How to create a dynamic hyperlink which point to a BLOB column

Hello,
I am fighting with the issue for about 2 days.
My purpose is to use Oracle Report Builder to build a report of our employee directory which contains employee's information and also employee's picture. The requirement is that our report is going to generate a html file to our web server. By creating a dynamic hyperlink to the Employee's name in the report output file (the html file generated to our web server), it should then display the corresponding employee's picture which is a BLOB column stored in our oracle database.
I only can create the hyperlink for the employee's name if the link is static, like 'http://www.google.com
But from the Oracle Reports 10g Release2 (10.1.2), about the exmaple 1: Dynamic hyperlink, I refered the link
http://www.oracle.com/webapps/online-help/reports/10.1.2/state/content/navId.3/navSetId._/vtTopicFile.htmlhelp_rwbuild_hs%7Crwcontxt%7Cprops%7Cpi_lay_hyperlink%7Ehtm/
The link gave he following example shows a value for the Hyperlink property that specifies a link to a destination identified dynamically:
'DEPT_DETAILS_' || LTRIM(TO_CHAR(:DEPTNO))
where :DEPTNO is a column value retrieved from the database at runtime.
I tried as the same way to want it dynamcially shows the column :EMP_PHTOT, which is one BLOB column, but it was failed.
Anyone knows how to implement this? Any inputs is appreciated!
Thanks,
Jing

This forum is for the SQLDeveloper tool. You might get better responses on the reports forum Reports

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How to create dynamic link which point to a BLOB column in report

Hello,
I am fighting with the issue for about 2 days.
My purpose is to use Oracle Report Builder to build a report of our employee directory which contains employee's information and also employee's picture. The requirement is that our report is going to generate a html file to our web server. By creating a dynamic hyperlink to the Employee's name in the report output file (the html file generated to our web server), it should then display the corresponding employee's picture which is a BLOB column stored in our oracle database.
I only can create the hyperlink for the employee's name if the link is static, like 'http://www.google.com
But from the Oracle Reports 10g Release2 (10.1.2), about the exmaple 1: Dynamic hyperlink, I refered the link
http://www.oracle.com/webapps/online-help/reports/10.1.2/state/content/navId.3/navSetId._/vtTopicFile.htmlhelp_rwbuild_hs%7Crwcontxt%7Cprops%7Cpi_lay_hyperlink%7Ehtm/
The link gave he following example shows a value for the Hyperlink property that specifies a link to a destination identified dynamically:
'DEPT_DETAILS_' || LTRIM(TO_CHAR(:DEPTNO))
where :DEPTNO is a column value retrieved from the database at runtime.
I tried as the same way to want it dynamcially shows the column :EMP_PHTOT, which is one BLOB column, but it was failed.
Anyone knows how to implement this? Any inputs is appreciated!
Thanks,
Jing

What exactly is the error messag u are getting ?
If u have a hyperlink which refers to www.oracle.com in ur pdf, does it work ?
I think simple URL from PDF will not retrieve any data from the oracle database since it has to make some database connection.
My suggestion would be whenever request for employee information comes,
extract that picture from blob and put it a virtual folder in the application server.
And from the pdf/report access the URL with reference to the picture...
Rajesh Alex

How to create an ADF table which has a command button column?

Hi
Thank you for reading my post
how i can create a tabl that one of its column is a command button.
when i press the command button it will , for example delete that row or do some action.
indeed i want to know
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<BLOCKQUOTE>quote:<HR>Originally posted by Rainer Wagner ([email protected]):
Imagine a table T_Q with columns C_1, C_2, C_3 and UN_123.
C_1, C_2 and C_3 are all numeric and given by the user.
UN_123 has to be a calculated sequence number starting by 1 and incremented by 1 for each combination of C_1, C_2 and C_3, i.e., the sequence number depends on the key values C_1, C_2 and C_3.
Could anybody provide a code sample on how to create a BEFORE INSERT trigger , which calculates the value of the column UN_123 based on the values of C_1, C_2 and C_3 ??
Premise: Rather than using any sequence, the trigger code should only be based on the table T_Q<HR></BLOCKQUOTE>
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How to create a dynamic RTF report which creates dynamic columns based on dynamic column selection from a table?

