How to do SQL Command for this
Hi,
I have 2 tables.
TempTT TempTB
Name Place DeviceName Products
Factory_55 Indonesia Factory_55##11122 Pencils
Factory_22 USA Factory_22##23444 Pens
Factory_33 UK Factory_22##82922 Erasers
How do I do my SQL command if I wanted to extract DeviceName from TempTB
if TempTT.Name is found in TempTB.DeviceName??
Please advise me. Thank you!!
I do not want to join them. I show my table here again. I wanted to SELECT DeviceName from TempTB if the Name from TempTT is found in DeviceName of TempTB. Thanks alot!
TempTT
Name Place
Factory_55 Indonesia
Factory_22 USA
Factory_33 UK
TempTB
DeviceName Products
Factory_55##11122 Pencils
Factory_22##23444 Pens
Factory_22##82922 Erasers
Similar Messages
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How to write SQL hints for this query?
The query is like:
select * from foo, t
where foo.name in
(select name from bar
where id in (
select id from car
where date < sysdate
and foo.a = t.b;
I want the innermostsubquery 'select id from car ...' to be executed first, and the subquery 'select name from bar ...' to be execute second, and the outermost query 'select * from foo,t ...' to be executed the last. How can I write the Oracle sql hints to force the order?
Thanks.user553560
You might be able to create a large set of hints to force the access path you want - but unless you really know what you are doing with hints, you may find that your solution is very unstable (it might be luck rather than correctness that let's it work to start with).
The difficulty in this query is the double layer of IN subqueries, so if you can rewrite the query, you might try manually unnesting as follows:
select
t1.*. t.*
from
select
distinct t2.name
from t2
where t2.id in (
select t3.id
from t3
where t3.dated < sysdate
) v,
t1,
t
where
t1.name = v.name
and t1.a = t.bDepending on your indexing and statistics, you may find that a simple /*+ unnest */ hint in the first subquery will be sufficient to do this for your. Again depending on the statistics you may find that you have to put extra hints into the above to make Oracle use the join method and indexes you think appropriate.
N.B. The first step (as others have noted) is to check that your statistics are good before you start manipulating the code or using hints.
Regards
Jonathan Lewis
http://jonathanlewis.wordpress.com
http://www.jlcomp.demon.co.uk -
How to write sql query for counting pairs from below table??
Below is my SQL table structure.
user_id | Name | join_side | left_leg | right_leg | Parent_id
100001 Tinku Left 100002 100003 0
100002 Harish Left 100004 100005 100001
100003 Gorav Right 100006 100007 100001
100004 Prince Left 100008 NULL 100002
100005 Ajay Right NULL NULL 100002
100006 Simran Left NULL NULL 100003
100007 Raman Right NULL NULL 100003
100008 Vijay Left NULL NULL 100004
It is a binary table structure.. Every user has to add two per id under him, one is left_leg and second is right_leg... Parent_id is under which user current user is added.. Hope you will be understand..
I have to write sql query for counting pairs under id "100001". i know there will be important role of parent_id for counting pairs. * what is pair( suppose if any user contains both left_leg and right_leg id, then it is called pair.)
I know there are three pairs under id "100001" :-
1. 100002 and 100003
2. 100004 and 100005
3. 100006 and 100007
100008 will not be counted as pair because it does not have right leg..
But i dont know how to write sql query for this... Any help will be appreciated... This is my college project... And tommorow is the last date of submission.... Hope anyone will help me...
Suppose i have to count pair for id '100002'. Then there is only one pair under id '100002'. i.e 100004 and 100005Sounds like this to me
DECLARE @ID int
SET @ID = 100001--your passed value
SELECT left_leg,right_leg
FROM table
WHERE (user_id = @ID
OR parent_id = @ID)
AND left_leg IS NOT NULL
AND right_leg IS NOT NULL
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs -
How to run PL/SQL commands in this SQL browser
How to run PL/SQL commands in this SQL browser
This discussion should help Re: my pl/sql codes does not run in express edition what can i do????
