How to fill internal table dynamically

Question

Hi All,
   how to fill internal table dynamically.
for example:
begin of itab occurs 0,
empid like pa0000-pernr,
empname like pa0001-ename,
grade(5),
end of itab.
now i want to append dynamically field itab-grade along with rest fields.
is this possible?? if yes kindly let me know how to do that.
Regards,
Kiran I

Answer 1

Hi kiran,
To fill and create and internal table dynamically you can use this code.
TYPE-POOLS: slis.
DATA: it_fcat TYPE slis_t_fieldcat_alv,
      is_fcat LIKE LINE OF it_fcat.
DATA: it_fieldcat TYPE lvc_t_fcat,
      is_fieldcat LIKE LINE OF it_fieldcat.
DATA: new_table TYPE REF TO data.
DATA: new_line  TYPE REF TO data.
FIELD-SYMBOLS: <l_table> TYPE ANY TABLE,
               <l_line>  TYPE ANY,
               <l_field> TYPE ANY.
is_fieldcat-fieldname = 'FIELD1'.
is_fieldcat-ref_field = 'MATNR'.
is_fieldcat-ref_table = 'MARA'.
APPEND is_fieldcat TO it_fieldcat.
is_fieldcat-fieldname = 'FIELD2'.
is_fieldcat-ref_field = 'SPRPS'.
is_fieldcat-ref_table = 'PA0001'.
APPEND is_fieldcat TO it_fieldcat.
is_fieldcat-fieldname = 'FIELD3'.
is_fieldcat-ref_field = 'BEGDA'.
is_fieldcat-ref_table = 'PA0002'.
APPEND is_fieldcat TO it_fieldcat.
Create a new Table
CALL METHOD cl_alv_table_create=>create_dynamic_table
  EXPORTING
    it_fieldcatalog = it_fieldcat
  IMPORTING
    ep_table        = new_table.
Create a new Line with the same structure of the table.
ASSIGN new_table->* TO <l_table>.
CREATE DATA new_line LIKE LINE OF <l_table>.
ASSIGN new_line->* TO <l_line>.
Test it...
DO 40 times.
  ASSIGN COMPONENT 'FIELD1' OF STRUCTURE <l_line> TO <l_field>.
  <l_field> = '12345'.
  ASSIGN COMPONENT 'FIELD2' OF STRUCTURE <l_line> TO <l_field>.
  <l_field> = 'X'.
  ASSIGN COMPONENT 'FIELD3' OF STRUCTURE <l_line> TO <l_field>.
  <l_field> = '20030101'.
  INSERT <l_line> INTO TABLE <l_table>.
ENDDO.
LOOP AT <l_table> ASSIGNING <l_line>.
ASSIGN COMPONENT 'field1' OF STRUCTURE <l_line> TO <l_field>.
  WRITE  / <l_line>.
ENDLOOP.
regards,
Aashish Garg