How to avoid the double memory assignment for an array which I connected to the shift register?

Hi,
I need to read a big block of data into an array. When I stop the program and then restart, I hope the program to use the previously load arrary instead of reloading it. So I put the initiat Data loading in a for loop (N =1) and connect the array to a shift Register. The problem here is it assigns memory twice, for the initiator data loading and shift register. Is there any way to limit the memory assaignment to 1 since I only need one copy.
Thanks.

JWJ wrote:
Since my original file is more than 2M and really comlicated, I just make a simple demo file to show my purpose.
Your current code is way too confusing, so I assume that the full code makes more sense. The program is unusable because the main FOR loop gets locked in an inner loop that consumes all CPU doing nothing.
I think that branching the main array into the (1) case structure and (2) inner while loop costs you an extra allocation. Here's a more reasonable way to do things. It elimiates the buffer allocation going into the case structure.
LabVIEW Champion . Do more with less code and in less time .
Attachments:
DemoMOD.vi ‏11 KB

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job => X
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33 35 2 123 456 789 543 241 643 243 135 RRRRRR 55
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