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How execute pl/sql command from Oracle ADF Business Components
can't find examples for how execute pl/sql command from Oracle ADF Business Components and how call pl/sql package procedure from ADF Business Components.
insert,update,delete rows in view object instance cache is good but if i must do some complex operations while insert,update,delete rows..it's more better for me to call
pl/sql procedure from oracle db.Am i wrong ????Roman,
this should be similar to how it worked in JDeveloper 9.0.3. hava a look at <JDev903 Home>\BC4J\samples\StoredProc for a code example.
Frank -
Need help on Sql command for count
Hi,
I have the following table.
Temp_Set Table
ID Names Action
1 John Delete
2 John Add
3 Mary Update
4 Sim Add
5 Sim Update
How do I do a SELECT sql command for count(names) > 1 ?
Please kindly advise me. Thank you very much.It doesnt work when I do this
SELECT * FROM Temp_Set
HAVING Count(names) > 1
It prompts me the following error:
ORA-00937: not a single-group group function
00937.00000 - "not a single-group group function"
*Cause:
*Action:
Error at Line:16 Column:7i am not sure but you can try this:
SELECT B.* FROM
(SELECT NAMES, COUNT(1) CNT FROM TEMP_SET GROUP BY NAMES) A, TEMP_SET B
WHERE A.NAMES = B.NAME
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Hi,
I need a PL/SQL code for this one...
Let me know if something is not clear...
1) The table CLOB_CLOBJECT_CDA has the columns described below...
Explaining only those fields which are important in this context
-- CDA_STEP_ID : Basically a Sequence
-- CLOBJECT_SOURCE1_ID : Every id has got a set of records
-- CLOBJECT_SOURCE2_ID : Every id has got a set of records
-- LVL : There are total 8 levels..
This is the main aim :
1) There are total 16 million rows..(limited to 10 rows here)
2) We need to go through level by level (LVL column) & insert the intersection records (CLOBJECT_SOURCE1_ID intersect CLOBJECT_SOURCE2_ID)
into another table...but this is how it goes..
Level (LVL column) 3's basically have CLOBJECT_SOURCE1_ID as level (LVL column) 2 CDA_STEP_ID's..
(consider the statement --** where CLOBJECT_SOURCE1_ID = 285 which is same as 1st insert statement step id)..
The above process goes for next levels until 8..(so have to use loops)
So for ex :
We go through the first insert statement and insert the insertion records only when both CLOBJECT_SOURCE1_ID & CLOBJECT_SOURCE2_ID has got records ..
If we don't find any records for both of them we should skip the corresponding step id when we go to the next levels...
Let's go through the 1st insert statement...
-- We have CDA_STEP_ID = 285 & two sources CLOBJECT_SOURCE1_ID as 19 & CLOBJECT_SOURCE2_ID as 74...
-- We see the table CLOBJECT_COUNTS & check whether we have counts for both 19 & 74 ..(In fact we insert counts into this table only if they have records)
-- If so, we insert the intersection records into CDA_MRN_RESULTS ( we do have counts for both of them..) with CDA_STEP_ID 285...
-- Then we insert the step id which is 285 along with the count into CLOBJECT_COUNTS..
Let's go through another insert statement...
-- Consider CDA_STEP_ID = 288 which has two sources CLOBJECT_SOURCE1_ID as 19 & CLOBJECT_SOURCE2_ID as 92...
-- We see the table CLOBJECT_COUNTS & check whether we have counts for both 19 & 92 ..(we have records for 19 but not for 92)
-- So we should not proceed with this..& also skip all those records (future records with increasing levels..basically level 3's) which have got 288 as CLOBJECT_SOURCE1_ID..
(As said earlier that the present CDA_STEP_ID will always be CLOBJECT_SOURCE1_ID in the next level)...
