How to find the difference between two date?

Hi,
I currently writing a date comparision program. Below is the idea analogy,
Currently i need to find how many day differences between 30 July 2003 and 22 June 2004. How can i use java to code it?
Thanks.

there doesn't seem to be a direct way but try this:int daysBetween = 0;
Calendar c = new GregorianCalendar(2004, Calendar.JULY, 30);
Calendar d = new GregorianCalendar(2003, Calendar.JUNE, 22);
while (c.get(Calendar.YEAR) != d.get(Calendar.YEAR)) {
    daysBetween += 360;
    d.add(Calendar.DAY_OF_YEAR, 360);
daysBetween += c.get(Calendar.DAY_OF_YEAR) - d.get(Calendar.DAY_OF_YEAR);This gives the correct result of 404 (= 8 days from June 22 to June 30 + 366 days between July 1 of 2003 and 2004 + 30 days from July 1 to July 30)

Similar Messages

  • How to get the difference between two date

    Hello,
    I want to know how to write a code the tell me the difference between two date, I am using
    oracle.jbo.domain.Date
    i have a rent date and return date so my code is
    Date rent=(Date)nr.getAttrbute("RentDate"),ret=(Date)nr.getAttrbute("ReturnDate");
    is there a way to know the difference in days between those two dates ?
    Thanks

    hi,
    try this.....
    DateFormat formatter = new SimpleDateFormat("E MMM dd HH:mm:ss Z yyyy");
    Date date = (Date)formatter.parse(dateStr); //// dateStr <- from date value (that is string value)
    Date dateto = (Date)formatter.parse(datetostr); //// datetostr <- to date value (to date getting from as a string)
    Calendar cal = Calendar.getInstance();
    cal.setTime(date);
    Calendar calto = Calendar.getInstance();
    calto.setTime(dateto);
    fromDate = cal.get(Calendar.DATE) + "/" + (cal.get(Calendar.MONTH) + 1) + "/" + cal.get(Calendar.YEAR);
    toDate = calto.get(Calendar.DATE) + "/" + (calto.get(Calendar.MONTH) + 1) + "/" + calto.get(Calendar.YEAR);
    // System.out.println("from Date : " + fromDate);
    if ((fromDate != null && toDate != null) && (date.compareTo(dateto) > -1) ) {                  
    fc.addMessage("VacationQueryComponent", new FacesMessage(FacesMessage.SEVERITY_ERROR, "From Date cannot be lower than To Date", "From Date cannot be lower than To Date"));
    fc.renderResponse();
    thks.

  • Find the difference between two dates for the specific month and year

    Hi,
    I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
    for that date. In this case I input Jan 2013. How can I sql this ?

    I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
    First let me understand you:
    You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
    declare @for_month int = 1 --January
    declare @for_year int = 2013
    declare @StartDate date = '2012-12-20'
    declare @EndDate date = '2013-01-04'
    SELECT
    CASE
    WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
    DATEDIFF(DAY, @StartDate,@EndDate)
    WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
    DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
    WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
    DATEDIFF(DAY, @StartDate,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, @StartDate) + 1, 0))) + 1
    WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
    DATEDIFF(DAY, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime), DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime)) + 1, 0))) + 1
    ELSE
    0
    END as [DD]
    I don't know how you calculate day range between 01/01/2013 and 04/01/2013
    is 4, it is actually is 3 but if that is the case, you can add 1 from the condition.

  • How to calculate the difference between two dates?

    Hello,
    I would like to write some code which figures out how many days are between the Date_of_change (which is of datatype DATE, length 7 and of format DD-MON-YY) and the current date today. Then if the difference between Date_of_change and the current date is greater that 30 days for example then I would like to delete that record from the database.
    Thanks
    Doug

