How to create grid control in java

hi,
i want grid control in java like visual basic. can any one give me solution.

I am new to this. I want to display the data from database like a grid control. Ok, what problems are you having. You been given a link to the tutorial which shows you how to build a table.
There is also a tutorial on [url http://java.sun.com/docs/books/tutorial/]JDB Database Access here:
http://java.sun.com/docs/books/tutorial/
Start by creating your SQL statement and iterating throught the ResultSet. Once you know how to do that, instead of outputting the data you simply build a DefaultTableModel and create the JTable.

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I know there are lots of experts in this forum
thats y i'm putting this general question.
Will all devices come with an Active X Control.
"To capture a device's events we can use ActiveX Control."
Hows this statement implemented.???
Thanks for the Sample code

I am new to this. I want to display the data from database like a grid control. Ok, what problems are you having. You been given a link to the tutorial which shows you how to build a table.
There is also a tutorial on [url http://java.sun.com/docs/books/tutorial/]JDB Database Access here:
http://java.sun.com/docs/books/tutorial/
Start by creating your SQL statement and iterating throught the ResultSet. Once you know how to do that, instead of outputting the data you simply build a DefaultTableModel and create the JTable.

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Hi,
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Thanks
Satya

@vlsn -- you have to follow what shay said.
Do the following in Model layer ::
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private int sno;
private String orderNum;
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*public int getSno() {*
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gridValues = new ArrayList<gridProps>();
if(btnValue.equals("completeBtn"))
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Right click gridPopulate class and create this as data control.This class will be seen in Data control list.Under this data control,Drag the grid property collection(created earlier) to your page.Then execute your binding(gridPopulate) according to your logic.
Thanks.(My jdev version 11.1.1.5.0)

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Hi Friends,
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Plz tell me how to create table control without wizard.
for sflight table.
Scenario 1
I have one screen like 1000.
There i have taken carrid, connid, fldate as criteria.
Now i want to display Planetype, Price, Seatsmax in the table control.
Scenario 2
i have two screens 1001, 1002.
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and how to save new record in the dictionary table from that table control....

Hi
see the sample programs and design accordingly
syntax:
CONTROLS .
if you only want to determine the row of the table control. SY´-SUBRC allows you to check if the cursor is placed in a row of a table control.
u need to comment the performs of table control fields and write ur own perform statements. And u have to declare the table control fields as separate internal tables.
Go through this urls.
www.****************
www.sap-img.com
Check the below links.
just refer to the link below
http://www.sapmaterial.com/tablecontrol_sap.html
step by step procedure with screen shots
http://www.planetsap.com/howdo_a.htm
http://help.sap.com/saphelp_nw2004s/helpdata/en/9f/dbac5135c111d1829f0000e829fbfe/content.htm
http://sap.niraj.tripod.com/id25.html
Also you can see the below examples...
Go to se38 and give demodynpro and press F4.
YOu will get a list of demo module pool programs.
One more T-Code is ABAPDOCU.
YOu can find more examples there.
See the prgrams:
DEMO_DYNPRO_TABLE_CONTROL_1 Table Control with LOOP Statement
DEMO_DYNPRO_TABLE_CONTROL_2 Table Control with LOOP AT ITAB
http://www.geocities.com/ZSAPcHAT
http://www.allsaplinks.com/files/using_table_in_screen.pdf
Regards
Anji