I wrote the following code which is after the statement...
Let me have the create & insert statements here..
create table CLOB_CLOBJECT_CDA
CDA_STEP_ID NUMBER,
CDA_ID NUMBER,
CDA_SEQ_NUMBER NUMBER,
CLOBJECT_SOURCE1_TYPE VARCHAR2(3000),
CLOBJECT_SOURCE1_ID NUMBER,
CLOBJECT_OPERATOR VARCHAR2(3000),
CLOBJECT_SOURCE2_TYPE VARCHAR2(3000),
CLOBJECT_SOURCE2_ID NUMBER,
LVL NUMBER
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (285, 285, 1, 'CLOBJECT', 19, 'INTERSECT', 'CLOBJECT', 74, 2);
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (286, 286, 1, 'CLOBJECT', 19, 'INTERSECT', 'CLOBJECT', 75, 2);
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (287, 287, 1, 'CLOBJECT', 19, 'INTERSECT', 'CLOBJECT', 91, 2);
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (288, 288, 1, 'CLOBJECT', 19, 'INTERSECT', 'CLOBJECT', 92, 2);
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (4869, 4869, 1, 'CDA_STEP', 285, 'INTERSECT', 'CLOBJECT', 91, 3); -- **
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (4870, 4870, 1, 'CDA_STEP', 285, 'INTERSECT', 'CLOBJECT', 92, 3);
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (4871, 4871, 1, 'CDA_STEP', 285, 'INTERSECT', 'CLOBJECT', 93, 3);
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (4880, 4880, 1, 'CDA_STEP', 286, 'INTERSECT', 'CLOBJECT', 91, 3);
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (4881, 4881, 1, 'CDA_STEP', 286, 'INTERSECT', 'CLOBJECT', 92, 3);
insert into clob_clobject_cda (CDA_STEP_ID, CDA_ID, CDA_SEQ_NUMBER, CLOBJECT_SOURCE1_TYPE, CLOBJECT_SOURCE1_ID, CLOBJECT_OPERATOR, CLOBJECT_SOURCE2_TYPE, CLOBJECT_SOURCE2_ID, LVL)
values (4882, 4882, 1, 'CDA_STEP', 286, 'INTERSECT', 'CLOBJECT', 93, 3);
create table CDA_MRN_RESULTS
CDA_STEP_ID NUMBER,
MRN NUMBER,
INSERT_DATE_TIME DATE
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (19, 1, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (19, 2, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (19, 3, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (74, 1, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (74, 2, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (74, 4, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (75, 1, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (75, 2, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (75, 6, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (91, 2, to_date('19-10-2011', 'dd-mm-yyyy'));
insert into cda_mrn_results (CDA_STEP_ID, MRN, INSERT_DATE_TIME)
values (91, 3, to_date('19-10-2011', 'dd-mm-yyyy'));
create table CLOBJECT_COUNTS
CDA_STEP_ID NUMBER,
CLOBJECT_COUNT NUMBER,
DATE_TIME DATE
Insert into CLOBJECT_COUNTS values (19,3, to_date('19-10-2011', 'dd-mm-yyyy'));
Insert into CLOBJECT_COUNTS values (74,3, to_date('19-10-2011', 'dd-mm-yyyy'));
Insert into CLOBJECT_COUNTS values (75,3, to_date('19-10-2011', 'dd-mm-yyyy'));
Insert into CLOBJECT_COUNTS values (91,2, to_date('19-10-2011', 'dd-mm-yyyy'));The output goes into two tables...
CDA_MRN_RESULTS : O/p of intersection records between source1 & source2 id
CLOBJECT_COUNTS : Step id with counts ...(useful for skipping next level step id's if either of source id has "0" counts)
Any help is appreciated..
