How to find the hours between two timing

Question

Hai All
I had a problem that i need to calculate a working hours
For example
Intime outtime
0815 1715
so i need to calculate a time between these two timing
how can i do using function for 100 nos
Regards
Srikkanth.M

Answer 1

Srikkanth.M wrote:
Hai Man
I think i got half a way, But the time is not coming exactly. so how can i do the same code that u have give inside a function is it possible to do a function with these three requirementThis can be done in the following way, but a function should always return a value.
Here I have just returned a dummy value of 1.
create or replace
function testingFunction (<paramters if any>) return number
as
begin
update testTable set (wtime,ltime,etime)=(select extract(hour from (to_date('0930','HH24:MI')-to_date('1200','HH24MI')) day to second),
case when extract(hour from (to_date('0930','HH24:MI')-to_date('1200','HH24MI')) day to second) > 0830
then extract(hour from (to_date('1200','HH24:MI')-to_date('0830','HH24MI')) day to second)
else 0 end,
case when To_number('0900') > to_number('0815') then extract(hour from (to_date('0900','HH24:MI')-to_date('0815','HH24MI')) day to second)
else 0 end from dual);
return 1;
end;
A better option would be to create a stored procedure and call that. Just like the way I have done below
create or replace
procedure testingprocedure (<paramters if any>)
as
begin
update testTable set (wtime,ltime,etime)=(select extract(hour from (to_date('0930','HH24:MI')-to_date('1200','HH24MI')) day to second),
case when extract(hour from (to_date('0930','HH24:MI')-to_date('1200','HH24MI')) day to second) > 0830
then extract(hour from (to_date('1200','HH24:MI')-to_date('0830','HH24MI')) day to second)
else 0 end,
case when To_number('0900') > to_number('0815') then extract(hour from (to_date('0900','HH24:MI')-to_date('0815','HH24MI')) day to second)
else 0 end from dual);
end;
and call the procedure
testingprocedure(<parameters if any>);
Naveen