    Something like this should work:
    SQL> select * from emp order by hiredate ;
         EMPNO ENAME      JOB              MGR HIREDATE           SAL       COMM     DEPTNO
          7934 MILLER     CLERK           7782 21-OCT-2005       1300                    10
          7902 FORD       ANALYST         7566 22-OCT-2005       3000                    20
          7900 JAMES      CLERK           7698 23-OCT-2005        950                    30
          7876 ADAMS      CLERK           7788 24-OCT-2005       1100                    20
          7844 TURNER     SALESMAN        7698 25-OCT-2005       1500          0         30
          7839 KING       PRESIDENT            26-OCT-2005       5000                    10
          7788 SCOTT      ANALYST         7566 27-OCT-2005       3000                    20
          7782 CLARK      MANAGER         7839 28-OCT-2005       2450                    10
          7698 BLAKE      MANAGER         7839 29-OCT-2005       2850                    30
          7654 MARTIN     SALESMAN        7698 30-OCT-2005       1250       1400         30
          7566 JONES      MANAGER         7839 31-OCT-2005       2975                    20
          7521 WARD       SALESMAN        7698 01-NOV-2005       1250        500         30
          7499 ALLEN      SALESMAN        7698 02-NOV-2005       1600        300         30
          7369 SMITH      CLERK           7902 03-NOV-2005        800                    20
    14 rows selected.
    SQL> delete from emp where hiredate < sysdate - 30 ;
    10 rows deleted.
    SQL> select * from emp order by hiredate ;
         EMPNO ENAME      JOB              MGR HIREDATE           SAL       COMM     DEPTNO
          7566 JONES      MANAGER         7839 31-OCT-2005       2975                    20
          7521 WARD       SALESMAN        7698 01-NOV-2005       1250        500         30
          7499 ALLEN      SALESMAN        7698 02-NOV-2005       1600        300         30
          7369 SMITH      CLERK           7902 03-NOV-2005        800                    20
    4 rows selected.
    SQL>

  • How to get the difference between two dates???

    HI I have two dates and I want to test if there is an hour between them.
    Is there a way to compare two dates like mySQL can with dateDiff(date1,date2);
    Thanks alot.
    Graham

    This link is now out of date as they have revamped the structure. Yep. Here it is again: http://forum.java.sun.com/thread.jsp?forum=31&thread=502686
    I've also noticed that my comment regarding daylight saving was misleading. The demonstrated method for calculating difference between Dates is reliable. However, one needs to be careful when interpreting Dates in a daylight saving timezone.

  • How to find the difference between two timestamp column

    Dear All,
    please Solve my issue,
    I have Table name Record which has the following columns,
    Empid in number column, dat in timestamp
    which has the following values
    Expand|Select|Wrap|Line Numbers
    empid dat
    ====== ====
    101 4/9/2012 9:48:54 AM
    101 4/9/2012 9:36:28 AM
    101 4/9/2012 6:16:28 PM
    101 4/10/2012 9:33:48 AM
    101 4/10/2012 12:36:28 PM
    101 4/10/2012 8:36:12 PM
    101 4/11/2012 9:36:28 AM
    101 4/11/2012 4:36:22 PM
    Here I need to display the following columns,
    empid,min(dat) as start,max(dat) as end and difference(max(dat)-min(dat) for each day,
    for eg,
    Empid Strart end difference
    101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
    like this.
    Here 3 different days are exists so It should return 3 records with the above mentioned columns,
    Please Help me to get this.
    Thank you,
    Regards,
    Gurujothi
    Edited by: Gurujothi on Apr 25, 2012 4:45 AM

    >
    101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
    >
    why 4/9/2012 9:48:54?
    why not 4/9/2012 9:36:28 AM ?
    SQL>
    SQL> with t as
      2  (select  101 empid, to_timestamp('4/9/2012 9:48:54 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
      3  select 101, to_timestamp('4/9/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
      4  select 101, to_timestamp('4/9/2012 6:16:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
      5  select 101, to_timestamp('4/10/2012 9:33:48 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
      6  select 101, to_timestamp('4/10/2012 12:36:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
      7  select 101, to_timestamp('4/10/2012 8:36:12 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
      8  select 101, to_timestamp('4/11/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
      9  select 101, to_timestamp('4/11/2012 4:36:22 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual
    10  )
    11  select empid, min(dat) as start_dat
    12  , max(dat) as end_dat
    13  , max(dat)-min(dat) diff
    14  from t
    15  group by empid, trunc(dat)
    16  /
         EMPID START_DAT                                         END_DAT                                           DIFF
           101 04.09.12 09:36:28,000000000                       04.09.12 18:16:28,000000000                       +000000000 08:40:00
           101 04.11.12 09:36:28,000000000                       04.11.12 16:36:22,000000000                       +000000000 06:59:54
           101 04.10.12 09:33:48,000000000                       04.10.12 20:36:12,000000000                       +000000000 11:02:24
    SQL>

