How to generate random numbers in a range?

Hello. i am having trouble finding out how to generate a random number in a certain range. For example i have an array of 100 elements and i want to access one of the elements between 50 and 60, however i cannot find how to generate a random number between these two values.
Thanks in advance

java.util.Random.nextInt(int)
Note that you can get a number between 0 and (max -
min), exclusive. Then add min, and you've got your
number.Obviously you didn't read this. It says to get a number between 0 and (max - min) which is actually what you did. But after that you need to add min. The first step would get a number in between 0 and 5. When you add 20 you'd get a number between 0+20=20 and 5+20=25.

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How to generate random numbers in a range using random class?

I know how to use Math.random for this, but how would I generate random numbers using the random class?
Say I want a number between 40 and 50, inclusive--how would I do this?
What i have in mind is:
int randomNumber = random.nextInt(max) + min;
where max is 50 and min is 40. Is this correct?

Fredddir_Java wrote:
I know how to use Math.random for this, but how would I generate random numbers using the random class?
Say I want a number between 40 and 50, inclusive--how would I do this?
What i have in mind is:
int randomNumber = random.nextInt(max) + min;
where max is 50 and min is 40. Is this correct?What happened when you generated a couple hundred numbers that way? Did you get all the ints in the range you wanted?

How to generate random numbers from 1 to 5

How to generate random numbers from 1 to 5
-1110340081
Solved!
Go to Solution.

(You should not mark a post as solution unless it actually contains a solution to the original problem)
Do you want to share your code? Did you test to make sure that all numbers equally probable?
LabVIEW Champion . Do more with less code and in less time .

How to generate random numbers that doesnt contain characters?

How do we generate random numbers in ESB ROuting Service/ XSL transformation that does not contain characters. I have been using "orcl:generate-guid()" , but it contains some characters, so, I substring it to get only numbers. I dont want to take this risk and in future, my substring itself may contain characters.
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If the goal is to have a pseudo random number then consider using the translate function to replace the occurances of the A - E characters with another digit. For example:
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I would perform a large sample test to see just how unique the values end up being.
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Hope this helps,
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How t generate random numbers at everytime of exceutuion of the program

dear friends
i am facing a problem that the random numbers generated at time of each exectuion of the program are not the same, i want to generate the same random numbers every time time i run the program. i need your help. i am giving the code in c++ if anybody can help in providing the solution so that i get the same random numbers at every run of the program. waiting for your help
wit regards
jaya shankar
#include<iostream.h>
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<math.h>
class density
int s[150][150],parent[150][150],i,j,l,n,loop;
public:
void bd(void);
void css(void);
void density :: bd(void)
cout<<"ENTER THE POPULATION SIZE = ";
cin>>n;
cout<<"\nENTER THE NO.OF LOOPS = ";
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int a,b;
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d.bd();
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This will help you I think.
import java.io.*;
import java.util.*;
public class RandomTest
     public static void main( String arg[]) throws Exception
          Random number = new Random(100);
          for( int i = 0 ; i < 15; i++){
               System.out.println( number.nextInt( 100 )) ;

How to generate random numbers of the same at each time of execution of thm

dear friends
i am facing a problem that the random numbers generated at time of each exectuion of the program are not the same, i want to generate the same random numbers every time time i run the program. i need your help. i am giving the code in c++ if anybody can help in providing the solution so that i get the same random numbers at every run of the program. waiting for your help
wit regards
jaya shankar
#include<iostream.h>
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<math.h>
class density
int s[150][150],parent[150][150],i,j,l,n,loop;
public:
void bd(void);
void css(void);
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cout<<"ENTER THE POPULATION SIZE = ";
cin>>n;
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cin>>loop;
for(i=0;i<n;i++)
for(j=0;j<80;j++)
s[j]=rand()%2;
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int a,b;
float c;
for(i=0;i<n;i=i+2)
b=rand()%100;
cout<<"random b="<<b;
main()
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Do not randomize the random number interface when you start your application. When the random number interface is not randomized when starting you get the same sequence of numbers each and every time you use it.

How to generate random numbers with a known distribution of f(X)=(8X^2 + 1)*Exp( -X^2 )

Dear All,
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I have searched a lot, but I still do not know how to realize it.
Any help on this topic would be highly appreciated.

Make a lookup table of the integral of your function (normalized to 1)
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Greetings from Germany
Henrik
LV since v3.1
“ground” is a convenient fantasy
'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'

How to generate random numbers with a known distribution f(X)=(8X^2 + 1)*Exp( -X^2 ).

I need to simulate a random number generator which can generate numbers X with the probability distribution of
f (X) = ( 8X^2 + 1)*Exp ( -X^2 ).
This distribution is not a common distribution.
I have searched a lot, but I still do not know how to realize it.
Thanks a lot!
Solved!
Go to Solution.

Don't forget to index back into the original X array for correctly scaled data. Here's a simple example (LV 8.0):
Seems to work just fine.
LabVIEW Champion . Do more with less code and in less time .
Attachments:
DistributionSimulation.png ‏25 KB
DistributionSim4.vi ‏44 KB

How to generate random letter?

i know how to generate random numbers but is there anyway to generate random letters? or colors?
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marufai wrote:
-uj-
as i'm new in java...can u show me how to make random number from array list?
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so if i wan generate btw A to Z am i suppose to type A to Z out?
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Find the below code,
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lemme know if it compiles
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thanking you,
pola pradeep

i am afraid that whether ur looking for this. bcoz its a simple for loop
<script language="JavaScript">
//count = limit value for u
for(i=0;i<count;++i){
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or if ur looking for something else, pls mention ur requrment precisely
aleena

How to generate random numbers in a range?

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