How to get file name in adapter module

Hi all
Is it possible to get the file name in a adapte module? If so how can I achieve this?

Hi,
Check below thread. it shows code for file name.
[Re: Query regarding Adapter Module development]
-Gouri

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How to get file name of the form attachment?

Hi,
is there anybody who is able to help me with the following problem???
I started my process from Workspace ES and as a first step I attached one locale file (IMG.JPG or IMG.TIF e.g.) as a form attachment. I used "Attachments" bookmark in the Workspace ES.
I need to get file name of attached file in the process!!!
I tried to use "getTaskAttachments" component to get file name of form attachment but without success. This component successfully obtained attached file an stored it in the variable (type list, subtype document) but didn't produce all file attribute informations such as basename or Content Type:
Is there some possibility to obtain file name (including file extension) by using "standard" tools and components of ALC?
Thanks for your suggestions.

Hi LekomDev,
I faced the same situation some time back and this is what I know.
Based on the file type few of the attributes will or will not be populated. (This is what the official documentation says about Document attributes)
The file name that you are looking for would mostly be in 'name' attribute of Document object. The 'wsfilename' attribute is the atrribute which gets used to show the file name into Attachments tab of the workspace.
So, if you are just interested in knowing the filenames then 'name' attribute is the place that you are looking for.
But if you are trying to solve an issue in which Attachments against a Task isn't showing the filenames properly then you would need to copy the 'name' attribute value into 'wsfilename' attribute and then the Attachmetns against a Task would have the correct names.
Tip: Use the Record and Playback option of the workbench to inspect the Document variable and you would see all of the values for a Document variable at desired step in your orchestration.
hope this helps,
cheers,
Parth Pandya
Blog: http://livecyclekarma.wordpress.com

How to get file name using File adapter Sync read

Hi All,
I am using SOA 10.1.3.3 and JDEV 10.1.3.3.
I have an async bpel process.
I have to read file name in this process... so i have used file adapter sync read operation.
How can we get the file name with out payload using sync read.
For normal read (Inbound Spec)we have UseHeaders="true" property.
Is there any property for sync read to read the file name.
Please help me
Regards
PavanKumar.M
Edited by: [email protected] on Oct 27, 2009 11:23 PM

Hi Eric,
The info in the link provided by you is for a normal read.
I need to read he file name using Sync read operation.
Regards
PavanKumar.M

How to get file name from file adapter (Read Operation)

Hi All,
I am reading files from local location, in jca file i gave filename property =*.* ( which reads all files), and now I want to read the incoming file name inside bpel and I want to copy the file name to some variable. Is this possible?

Yes, its possible.
In your receive activity,set below property in its properties tab:
<bpelx:property name="jca.file.FileName" variable="FileName"/>
Before that make sure to create a variable "FileName" of string type.
Whatever file your file adapter will read,its name will be stored in this variable.
Hope this helps.
Regards,
Karan
http://learn-oraclesoa.blogspot.com/

How to get File name in Proxy program

Hi,
According to my business scenario, one XML file name comes from Legacy system and stores in a predefined directory. Now XI has to pick up that XML file and needs to call BAPI's which in turn updates the Target system ( SAP Tables).
Now my problem is , XML File name is a combination of three fileds those are DATE , OBJECTKEY AND WORKFLOWNAME.
Ex : YYYYMMDD_1234565789_WORKFLOWNAME.XML
DATE_OBJECTKEY_WORKFLOWNAME.XML
In proxy i need to get the file name and split into three fields ( those are DATE , OBJECTKEY AND WORKFLOWNAME ) which needs to send as import parameters in BAPI's.
So please let me know from anyone in this group how to get the file name in the proxy program.
Thanks & Regards
K. naveen Kumar

Hi,
have a look at my new weblog:
/people/michal.krawczyk2/blog/2005/11/10/xi-the-same-filename-from-a-sender-to-a-receiver-file-adapter--sp14
to see how you can access filename
Regards,
michal

How to get file name for failed request in JSOM

hello friends,
i am uploading files to sharepoint 2013 document library. due to some problem when a file is not uploaded request is failed and failed callback handler is executed. at this time how i can know for which file has not been uploaded.
as i am uploading multiple files so it is necessary to know for which file error occurs.
please help
Thanks in advance.
Mukesh

