct partition. However, I prefer the following method of getting the partition name. It gives you the name of the partition for a row in a table. This is also useful for existing data (not just new partitions) if you ever need to find the partition where a certain row lives.
select subobject_name
into v_partition
from ALL_OBJECTS
where OWNER = 'SCHEMA_OWNER'
AND data_object_id in (select dbms_rowid.rowid_object(rowid)
                                 from FACT_TABLE
                                 where PARTITION_KEY_COL = MY_VALUE
                                 and rownum = 1);You can then use the partition name to load your facts, gather statistics, or rename the partition.

How to get data for current week and previous week using customer exit in Bex.

Hi everyone,
I have a scenario in which I need to display data for current week and previous week (based on "sy_datum" the program has to calculate current week and previous week) in Bex using Customer exit. I have created one variable in Bex Query Designer and I have written code for the variable in CMOD. But it is not working fine, (I know that we can do the same by using offset value in Bex). Can some one guide me how to achieve my requirement using customer exit.
Thanks in Advance,
G S Ramanjaneyulu.

Hi krishna,
Thanks for your quick reply, can you have a look at my code,
case i_vnam.
WHEN 'ZPWK_CWK'.
ranges : pre_week for sy-datum.
data : start_date type DATS,
       end_date TYPE dats .
************FM TO GET FIRST DATE OF CURRENT WEEK ************************
CALL FUNCTION 'BWSO_DATE_GET_FIRST_WEEKDAY'
EXPORTING
    DATE_IN = sy-datum
IMPORTING
    DATE_OUT = start_date.   " WEEK FIRST DATE
end_date = START_DATE + 6.   " WEEK LAST DATE
END_DATE   = START_DATE - 1.   " PREVIOUS WEEK END DATE
START_DATE = START_DATE - 7.   " PREVIOUS WEEK START DATE
**********PREVIOUS WEEK DATES IN PRE_WEEK******************
pre_week-SIGN   = 'I'.
pre_week-option = 'BT'.
pre_week-LOW    = START_DATE.
pre_week-HIGH   = END_DATE.
APPEND pre_week.
CLEAR : START_DATE,END_DATE.
endcase.
Regards,
G S Ramanjaneyulu.

How to Achieve this in SQL Query?

How to Achieve this ?
I have a table with numeric value populated like this
create table random_numeral (numerals Number(10));
insert into random_numeral values (1);
insert into random_numeral values (2);
insert into random_numeral values (3);
insert into random_numeral values (4);
insert into random_numeral values (5);
insert into random_numeral values (6);
insert into random_numeral values (56);
insert into random_numeral values (85);
insert into random_numeral values (24);
insert into random_numeral values (11);
insert into random_numeral values (120);
insert into random_numeral values (114);
Numerals
1
2
3
4
5
6
56
85
24
11
120
114
I want to display the data as follows
col1 / col2 / col3
1 / 2 / 3
4 / 5 / 6
11 / 24 / 56
85 / 114 / 120
Can anyone Help me?

I hope there might be some simple way to do this and waiting for experts to reply.
Try the below query.
SQL> select * from random_numeral;
NUMERALS
         1
         2
         3
         4
         5
         6
        56
        85
        24
        11
       120
NUMERALS
       114
       100
       140
14 rows selected.
SQL> select a.numerals ||' / '||b.numerals||' / '||c.numerals from
2          (select numerals,rownum rn1 from
3          (
4              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
5              from random_numeral
6          )
7          where rn=1) a,
8          (select numerals,rownum rn1 from
9          (
10              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
11              from random_numeral
12          )
13          where rn=2) b,
14          (select numerals,rownum rn1 from
15          (
16              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
17              from random_numeral
18          )
19          where rn=0) c
20 where   a.rn1=b.rn1(+)
21 and b.rn1=c.rn1(+)
22 /
A.NUMERALS||'/'||B.NUMERALS||'/'||C.NUMERALS
1 / 2 / 3
4 / 5 / 6
11 / 24 / 56
85 / 100 / 114
120 / 140 /
SQL>Cheers,
Mohana

