How to get Driver and url names from a connection pool

Hi,
How to get the DriverName and URL from an existing pool, If I know the name of
connection pool ? Is it possible to know the name of related pool , if I know
the name of datasource?
Thx
Manish

hi
there are 2 ways:
url must be: jdbc:weblogic:pool[:connectionPoolID]
or
jdbc:weblogic:jts[:connectionPoolID] (if you want to use jts with your JDBC connection.)
see http://e-docs.bea.com/wls/docs60//javadocs/weblogic/jdbc/pool/Driver.html
However, I think it is safer to configure and use DataSource to get connection.
Nicolas
"kumar" <[email protected]> wrote:
>
Hi,
How to get the DriverName and URL from an existing pool, If I know the name
of
connection pool ? Is it possible to know the name of related pool , if I
know
the name of datasource?
Thx
Manish

Similar Messages

How to get the Portal Page name from PLSQL?

Can anyone tell me how to get the portal page name from my dynamic page using plsql?
Apparently you can get the page id and work it out from there, but my calls to get the page id are not returning any values anyway.
My code for attempting to get the page id is below.
<oracle>
declare
v_pageid varchar2(30);
begin
v_pageid := wwpro_api_parameters.get_value('_pageid', '/pls/portal30');
htp.print('Page is '|| v_pageid);
end;
</oracle>
Ideally I'd actually just like to get the page name. Is there a straightforward way to do this?
Thanks in advance!
Sarah

Few clarifications -
1. wwpro_api_parameters cannot be used to get default portal
page parameters such as '_pageid', '_dad', '_schema' etc.,
2. Page information can be obtained through any components which
are available in that particular page. For example, in case of
dynamic page, we need to publish it as a portlet and add it to the
page. This process creates necessary packages in the DB, but we
will not have access to the portlet methods.
So, I would prefer creating a simple DB provider & portlet and access
page title from its show method as follows -
//Declare local variable l_page_id, l_page_title as varchar2
select page_id into l_page_id from wwpob_portlet_instance$ where
portlet_id = p_portlet_record.portlet_id and
provider_id = p_portlet_record.provider_id;
select name into l_page_title from wwpob_page$ where id=l_page_id;
More information on DB provider can be found at
http://portalstudio.oracle.com/pls/ops/docs/FOLDER/COMMUNITY/PDK/articles/understanding.database.providers.html
Secondly, usage of wwpro_api_parameters.get_value method is
incorrect. This method expects two arguments -
<ul>
<li><b>p_name : </b> The name of the parameter to be returned.</li>
<li><b>p_reference_path : </b> An unique identifier for a portlet instance on the current page.</li>
</ul>
p_reference_path would be something like 99_SNOOP_PORTLET_76535103 and not some type of path as its name suggests.
The following code fragment fetches all parameters available
for a portlet.
Note : Copy this code into 'show' method of your portlet.
//Declare l_names, l_values as owa.vc_arr
* Retreive all of the names of parameters for this portlet
l_names := wwpro_api_parameters.get_names(
p_reference_path=>p_portlet_record.reference_path);
* Retreive all of the values of parameters for this portlet
l_values := wwpro_api_parameters.get_values(p_names=>l_names,
p_reference_path=>p_portlet_record.reference_path);
//Loop through these arrays to get parameter information
htp.p('<center><table BORDER COLS=2 WIDTH="90%" >');
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.tableData(wwui_api_portlet.portlet_heading('Name',1));
htp.tableData(wwui_api_portlet.portlet_heading('Value',1));
htp.tableRowClose;
if l_names.count = 0 then
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.p('<td COLSPAN="2">'
||wwui_api_portlet.portlet_text(
'No portlet parameters were passed on the URL.',1)
||'</td>');
htp.tableRowClose;
else
for i in 1..l_names.count loop
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.tableData(l_names(i));
htp.tableData(l_values(i));
htp.tableRowClose;
end loop;
end if;
htp.p('</table></center>');
Hope it helps...
-aMJAD.

How to get list of file names from a directory?

How to get list of file names from a directory?
Please help

In addition, this:
String filename = files;Should be this:
String filename = files;
That's just because he didn't use the "code" tags, so [ i ] made everything following it become italicized.

How to get the actual font name from a font file?