Hi Z..
it will be hard for any one to understand the code. how ever I have provided bellow.
theme is I need to upload multiple files selecting one by one asynchronously when a file will begin to upload It will show status of file name with processing image. similarly for other files.
ones file successfully uploaded processing image will get hidden. and delete will appear.
when error occurs for a file then processing div need to be removed for which I need file name when request failed. in failed handler
function uploadData()
var input = $("#fldFile")[0];
if (input) {
$("#uploadedfile").append("<div class='file'><label>" + input.files[0].name + "</label><div class='image'><img src='/_layouts/15/KPMG.VendorPortal.DMS/processing.gif' alt='processing..'/><img src='/_layouts/15/KPMG.VendorPortal.DMS/error.png' alt='delete' style='display:none;' /></div>");
file = input.files[0];
filename = input.files[0].name;
fr = new FileReader();
fr.onload = uploaddocument;
fr.readAsDataURL(file);
function uploaddocument()
web = clientContext.get_web();
clientContext.load(web);
list = web.get_lists().getByTitle("TempLibrary");
rootFolderUrl = list.get_rootFolder();
file = this.result;
clientContext.load(rootFolderUrl);
clientContext.executeQueryAsync(onuploaddocumentsuccess, failed);
function onuploaddocumentsuccess()
fileCreateInfo = new SP.FileCreationInformation();
fileCreateInfo.set_url(rootFolderUrl.get_serverRelativeUrl() + "/" + foldername + "/" + filename);
fileCreateInfo.set_overwrite(true);
fileCreateInfo.set_content(new SP.Base64EncodedByteArray());
// Read the binary contents of the base 64 data URL into a Uint8Array
// Append the contents of this array to the SP.FileCreationInformation
var arr = convertDataURIToBinary(file);
for (var i = 0; i < arr.length; ++i) {
fileCreateInfo.get_content().append(arr[i]);
// Upload the file to the root folder of the document library
uploadedfile= list.get_rootFolder().get_files().add(fileCreateInfo);
clientContext.load(uploadedfile);
clientContext.executeQueryAsync(documentuploaded, documentfailed);
function documentuploaded()
var fname = uploadedfile.get_name();
$("#uploadedfile").children("div").each(function () {
var flabelname = $(this).children("label").text();
if (flabelname.trim() == fname.trim())
$(this).children("div").children("img").get(0).style.display="none";
$(this).children("div").children("img").get(1).style.display="block";
alert("uploaded");
function documentfailed(sender,args)
Mukesh

How to get file name in faultpolices file for file based rejection handler

Hi All,
I am implementing the file rejection handler in fault polices.xml
Now i want to catch exact file name and use this in faultpolices.xml under Filename tag and move the rejected file to custom directory.
Can some please let me know is it possible to catch the exact filename and use the same name in rejection handle.
Suppose If we don't handle the rejection handler then these files will move to the default path in SOA HOME. But the file name remains the same. So i think this can be changed in SOA, but i am afraid i how can i do it.
Please suggest me.
Regards,
Tarak.

Hi,
have a look at my new weblog:
/people/michal.krawczyk2/blog/2005/11/10/xi-the-same-filename-from-a-sender-to-a-receiver-file-adapter--sp14
to see how you can access filename
Regards,
michal

How to get File name in Java Callout

Hi,
We are receiving EDI files with random file names through SFTP listening channel. How can we get the file name in the java callout.
~Ismail M

You can try to find it out under CalloutMessage.
CalloutMessage.getParameters().getProperty("filename")
Thanks,
Kathar

How to get file name and set it as static text in a dialog

Hi,
I m new to InDesign Programming.
I have a menu that creates a dialog with different controls in it.
The dialog will appear only if there is an open file. I need to display the name of the open file as a static text in the dialog. I know to get the name of the current file but don't know how to pass this each time the dialog is opened.
Can someone help me in doing this?
I m using InDesign CS3 in MAC OS.
Thank You.

those are the methods, but you can't use getCharacterEncoding(), actually, cuz it seems it's not necessarily filled in.. or at least that might be on some servers only, like Tomcat 4. As for encodings, you need to do a search for character encoding names and use the appropriate one.

How to get file name on the base of extension

hi
reply me
how to get the filename on the base of extension from the
current directory......
for example
i create file with the "igg" extension and save in the folder
where the exe file of director save....
i want when exe run then exe file read filename of the
define( "igg" ) extension with out path just name of the file with
igg extension
tel me how
regards
farhana khan

Here's a solution that requires no xtras:
on GetFilesWithExtension(aFolderPath, aExtension)
-- INPUT: <aFolderPath> should be a valid string
folder path
-- <aExtension> may be a string file extension,
without the
-- dot. For example: "txt" or "igg"
-- OUTPUT: Returns an error symbol or a linear list of file
names
-- in the given folder. If an extension is given, only
-- files with the given extension will be listed. If not,
-- all files and folders will be listed.
vFileList = []
if not stringP(aFolderPath) then
return #stringPathExpected
end if
vIgnoreExtension = not stringP(aExtension)
vDelimiter = the itemDelimiter
the itemDelimiter = "."
n = 0
repeat while TRUE
n = n + 1
vFileName = getNthFileNameInFolder(aFolderPath, n)
if vFileName = "" then
exit repeat
end if
if vIgnoreExtension then
vFileList.append(vFileName)
else if the last item of vFileName = aExtension then
vFileList.append(vFileName)
end if
end repeat
the itemDelimiter = vDelimiter
return vFileList
end GetFilesWithExtension
You can also use
Buddy API's baFileList,
which allows you to do wildcard searching.

