How to get first emp for each dept?

Hi,
I need to do a query to pick up one employee (the first one based on ename or empno)from each department, but I don't want to use min function (for some reason it didn't work on my real date), rather I like to use something like this: The problem is I can only pick one instead of one for each dept.
select ee.* from
(select * from emp
order by ename
) ee,
emp e
where rownum <2
and e.deptno=ee.deptno
Thanks

How about this (if I understood your question correctly)?
select * from
(select distinct deptno from emp) depts,
(select deptno, min(ename) from emp group by deptno) ees
where ees.deptno = depts.deptno;
Test:
14:10:26 ==> create table emp (deptno number, ename varchar2(50));
Table created.
14:10:27 ==> insert into emp values (10, 'Joe');
1 row created.
14:10:27 ==> insert into emp values (10, 'Mary');
1 row created.
14:10:27 ==> insert into emp values (10, 'Ethel');
1 row created.
14:10:27 ==> insert into emp values (20, 'Luke');
1 row created.
14:10:27 ==> insert into emp values (10, 'Sue');
1 row created.
14:10:27 ==> insert into emp values (20, 'Bob');
1 row created.
14:10:27 ==> insert into emp values (30, 'Randy');
1 row created.
14:10:28 ==> select * from
14:10:35 2 (select distinct deptno from emp) depts,
14:10:35 3 (select deptno, min(ename) from emp group by deptno) ees
14:10:35 4 where ees.deptno = depts.deptno;
DEPTNO DEPTNO MIN(ENAME)
10 10 Ethel
20 20 Bob
30 30 Randy

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