  • Calculate the Difference Between two dates excluding weekends and Holidays

    Hi,
    We need to calculate the difference between the two dates by excluding the Local public holidays (It is global and varies across countries) and weekends should not be included in calculation for a business day in OBIEE.
    We have two dates: Open date and close date when ever close date is null we are calculating age based on taking the current timestamp and need to exclude the weekends and Holidays when ever the close date is null.
    Ex:
    Col1 col2 Total
    11/9/2010 2:46:38 PM Null 13
    11/2/2010 8:06:26 PM 11/3/2010 5:37:03 PM 1
    (In the Total we shouldn't include the weekends,holidays)
    Please let me know how to calculate the difference between two dates by excluding the weekends and holidays.
    Thanks
    Edited by: user10441472 on Nov 22, 2010 3:14 PM

    You already asked this question and I answered it...
    Re: calculation of Business day in OBIEE

  • Extract Time from date and Time and Need XLMOD Funtion to find the Difference between Two Time.

    X6 = "1/5/15 5:16 AM" & NOW ....................difference by Only Time
    not date
    X6 date and Time will be changing, Its not Constant
                Dim myDateTime As DateTime = X6
                Dim myDate As String = myDateTime.ToString("dd/MM/yy")
                Dim myTime As String = myDateTime.ToString("hh:mm tt")
                Dim myDateTime1 As DateTime = Now
                Dim myDate1 As String = myDateTime1.ToString("dd/MM/yy")
                Dim myTime1 As String = myDateTime1.ToString("hh:mm tt")
    Need to use this function to find the Difference between Two Time. due to 12:00 AM isuue
    Function XLMod(a, b)
        ' This replicates the Excel MOD function
        XLMod = a - b * Int(a / b)
    End Function
    Output Required
     dim dd  = XLMod(myTime - myTime1)
    Problem is myTime & myTime1 is String Need to convert them into Time, Later use XLMOD Funtion.

    Induhar,
    As an addendum to this, I thought I'd add this in also: If you have two valid DateTime objects you might consider using a class which I put together a few years ago
    shown on a page of my website here.
    To use it, just instantiate with two DateTime objects (order doesn't matter, it'll figure it out) and you'll then have access to the public properties. For this example, I'm just showing the .ToString method:
    Option Strict On
    Option Explicit On
    Option Infer Off
    Public Class Form1
    Private Sub Form1_Load(ByVal sender As System.Object, _
    ByVal e As System.EventArgs) _
    Handles MyBase.Load
    Dim date1 As DateTime = Now
    Dim date2 As DateTime = #1/1/1970 2:35:00 PM#
    Dim howOld As New Age(date1, date2)
    MessageBox.Show(howOld.ToString, "Age")
    Stop
    End Sub
    End Class
    I hope that helps, if not now then maybe at some point in the future. :)
    Still lost in code, just at a little higher level.
      Thanx frank, can use this in Future....

  • Need to find the Difference between two table

    Hello ,
    I have stucked in program as below scenario:-
    I have two tables of huge data of same structure in a same schema.I need to find the difference exact values in tables.
    By using MINUS we can find the difference between two table ,i need to find the what exact difference in the there values with colunm and value at that column.
    Example TableA
    Col1 col2 col3 col4 col5.... col50
    10 ABC 2001 EE 444 TT
    40 XYZ 3002 RR 445 TT3
    80 DEF 6005 YY 446 YY8
    TableB
    Col1 col2 col3 col4 col5.... col50
    10 ABC 2001 EE 444 TT
    40 XYZ 3002 RR 445 TT3
    81 DEF 6005 Yu 447 YY8
    I need to the out put like this :-
    The Diffence between two table is
    TableA.COL1=80 TableB.Col1=81, Different
    TableA.Col4=YY TableB.col4=Yu,Different
    TableA.Col5=446TableB.col5=447,Different
    Please suggest me to write the pl/sql program for the same
    thanx in advance
    KK

