How to get file name on the base of extension

Question

hi
reply me
how to get the filename on the base of extension from the
current directory......
for example
i create file with the "igg" extension and save in the folder
where the exe file of director save....
i want when exe run then exe file read filename of the
define( "igg" ) extension with out path just name of the file with
igg extension
tel me how
regards
farhana khan

Answer 1

Here's a solution that requires no xtras:
on GetFilesWithExtension(aFolderPath, aExtension)
-- INPUT: <aFolderPath> should be a valid string
folder path
-- <aExtension> may be a string file extension,
without the
-- dot. For example: "txt" or "igg"
-- OUTPUT: Returns an error symbol or a linear list of file
names
-- in the given folder. If an extension is given, only
-- files with the given extension will be listed. If not,
-- all files and folders will be listed.
vFileList = []
if not stringP(aFolderPath) then
return #stringPathExpected
end if
vIgnoreExtension = not stringP(aExtension)
vDelimiter = the itemDelimiter
the itemDelimiter = "."
n = 0
repeat while TRUE
n = n + 1
vFileName = getNthFileNameInFolder(aFolderPath, n)
if vFileName = "" then
exit repeat
end if
if vIgnoreExtension then
vFileList.append(vFileName)
else if the last item of vFileName = aExtension then
vFileList.append(vFileName)
end if
end repeat
the itemDelimiter = vDelimiter
return vFileList
end GetFilesWithExtension
You can also use
Buddy API's baFileList,
which allows you to do wildcard searching.