How to create GPT Partition for onekey recovery windows8

Plz any one can help me.....
i have purchased laptop last week with following configurations:
Lenovo G510 i5 2.5ghz with windows 8 and OneKey recovery feature.
My laptop was with windows 8 but i upgrade my hard drive 500 GB to 1 TB.
But now i am unable to recover my windows8 image by using OneKeyrecovery (novo).
So plz help me how to craete GPT partition style that will support for onekey recovery and recover Windows 8 image that is in my external hard drive.
Please send me the complete procedure to create GPT partition style supported for onekey recovery.
Also solve the following questions plz.
1. How to create GPT partition style supported for onekey recovery?
2. Total Number of partitions and their actual sizes.
3. Size of C:
4. Size of D:
5. Size of recovery partition
6.Size of all partitions
Plz reply me at: ********@yahoo.com
Regards: Aamir
Moderator note: email address removed to keep away from the spambots.
Solved!
Go to Solution.

Dear Customer
Welcome in lenovo community
Please use the below link to download and install the Lenovo Recovery application so that you can do what you looking for
Link : http://support.lenovo.com/en_US/downloads/detail.page?DocID=DS035708
Thanks
Alaa
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Creating DOMAIN INDEX on INTERVAL PARTITIONING

Hi !
I hava a problem, and I hope someone can help me!
Two questions are asked below:
1. Main question: HOW CAN I SOLVE THIS PROBLEM, ARE THERE OTHER WAYS DOING THE SAME JOB (MAYBE FASTER) ?
2. Additionally: Is there a way to accelerate the deletion process
Step 1: Creating the table* For Information how I create the table:
CREATE TABLE LOC_EXAMPLE
COLUMN1 NUMBER
COLUMN2 NUMBER
COLUMN3 NUMBER
COLUMN4 NUMBER
START_TIME TIMESTAMP
GEOLOC MDSYS.SDO_GEOMETRY,
TABLESPACE DB_DATA
PCTUSED 0
PCTFREE 10
INITRANS 1
MAXTRANS 255
STORAGE (
INITIAL 64K
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
BUFFER_POOL DEFAULT
NOLOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
MONITORING
PARTITION BY RANGE (START_TIME)
INTERVAL (NUMTODSINTERVAL(1,'DAY'))
PARTITION PART_LOC_EXAMPLE VALUES LESS THAN (TO_DATE('01-01-2008','dd-MM-yyyy'))
ALTER TABLE LOC_EXAMPLE
ADD CONSTRAINT PK_LOC_EXAMPLE PRIMARY KEY (COLUMN2,COLUMN4)
DELETE FROM USER_SDO_GEOM_METADATA VALUE WHERE TABLE_NAME = 'LOC_EXAMPLE'
INSERT INTO USER_SDO_GEOM_METADATA VALUES ('LOC_EXAMPLE','GEOLOC', MDSYS.SDO_DIM_ARRAY( MDSYS.SDO_DIM_ELEMENT('X',-180,180,0.001111949), MDSYS.SDO_DIM_ELEMENT('Y',-90,90,0.001111949) ), 8307)
STEP 2: I TRY TO CREATE SPATIAL INDEX (ITS A DOMAIN INDEX IF I'M NOT WRONG) ON PARTITIONED TABLE*
(PARTITIONED TABLE is an extension of range partitioning)
CREATE INDEX LOC_EXAMPLE_idx ON LOC_EXAMPLE'(GEOLOC)
INDEXTYPE IS MDSYS.SPATIAL_INDEX LOCAL;
THE SECOND STEP IS NOT POSSIBLE AS THE ORACLE DOCUMENTATION SAYS:
When using interval partitioning, consider the following restrictions:
-You can only specify one partitioning key column, and it must be of NUMBER or DATE type.
-Interval partitioning is not supported for index-organized tables.
-You cannot create a domain index on an interval-partitioned table.
1) I THINK IT IS IMPOSSIBLE FOR ME TO PASS ON INTERVAL PARTITIONING (AMOUNT OF DATA IS REALY BIG).
This partitioning is also used to delete datas from database once a mounth (scheduled on the basis of the partitions).
Is there a way to accelerate the deletion process?
2) I NEED A SPATIAL INDEX! NO WAY TO PASS ON IT!
HOW CAN I SOLVE THIS PROBLEM, ARE THERE OTHER WAYS DOING THE SAME JOB (MAYBE FASTER) ?
Why is it not possible to create a domain index on interval partitioning, any reason?
Will this be possible anytime?
I would be grateful to read any advise ...!
Thanking you in anticipation,
Ali

There is a forum here at OTN for spatial. Please delete the contents of this post and ask your question there. Thanks.