Hi All,
Suppose I have table, whose structure changes frequently on daily basis.
For eg. desc my_table gives you following column name on Day 1
SQL > desc my_table;
Output
Name
Age
Phone
On Day 2, two more columns are added, viz, Address and Salary.
SQL > desc my_table;
Output
Name
Age
Phone
Address
Salary
Now I want to create an Dynnamic RTF report which would fetch data from ALL columns from my_table on daily basis. For that I have defined a concurrent program with XML as output type and have attached a data template/data definition to it which takes in XML as input and gives final output of conc program in EXCEL layout. I am able to do this for constant number of columns, but dont know how to do it when the number of columns to be displayed changes dynamically.
For Day 1 my XML file should be like this.
<?xml version="1.0" encoding="UTF-8"?>
<dataTemplate name="XYZ" description="iExpenses Report" Version="1.0">
<dataQuery>
<sqlStatement name="Q2">
<![CDATA[
SELECT Name
,Age
,Phone
FROM my_table
]]>
</sqlStatement>
</dataQuery>
<dataStructure>
<group name="G_my_table" source="Q2">
<element name="Name" value="Name" />
<element name="Age" value="Age" />
<element name="Phone" value="Phone" />
</group>
</dataStructure>
</dataTemplate>
And my Day 1, EXCEL output from RTF template should be like this.
Name Age Phone
Swapnill 23 12345
For Day 2 my XML file should be like this. With 2 new columns selected in SELECT clause.
<?xml version="1.0" encoding="UTF-8"?>
<dataTemplate name="XYZ" description="iExpenses Report" Version="1.0">
<dataQuery>
<sqlStatement name="Q2">
<![CDATA[
SELECT Name
,Age
,Phone
,Address
,Salary
FROM my_table
]]>
</sqlStatement>
</dataQuery>
<dataStructure>
<group name="G_my_table" source="Q2">
<element name="Name" value="Name" />
<element name="Age" value="Age" />
<element name="Phone" value="Phone" />
<element name="Address" value="Address" />
<element name="Salary" value="Salary" />
</group>
</dataStructure>
</dataTemplate>
And my Day 2, EXCEL output from RTF template should be like this.
Name Age Phone Address Salary
Swapnill 23 12345 Madrid 100000
Now, I dont know below things.
Make the XML dynamic as in on Day 1 there must be 3 columns in the SELECT statement and on Day 2, 5 columns. I want to create one dynamic XML which should not be required to be changed if new columns are added in my_table. I dont know how to create this query and also create their corresponding elements below.
Make the RTF template dyanamic as in Day1 there must 3 columns in EXCEL output and on Day 2, 5 columns. I want to create a Dynamic RTF template which would show all the columns selected in Dynamic XML.I dont know how the RTF will create new XML tags and how it will know where to place it in the report. Means, I can create RTF template on Day 1, by loading XML data for 3 columns and placing 3 XML tags in template. But how will it create and place tags for new columns on Day 2?
Hope, you got my requirement, its a challenging one. Please let me know how I can implement the required solution using RTF dynamically without any manual intervention.
Regards,
Swapnil K.
Message was edited by: SwapnilK

Hi All,
I am able to fulfil above requirement. Now I am stuck at below point. Need your help!
Is there any way to UPDATE the XML file attached to a Data Definition (XML Publisher > Data Definition) using a standard package or procedure call or may be an API from backend? I am creating an XML dynamically and I want to attach it to its Data Definition programmatically using SQL.
Please let me know if there is any oracle functionality to do this.
If not, please let me know the standard directories on application/database server where the XML files attached to Data Definitions are stored.
For eg, /$APPL_TOP/ar/1.0/sql or something.
Regards,
Swapnil K.