    Thanx friends for all your efforts
    I have a sample code for the same,this will compare the two tables for single row in each table .
    what r the modification needed for the multiple rows of values in the two tables??
    Please suggest!!
    CREATE OR REPLACE PROCEDURE test_compare
    IS
    TYPE t_col
    IS
    TABLE OF VARCHAR2 (30)
    INDEX BY PLS_INTEGER;
    l_col t_col;
    j NUMBER := 0;
    l_sql VARCHAR2 (2000);
    col1 VARCHAR2 (30);
    col2 VARCHAR2 (30);
    val1 NUMBER;
    val2 NUMBER;
    status VARCHAR2 (30);
    CURSOR c1
    IS
    SELECT column_id, column_name
    FROM all_tab_columns
    WHERE table_name = 'TEST1';
    BEGIN
    FOR i IN c1
    LOOP
    j := j + 1;
    l_col (j) := i.column_name;
    END LOOP;
    FOR k IN 1 .. j
    LOOP
    l_sql :=
    'SELECT '
    || ''''
    || l_col (k)
    || ''''
    || ', '
    || 'TEST2.'
    || l_col (k)
    || ', '
    || ''''
    || l_col (k)
    || ''''
    || ', '
    || 'TEST1.'
    || l_col (k )
    || ', '
    || 'DECODE(TEST2.'
    || l_col (k)
    || ' -TEST1.'
    || l_col (k)
    || ', 0, ''NO CHANGE'', ''CHANGED'') FROM TEST2, TEST1';
    EXECUTE IMMEDIATE l_sql INTO col1, val1,col2, val2, status;
    IF status = 'CHANGED'
    THEN
    DBMS_OUTPUT.put_line( 'TEST2.'
    || col1
    || '='
    || val1
    || ', TEST1.'
    || col2
    || '='
    || val2
    || ', '
    || status);
    END IF;
    END LOOP;
    EXCEPTION
    WHEN OTHERS
    THEN
    DBMS_OUTPUT.put_line ('Error:- ' || SQLERRM);
    END;
    /

  • Find the difference between two columns in an ssrs matrix ? MSCRM

    Hi All,
    I am working in reporting part of our project (On-line MSCRM 2013) & in reporting services.
    I am trying to create report using fetch xml based. Below is the snap what we required the result.
    Kindly help me, how to get the difference in both column. (Its a matrix table where year is grouped).
    We need difference between both year Like (Plan Revenue of 2013 & Plan Revenue of 2014 difference in Plan Revenue Diff section) and same for Actual
    Revenue.
    https://social.microsoft.com/Forums/en-US/054d5ca4-0d38-4dc6-84a8-88866cc228fe/find-the-difference-between-two-columns-in-an-ssrs-matrix-mscrm?forum=crmdevelopment
    Thanks,
    Mohammad Sharique

    Hi Bro,
    I used parametrized option for year and done the report,Currently we are getting values in Difference column now i want to show
    that value in percentage. How can we show the percentage based on that value. Means i want to show the Difference in Percentage. 
    Kindly help me i tried but getting some issue. Below i am mentioning the code and snap with result.
    Below expression using to showing Plan Revenue in Percentage for year.
    =
    Sum(IIF(Fields!new_year.Value =Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
    - Sum(IIF(Fields!new_year.Value =Parameters!EndYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
    /IIF(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))>0,
    (Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0))))
    ,1)
    )*100))
    Result issue is as below in snap with highlighted in red colour.
    Kindly help me on this issue also :)

  • Function Module to find the Difference between two times.

