How to find out the URL in message

Hi,
I am giving the input is
<message>hai www.google.com</message>
here iam giving "hai" is the message and "www.google.com" is the url link.
but in my application i will get the input from message and passed to urllink here the output shows "hai www.google.com" is the url link.
but i want to separate the message (" hai") and url link("www.google.com") separatly.
pls can any body help on this issue.
how to resolve this issue.

in xsl you can use the function tokenize
http://www.xml.com/pub/a/2003/05/07/tr.html
you will spilt the string with the ' ' character and after that you can loop over the array
in the array the first element will be your 'hai' string and the second will be your url
if im not wrong this is a xsl stylesheet 2.0 function, but you can replace the identifier in the xsl which is generated from jdeveloper/bpel from 1.0 to 2.0

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