How to get name of an entry?

Question

I search in my schema with code below:
List<OrganizationPojo> organizationPojoList = new ArrayList<OrganizationPojo>();
     DirContext ctx = null;
     try { 
     // get a handle to an Initial DirContext
     ctx = new InitialDirContext(env);
     String[] attrIDs = { "dc", "objectClass","ou" };
     SearchControls ctls = new SearchControls();
     ctls.setReturningAttributes(attrIDs);
     ctls.setSearchScope(SearchControls.SUBTREE_SCOPE);
     String filter = "(&(dc=*) (objectClass=organizationalUnit) (ou=*))";
     NamingEnumeration answer = ctx.search(searchBaseDn, filter, ctls);
     try
               while (answer.hasMore())
                         SearchResult sr = (SearchResult) answer.next();
                         LdapName dn = new LdapName((String)sr.getNameInNamespace());
                         LdapName rdn = new LdapName((String)sr.getName());
I learned SearchResult.getName returns the name "relative to search base"
But i only want to get the name of entry.
I am getting dn correctly but can not find out how to get rdn relative to parent in the tree.

Answer 1

More generally, to get the RDN of any search result, you're nearly there:
List<Rdn> rdns = new LdapName(sr.geNameInNamespace()).getRdns();
Rdn rdn = rdns.get(rdns.size()-1);