How to get the pull path name from a file upload window

Hello everyone!
I have encountered the following problem with the following JSP code:
<form method="post" action="filename.jsp">
Upload JAVA program:
<input type=file size=20 name="fname" accept="java">
<input type=submit value="go">
</form>
<%
String s = "";
if (request.getParameter("fname") != null)
s = request.getParameter("fname")
%>
The value of s is alway the filename. However I want to get the full path in addition to the filename, so that I can read the file. Does anyone know how to get the pull name of the file?
thanks a lot in advance,

Dear Sir,
thanks a lot for your reply. Please let me explain what I intended to do: I want to upload a file from the local machine and then read the content of the file. Therefore I need to the fullpath of the filename like /var/local/file.java instead of file.java. The latter is what I got.
The problem I have with your code is that the function like "request.getServerScheme()" is not recognized. Maybe is it because I didn't install servelet package? I only installed javax package btw. Also my application runns on Tomcat server if this could give you some information. The error message I had is as follows:
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
[javac] Compiling 1 source file
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:133: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
url = request.getServerScheme()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:136: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
+ ((("http".equals(request.getServerScheme()) && request.getServerPort() != 80)
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:137: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
||("https".equals(request.getServerScheme()) && request.getServerPort() != 443))
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:139: cannot resolve symbol
symbol : method getServletConfig ()
location: interface javax.servlet.http.HttpServletRequest
+ "/" + request.getServletConfig().getServletName()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:140: cannot resolve symbol
symbol : variable path
location: class org.apache.jsp.addExercise_jsp
+ "/" + path
^
5 errors
     org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:128)
     org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:351)
     org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:413)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:453)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:437)
     org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:555)
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:291)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:856)

Similar Messages

  • How to get the full path name of a file

    Hey everybody, I'm new here and in Java.
    so I will explain my question by giving an example:
    I want to send file from the Desktop by the "Send to" on the popup menu to my program.
    I want to know how can I read the full path name and the file name, and show it on my text box.
    Thanx alot

    If this is a client side application then I'd say look into drag-n-drop tutorials.
    i.e. drag file to your application, action listener fires, create File object giving you full name and path of users action.
    If this is a web application then look into the "multipart/form-data" content type specifications on how to upload files.
    i.e. user specifies file from <input type='file' ... /> type, submits, servlet receives data and recreates file locally on application server side.
    If you are thinking that all you need to send a file to a program is the full path and name in a textbox its a little bit more complicated then that.
    Good luck, hope that helps!

  • How to get the Portal Page name from PLSQL?

    Can anyone tell me how to get the portal page name from my dynamic page using plsql?
    Apparently you can get the page id and work it out from there, but my calls to get the page id are not returning any values anyway.
    My code for attempting to get the page id is below.
    <oracle>
    declare
    v_pageid varchar2(30);
    begin
    v_pageid := wwpro_api_parameters.get_value('_pageid', '/pls/portal30');
    htp.print('Page is '|| v_pageid);
    end;
    </oracle>
    Ideally I'd actually just like to get the page name. Is there a straightforward way to do this?
    Thanks in advance!
    Sarah