Creating DOMAIN INDEX (SPATIAL) on INTERVAL PARTITIONING

Hi !
I hava a problem, and I hope someone can help me!
Two questions are asked below:
1. Main question: HOW CAN I SOLVE THIS PROBLEM, ARE THERE OTHER WAYS DOING THE SAME JOB (MAYBE FASTER) ?
2. Additionally: Is there a way to accelerate the deletion process
Step 1: Creating the table For Information how I create the table:
CREATE TABLE LOC_EXAMPLE
COLUMN1 NUMBER
COLUMN2 NUMBER
COLUMN3 NUMBER
COLUMN4 NUMBER
START_TIME TIMESTAMP
GEOLOC MDSYS.SDO_GEOMETRY,
TABLESPACE DB_DATA
PCTUSED 0
PCTFREE 10
INITRANS 1
MAXTRANS 255
STORAGE (
INITIAL 64K
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
BUFFER_POOL DEFAULT
NOLOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
MONITORING
PARTITION BY RANGE (START_TIME)
INTERVAL (NUMTODSINTERVAL(1,'DAY'))
PARTITION PART_LOC_EXAMPLE VALUES LESS THAN (TO_DATE('01-01-2008','dd-MM-yyyy'))
ALTER TABLE LOC_EXAMPLE
ADD CONSTRAINT PK_LOC_EXAMPLE PRIMARY KEY (COLUMN2,COLUMN4)
DELETE FROM USER_SDO_GEOM_METADATA VALUE WHERE TABLE_NAME = 'LOC_EXAMPLE'
INSERT INTO USER_SDO_GEOM_METADATA VALUES ('LOC_EXAMPLE','GEOLOC', MDSYS.SDO_DIM_ARRAY( MDSYS.SDO_DIM_ELEMENT('X',-180,180,0.001111949), MDSYS.SDO_DIM_ELEMENT('Y',-90,90,0.001111949) ), 8307)
STEP 2: I TRY TO CREATE SPATIAL INDEX (ITS A DOMAIN INDEX IF I'M NOT WRONG) ON PARTITIONED TABLE
(PARTITIONED TABLE is an extension of range partitioning)
CREATE INDEX LOC_EXAMPLE_idx ON LOC_EXAMPLE'(GEOLOC)
INDEXTYPE IS MDSYS.SPATIAL_INDEX LOCAL;
THE SECOND STEP IS NOT POSSIBLE AS THE ORACLE DOCUMENTATION SAYS:
When using interval partitioning, consider the following restrictions:
-You can only specify one partitioning key column, and it must be of NUMBER or DATE type.
-Interval partitioning is not supported for index-organized tables.
-You cannot create a domain index on an interval-partitioned table.
1) I THINK IT IS IMPOSSIBLE FOR ME TO PASS ON INTERVAL PARTITIONING (AMOUNT OF DATA IS REALY BIG).
This partitioning is also used to delete datas from database once a mounth (scheduled on the basis of the partitions).
Is there a way to accelerate the deletion process?
2) I NEED A SPATIAL INDEX! NO WAY TO PASS ON IT!
HOW CAN I SOLVE THIS PROBLEM, ARE THERE OTHER WAYS DOING THE SAME JOB (MAYBE FASTER) ?
Why is it not possible to create a domain index on interval partitioning, any reason?
Will this be possible anytime?
I would be grateful to read any advise ...!
Thanking you in anticipation,
Ali

Is it possible to just use a normal range-partitioned table?
CREATE TABLE LOC_EXAMPLE
START_TIME TIMESTAMP
GEOLOC MDSYS.SDO_GEOMETRY,
PARTITION BY RANGE (START_TIME)
PARTITION P1 VALUES LESS THAN (TO_DATE('01-01-2008','dd-MM-yyyy'))
alter table loc_example add partition p2 VALUES LESS THAN (TO_DATE('02-01-2008','dd-MM-yyyy'));
alter table loc_example drop partition p1;
I understand it is not as perfect as interval partitioning, since
you have to drop an old partition/add a new one either manually
or by some script. But you should be able to create a spatial domain index
on it.