How to create a dynamic link in a Form to link to a specific FOLDER

Hello,
I have created a reports of all employees of my department.
This reports shows me the empno and ename
When I clicked on a empno ( for example empno = 1 ) then then I got a MASTER DETAIL FORM about that employee(empno = 1) .
Who he or she is and which course he or she had followed.
I want create a dynamic link in the MASTER DETAIL FORM which shows me directly the folder of that employee ( in this example folder 1 ).
If I clickt on the report with all employees of my department on an other number ( for example empno = 3333333) then if I click on the dynamic link in the MASTER DETAIL FORM I want to see the folder of employee 3333333 !!! You know what I mean ?
What I want to know is, how to create a dynamic link that shows me directly a folder which is dependent on which empno I had clicked on in the report ( report with employee numbers and ename )
Is there any way to pass some parameters into a link to a Folder ? Is this possible in Portal ? Does anyone know how to do this, or do you have a suggestion how to solve this problem ?
Thanks a lot !!!
Chu Lam

Hi Chetan,
I am glad that someone had replied on my question.
I will explain it to you again.
I have created a report that shows me all employees. If I click on a employee number then I get an MASTER DETAIL FORM on my screen with all the information(where he works now and which number I have to dial ifhow can I reach him by telephone) of that employee on which number I clicked on.
I really like this mechanism. (You click on a number and the information that you see in the next screen is dependent of the number you clicked on ! )I have created all this. It works fine.
What I want is to expand this example.
Every employee has a FOLDER (yes, those ones in Content Area ) which they can insert text or image into that folder. The folder name is just the employee number. ( employee with employee number 3303, he owns a folder which is named 3303 and an employee with empno 9999, he or she owns a folder with the name 9999. )
Every employee can tell more about himself in that FOLDER by iserting text and images. For example : What he likes, pictures of his vacation, something like this.
What I want is this :
If I click on the first report,which provides me all employees on screen, on a employee number 3303 then I get a Master Detail Form on my screen with all information about that employee with employee number 3303. And I want in this MASTER DETAIL FORM to create a link that shows me directly the FOLDER of that employee ( 3303), so I can learn more about employee with employee number 3303. But I don't know how to create this link.
That link had to be dependent on the employee number. The difficult thing about this link is that this link had to be dynamic.
I hope this will make it clear to you :
(report all employees:)
empno ename
3301 john smith
3302 peter clark
3303 wilson jones
If I click on a empno ( for example 3303) then I get a MASTER DETAIL FORM which provides me information.
(MASTER DETAIL FORM )
EMPNO 3303
ENAME wilson jones
department New York
mobile number 98908763
Company tel. no day
AOL 097485838 monday till wednesday
Oracle 04848584333 thursday and friday
LINK
(what I want is to create a link here )
If I click on LINK in this MASTER DETAIL FORM then I want to link to the FOLDER of this employee ! ( In this example it is FOLDER 3303.
BUT IF I CLICKED ON THE FIRST REPORT ON A DIFFERENT NUMBER ( FOR EXAMPLE 3301) THEN IF I CLICK ON LINK IN THE MASTER DETAIL FORM THEN I HAVE TO LINKED TO FOLDER 3301.
I just want to know how to make a link like this ( create a dynamic link to a specific folder ).
Thanks in Advance.
Chu

How to create a dynamic property in JavaFX

public class Person() {
private SimpleStringProperty _Name = new SimpleStringProperty();
public final String NameGet() {
return this._Name.getValue();
public final void NameSet(String Name) {
this._Name.setValue(ColumnName);
public StringProperty NameProperty() {
return this._Name;
private SimpleStringProperty _SurName = new SimpleStringProperty();
public final String SurNameGet() {
return this._SurName.getValue();
public final void SurNameSet(String SurName) {
this._Name.setValue(ColumnName);
public StringProperty SurNameProperty() {
return this._SurName;
How to create a dynamic property in JavaFX ?
ObservableMap, ObservableMapValue, MapPropertyBase, MapProperty
Which one should I use. Can you give an example?