    Few clarifications -
    1. wwpro_api_parameters cannot be used to get default portal
    page parameters such as '_pageid', '_dad', '_schema' etc.,
    2. Page information can be obtained through any components which
    are available in that particular page. For example, in case of
    dynamic page, we need to publish it as a portlet and add it to the
    page. This process creates necessary packages in the DB, but we
    will not have access to the portlet methods.
    So, I would prefer creating a simple DB provider & portlet and access
    page title from its show method as follows -
    //Declare local variable l_page_id, l_page_title as varchar2
    select page_id into l_page_id from wwpob_portlet_instance$ where
    portlet_id = p_portlet_record.portlet_id and
    provider_id = p_portlet_record.provider_id;
    select name into l_page_title from wwpob_page$ where id=l_page_id;
    More information on DB provider can be found at
    http://portalstudio.oracle.com/pls/ops/docs/FOLDER/COMMUNITY/PDK/articles/understanding.database.providers.html
    Secondly, usage of wwpro_api_parameters.get_value method is
    incorrect. This method expects two arguments -
    <ul>
    <li><b>p_name : </b> The name of the parameter to be returned.</li>
    <li><b>p_reference_path : </b> An unique identifier for a portlet instance on the current page.</li>
    </ul>
    p_reference_path would be something like 99_SNOOP_PORTLET_76535103 and not some type of path as its name suggests.
    The following code fragment fetches all parameters available
    for a portlet.
    Note : Copy this code into 'show' method of your portlet.
    //Declare l_names, l_values as owa.vc_arr
    * Retreive all of the names of parameters for this portlet
    l_names := wwpro_api_parameters.get_names(
    p_reference_path=>p_portlet_record.reference_path);
    * Retreive all of the values of parameters for this portlet
    l_values := wwpro_api_parameters.get_values(p_names=>l_names,
    p_reference_path=>p_portlet_record.reference_path);
    //Loop through these arrays to get parameter information
    htp.p('<center><table BORDER COLS=2 WIDTH="90%" >');
    htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
    htp.tableData(wwui_api_portlet.portlet_heading('Name',1));
    htp.tableData(wwui_api_portlet.portlet_heading('Value',1));
    htp.tableRowClose;
    if l_names.count = 0 then
    htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
    htp.p('<td COLSPAN="2">'
    ||wwui_api_portlet.portlet_text(
    'No portlet parameters were passed on the URL.',1)
    ||'</td>');
    htp.tableRowClose;
    else
    for i in 1..l_names.count loop
    htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
    htp.tableData(l_names(i));
    htp.tableData(l_values(i));
    htp.tableRowClose;
    end loop;
    end if;
    htp.p('</table></center>');
    Hope it helps...
    -aMJAD.

  • How to get the absolute path of logicalhost server domain on Windows Sun

    i am reading a file from Xsql Folder, that is located in the logicalhost Sun\AppServer\domains\domain1\applications\j2ee-apps.(IN Sun Application Server)
    I am pretty sure that using the absolute path will solve this issue, so my first question is: How to get the absolute path of logicalhost server domain on Windows?
    i tried with System.getProperty("com.sun.aas.instanceRoot").
    but i am able to retrive Sun\AppServer\domains\domain1 upto this .i am unable to retrive Sun\AppServer\domains\domain1\applications\j2ee-apps.
    please suggest me how u can get absolute path in sun application server

    Take a look here

  • How to get the absolute path of logicalhost server domain on Windows?

    My logicalhost server domain behaves strangely. I am reading a file from collaboration definiton, that is located in the logicalhost/is/domains/domain1/config folder. I thought, that this folder is used as an application root folder so I can read files like ./file from there. And it worked.
    But then I've installed the domain as a Windows service, restarted the PC. When the domain1 gets started, I get exceptions saying that the file can't be found. Then I restart the domain (in domainmgr.bat) and it works again.
    I am pretty sure that using the absolute path will solve this issue, so my first question is: How to get the absolute path of logicalhost server domain on Windows?
    And my second question is: Why does this happen?

    The default folder for a Windows Service is the system32 folder contrary to the instance root folder when starting it as a normal process.
    That's the why, haven't tried the how, but you should be able to get the value by calling System.getProperty("com.sun.aas.instanceRoot").
    Hope this helps
    Paul

  • Programming help - how to get the read-only state of PDF file is windows explorer preview is ON?

    Programming help - how to get the read-only state of PDF file is windows explorer preview is ON?
    I'm developing an application where a file is need to be saved as pdf. But, if there is already a pdf file with same name in the specified directory, I wish to overwrite it. And in the overwrite case, read-only files should not be overwritten. If the duplicate(old) file is opened in windows (Win7) explorer preview, it is write protected. So, it should not be overwritten. I tried to get the '
    FILE_ATTRIBUTE_READONLY' using MS API 'GetFileAttributes', but it didn't succeed. How Adobe marks the file as read-only for preview? Do I need to check some other attribute of the file?
    Thanks!

    Divya - I have done it in the past following these documents. Please read it and try it it will work.
    Please read it in the following order since both are a continuation documents for the same purpose (it also contains how to change colors of row dynamically but I didnt do that part I just did the read_only part as your requirement) 
    http://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/f0625002-596c-2b10-46af-91cb31b71393
    http://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/d0155eb5-b6ce-2b10-3195-d9704982d69b?quicklink=index&overridelayout=true
    thanks!
    Jason PV

  • How to get the actual font name from a font file?