Create table interval partition on a column timestamp with local time zone

Hi
Does anyone have an example for 11g on how to create a table with interval partitioning on a column defined as timestamp with local time zone. I know it's possible. the following does not work.
CREATE TABLE KOMODO_EXPIRED_RESULTS
TEST_EVENT_KEY NUMBER NOT NULL,
HPS_DEVICE_KEY NUMBER NOT NULL,
RCS_DEVICE_KEY NUMBER,
EVENT_START_TIMESTAMP TIMESTAMP(6) with local time zone NOT NULL,
BOOTROMVERSION NUMBER,
CHANNELNUMBER NUMBER,
CLIENTVERSION VARCHAR2(4000 BYTE),
ETHERNET_CRC_ERROR_COUNT NUMBER,
ETHERNET_DROPPED_PACKETS NUMBER,
ETHERNET_THROUGHPUT NUMBER,
ETHERNET_TRAFFIC_IN NUMBER,
ETHERNET_TRAFFIC_OUT NUMBER,
IPADDRESS VARCHAR2(4000 BYTE),
KOMODO_ID VARCHAR2(4000 BYTE),
LASTREBOOTTIME VARCHAR2(4000 BYTE),
OSVERSION VARCHAR2(4000 BYTE),
RECEIVER_AUDIOACCESSCONTROLER NUMBER,
RECEIVER_AUDIOBUFFEROVERFLOWS NUMBER,
RECEIVER_AUDIOBUFFERUNDERRUNS NUMBER,
RECEIVER_AUDIOCODEC VARCHAR2(4000 BYTE),
RECEIVER_AUDIODATADROPPED NUMBER,
RECEIVER_AUDIODATATHROUGHPUT NUMBER,
RECEIVER_AUDIODECODERERRORS NUMBER,
RECEIVER_AUDIODESCBUFFERUNDER NUMBER,
RECEIVER_AUDIODESCCRYPTOERROR NUMBER,
RECEIVER_AUDIODESCDATADROPPED NUMBER,
RECEIVER_AUDIODESCDATATHROUGH NUMBER,
RECEIVER_AUDIODESCDECODERERRO NUMBER,
RECEIVER_AUDIODESCDRMERRORS NUMBER,
RECEIVER_AUDIODESCPTSDELTA NUMBER,
RECEIVER_AUDIODESCPTSDELTAHAL NUMBER,
RECEIVER_AUDIODESCSAMPLESDROP NUMBER,
RECEIVER_AUDIODSPCRASHES VARCHAR2(4000 BYTE),
RECEIVER_AUDIOPTSDELTAHAL NUMBER,
RECEIVER_AUDIOSAMPLESDECODED NUMBER,
RECEIVER_AUDIOSAMPLESDROPPED NUMBER,
RECEIVER_AUDIOUNDERRUN NUMBER,
RECEIVER_BITRATE NUMBER,
RECEIVER_BUFFEROVERRUN NUMBER,
RECEIVER_BYTESCCRECEIVED NUMBER,
RECEIVER_BYTESRECEIVED NUMBER,
RECEIVER_CHANNEL NUMBER,
RECEIVER_DECODERSTALL NUMBER,
RECEIVER_DISCONTINUITIES NUMBER,
RECEIVER_DISCONTINUITIESPACKE NUMBER,
RECEIVER_DRIFT NUMBER,
RECEIVER_DROPPEDPACKETSUNTILR NUMBER,
RECEIVER_ECMLOOKUPERROR NUMBER,
RECEIVER_ECMPARSEERRORS NUMBER,
RECEIVER_PMTCHANGED NUMBER,
RECEIVER_REBUFFER NUMBER,
RECEIVER_SELECTCOMPONENTAUDIO NUMBER,
RECEIVER_TIMELINEDISCONTINUIT NUMBER,
RECEIVER_VIDEOACCESSCONTROLER NUMBER,
RECEIVER_VIDEOACCESSCONTROLUN NUMBER,
RECEIVER_VIDEOBUFFEROVERFLOWS NUMBER,
RECEIVER_VIDEOBUFFERUNDERRUNS NUMBER,