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Hi,
I have created a Fusion Web Application (ADF) in jdev 11g. In the application model project, I created a java class. Inside the java class, I have a public method as below
public Asset [] searchAsset3(SearchTerm s) // SearchTerm is a java bean. It implements java.io.Serializable.
I created data control from my java class. After that, I see an xml file generated under the same folder of my java class. Here is the xml content.
<?xml version="1.0" encoding="UTF-8" ?>
<JavaBean xmlns="http://xmlns.oracle.com/adfm/beanmodel" version="11.1.1.53.62"
id="AIAAsset" Package="oracle.apps.aia.oer.model"
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Type="com.flashline.registry.openapi.entity.Asset"
BeanClass="com.flashline.registry.openapi.entity.Asset"
id="searchAsset" ReturnNodeName="Asset"
CollectionBeanClass="UpdateableCollection">
<ParameterInfo id="name" Type="java.lang.String" isStructured="false"/>
<ParameterInfo id="version" Type="java.lang.String" isStructured="false"/>
<ParameterInfo id="description" Type="java.lang.String"
isStructured="false"/>
</MethodAccessor>
<MethodAccessor IsCollection="true"
Type="com.flashline.registry.openapi.entity.AssetSummary"
BeanClass="com.flashline.registry.openapi.entity.AssetSummary"
id="searchAssetSummary" ReturnNodeName="AssetSummary"
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<ParameterInfo id="name" Type="java.lang.String" isStructured="false"/>
<ParameterInfo id="version" Type="java.lang.String" isStructured="false"/>
<ParameterInfo id="description" Type="java.lang.String"
isStructured="false"/>
<ParameterInfo id="type" Type="java.lang.String" isStructured="false"/>
</MethodAccessor>
<MethodAccessor IsCollection="true"
Type="com.flashline.registry.openapi.entity.Asset"
BeanClass="com.flashline.registry.openapi.entity.Asset"
id="searchAsset3" ReturnNodeName="Asset"
CollectionBeanClass="UpdateableCollection">
<ParameterInfo id="s" Type="com.flashline.registry.openapi.query.SearchTerm"
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<ConstructorMethod IsCollection="true"
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id="AIAAsset"/>
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Arnold.

Then, my other question is how do you do the bindings? I drag and drop the attributes from SearchTerm bean. Now the pagedef file has the AttributeValues added but my method is actually expecting one input parameter of type SearchTerm. How do you bind the attributes to the input of the method? Thanks.
See below of my pagedef xml file.
<?xml version="1.0" encoding="UTF-8" ?>
<pageDefinition xmlns="http://xmlns.oracle.com/adfm/uimodel"
version="11.1.1.53.62" id="SearchAssetBySearchTerm1PageDef"
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<parameters/>
<executables>
<variableIterator id="variables"/>
<methodIterator Binds="SearchTerm.result" DataControl="AIAAsset"
RangeSize="25"
BeanClass="com.flashline.registry.openapi.query.SearchTerm"
id="SearchTermIterator"/>
</executables>
<bindings>
<methodAction id="SearchTerm" RequiresUpdateModel="true"
Action="invokeMethod" MethodName="SearchTerm"
IsViewObjectMethod="false" DataControl="AIAAsset"
ClassName="com.flashline.registry.openapi.query.SearchTerm"
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<AttrNames>
<Item Value="key"/>
</AttrNames>
</attributeValues>
<attributeValues IterBinding="SearchTermIterator" id="operator">
<AttrNames>
<Item Value="operator"/>
</AttrNames>
</attributeValues>
<attributeValues IterBinding="SearchTermIterator" id="value">
<AttrNames>
<Item Value="value"/>
</AttrNames>
</attributeValues>
<methodAction id="searchAsset3" RequiresUpdateModel="true"
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*<NamedData NDName="s"*
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Hi all,
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Avis_su
<html>
<head><title>JSP Page</title></head>
<body>
<SCRIPT language = "JavaScript">

</script>
</body>
</html>

Run this program to get your answer:
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ion belongs on a Java forum.\n"
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I am reading the following link :-
http://www.itidea.nl/index.php/what-about-you-must-fill-out-all-required-properties-before-completing-this-action-when-publishing-a-page/
which says that i need to create a control and add it to a page layout. but can anyone help me in understanding how i can create a user control and add them to page layout ?
Thanks