Thanks..I tried to code this..but looping takes a lot of time..I want to skip certain rows where source1_step_id & source_2_step_id are not in clobject_counts table as we proceed to the next levels..Not sure how to skip the rows..
declare
cursor c1 (p_level varchar2 ) is
Select * from clob_clobject_cda
where lvl = p_level ;
TYPE V_TT IS TABLE OF C1%ROWTYPE INDEX BY PLS_INTEGER;
L_TT V_TT;
v1 number;
v2 number;
v_step_id number;
v_operator varchar2(100) := '';
begin
for i in 2..8 loop
open c1(i);
LOOP
FETCH C1 BULK COLLECT INTO L_TT LIMIT 500;
FOR indx IN 1 .. L_TT.COUNT
LOOP
v1 := L_TT(indx).clobject_source1_id;
v2 := L_TT(indx).clobject_source2_id;
v_step_id := L_TT(indx).cda_step_id;
v_operator := L_TT(indx).clobject_operator;
Execute Immediate ('Insert into cda_mrn_results Select --+ parallel (cm 128)
distinct ' || v_step_id || ', mrn, trunc(sysdate) dt from cda_mrn_results cm
where cda_step_id = ' || v1 || '
and cda_step_id in (Select cda_step_id from clobject_counts) ' ||
v_operator ||
' Select --+ parallel (cm 128)
distinct ' || v_step_id || ', mrn, trunc(sysdate) dt from cda_mrn_results cm
where cda_step_id = ' || v2 || '
and cda_step_id in (Select cda_step_id from clobject_counts) ' );
Insert --+ Append
into clobject_counts Select cda_step_id, count(distinct mrn),
insert_date_time dt from cda_mrn_results where cda_step_id = v_step_id group by cda_step_id,insert_date_time;
COMMIT;
END LOOP;
EXIT WHEN L_TT.COUNT = 0;
END LOOP;
CLOSE C1;
End Loop;
Commit;
End; -
How to create sql query for item master with operator LIKE with variables?
hi all,
How to create sql query for item master with
operator LIKE(Contains,Start With,End With) with variables using query generator in SAP B1 ?
JeyakanthanHi Jeyakanthan,
here is an example (put the like statement into the where field)
SELECT T0.CardCode, T0.CardName FROM OITM T0 WHERE T0.CardName Like '%%test%%'
The %% sign is a wildcard. If you need start with write 'test%%' and otherwise ends with '%%test'. For contains you need '%%test%%'. You also could combinate this statements like 'test%%abc%%'. This means starts with test and contains abc.
Regards Steffen -
I want sql query for this output
hi guys
could u tell how can i write sql query for this out put
i have one table like this
ID ACCOUTID TAX
1 1 A
2 1 B
3 2 C
4 2 D
5 3 E
7 NULL F
8 NULL G
MY OUT PUT MUST BE LIKE THIS
ID AID TAX
2 1 A
4 2 D
7 NULL F
8 NULL G
HERE IN THIS OUTPUT I SHOULD HAVE
MAXIMAM ID VALUE FOR A REPEATED AID VALUES
AND
THE ROWS AID VALUES IS NULL ALSO MUST PAPULATED IN THE OUTPUT.
I KNOW ONE SOLUTION LIKE THIS
SELECT MAX(ID),AID,TAX
FROM TABLE T
GROUP BY AID,TAX
UNION ALL
SELECT ID, AIC,TAX
FROM TABLE T
WHERE AID IS NULL;
BUT I WANT SAME RESULT WITH OUT USING LOGICAL OPERATORS.
