How to disable programmatically created Submit Button in ProcessFormRequest

Hi All,
I'm working on an issue where i have created an Upload button Programmatically. The upload button should get disabled after it is clicked. The code for the upload button creation is as below. This has been added in the processRequest of CO.
OASubmitButtonBean oasb;
oasb =
(OASubmitButtonBean)pageContext.getWebBeanFactory().createWebBean(pageContext,
OAWebBeanConstants.BUTTON_SUBMIT_BEAN,
null,
"BUTTON_SUBMIT");
oasb.setID("Upload");
oasb.setUINodeName("Upload");
oasb.setEvent("Upload");
oasb.setText("Upload");
Now, when i handle the upload button click in the processFormRequest, i should also disable the button at the end. I followed the below method in the processFormRequest but it threw a null pointer exception at the point where i have disabled the button.
public void processFormRequest(OAPageContext pageContext, OAWebBean webBean)
super.processFormRequest(pageContext, webBean);
String strEvent = pageContext.getParameter(EVENT_PARAM);
OAApplicationModule am = pageContext.getApplicationModule(webBean);
if (strEvent.equals("Upload"))
OASubmitButtonBean oasb2 = (OASubmitButtonBean)webBean.findIndexedChildRecursive("Upload");
oasb2.setDisabled(true); --- this is where the null pointer exception gets thrown
I'm not sure if this is the way to go about it. Could you please let me know how to handle the above request?
Regards,
Shreyas
Edited by: user11258661 on Mar 28, 2012 7:15 AM

Hi Ram,
Thank you for the response. I have created the button programmatically. So I'm not sure how to add the newly created button to the webBean as child. I'm new to OAF. So could you please elaborate. A code snippet might help.
Thanks in advance.
Regards,
Shreyas

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