How to get the full path name of a file

Hey everybody, I'm new here and in Java.
so I will explain my question by giving an example:
I want to send file from the Desktop by the "Send to" on the popup menu to my program.
I want to know how can I read the full path name and the file name, and show it on my text box.
Thanx alot

If this is a client side application then I'd say look into drag-n-drop tutorials.
i.e. drag file to your application, action listener fires, create File object giving you full name and path of users action.
If this is a web application then look into the "multipart/form-data" content type specifications on how to upload files.
i.e. user specifies file from <input type='file' ... /> type, submits, servlet receives data and recreates file locally on application server side.
If you are thinking that all you need to send a file to a program is the full path and name in a textbox its a little bit more complicated then that.
Good luck, hope that helps!

Similar Messages

How to get the pull path name from a file upload window

Hello everyone!
I have encountered the following problem with the following JSP code:
<form method="post" action="filename.jsp">
Upload JAVA program:
<input type=file size=20 name="fname" accept="java">
<input type=submit value="go">
</form>
<%
String s = "";
if (request.getParameter("fname") != null)
s = request.getParameter("fname")
%>
The value of s is alway the filename. However I want to get the full path in addition to the filename, so that I can read the file. Does anyone know how to get the pull name of the file?
thanks a lot in advance,

Dear Sir,
thanks a lot for your reply. Please let me explain what I intended to do: I want to upload a file from the local machine and then read the content of the file. Therefore I need to the fullpath of the filename like /var/local/file.java instead of file.java. The latter is what I got.
The problem I have with your code is that the function like "request.getServerScheme()" is not recognized. Maybe is it because I didn't install servelet package? I only installed javax package btw. Also my application runns on Tomcat server if this could give you some information. The error message I had is as follows:
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
[javac] Compiling 1 source file
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:133: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
url = request.getServerScheme()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:136: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
+ ((("http".equals(request.getServerScheme()) && request.getServerPort() != 80)
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:137: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
||("https".equals(request.getServerScheme()) && request.getServerPort() != 443))
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:139: cannot resolve symbol
symbol : method getServletConfig ()
location: interface javax.servlet.http.HttpServletRequest
+ "/" + request.getServletConfig().getServletName()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:140: cannot resolve symbol
symbol : variable path
location: class org.apache.jsp.addExercise_jsp
+ "/" + path
^
5 errors
     org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:128)
     org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:351)
     org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:413)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:453)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:437)
     org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:555)
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:291)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:856)

How to get the full path instead of just the file name, in �FileChooser� ?

In the FileChooserDemo example :
In the statement : log.append("Saving: " + file.getName() + "." + newline);
�file.getName()� returns the �file name�.
My question is : How to get the full path instead of just the file name,
e.g. C:/xdirectory/ydirectory/abc.gif instead of just abc.gif
import java.io.*;
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.filechooser.*;
public class FileChooserDemo extends JFrame {
static private final String newline = "\n";
public FileChooserDemo() {
super("FileChooserDemo");
//Create the log first, because the action listeners
//need to refer to it.
final JTextArea log = new JTextArea(5,20);
log.setMargin(new Insets(5,5,5,5));
log.setEditable(false);
JScrollPane logScrollPane = new JScrollPane(log);
//Create a file chooser
final JFileChooser fc = new JFileChooser();
//Create the open button
ImageIcon openIcon = new ImageIcon("images/open.gif");
JButton openButton = new JButton("Open a File...", openIcon);
openButton.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
int returnVal = fc.showOpenDialog(FileChooserDemo.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//this is where a real application would open the file.
log.append("Opening: " + file.getName() + "." + newline);
} else {
log.append("Open command cancelled by user." + newline);
//Create the save button
ImageIcon saveIcon = new ImageIcon("images/save.gif");
JButton saveButton = new JButton("Save a File...", saveIcon);
saveButton.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
int returnVal = fc.showSaveDialog(FileChooserDemo.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//this is where a real application would save the file.
log.append("Saving: " + file.getName() + "." + newline);
} else {
log.append("Save command cancelled by user." + newline);
//For layout purposes, put the buttons in a separate panel
JPanel buttonPanel = new JPanel();
buttonPanel.add(openButton);
buttonPanel.add(saveButton);
//Explicitly set the focus sequence.
openButton.setNextFocusableComponent(saveButton);
saveButton.setNextFocusableComponent(openButton);
//Add the buttons and the log to the frame
Container contentPane = getContentPane();
contentPane.add(buttonPanel, BorderLayout.NORTH);
contentPane.add(logScrollPane, BorderLayout.CENTER);
public static void main(String[] args) {
JFrame frame = new FileChooserDemo();
frame.addWindowListener(new WindowAdapter() {
public void windowClosing(WindowEvent e) {
System.exit(0);
frame.pack();
frame.setVisible(true);