RECEIVER_VIDEOCODEC VARCHAR2(4000 BYTE),
RECEIVER_VIDEOCRYPTOERROR NUMBER,
RECEIVER_VIDEODATADROPPED NUMBER,
RECEIVER_VIDEODATATHROUGHPUT NUMBER,
RECEIVER_VIDEODECODERERRORS NUMBER,
RECEIVER_VIDEODRMERRORS NUMBER,
RECEIVER_VIDEODSPCRASHES VARCHAR2(4000 BYTE),
RECEIVER_VIDEOFIFORD NUMBER,
RECEIVER_VIDEOFIFOSIZE NUMBER,
RECEIVER_VIDEOFRAMESDECODED NUMBER,
RECEIVER_VIDEOFRAMESDROPPED NUMBER,
RECEIVER_VIDEOPTSDELTA NUMBER,
RECEIVER_VIDEOPTSDELTAHAL NUMBER,
RECEIVER_VIDEOUNDERRUN NUMBER,
SUBNETMASK VARCHAR2(4000 BYTE),
TUNER_BITRATE NUMBER,
TUNER_BUFFERFAILURE NUMBER,
TUNER_CCPACKETSRECEIVED NUMBER,
TUNER_CHANNEL NUMBER,
TUNER_DATATIMEOUTS NUMBER,
TUNER_DELIVERYMODE VARCHAR2(4000 BYTE),
TUNER_DROPPAST NUMBER,
TUNER_FILL NUMBER,
TUNER_HOLE NUMBER,
TUNER_HOLEDURINGBURST NUMBER,
TUNER_HOLEDURINGBURSTPACKETS NUMBER,
TUNER_HOLETOOLARGEPACKETS NUMBER,
TUNER_MAXIMUMHOLESIZE NUMBER,
TUNER_MULTICASTADDRESS VARCHAR2(4000 BYTE),
TUNER_MULTICASTJOINDELAY NUMBER,
TUNER_OUTOFORDER NUMBER,
TUNER_OVERFLOWRESET NUMBER,
TUNER_OVERFLOWRESETTIMES NUMBER,
TUNER_PACKETSEXPIRED NUMBER,
TUNER_PACKETSPROCESSED NUMBER,
TUNER_PACKETSRECEIVED NUMBER,
TUNER_PACKETSWITHOUTSESSION NUMBER,
TUNER_PARSEERRORS NUMBER,
TUNER_SRCUNAVAILABLERECEIVED NUMBER,
TUNER_TOTALHOLEPACKETS NUMBER,
TUNER_TOTALPACKETSEXPIRED NUMBER,
TUNER_TOTALPACKETSRECEIVED NUMBER,
TUNER_UNICASTADDRESS VARCHAR2(4000 BYTE),
RECEIVER_TUNEDFOR NUMBER,
MACADDRESS VARCHAR2(4000 BYTE),
RECEIVER_TOTALAVUNDERRUNS NUMBER,
RECEIVER_TOTALDISCONTINUITIES NUMBER,
SERVICEID VARCHAR2(4000 BYTE),
DRIVEPRESENT VARCHAR2(4000 BYTE),
STB_STATE VARCHAR2(32 BYTE),
PREV_EXPIRED NUMBER,
PREV_HOLES NUMBER,
PREV_RECEIVED NUMBER,
PREV_TIMESTAMP TIMESTAMP(6),
PREV_REBOOT VARCHAR2(4000 BYTE),
TOTALPACKETSEXPIRED_RATE NUMBER,
TOTALHOLEPACKETS_RATE NUMBER,
TOTALPACKETSRECEIVED_RATE NUMBER,
CONSTRAINT KOMODO_EXPIRED_RESULTS_PK
PRIMARY KEY
(HPS_DEVICE_KEY, EVENT_START_TIMESTAMP)
USING INDEX
TABLESPACE HPS_SUMMARY_INDEX
TABLESPACE HPS_SUMMARY_DATA
PARTITION BY RANGE (EVENT_START_TIMESTAMP)
INTERVAL( NUMTODSINTERVAL(1,'DAY'))
PARTITION DEFAULT_TIME_PART_01 VALUES LESS THAN (TIMESTAMP' 2010-08-01 00:00:00.000000000 +00:00')
LOGGING
COMPRESS FOR ALL OPERATIONS
TABLESPACE HPS_SUMMARY_DATA
NOCACHE
PARALLEL ( DEGREE DEFAULT INSTANCES DEFAULT )
MONITORING
/