Hi
I have only the font Path I have to get the font name from that path. Any idea how to get the actual font name?
Thanks,

I would ask you these questions:
Why do you need to do this? What are you ultimately trying to accomplish?
Are you really asking about the InDesign SDK?
Do you really need to get the "name" of a font from an arbitrary file? Or do you want information about a font installed on the system? If so, what OS?
Do you need to be able to handle any font format?
Which font "name" do you mean?
What language do you want the name in?
(1) It's not clear what you're trying to accomplish. A bit more information about your ultimate goal would be helpful.
(2) This question is not at all specific to the InDesign SDK. Are you really trying to do something in the context of an InDesign plug-in? If so, you probably want to look at IID_IFONTFAMILY and the IFontFamily::GetFamilyName function.
(3) If you are asking more generally, Windows and Mac both have system API calls to get this information, although those tend to deal with installed system fonts, not with arbitrary font files per se.
Also, you can parse the name table from a True Type or Open Type font without using any system APIs; as True Type and Open Type are well-documented standards. I would start by reading these:
The Naming Table
Font Names Table
(4) Although there are other standards, such as Type 1 (PostScript) fonts, and True Type Collection files and other formats, especially on Mac.
(5) Also, when you start down this road, you will quickly realize that your seemingly simple question is actually ambiguous, and that the answer is kind of complicated, because a font can have many names (a family name, a full font name, a style name, a PostScript name, etc.).
(6) And not only does a font have multiple names, it can have each of those names in multiple languages and encodings.
Any clarification would make this a better question.

How to get the failover partner name from C++ client

Hi All,
I have configured the mirroring session for my application.
I want to modify the connection string with failover partner name.
Could any one please let me to know how to get the failover partner instance from C++ client dynamically.
Thanks,
Prasad.

Are you looking for this?
http://www.connectionstrings.com/sql-server-2012/
http://stackoverflow.com/questions/25534972/auto-failover-multiple-connections-to-mirror-database-when-principal-goes-down

How find print program and form name from the spool list

Hi,
I have a requirement to find print program and form name from the spool list.
I got the list of programs and forms from TNAPR table, I also want to find out any custom program sending the form directly to the spool.
Cheers
Sam

Hi
Try TSP01-Suffix2
Regards
Raj

How to get the target file name from an URL?

Hi there,
I am trying to download data from an URL and save the content in a file that have the same name as the file on the server. In some way, what I want to do is pretty similar to what you can do when you do a right click on a link in Internet Explorer (or any other web browser) and choose "save target as".
If the URL is a direct link to the file (for example: http://java.sun.com/images/e8_java_logo_red.jpg ), I do not have any problem:
URL url = new URL("http://java.sun.com/images/e8_java_logo_red.jpg");
System.out.println("Opening connection to " + url + "...");
// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
                fileName=st.nextToken();
System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
    byte[] buf = new byte[1024];
    int i = 0;
    while ((i = is.read(buf)) != -1) {
        fos.write(buf, 0, i);
} catch (Throwable e) {
    e.printStackTrace();
} finally {
    if (is != null)
        is.close();
    if (fos != null)
        fos.close();
}Everything is fine, the file name I get is "e8_java_logo_red.jpg", which is what I expect to get.
However, if the URL is an indirect link to the file (for example: http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719 , which link to a file named JavaSetup6u18-rv.exe ), the similar code return AutoDL?BundleId=37719 as file name, when I would like to have JavaSetup6u18-rv.exe .
URL url = new URL("http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719");
System.out.println("Opening connection to " + url + "...");
// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
                fileName=st.nextToken();
System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
    byte[] buf = new byte[1024];
    int i = 0;
    while ((i = is.read(buf)) != -1) {
        fos.write(buf, 0, i);
} catch (Throwable e) {
    e.printStackTrace();
} finally {
    if (is != null)
        is.close();
    if (fos != null)
        fos.close();
}Do you know how I can do that.
Thanks for your help
// JB
Edited by: jb-from-sydney on Feb 9, 2010 10:37 PM