simply use file.getPath()
That should do it!Thank you !
It takes care of the problem !!

How to get the full path of the fmx's directory.

Hi all,
I will ship my project to a customer. So I must install forms runtime at the customer's machine.
I put all of the fmx files of my project into a certain directory at the customer's machine, and I create a desktop shortcut of the forms runtime. In the "start in" field of the shortcut property I put the full path of the directory where I put the fmx files. And in the target field of the shortcut property I put after the ifrun60.exe the name of the fmx file which to call first.
Now , in one of my forms file I want to get the full path of this directory because I must call Ora_Ffi.Load_Library. And the library which I want to load resides on that directory.
So how to get programatically the directory where the fmx files reside.
I know that there is the registry entry FORMS60_PATH, but we plan to ship many projects to that customer; so if I use the FORMS60_PATH variable then there will be an error because there will be many directories. And the customer can launch many of the projects at the same time.
So how to get it.
Thank you very much indeed.

If you are using the d2kwutil library, then you can use the win_api_environment.Get_Working_Directory() function.
If not, I doubt that there is anyway to get it since the get_application_property(current_form) does not return the full path of the form as it used to in prior versions of Oracle forms such as 4.5.

How to get the full path of a file

    If the user selects a file through a browse button, Is there a way, I can get the full path of the file. The file can be from his local hard drive as well.. Can someone advise

To upload multiple files (example is for 3), try something like this.
== Form section ==
There would be three(3) file form fields for the selection of a file/document to upload, which
each being uniquely named.
<div style="clear: both;">
<cfinput type="file" name="upload_01" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
<div style="clear: both;">
<cfinput type="file" name="upload_02" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
<div style="clear: both;">
<cfinput type="file" name="upload_03" dir="ltr" lang="en" size="70" xml:lang="en">
</div>
== Processing section ==
Checks to see if any files / documents were selected for upload. If none were, then
displays an alert indicating as such. If at least one file/document was selected, then
the process would process the upload.
<cfif isdefined('form.upload_01') and trim(form.upload_01) eq "" and
isdefined('form.upload_02') and trim(form.upload_02) eq "" and
isdefined('form.upload_03') and trim(form.upload_03) eq ""
>
    <p>Did not select any files to upload</p>
<cfelse>
    <cfif isdefined('form.upload_01') and trim(form.upload_01) neq "">
        <cffile
            action="upload"
            destination="C:\path\to\upload\files\to"
            filefield="upload_01"
            nameconflict="overwrite"
            accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
            <cfcookie name="upload_01_doc" value="#cffile.serverfile#">
            <cfcookie name="upload_01_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cfif isdefined('form.upload_02') and trim(form.upload_02) neq "">
        <cffile
            action="upload"
            destination="C:\path\to\upload\files\to"
            filefield="upload_02"
            nameconflict="overwrite"
            accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
            <cfcookie name="upload_02_doc" value="#cffile.serverfile#">
            <cfcookie name="upload_02_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cfif isdefined('form.upload_03') and trim(form.upload_03) neq "">
    <cffile
        action="upload"
        destination="C:\path\to\upload\files\to"
        filefield="upload_03"
        nameconflict="overwrite"
        accept="
              application/msword
            , application/vnd.openxmlformats-officedocument.wordprocessingml.document
            , application/vnd.ms-excel
            , application/vnd.openxmlformats-officedocument.spreadsheetml.sheet
            , application/pdf">
        <cfcookie name="upload_03_doc" value="#cffile.serverfile#">
        <cfcookie name="upload_03_doc_ext" value="#cffile.serverfileext#">
    </cfif>
    <cflocation url="completed.cfm" addtoken="no">
</cfif>
== Completed section ==
Can confirm to the person what files were actually uploaded, by displaying file name and file extension.
You can you use the file extension information to display a respective icon for the file type.
<cfoutput>
<cfif isdefined('cookie.upload_01_doc')>
01. #cookie.upload_01_doc# - #cookie.upload_01_doc_ext#<br /></cfif>
<cfif isdefined('cookie.upload_02_doc')>
02. #cookie.upload_02_doc# - #cookie.upload_02_doc_ext#<br /></cfif>
<cfif isdefined('cookie.upload_03_doc')>
03. #cookie.upload_03_doc# - #cookie.upload_03_doc_ext#<br /></cfif>
</cfoutput>
Leonard B

