How to count number of repeated characters in a String

I have a String.... 10022002202222.
I need to know how many 2's are there in the string... here the string contains eight 2's..
Thanks in advance..

it is workingYes, but... attention to surprises...
SQL> var v1 varchar2(1000);
SQL> exec :v1 := 'How to count the number of occurences of a characters in a string';
PL/SQL procedure successfully completed.
SQL> select length(:v1) - length(replace(:v1,'c')) from dual;
LENGTH(:V1)-LENGTH(REPLACE(:V1,'C'))
                                   6
SQL> exec :v1 := 'cccccc';
PL/SQL procedure successfully completed.
SQL> select length(:v1) - length(replace(:v1,'c')) from dual;
LENGTH(:V1)-LENGTH(REPLACE(:V1,'C'))
SQL> select length(:v1) - nvl(length(replace(:v1,'c')),0) from dual;
LENGTH(:V1)-NVL(LENGTH(REPLACE(:V1,'C')),0)
                                          6
SQL>

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