Thanks for your answer.
By following your idea, I found out that one of the header ( content-disposition ) can contain the name to be used if the file is downloaded. Here is the full code that allow you to download locally a file on the Internet:
      * Download locally a file from a given URL.
      * @param url - the url.
      * @param destinationFolder - The destination folder.
      * @return the file
      * @throws IOException Signals that an I/O exception has occurred.
     public static final File downloadFile(URL url, File destinationFolder) throws IOException {
          URLConnection urlC = url.openConnection();
          InputStream is = urlC.getInputStream();
          FileOutputStream fos = null;
          String fileName = getFileName(urlC);
          destinationFolder.mkdirs();
          File localFile = new File(destinationFolder, fileName);
          fos = new FileOutputStream(localFile);
          try {
               byte[] buf = new byte[1024];
               int i = 0;
               while ((i = is.read(buf)) != -1) {
                    fos.write(buf, 0, i);
          } finally {
               if (is != null)
                    is.close();
               if (fos != null)
                    fos.close();
          return localFile;
      * Returns the file name associated to an url connection.<br />
      * The result is not a path but just a file name.
      * @param urlC - the url connection
      * @return the file name
      * @throws IOException Signals that an I/O exception has occurred.
     private static final String getFileName(URLConnection urlC) throws IOException {
          String fileName = null;
          String contentDisposition = urlC.getHeaderField("content-disposition");
          if (contentDisposition != null) {
               fileName = extractFileNameFromContentDisposition(contentDisposition);
          // if the file name cannot be extracted from the content-disposition
          // header, using the url.getFilename() method
          if (fileName == null) {
               StringTokenizer st = new StringTokenizer(urlC.getURL().getFile(), "/");
               while (st.hasMoreTokens())
                    fileName = st.nextToken();
          return fileName;
      * Extract the file name from the content disposition header.
      * <p>
      * See <a
      * href="http://www.w3.org/Protocols/rfc2616/rfc2616-sec19.html">http:
      * //www.w3.org/Protocols/rfc2616/rfc2616-sec19.html</a> for detailled
      * information regarding the headers in HTML.
      * @param contentDisposition - the content-disposition header. Cannot be
      *            <code>null>/code>.
      * @return the file name, or <code>null</code> if the content-disposition
      *         header does not contain the filename attribute.
     private static final String extractFileNameFromContentDisposition(
               String contentDisposition) {
          String[] attributes = contentDisposition.split(";");
          for (String a : attributes) {
               if (a.toLowerCase().contains("filename")) {
                    // The attribute is the file name. The filename is between
                    // quotes.
                    return a.substring(a.indexOf('\"') + 1, a.lastIndexOf('\"'));
          // not found
          return null;
     }

Getting links and its names from a html file

Hi everyone
My problem about the a getting links with name from a html file. For example
İn a web page in this site ?SUN? when use click SUN the browser open http://java.sun.com
İ want both of them, so the links and name. I can succeeded the get link but i don t know how to get the link name.
For example :
<B>setRightComponent(Component)</B>
İn this code segment i want to get B tag. But how i don t know. To get A tag i used this code
List result = new ArrayList();
try {
// Create a reader on the HTML content
URL url = new URI(uriStr).toURL();
URLConnection conn = url.openConnection();
Reader rd = new InputStreamReader(conn.getInputStream());
// Parse the HTML
EditorKit kit = new HTMLEditorKit();
HTMLDocument doc = (HTMLDocument)kit.createDefaultDocument();
kit.read(rd, doc, 0);
// Find all the A elements in the HTML document
HTMLDocument.Iterator it = doc.getIterator(HTML.Tag.A);
while (it.isValid()) {
SimpleAttributeSet s = (SimpleAttributeSet)it.getAttributes();
String link = (String)s.getAttribute(HTML.Attribute.HREF);
if (link != null) {
result.add(link);
it.next();
İ can use B tag but i don t know hot to get its value because it has no prefix such as HREF....
i am sorry if i use a bad explanation style or incorrect word.