How to get the full path of the plug-in on Mac

I use SDK function "GetPluginFileSpecification" to get the full path of the plug-in .On Windows,I success(for example I get "C:\Adobe\plugin.aip"), On Mac , I only get the plug-in's name(for example"plugin.aip").If I want to get the full path of the plug-in on Mac,is there other function I can use ?

Thank you for the answer.
Unfortunately i'm working on Photoshop plugin, not illustrator.
i was looking for solution on google and i found this post.
I hope you can help me becouse this plug-in is very simple, it must execute a file in the same directory where the plugin is installed.
If i execute system("./Appname.app/Contents/MacOS/AppName"); the plugin search in my home directory (on windows and on MacOS).
i try to write:
   SPPluginsSuite* sSPPlugins;
    SPPluginRef fPluginRef = message->d.self;
    SPPlatformFileSpecification filespec;
    sSPPlugins->GetPluginFileSpecification(message->d.self, &fileSpec);
    filespec.mReference
    ai::FilePath path(platformFileSpec);
    std::cout << path.GetFullPath().as_Platform() << std::endl;
but i have several errors.
Thank you

How to get the full path or name of the Layer to which Filter is applied?

Hi All,
I have created a layer using some background image as source. How to get the name or ful path of the background image?
I checked the documentation and found GetPathNameProc(SPPlatformFileSpecification*) function, but I couldn't get the parameter SPPlatformFileSpecification*.
Is there any other way to get the file path of background layer in my custom filter?
Thanks,
Dheeraj

If this is a client side application then I'd say look into drag-n-drop tutorials.
i.e. drag file to your application, action listener fires, create File object giving you full name and path of users action.
If this is a web application then look into the "multipart/form-data" content type specifications on how to upload files.
i.e. user specifies file from <input type='file' ... /> type, submits, servlet receives data and recreates file locally on application server side.
If you are thinking that all you need to send a file to a program is the full path and name in a textbox its a little bit more complicated then that.
Good luck, hope that helps!

How to get the full path of a specific programe(flash media live encoder in my case) in air?

I need to call it in air,but first of all how can I figure out where it's installed programatically?

If you are using the d2kwutil library, then you can use the win_api_environment.Get_Working_Directory() function.
If not, I doubt that there is anyway to get it since the get_application_property(current_form) does not return the full path of the form as it used to in prior versions of Oracle forms such as 4.5.

Tree control - How to get the full path of selected Item in tree control

I am Flex newbie. When the user clicks the particular item in
the tree control I just wanted to get it name along with it's full
parent.
Here is my XML
var dirXML:XML=<root basename="/home/tcegrid">
<Directories>
<Dir Name=".autosave" />
<Dir Name=".emacs.d" />
<Dir Name="AnsysDistributed">
<Dir Name="opt"/>
<Dir Name="root" />
</Dir>
<Dir Name="postgres"/>
<Dir Name="FineTurbo"/>
<Directories>
</root>
The above XML is data provider for Tree control. When the
user clicks the Dir Name called opt. I wanted it absolute path in
XML. say Directories.Dir.Dir.@Name is opt
Can any one tell me how to get this?