I am not sure it can be done.
SQL> create table sales
2 (
3 sales_id number,
4 sales_dt TIMESTAMP(6) with local time zone NOT NULL
5 )
6 partition by range (sales_dt)
7 interval (numtoyminterval(1,'MONTH'))
8 ( partition p0901 values less than (to_date('2009-02-01','yyyy-mm-dd')) );
create table sales
ERROR at line 1:
ORA-14751: Invalid data type for partitioning column of an interval partitioned
table
SQL> ed
Wrote file afiedt.buf
1 create table sales
2 (
3 sales_id number,
4 sales_dt TIMESTAMP(6)
5 )
6 partition by range (sales_dt)
7 interval (numtoyminterval(1,'MONTH'))
8* ( partition p0901 values less than (to_date('2009-02-01','yyyy-mm-dd')) )
SQL> /
Table created.

How to achieve this photographic slide display/navigation

Hi,
I would like to know how to achieve the following:
1. Go to
http://www.corneliaadams.com/
& then click on 'michael mundy' link. this opens up a page with
a slideshow of photographs that i really love. I have very basic
knowledge of scripting ,a nd i usually achieve my goals by
modifying flas that i have seen or by following tutorials (as
opposed to writing it myself). the great thng about the above
version is taht the images slide to an exact position when you
click on the forward or back arrows, and they slow down ever so
slightly just before stopping. Can anyone point me in the right
directoin with how to achieve this, or offer a tutorial. I am
really starting from scratch, and would lik eto end up with the
same clean and professional outcome.
2. regarding the same above link, when you are at the main
site, and then you click the michael mundy' link, what is it that
happens, is it a new html popup page that opens of specified
dimensions and the embedded swf is set to stretch to maximum
width/height? or is it a lone swf that pops up (with no html page)?
or is that impossible?
Many Many Many thanks in advance,
Cheska

I hope there might be some simple way to do this and waiting for experts to reply.
Try the below query.
SQL> select * from random_numeral;
NUMERALS
         1
         2
         3
         4
         5
         6
        56
        85
        24
        11
       120
NUMERALS
       114
       100
       140
14 rows selected.
SQL> select a.numerals ||' / '||b.numerals||' / '||c.numerals from
2          (select numerals,rownum rn1 from
3          (
4              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
5              from random_numeral
6          )
7          where rn=1) a,
8          (select numerals,rownum rn1 from
9          (
10              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
11              from random_numeral
12          )
13          where rn=2) b,
14          (select numerals,rownum rn1 from
15          (
16              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
17              from random_numeral
18          )
19          where rn=0) c
20 where   a.rn1=b.rn1(+)
21 and b.rn1=c.rn1(+)
22 /
A.NUMERALS||'/'||B.NUMERALS||'/'||C.NUMERALS
1 / 2 / 3
4 / 5 / 6
11 / 24 / 56
85 / 100 / 114
120 / 140 /
SQL>Cheers,
Mohana

Range interval partitioning with null value

Hello,
I have question, how can I create table with partition and after that I will insert null value in the partition key like this kind of
range interval partitioning with null value.
I have Oracle 11g.
Thanks
Mohammed

user13777053 wrote:
Thank you, but my question is about range interval not for range?http://docs.oracle.com/cd/E11882_01/server.112/e25523/partition.htm#VLDBG00220
A MAXVALUE literal can be defined for the highest partition. MAXVALUE represents a virtual infinite value that sorts higher than any other possible value for the partitioning key, *including the NULL value.*
So since you're trying to partition by interval (which doesn't support a MAXVALUE clause) you're out of luck.
There's probably fancy hacks and what not you could try to implement, but i'm not about to recommend any of those here :)
Cheers,

