How to convert (multiple) rows output to multiple (columns)

Question

Hii
I have wierd query. But not sure of how to get result out of it!!!
My query returns two rows for a query that i have posed.
Current Result
10
20
Expected Result
10 20
My problem here is i wanted the above two values to be stored in two variables in a single select statement.
If i use a cursor my problem will be solved.But i am not much intrested to use a cursor for a simple select statement.
is there any possibilty that i can convert the output of two rows to two columns??
I am using Oracle Release 10.1.0.2.0
Operating system Windows Xp.
People here will not appreciate the tags "Urgent". I know that :-(.
But some how i am forced to use this tag "urgent". Sorry for that.
If no answers i will in other way have to go to cursor :-(
Any help will be appreciated.
Thanks,
Pavan

Answer 1

Another solution with model and you don't need a subquery
SELECT  DEPT ,SUBSTR(LOCATION1,2) LOCATION1, SUBSTR(LOCATION2,2) LOCATION2,SUBSTR(LOCATION3,2) LOCATION3
    FROM   T
    MODEL
      RETURN UPDATED ROWS 
     PARTITION BY ( DEPT )
      DIMENSION BY ( ROW_NUMBER() OVER (PARTITION BY DEPT ORDER BY LOCATION ) AS POSITION )
      MEASURES     ( location,CAST ( LOCATION AS VARCHAR2(15)) AS LOCATION1 ,CAST ( LOCATION AS VARCHAR2(15)) AS LOCATION2,
                               CAST ( LOCATION AS VARCHAR2(15)) AS LOCATION3 )IGNORE NAV
     RULES
       UPSERT
       ITERATE( 1000)
         UNTIL ( PRESENTV(LOCATION[ITERATION_NUMBER+2],1,0) = 0)
       ( LOCATION1[0] =LOCATION1[0] || CASE WHEN ITERATION_NUMBER+1=1 THEN  ',' || LOCATION1[ ITERATION_NUMBER+1] END,
         LOCATION2[0] =LOCATION2[0] || CASE WHEN ITERATION_NUMBER+1=2 THEN  ',' || LOCATION2[ ITERATION_NUMBER+1] END,
          LOCATION3[0] =LOCATION3[0] || CASE WHEN ITERATION_NUMBER+1=3 THEN  ',' || LOCATION3[ ITERATION_NUMBER+1] END  )
   ORDER BY DEPT
Demo
SQL> WITH T AS (   SELECT 'AB' DEPT,'MEB' LOCATION FROM DUAL UNION ALL
  2                SELECT 'AB','MEB1' FROM DUAL UNION ALL
  3                SELECT 'AB','MEB2' FROM DUAL UNION ALL
  4                SELECT 'BC','MEB' FROM DUAL UNION ALL
  5                SELECT 'BC','MEB' FROM DUAL UNION ALL
  6                SELECT 'CD','MEN' FROM DUAL UNION ALL
  7                SELECT 'CD','MEN' FROM DUAL
  8                )
  9  SELECT  DEPT ,SUBSTR(LOCATION1,2) LOCATION1, SUBSTR(LOCATION2,2) LOCATION2,SUBSTR(LOCATION3,2)
LOCATION3
10      FROM   T
11      MODEL
12        RETURN UPDATED ROWS 
13       PARTITION BY ( DEPT )
14        DIMENSION BY ( ROW_NUMBER() OVER (PARTITION BY DEPT ORDER BY LOCATION ) AS POSITION )
15        MEASURES     ( location,CAST ( LOCATION AS VARCHAR2(15)) AS LOCATION1 ,CAST ( LOCATION AS
VARCHAR2(15)) AS LOCATION2,
16             CAST ( LOCATION AS VARCHAR2(15)) AS LOCATION3 )IGNORE NAV
17       RULES
18         UPSERT
19         ITERATE( 1000)
20           UNTIL ( PRESENTV(LOCATION[ITERATION_NUMBER+2],1,0) = 0)
21         ( LOCATION1[0] =LOCATION1[0] || CASE WHEN ITERATION_NUMBER+1=1 THEN  ',' || LOCATION1[ I
TERATION_NUMBER+1] END,
22        LOCATION2[0] =LOCATION2[0] || CASE WHEN ITERATION_NUMBER+1=2 THEN  ',' || LOCATION2[ ITER
ATION_NUMBER+1] END,
23        LOCATION3[0] =LOCATION3[0] || CASE WHEN ITERATION_NUMBER+1=3 THEN  ',' || LOCATION3[ ITER
ATION_NUMBER+1] END  )
24     ORDER BY DEPT
25     /
DE LOCATION1      LOCATION2      LOCATION3
AB MEB            MEB1           MEB2
BC MEB            MEB
CD MEN            MEN
SQL>
SQL>