COULD U PLZ TELL A SOL.Will this help:
SQL> with t as
2 (
3 select 1 ID, 1 ACCOUTID, 'A' TAX from dual union all
4 select 2, 1, 'B' from dual union all
5 select 3, 2, 'C' from dual union all
6 select 4, 2, 'D' from dual union all
7 select 5, 3, 'E' from dual union all
8 select 7, NULL, 'F' from dual union all
9 select 8, NULL, 'G' from dual
10 )
11 --
12 select id, ACCOUTID AID, Tax
13 from
14 (
15 select t.*
16 ,count(1) over (partition by t.ACCOUTID) cn
17 ,row_number() over (partition by t.ACCOUTID order by id desc) rn
18 from t
19 )
20 where cn > 1
21 and (rn = 1 or ACCOUTID is null)
22 /
ID AID T
2 1 B
4 2 D
8 G
7 F
-- If I leave out the OR condition then you'll get this:
SQL> ed
Wrote file afiedt.buf
1 with t as
2 (
3 select 1 ID, 1 ACCOUTID, 'A' TAX from dual union all
4 select 2, 1, 'B' from dual union all
5 select 3, 2, 'C' from dual union all
6 select 4, 2, 'D' from dual union all
7 select 5, 3, 'E' from dual union all
8 select 7, NULL, 'F' from dual union all
9 select 8, NULL, 'G' from dual
10 )
11 --
12 select id, ACCOUTID AID, Tax
13 from
14 (
15 select t.*
16 ,count(1) over (partition by t.ACCOUTID) cn
17 ,row_number() over (partition by t.ACCOUTID order by id desc) rn
18 from t
19 )
20 where cn > 1
21* and rn = 1
SQL> /
ID AID T
2 1 B
4 2 D
8 G
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How to create a hirarchy for this characteristic having lengh 50?
Hi guru's
I have a scenario like characteristic is having lengh 50.Now I want to create a hierarchy for this characteristic.
But Hirarchy allows maximum lengh 32chrs only.
So could you please let me know how to create a hirarchy for this characteristic having lengh 50?
Thanks in advance
SivanandIsn't this the same question as here:
Hi all, Have a problem, Please let me know urgently.
Why the duplicate postings with different names?? -
Arabic is not listed as a display language in iTunes for Windows 7. How can I add support for this language?
Edit ---> referance -----> general ------> language
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Need pl/sql stmnts. for this simple logic
Hi,
I need PL/SQL program for this simple logic i am doing mistake somewhere unbale to trace
out ..
select * from GSR03_PO_DTL;
PO_NUM
L53177000 -- > no changes reqd (only one entry with new format)
L00041677 --> to be updated to L41677000(only one entry with OLD format)
L43677000 -- > no change reqd (exists one row with new format and old format like below)
L00043677 -- > to be deleted this is old format (and new format like above already exists)
EX:
L00012345 --- old format
L12345000 --- new format
Hope question is clear. I written the following program.
update is working fine but delete is not working.
Please help.
Thanks in Advance
Devender
declare
Cursor c_test is
(select po_num from GSR03_PO_DTL);
BEGIN
FOR r_test in c_Test
LOOP
dbms_output.put_line (r_test.po_num);
IF ('L'||substr(r_test.po_num,5,5)) = ('L'||substr(r_test.po_num,2,5)) then
dbms_output.put_line ('delete stmnt');
END IF;
EXIT WHEN c_test%NOTFOUND;
END LOOP;
FOR r_test in c_Test
LOOP
IF r_test.po_num like 'L000%' then
IF ('L'||substr(r_test.po_num,5,5)) is not NULL then
update GSR03_PO_DTL set PO_NUM = 'L'||substr(po_num,5,5)||'000'
where po_num like 'L000%' ;
dbms_output.put_line ('update stmnt');
END IF;
END IF;
END LOOP;
END;
*********************No need for PL/SQL, man.
SQL> SELECT po_no FROM po1
2 /
PO_NO
L53177000
L00041677
L43677000
L00043677
SQL> UPDATE po1 y
2 SET y.po_no = 'L'||substr(y.po_no,5,5)||'000'
3 WHERE y.po_no LIKE 'L000%'
4 AND NOT EXISTS ( SELECT null FROM po1 x
5 WHERE x.po_no = 'L'||substr(y.po_no,5,5)||'000')
6 /
1 row updated.