    Hi All,
    Wud you plz let me know the Function Module to find the Difference between two times.
    Input Time1( Hours:Minutes) Time2 ( Hours:Minutes)
    Need Output in Hours:Minutes only . ( No seconds Needed )
    Ex :
    Input :
           06:00 to 18:00 Output : 12:00
    and  20:00 to 06:00 Output: 10:00 with +ve sign only. No -ve sign.
    Thanks,
    N.L.Narayana

    check this .
    data : p_timel like sy-uzeit,
           p_timeh like sy-uzeit,
           diff like sy-uzeit,
           di(8) type c .
           p_timel = '200000'.
           p_timeh = '060000'.
           diff = p_timeh - p_timel.
           concatenate diff+0(2) ':' diff+2(2) into di.
           write:/ di.
    also check for this.
           p_timel = '060000'.
           p_timeh = '180000'.
    see if this can be implemented in ur code .
    or else  u can try with  Fm L_TO_TIME_DIFF passing startdate enddate starttime endtime with UOM as MIN
    hope this helps regards,
    vijay

  • Java code to get the difference between two dates in days

    Hi ppl,
    I need to write a user defined function to get the difference between two date nodes, in days.Please help me out
    regards,
    Prashanth

    Hi,
    have a look at those two:
    (How do I calculate the difference between two dates?)
    http://joda-time.sourceforge.net/faq.html
    Calculating the Difference Between Two Datetime Stamps
    http://www.xmission.com/~goodhill/dates/deltaDates.html
    Get difference in days
    http://javaalmanac.com/egs/java.util/CompDates.html
    Regards,
    michal

  • How to find the difference between 2 time values in Java

    hi all,
    i have 2 time values
    String time1="6:20";
    String time2="21:30"
    How to find the difference between 2 times in Java?
    pls help
    thanx in advance....

    Calculating Java dates: Take the time to learn how to create and use dates
    Working in Java time: Learn the basics of calculating elapsed time in Java
    Formatting a Date Using a Custom Format
    Parsing a Date Using a Custom Format

  • Calculate the difference between two dates times in infopath form 2013

    Hi,
    I have an infopath 2013 form that contains three fields:
    2 date time and the 3rd contains the difference between the two in hours
    how I can make the difference between the two so that the display will be like this:
    Date Time1           08/21/2014           22:00 
    Date Time2           08/22/2014           1:00
    Diff Field                                             3:00

    Hi,
    Please refer to the following article which matches your requirement exactly.
    Calculate the difference between two date picker controls in InfoPath using rules and formulas - no code!
    Please mark it answered, if your problem resolved.

  • Calculate the difference between two dates

    I would like to calculate the difference between two dates in PL/SQL and return the result as a number of days expressed as an integer value.

    Denes,
    A fair point, I should really have posted this on the SQL forum (I'm new to the forum as well as PL/SQL) but thanks for responding anyway. It does raise a question as to how to implement this in ApEx though.
    I have created the function and am calling it as shown below from the source window of a form. The source type is 'PL/SQL expression or function' and the expression in the source window of the form is:
    calc_date_difference (:p26_c_payment, :p26_c_rec)
    The two parameters being passed are of type date but I'm not sure how to handle the ruturned number and populate the form in ApEx with this value.
    Is it possible to do it this way or am I taking completely the wrong approach?
    Regards
    Sandy
    This is not ApEx related but SQL related:
    CREATE OR REPLACE FUNCTION calc_date_difference (
    p_date_1   VARCHAR2,
    p_date_2   VARCHAR2
    RETURN NUMBER
    v_difference   NUMBER;
    v_sql_err      VARCHAR2 (4000);
    BEGIN
    v_difference := TRUNC (TO_DATE (p_date_1)) - TRUNC
    (TO_DATE (p_date_2));
    RETURN v_difference;
    CEPTION
    WHEN OTHERS
    THEN
    v_sql_err := SQLERRM || CHR (10) || CHR (10) ||
    SQLCODE;
    ND calc_date_difference;and
    SQL> SELECT calc_date_difference ('23.01.2007',
    '20.01.2007') diff
    2    FROM DUAL;
    DIFF
    3
    Denes Kubicek                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                           

Maybe you are looking for