How to find working workingDirectory on run time

Question

How can I see my working Direcftory at run time.

Answer 1

Are you trying to get the working directory on the server side or the client side?
As Fabrizio mentioned, you can use WebUtil, but this would return the client side information. To obtain the server side details, you can use imported java. Fortunately, because the server side jvm already has everything you need to do this, there is no need to know how to code in java. Refer to the Forms Java Importer documentation for details:
http://www.oracle.com/webapps/online-help/forms/10g/topics/java_importer/c_javaimporter.html
All you need to do is import the following java packages into your form:
java.lang.System
java.lang.Exception
Then add some pl/sql similar to this to your form:
PROCEDURE java_call IS
     jo     ora_java.jobject;     
     rv     ora_java.jobject;
     ex     ora_java.jobject;     
Begin
-- Get server side working directory.
-- This is the same value which is set in formsweb.cfg
     MESSAGE (SYSTEM.getProperty('user.dir'));     
EXCEPTION
WHEN ORA_JAVA.JAVA_ERROR then
          message('Unable to call out to Java, ' || ORA_JAVA.LAST_ERROR);
WHEN ORA_JAVA.EXCEPTION_THROWN then
          ex := ORA_JAVA.LAST_EXCEPTION;
          message (Exception_.toString(ex));
END;Once imported, you will have easy access to a variety of server side (Java) properties which can return valuable information. Refer to the following:
Link: [http://java.sun.com/j2se/1.4.2/docs/api/java/lang/System.html#getProperties()]