SQL> DELETE FROM po1 y
2 WHERE y.po_no LIKE 'L000%'
3 AND EXISTS ( SELECT null FROM po1 x
4 WHERE x.po_no = 'L'||substr(y.po_no,5,5)||'000')
5 /
1 row deleted.
SQL> SELECT po_no FROM po1
2 /
PO_NO
L53177000
L41677000
L43677000
SQL> Cheers, APC -
How to write Select statement for this codition
I need to check whether SGTXT contains BELNR value.
SGTXT is a text field and It should be matched with BELNR
How to write select statement for this.
Select AUGBL AUGDT into t_BSAD
from BSAD
where SGTXT should have the given BELNR Value.
Plz note : Here I cannot give as SGTXT = BELNR as coz BELNR have only 10 digits.Hi,
data temp(12).
concatenate '%' belnr '%' into temp.
Select AUGBL AUGDT into t_BSAD
from BSAD
where SGTXT like temp.
If belnr is having multiple values,just create a internal table as follows.
types : begin of ty,
belnr....
temp(12),
end of ty.
data itab_ type standard table of ty.
data wa type ty.
loop at itab into wa.
concatenate '%' wa-belnr '%' into wa-temp.
modify itab from wa index sy-tabix transporting temp.
endloop.
Change your select statement accordingly.
Kindly reward poits if it helps. -
APP-ALR-04106: Please correct the user-defined SQL statement for this alert
Hi All,
I have created an alert for engineering module in R12. It got tested and was working fine. when the user testing it, while trigger the alert getting the error, "APP-ALR-04106: Please correct the user-defined SQL statement for this alert".
when verified the alert, it got verified and ran also. It parsed the query successfully and when run it fetched few records.
Need help in resolving the issue.
Thanks in advance.
Regards,
sri
Edited by: user10939296 on Jan 18, 2010 1:16 AMHi Sri;
I have already gone through the Note: 948037.1. But this note is related to 11i. The solution provided in the Note is for 11i.
I am facing this issue in R12. Is this patch applicable to R12?I belive its not. But u can check Solution part 4 for your instance, at least it can give you idea. The other note in metalink related bug and all for R11 too.
I belive its better way to rise Sr while waiting other forum user response to that thread
Regard
Helios -
Is it possible to share my calendar with all my subscription? If so How can i find URL for this?
Hi yilmazfromlondon,
The resource below explains how to share your iCloud calendars publicly. Is this what you are asking about?
iCloud: Share a calendar with others
http://support.apple.com/kb/PH2690
iCloud: Share a calendar with others
You can share a calendar both publicly and privately with other people. For specifics about viewing and editing privileges for shared calendars, and how participants can access the calendars, see Calendar sharing overview.
Share a calendar privately
Click the Share button to the right of the calendar name in the sidebar, then select Private Calendar.
Note: You can also share the same calendar publicly. For instructions, see the next task, “Share a calendar publicly.”
Type the invitee’s email address in the Add Person field and press Return.
Click the pop-up menu with the invitee’s name and choose access privileges (View & Edit or View Only).
For each person you want to share the calendar with, repeat steps 2 and 3.
When you’ve invited everyone and set their privileges, click OK.
Invitation emails are sent from your iCloud email address to the participants you specified.
Share a calendar publicly
Click the Share button to the right of the calendar you want to share, then select Public Calendar.
Note: You can also share the same calendar privately. For instructions, see the previous task, “Share a calendar privately.”
To invite people to view the calendar, click Email Link.
Type one or more email addresses in the To field, then click Send.
The people you specify automatically receive an invitation email that includes the calendar’s URL. An invitee doesn’t need to be an iCloud user to accept an invitation to view a shared public calendar.
In the sidebar, a shared calendar has a dark Share button.
You can also resend invitations to one or more invited participants at any time.
Last Modified: Feb 5, 2015
Cheers,
Judy
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