I'm not sure what you mean by "dynamic property"; can you be more explicit?
Your code creates two properties that can be read, written, and observed for changes, though it's probably better to use the standard naming scheme for the methods (e.g they should be getName(), setName(...) and nameProperty()).
An ObservableMap is an extension of the java.util.Map interface that can be observed; i.e. you can register a listener that will be notified if a key-value pair is added or removed from the map.
ObservableMapValue is an interface that defines an observable reference to an ObservableMap; i.e. it has a get() method returning an ObservableMap and a set(...) method taking an ObservableMap. You can register a ChangeListener which is notified when the set(...) method is called. It additionally functions as an ObservableMap, so you can also register listeners that get notified when key-value pairs are added or removed from the underlying observable map.
MapProperty and MapPropertyBase are effectively partial implementations of ObservableMapValue. SimpleMapProperty is a full implementation.
If you just need a single ObservableMap (i.e. not an observable reference to one), then the FXCollections.observableHashMap() factory method will provide one.

Create a dynamic hyperlink in a picture.

Hello forum,
Can someone help me create a dynamic hyperlink in a picture? Essentially what I have is a drop down box with a list of games. On the same sheet, I have a picture with the Wikipedia icon. What I would like to do is select the game from from the drop
down list and be able to click on the Wikipedia picture on the sheet and have my browser open to the Wikipedia page of the game.
Hopefully I've explained this pretty clearly. Thanks in advance for any help.

Hi,
According to your description, my understanding is that you have a drop down box control and one Wikipedia icon picture in Excel
sheet. And you add the hyperlinks which related to the game behind the picture. If you choose the game name from the drop down box, the Wikipedia icon picture will not change but the hyperlink will change to game introduction and we can click the Wikipedia
picture to open the Wikipedia page in browser.
If it is, your required might use VBA coding/programing. Please post your question to MSDN forum to get more help.
http://social.msdn.microsoft.com/Forums/en-US/home?forum=exceldev&filter=alltypes&sort=lastpostdesc
The reason why we recommend posting appropriately is you will get the most qualified pool of respondents, and other partners who read the forums regularly can either share their knowledge or learn from your interaction with us. Thank you for your understanding.
George Zhao
TechNet Community Support

How to create the dynamic report

Hi,
please help me, how to create the dynamic report

Hi,
Try this..
DATA: p_temp(30) TYPE c DEFAULT 'ZTEST_REPORT'.
TYPES: BEGIN OF t_abapcode occurs 0,
        row(72) TYPE c,
       END OF t_abapcod.
T_ABAPCODE-ROW = 'REPORT ZTEST_REPORT.'.
APPEND T_ABAPCODE.
T_ABAPCODE-ROW = 'WRITE: / ''TEST REPORT''. '.
APPEND T_ABAPCODE.
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naren

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Oracle supports feedback form metalink was; "What you exactly want to approach is not possible in Htmldb"
I can guess that it is not
exactly possible since I looked at the forums and documantation etc. but
couldnt find anything similar than this link; "http://www.oracle.com/technology/products/database/htmldb/howtos/tabular_form.h
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SELECT
vozellik "Ãzellik",
CASE
WHEN (t2.nozellik_deger IS NULL AND t2.vcihaz_oz_deger IS NOT NULL) THEN
'HTMLDB_ITEM.freetext(' || rownum || ', NULL) ' || vozellik
WHEN (t2.nozellik_deger IS NOT NULL AND t2.vcihaz_oz_deger IS NULL) THEN
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', NULL, ''select vdeger a,vdeger b from tozellik_deger where noz_id = ' ||
t1.noz_id || ''' ) ' || vozellik
END AS "DeÄer"
FROM vcihaz_grup_ozellik t1, tcihaz_oz t2
WHERE t1.noz_id = t2.noz_id
AND t2.ncihaz_id = 191
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How to create a dynamic hyperlink which point to a BLOB column

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