> First problem i could not find a User Control (Farm Solution only) under the Office/SharePoint section
if you mean New item in Visual Studio, then check it under general Web category. User controls are basic ASP.Net functionalities, not Sharepoint-specific. If it is not there, you may use the following trick:
1. Create new project in other VS instance using "ASP.Net Empty Web Application" template
2. Add new user control there (in this project type it should exist for sure under Web category. Called "Web User Control")
3. Copy all user control's files to the folder of your Sharepoint project (ascx, ascx.cs, ascx.designer.cs)
4. In VS instance with Sharepoint project add existing items: all copied user control files. They should be grouped under ascx file automatically after that
> The type or namespace name 'TaxonomyFieldControl' could not be found (are you missing a using directive or an assembly reference?)"
you need to add reference to Microsoft.SharePoint.Taxonomy.dll assembly, which is located in the GAC (assume that you have installed Sharepoint on your dev env)
Blog - http://sadomovalex.blogspot.com
Dynamic CAML queries via C# - http://camlex.codeplex.com
thanks a lot for your help. so can i do the following steps:-
I follow these steps to deploy a user control.
using Visual Studio 2012 , i added a new Farm solution.
then inside the farm solution i added a new User Control(Farm Solution Only).
3. inside the user control i entered the following code:-
using Microsoft.SharePoint;
using Microsoft.SharePoint.Taxonomy;
using Microsoft.SharePoint.WebControls;
using System;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
namespace WikiPopUp.ControlTemplates.WikiPopUp
[ToolboxData("<{0}:CustomValidationRequiredFieldsOnPage runat=server></{0}:CustomValidationRequiredFieldsOnPage>")]
public class CustomValidationRequiredFieldsOnPage : WebControl
protected override void CreateChildControls()
base.CreateChildControls();
if (SPContext.Current.FormContext.FormMode == SPControlMode.Edit)
bool arethere = AreThereAnyMissingRequiredFieldsOnPage();
if (arethere)
//SPPageStateControl:
//Provides an ASP.NET control that handles the Ribbon buttons controlling the state of a Microsoft SharePoint Server wiki or publishing page,
//such as the CheckInCheckOutButton or the PublishingButton.
SPPageStateControl baseParentStateControl = Page.Items[typeof(SPPageStateControl)] as SPPageStateControl;
//Publish button: SPListItem MissingRequiredFields checks this.FieldHasValue(link.Name, field);
//the field is empty (which is right) when the page is first created (MMD field is never filled in)
//when the field was once filled, saved and emptied the field in sp code still has the previous value and the check MissingRequiredFields succeeds
//after succeeding this check the page is validated (this.Page.Validate()) and this one fails which results SP validating the page as the Save button does
if (baseParentStateControl.HasError)
//this overwrites the previous PageErrorState
//and validates the page
//no popup anymore and status updates in yellow area
baseParentStateControl.EnsureItemSavedIfEditMode(false);
else
//there are missing fields at this listitem, but they're not on the page
//do nothing here, because the SerializedErrorState contains the navigate url to the Edit Properties page
//and a message pops up
/// <summary>
/// Check if required fields are missing which are present at the page
/// </summary>
/// <returns></returns>
private static bool AreThereAnyMissingRequiredFieldsOnPage()
foreach (Control control in SPContext.Current.FormContext.FieldControlCollection)
//get the control type
string type = control.GetType().Name;
FieldTypes controlType = (FieldTypes)Enum.Parse(typeof(FieldTypes), type);
switch (controlType)
case FieldTypes.TaxonomyFieldControl:
TaxonomyFieldControl tfc = control as TaxonomyFieldControl;
if (!tfc.IsValid)
return true;
break;
default:
break;
return false;
enum FieldTypes
DateTimeField, FieldValue, TextField, RichImageField, NoteField, RichHtmlField, PublishingScheduleFieldControl, TaxonomyFieldControl, BooleanField, ComputedField
4. i add a reference for the Sharepoint.taxnomy
5. then i deploy the solution to my site collection. and now i can see the new solution inside the farm solution under central administration.
but not sure if these are all the required steps to register the user control or still i need to do extra steps ?

How to create grid control in java

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