How to get file names of processes

i am writing an application engine for monitoring ps jobs and processes i want to send an email to support group with log file if any process runs to error. Can anybody tell me how to get the log/trace files generated for each process. i tried many ways but did not get any clue would greatly appreciate for giving me information.
thanks
shiv

Yes man it is possible, follow these steps if you want to automate process monitoring:
1. Create a view for retrieving all the processes which are errored in a specific time for example 180 minutes. You can use all the following record for various information about a process or job
PSPRCSRQST,PSOPRDEFN, PS_PRCSDEFN, PSPRCSPRFL, XLATTABLE_VW
2. Create a table to store the process instance which was last monitored
3. In application engine access the view which you have created in step 1, this view will give you all the processes which got errored out.
4. In application engine use SendMail function to send an email with the process instance details which are errored out.
5. After reading last row from the view update the table which you created in step 2 with the process instance you have read in last.
This design should be able to send an email to support group if the process is errored out.
Jayaprakash Tedla
Sr. Architect - PeopleSoft

File to idoc how to get file name at runtime

Hi Experts,
In my file to idoc scenario,
the requiremnt is like in mapping i have to give condition like if file name is name1 then one target filed is 40 and if file name is name2 then that target field is 60.
how can we achieve this ?
Regards,
rohit

Hi Rohit
mughdha is right but you can do it through graphical mapping easily
give condition in fix value under category conversion like this
1) source-> FIX VALUE ->if value is true then map FIX value
else nothing
double click on first FIX VALUE function and assign your input values for file (for ex 40 or 60,......) in the key field and in the value field assign TRUE
if this condition will be true the it willl map second FIX VALUE
else assign a constant with empty value
in second fix value assign values (for ex 40 or 60,......) which you have checked in first FIX VALUE function in key field and assign corresponding name which you required in the value field
hope this will solve your problem
Thanks
sandeep
if helpful reward points

How to get file name on picture?

Hi there.
Is there a way to get the file name on the picture when exporting or "save as" my pictures? I am going to run a web site where people can order pictures and it will be much easier if I can have LR "printing" the file name on the picture.
Regards,
Deon

Deon,
I would try having this done by the web gallery itself (not on but below the picture). LR web galleries offer that option while building them.
If you cannot achieve this, the most common way of putting metadata onto a picture during LR export is by using the LR/Mogrify 2 PlugIn.
Beat Gossweiler
Switzerland

How to get file names?

Hi,
I'm currently trying to use com.oreilly.servlet.MultipartRequest by Jason Hunter to handle file uploading. This is the first time i handling this using jsp. I facing problem of getting the file names. I created the upload logic in a bean and i wanted it passing back the file names.
1) The file names actually in Enumeration type. Can i know what actually is Enumeration type?
2) Is it possible i return those names by converting them into string and as an array type? then accessing it using getProperty?
Regards,
jeffcjm

jeffcjm wrote:
1) The file names actually in Enumeration type. Can i know what actually is Enumeration type?Read the java.util.Enumeration API: http://java.sun.com/j2se/1.5.0/docs/api/java/util/Enumeration.html
2) Is it possible i return those names by converting them into string and as an array type? then accessing it using getProperty?Yes.
On the other side, you may find this stuff useful too. It sets all parameters back in the HttpServletRequest#getParameter()/getParameterValues()/getParameterMap() and puts the files as attributes of the HttpServletRequest. Very useful. http://balusc.blogspot.com/2007/11/multipartfilter.html

How to get file name ?

i have a code
fileObject.getName() // it prints D:\myfile.txt
i dont want D:\ in front of it .
i can parse this string and throw away the D:\ in front of it ...but i dont want that
is there any other method in the API which could give me just the file name without directory .
like
fileObject.getfileNameOnlyWithoutDirectory() ==>myfile.txt

Franck_Lefevre wrote:
Nothing in the OP tells (or leads me to think) that FileObject is inheritiing from File.
That's why I made this suggestion.Well, I would assume using the name fileObject that it is a file, but as a syntactic point, I would have said
Is fileObject an instance of File? If not try
and then made your post. That 's probably just me, but without that it looks (and nearly anyone reading it would see it so) redundant, and so, pointless.
Like as I said, just as a syntactic point. ;-)

How to get file name in adapter module

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