import java.io.*;
import java.net.*;
import javax.swing.text.*;
import javax.swing.text.html.*;
class GetLinks
    public static void main(String[] args)
        throws Exception
        // Create a reader on the HTML content
        Reader reader = getReader( args[0] );
        // Parse the HTML
        EditorKit kit = new HTMLEditorKit();
        HTMLDocument doc = (HTMLDocument)kit.createDefaultDocument();
        doc.putProperty("IgnoreCharsetDirective", Boolean.TRUE);
        kit.read(reader, doc, 0);
        // Find all the A elements in the HTML document
        HTMLDocument.Iterator it = doc.getIterator(HTML.Tag.A);
        while (it.isValid())
            SimpleAttributeSet s = (SimpleAttributeSet)it.getAttributes();
            String href = (String)s.getAttribute(HTML.Attribute.HREF);
            int start = it.getStartOffset();
            int end = it.getEndOffset();
            String text = doc.getText(start, end - start);
            System.out.println( href + " : " + text );
            it.next();
    // If 'uri' begins with "http:" treat as a URL,
    // otherwise, treat as a local file.
    static Reader getReader(String uri)
        throws IOException
        // Retrieve from Internet.
        if (uri.startsWith("http:"))
            URLConnection conn = new URL(uri).openConnection();
            return new InputStreamReader(conn.getInputStream());
        // Retrieve from file.
        else
            return new FileReader(uri);
}

How to get the pull path name from a file upload window

Hello everyone!
I have encountered the following problem with the following JSP code:
<form method="post" action="filename.jsp">
Upload JAVA program:
<input type=file size=20 name="fname" accept="java">
<input type=submit value="go">
</form>
<%
String s = "";
if (request.getParameter("fname") != null)
s = request.getParameter("fname")
%>
The value of s is alway the filename. However I want to get the full path in addition to the filename, so that I can read the file. Does anyone know how to get the pull name of the file?
thanks a lot in advance,

Dear Sir,
thanks a lot for your reply. Please let me explain what I intended to do: I want to upload a file from the local machine and then read the content of the file. Therefore I need to the fullpath of the filename like /var/local/file.java instead of file.java. The latter is what I got.
The problem I have with your code is that the function like "request.getServerScheme()" is not recognized. Maybe is it because I didn't install servelet package? I only installed javax package btw. Also my application runns on Tomcat server if this could give you some information. The error message I had is as follows:
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
[javac] Compiling 1 source file
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:133: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
url = request.getServerScheme()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:136: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
+ ((("http".equals(request.getServerScheme()) && request.getServerPort() != 80)
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:137: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
||("https".equals(request.getServerScheme()) && request.getServerPort() != 443))
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:139: cannot resolve symbol
symbol : method getServletConfig ()
location: interface javax.servlet.http.HttpServletRequest
+ "/" + request.getServletConfig().getServletName()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:140: cannot resolve symbol
symbol : variable path
location: class org.apache.jsp.addExercise_jsp
+ "/" + path
^
5 errors
     org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:128)
     org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:351)
     org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:413)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:453)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:437)
     org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:555)
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:291)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:856)

How to get the long file name from an 8.3 name in Windows.

Because of a legacy string limitation, I have a list of files in 8.3 format. The actual files are saved with long names. How can I get the long name from the short name?
In JavaScript, I would get a file system object and get the file object from there with the short name. Then it's no problem to get the full name. But I don't see anything in Java that matches that. ???
Ideas?
Frank Perry, MSEE

Here is what I did.
String displayName = "somefi~1.txt";
File fO = new File("c:\\"); // I have a more involved path but that's not important here.
String stPath = fO.getPath() + displayName;
File fD = new File(stPath); // get the file using the short name.
File fDc = new File(fD.getCanonicalPath()); // get another file using the cononical name
String FulldisplayName = fDc.getName(); // get the long name from there.
It's roundabout but it works. Since getName() on the file read with the short name only returns the name used to get the file, I open it twice. The alternative is to parse the cononical name for the file name but that's clumbsy too.
Frank

How to get table and column names thats being used in SQL , that's generating all my reports on SSRS.

Good day,
I searched through the forum and cant find anything.
I have around 300 published reports on SSRS and we are busy migrating to a new system.
They have already setup their tables on the new system and I need to provide them with a list of table names and column names that are being used currently to generate the 300 reports on SSRS.
We use various tables and databases to generate these reports, and will take me forever to go through each query to get this info.
Is it at all possible to write a query in SQL 2008 that will give me all the table names and columns being used?
Your assistance is greatly appreciated.
I thank you.
Andre.