"Thamizhannal" <[email protected]> wrote in
message
news:gam9q8$4es$[email protected]..
>I am Flex newbie. When the user clicks the particular
item in the tree
>control
> I just wanted to get it name along with it's full
parent.
> Here is my XML
> var dirXML:XML=<root basename="/home/tcegrid">
> <Directories>
> <Dir Name=".autosave" />
> <Dir Name=".emacs.d" />
> <Dir Name="AnsysDistributed">
> <Dir Name="opt"/>
> <Dir Name="root" />
> </Dir>
> <Dir Name="postgres"/>
> <Dir Name="FineTurbo"/>
> <Directories>
> </root>
>
> The above XML is data provider for Tree control. When
the user clicks the
> Dir
> Name called opt. I wanted it absolute path in XML. say
> Directories.Dir.Dir.@Name is opt
> Can any one tell me how to get this?
loop until the parent() property of the XML node is empty.
HTH;
Amy

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Hi,
I write a servlet to upload a file from html page
<intput type=file name=fileupload>I am using
import org.apache.commons.fileupload.to upload file. i want to get the all fields in the form and file name and content of the file also.
It give the file name only
String filename= fileItem.getName();
o/p krish.jpgBut i want complete path naem like
d:/krishna/images/funny/krish.jpgI serach the API org.apache.commons.fileupload.*
But i did nt find the method to get it.
plz help me , which api or method to use here..

Krishna_Rao_chintu wrote:
But i need path and have to do some calculations on it.No, you don't. If you have requirements which say you do then the requirements are wrong. You couldn't do anything useful with the path on the client system even if you could get it.
is there any alternatives in java
I need path and have to calculate MD5, Presumably you need to calculate MD5 on the contents of the file and not on the name of the file.
and convert the file to binary format.... etc oprations on itSorry, "convert a file to binary format" is basically meaningless.
but we can get the content of the file using
byte [] get()/ getString() methods
If i get content is there any performance degrades?
ie if the content is lengthy is it take more time?Take more time than what? Degrading performance from what? It's certainly true that it would be quicker to not upload the file, but that's a pointless comparison. If you have some other process to compare with, let us know what it would be.

How to get the full identifier name?

I am using the Java Compiler API and walking through the AST to retrieve information. I was able to analyze this program:
package com.test;
import java.io.*;
public class Test
     public static void main(String[] args)
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}When I try to dump out the identifierTree using getName(), all I see is FOO instead of FOO.ALL and BAR instead of BAR.NONE, Am I misinterpreting the meaning of an identifier? Here is the fragment of my visitor code:
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Thanks for any ideas or suggestions.
Edited by: scott2006 on Dec 29, 2009 6:54 PM

