How to get current sequence in a stacked sequence

Hello,
I am trying to implement a progress bar for a stacked sequence; as the sequence increases, the bar increases etc... This may be trivial but I cant figureout how to determine the current sequence number.  There is no property node for a stacked sequence structure...
I am using labview 8.5 
Regards
hvo

First, what proces are you doing using teh sequence structure? In general, you should avoid using sequence structures, esspecially stacked sequence structures. I assume you are new to LabVIEW and data flow programming. Take some time to learn how to use data flow programming and you will find you rarely ever need to use sequence structures. There are lots of discussions which cover the negatives about sequence structures.
Now, given that you will need to develop your own variable which is used to update the progress bar throughout the sequence. The brute force method would be to wire a value through and use sequence locals. However if you went down this path you will quickly see why sequence structures are not recommended. A more generic method would be to create an Action Engine (search for action engine for lots of explanations on those) which would control the progress bar data. Each frame would need to call the action engine to update the progress bar.
Since it sounds like you are writing a fairly complex sequence I would recommend you do one of two things. First and probably the easiest would be to create a subVI for each frame and then simply use dataflow to wire these together in the order you want to execute them. The downside here is that you are creating subVIs which may or may not ever be reused. It is still a valid approach though. The second and more flexible approach would be to use a state machine to control your processing. This is much more flexible and easier to maintain than a stacked sequence.
Mark Yedinak
"Does anyone know where the love of God goes when the waves turn the minutes to hours?"
Wreck of the Edmund Fitzgerald - Gordon Lightfoot

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