There's no straightforward method for that I guess. There are couple of things you can use to get these details
1. query the ReportServer.dbo.Catalog table
for getting details
you may use script below for that
http://gallery.technet.microsoft.com/scriptcenter/42440a6b-c5b1-4acc-9632-d608d1c40a5c
2. Another method is to run the reports and run sql profiler trace on background to retrieve queries used.
But in some of these cases the report might be using a procedure and you will get only procedure. Then its upto you to get the other details from procedure like tables used, columns etc
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs

How To Get FileType and MIME Type from a File

Hi,
I am using following ways to get FileType and MIME Type.
I am able to get file type, but I am getting MIME Type as */*
Can any one please let me know how to get MIME Type, but it should not be time consuming process.
For File Type I am using following Code:
private String getFileData(InputStream inStream) {
fileName = C:\temp\temp.tiff
String filePath = Util.createTempFile(fileName);
RandomAccessFile raf = new RandomAccessFile(filePath, "rw");
while (inStream.available() > 0) {
     byte[] buf = new byte[inStream.available()];
     inStream.read(buf);
     raf.write(buf);
inStream.close();
raf.close();
File file = new File(filePath);
JFileChooser chooser = new JFileChooser();
String fileType = chooser.getTypeDescription(file);
file.delete();
//MIME Type I am getting from
DataHandler data = new DataHandler(new DocumentSource(inStream));
data.getContentType();
data.getContentType() is not working well in all cases.
Can any one help me on this.
Thanks in advance,
Ram.
Edited by: javausers07 on Apr 15, 2009 4:25 PM

javausers07 wrote:
Hi,
I am using following ways to get FileType and MIME Type.
I am able to get file type, but I am getting MIME Type as */*
Can any one please let me know how to get MIME Type, but it should not be time consuming process.
For File Type I am using following Code:
private String getFileData(InputStream inStream) {
fileName = C:\temp\temp.tiff
String filePath = Util.createTempFile(fileName);
RandomAccessFile raf = new RandomAccessFile(filePath, "rw");
while (inStream.available() > 0) {
     byte[] buf = new byte[inStream.available()];
     inStream.read(buf);
     raf.write(buf);
inStream.close();
raf.close();
File file = new File(filePath);Why do you do all above?
JFileChooser chooser = new JFileChooser();
String fileType = chooser.getTypeDescription(file);
file.delete();
//MIME Type I am getting from
DataHandler data = new DataHandler(new DocumentSource(inStream));
data.getContentType();
data.getContentType() is not working well in all cases.That's because there's no way to get MIME type of all files on all filesystems.
Kaj

Get path and file name from Bfile

Hi,
I'm using Bfile to store images in a database. Is there a way to get the path and file name of the image from Bfile, because I need to pass that information into an image processing function.
Many thanks.
Sheldon

Can you use FILEISOPEN in the DBMS_LOB package?
See http://download-west.oracle.com/docs/cd/B10501_01/appdev.920/a96591/adl03prg.htm#281893
-- CJ

How to get DocID and Document name

Hi All,
I am working on BO XR R3.1 version.i am looking to get DocID by BO SDK.i am able to see there is one fuction to for CUID (getCUID()) in BO sdk) same way can i get DocId like(986752) with single docid and documnet name.
or is there any fuction in BO SDK to show DocID & Documnet name of single report?

Hi Nitin,
See if this helps.
http://help.sap.com/businessobject/product_guides/boexir31/en/xi3-1_url_reporting_opendocument_en.pdf
Regards,
Shweta

How to get logged in user name from windows service c#

i use the below code to get logged in user name.
private string GetLoggedInUser()
string userName = "";
if (System.Security.Principal.WindowsIdentity.GetCurrent() != null)
userName = System.Security.Principal.WindowsIdentity.GetCurrent().Name;
return userName;
just do not understand why it is not giving a logged in user name rather it is return data in this format
NT AUTHORITY\SYSTEM but i want to get user name.
i try to run my service as Local Service and local system account but in every case i am getting this string
NT AUTHORITY\SYSTEM instead of logged in user name.
so please guide me what to change in code. thanks

System is the account the service is running under.
There can be none or many interactive users be logged in. What if none or multiple are logged in? Which one are you referring to then?
Armin

How to get Driver and url names from a connection pool

Similar Messages

Maybe you are looking for