Interval Partitioning

Hi everyone,
I've got a question about interval partitioning. I've got a fact table, W_GL_BALANCE_F that is fairly massive and I want to use interval partitioning on the BALANCE_DT_WID field. The values in the field are of the form YYYYMMDD || '000', i.e. 20100820000 would be today, 20100821000 would be tomorrow, etc.
I create the table with interval partitioning with an interval of 1000, and then when I go to insert the data, I get the error "Partition does not exist". I was a little confused because I thought interval partitions created partitions for any new value.
I ran some tests on a test table part_test(part_key number) partition range interval (1) ( partition "zero" less than 1). Then I inserted a few test records
INSERT INTO part_test (part_key) values (1);
INSERT INTO part_test (part_key) values (2);
INSERT INTO part_test (part_key) values (10);
INSERT INTO part_test (part_key) values (1000000); --- This causes error "Partition does not exist"
Obviously there are some additional rules to go along with using the intervals. I was under the impression that it would just create a range for any new value but it seems more complicated than that.
Can someone explain to me why the final record isn't able to have a new partition created for it?
I apologize if this is a dumb question, but I'm a little new to the different partitioning options.
Best regards and thanks for the help!
-Joe

Joe Bertram wrote:
Hi Tubby,
Just to give you a little more background, I am working with the Oracle BI Applications prepackaged data warehouse and ETLs. Because it's all prepackaged ETLs, I don't have too much flexibility to change the data being loaded, otherwise, I totally agree that using this date format is kind of strange. Thanks for the information, helps to know :)
Joe Bertram wrote:
I looked at other fields on the table for a potential partition key, and this field was the only one that was remotely uniformly distributed. That really isn't the first consideration you should have for partitioning. What are you trying to accomplish with partitioning? Are you looking to make data archival easier (dropping old partitions is the easiest way to go), or are you looking to enhance querying? Partitioning is a tool you implement for a given purpose ... so what's yours?
Joe Bertram wrote:>
You are correct, my test case was a little simplistic. I went back to the data the see why your case succeeded and mine failed. It turns out I missed one part in the date format. In addition to the date format as I laid it out, they also append the calendar ID which refers to the fiscal calender to which the date belongs. the actual format is <4-digit-cal_id>YYYYMMDD<000> i.e. 100120100820000 is today on calendar 1001, but there could also be a calendar 1007 which could have today's date i.e. 100720100820000.
drop table part_test;
create table part_test
part_key number
partition by range (part_key)
interval (1000)
partition zero_1 values less than (100120100820000)
INSERT INTO part_test (part_key) values (100120100820000);
INSERT INTO part_test (part_key) values (100720100820000); -- same day on calendar 1007, causes an errorIt pretty much seems to me that there would be too many potential partitions, so the DB gives up. Is that correct?That indeed seems to be the case, you could perhaps raise a service request with Oracle, but i'm not sure how eager they'd be to enhance the interval partitioning for this case. This data doesn't seem like it would be a good candidate for range partitioning. Again, we need to know what you're goal is from partitioning.
If housekeeping is paramount (keeping X days of data and purging old data) then i would suggest the following.
create table part_test
   part_key       number,
   magic_column   generated always as ( to_date(substr (part_key, 5, 8), 'yyyymmdd') ) virtual
   partition by range (magic_column)
   INTERVAL ( INTERVAL '1' DAY)
   partition zero_1 values less than ( to_date('20100820', 'yyyymmdd') )
);Partitioning by a virtual column, the date in this case.
It's possibly you have a more logical key to partition off of, but a RANGE partition scheme on your part_key doesn't sound good at all.

How to Create Multiple Partitions in Windows?

I have just carried out a clean install of Lion then used Boot Camp to install Windows.
With Snow Leopard I had the ability to create multiple partitions in Windows but this seems impossible in Lion for whatever reason.
Can anyone please tell me how to achieve this?

If you're using Boot Camp, I'd post your question on the Boot Camp section:
http://discussions.apple.com/category.jspa?categoryID=237

How to achieve Interval partition by Weekly ?

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