Here's a quick example:
import com.sun.source.tree.ClassTree;
import com.sun.source.tree.CompilationUnitTree;
import com.sun.source.tree.ExpressionTree;
import com.sun.source.tree.Tree;
import com.sun.source.tree.TreeVisitor;
import com.sun.source.util.JavacTask;
import com.sun.source.util.SimpleTreeVisitor;
import java.io.IOException;
import java.util.List;
import javax.lang.model.element.ElementKind;
import javax.lang.model.element.Name;
import javax.lang.model.element.TypeElement;
import javax.lang.model.util.Elements;
import javax.tools.JavaCompiler;
import javax.tools.JavaFileObject;
import javax.tools.StandardJavaFileManager;
import javax.tools.ToolProvider;
public class Main {
    public static void main(String[] args) throws IOException {
        JavaCompiler compiler = ToolProvider.getSystemJavaCompiler();
        StandardJavaFileManager fileManager = compiler.getStandardFileManager(null, null, null);
        Iterable<? extends JavaFileObject> fileObjects = fileManager.getJavaFileObjects(args);
        JavacTask task = (JavacTask)compiler.getTask(null, fileManager, null, null, null, fileObjects);
        Elements elements = task.getElements();
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        Iterable<? extends CompilationUnitTree> compilationUnitTrees = task.parse();
        for (CompilationUnitTree compilationUnitTree : compilationUnitTrees) {
            compilationUnitTree.accept(visitor, null);
    private static class CompilationUnitVisitor extends SimpleTreeVisitor<Void, Void> {
        private final Elements elements;
        public CompilationUnitVisitor(Elements elements) {
            super();
            this.elements = elements;
        @Override
        public Void visitCompilationUnit(CompilationUnitTree tree, Void ignore) {
            String currentPackagePrefix = "";
            ExpressionTree packageName = tree.getPackageName();
            if (packageName != null) {
                String packageNameString = String.valueOf(packageName);
                if (packageNameString.length() > 0) {
                    currentPackagePrefix = packageNameString + ".";
            TreeVisitor<Void, String> visitor = new ClassVisitor(this.elements);
            List<? extends Tree> typeDeclTrees = tree.getTypeDecls();
            for (Tree typeDeclTree : typeDeclTrees) {
                typeDeclTree.accept(visitor, currentPackagePrefix);
            return null;
    private static class ClassVisitor extends SimpleTreeVisitor<Void, String> {
        private final Elements elements;
        public ClassVisitor(Elements elements) {
            super();
            this.elements = elements;
        @Override
        public Void visitClass(ClassTree tree, String currentPackagePrefix) {
            Name simpleName = tree.getSimpleName();
            String canonicalName = currentPackagePrefix + simpleName;
            TypeElement typeElement = elements.getTypeElement(canonicalName);
            ElementKind elementKind = typeElement.getKind();
            boolean isInterface = (elementKind == ElementKind.INTERFACE);
            System.out.println(canonicalName + " is an interface: " + isInterface);
            List<? extends Tree> memberTrees = tree.getMembers();
            String memberPrefix = canonicalName + ".";
            for (Tree memberTree : memberTrees) {
                memberTree.accept(this, memberPrefix);
            return null;
}Edited by: kschneid on Jan 4, 2010 10:33 AM
Modified ClassVisitor.visitClass method to handle nested classes/interfaces

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Hi all,
I would like to get the local full path name, of a file selected from an item 'File browser'.
I see in wwv_flow_files the column 'name', but actually it's a kind of id like 'F1542335/myFile.gif' for example.
What i want is the local path of this file ("C:\Documents and Settings\All Users\....\myFile.gif").
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Anyway, thanks all for reading.
Ludo

Hello, thank you for the answer.
Please understand that I searched before posting, and not ony 15 min.
What i mean is that the value of a File Browser in an Apex applocation is something like 'F1542335/myFile.gif', but what I need is the local path location.
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I'll answer if I find some good things.
Thanks
Ludo
Edited by: user12945874 on 06-avr.-2010 3:59

How to get the full image directory when i upload the image to web page???

hai, how to get the full image directory when i upload the image to web page???
here is the example:
<form action="uploadfile.jsp" method="post">
image<input type="file" name="image" />
<input type="submit" value="submit"/>
<%
String s=request.getParameter("image");
%>
<%=s%>
</form>
i upload the image from C:\image\center.gif. i use request.getParameter just can get the image name like "center.gif". Can anybody help me how to get the full path name. Thanks a lot..

There is no need to get the path. It is also fairly pointless as the server cannot access the client's local file system.
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Anybody knows how to get document full path + file name into a variable in Sharepoint 2010 workflow?
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Hi SAMSUNG,
According to your description, my understanding is that you want to get the full path of a document in a list workflow.
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document. I used ‘Log to history list’ to check the value of the variable in Workflow History .
I hope this helps.
Thanks,
Wendy
Wendy Li
TechNet Community Support

How do I get the full path and filename of the current document?

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I actually just figured this out. For anyone else who would like to know, check out the propetizer sample code in the photoshop sdk. It makes a "filter" plug-in that just spits out all the properties of the document you could ever want to know about. The function I used to get the full path and filename of the current document is PIGetDocumentName(). I hope this helps someone eventually...

How to get the full path name of a file

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