    Hi
    I have only the font Path I have to get the font name from that path. Any idea how to get the actual font name?
    Thanks,

    I would ask you these questions:
    Why do you need to do this?  What are you ultimately trying to accomplish?
    Are you really asking about the InDesign SDK?
    Do you really need to get the "name" of a font from an arbitrary file?  Or do you want information about a font installed on the system?  If so, what OS?
    Do you need to be able to handle any font format?
    Which font "name" do you mean?
    What language do you want the name in?
    (1) It's not clear what you're trying to accomplish.  A bit more information about your ultimate goal would be helpful.
    (2) This question is not at all specific to the InDesign SDK.  Are you really trying to do something in the context of an InDesign plug-in?  If so, you probably want to look at IID_IFONTFAMILY and the IFontFamily::GetFamilyName function.
    (3) If you are asking more generally, Windows and Mac both have system API calls to get this information, although those tend to deal with installed system fonts, not with arbitrary font files per se.
    Also, you can parse the name table from a True Type or Open Type font without using any system APIs; as True Type and Open Type are well-documented standards.  I would start by reading these:
    The Naming Table
    Font Names Table
    (4) Although there are other standards, such as Type 1 (PostScript) fonts, and True Type Collection files and other formats, especially on Mac.
    (5) Also, when you start down this road, you will quickly realize that your seemingly simple question is actually ambiguous, and that the answer is kind of complicated, because a font can have many names (a family name, a full font name, a style name, a PostScript name, etc.).
    (6) And not only does a font have multiple names, it can have each of those names in multiple languages and encodings.
    Any clarification would make this a better question.

  • How to get the failover partner name from C++ client

    Hi All,
    I have configured the mirroring session for my application.
    I want to modify the connection string with failover partner name.
    Could any one please let me to know how to get the failover partner instance from C++ client dynamically.
    Thanks,
    Prasad.

    Are you looking for this?
    http://www.connectionstrings.com/sql-server-2012/
    http://stackoverflow.com/questions/25534972/auto-failover-multiple-connections-to-mirror-database-when-principal-goes-down

  • How to get the complete path name when uploading a file from servlet

    Hi,
    I write a servlet to upload a file from html page
    <intput type=file name=fileupload>I am using
    import org.apache.commons.fileupload.to upload file. i want to get the all fields in the form and file name and content of the file also.
    It give the file name only
    String filename= fileItem.getName();
    o/p krish.jpgBut i want complete path naem like
    d:/krishna/images/funny/krish.jpgI serach the API org.apache.commons.fileupload.*
    But i did nt find the method to get it.
    plz help me , which api or method to use here..

    Krishna_Rao_chintu wrote:
    But i need path and have to do some calculations on it.No, you don't. If you have requirements which say you do then the requirements are wrong. You couldn't do anything useful with the path on the client system even if you could get it.
    is there any alternatives in java
    I need path and have to calculate MD5, Presumably you need to calculate MD5 on the contents of the file and not on the name of the file.
    and convert the file to binary format.... etc oprations on itSorry, "convert a file to binary format" is basically meaningless.
    but we can get the content of the file using
    byte [] get()/ getString() methods
    If i get content is there any performance degrades?
    ie if the content is lengthy is it take more time?Take more time than what? Degrading performance from what? It's certainly true that it would be quicker to not upload the file, but that's a pointless comparison. If you have some other process to compare with, let us know what it would be.

  • How to get the absolute path of a file from the local disk given the file n

    how to get the absolute path of a file from the local disk given the file name

    // will look for the file at the current working directory
    // this is wherever you start the Java application (cound be C: and your
    // application is located in C:/myapp, but the working dir is C:/
    File file = new File("README.txt"); 
    if (file != null && file.exists())
        String absolutePath = file.getAbsolutePath();

  • How to get the full path instead of just the file name, in �FileChooser� ?

    In the FileChooserDemo example :
    In the statement : log.append("Saving: " + file.getName() + "." + newline);
    �file.getName()� returns the �file name�.
    My question is : How to get the full path instead of just the file name,
    e.g. C:/xdirectory/ydirectory/abc.gif instead of just abc.gif
    import java.io.*;
    import java.awt.*;
    import java.awt.event.*;
    import javax.swing.*;
    import javax.swing.filechooser.*;
    public class FileChooserDemo extends JFrame {
    static private final String newline = "\n";
    public FileChooserDemo() {
    super("FileChooserDemo");
    //Create the log first, because the action listeners
    //need to refer to it.
    final JTextArea log = new JTextArea(5,20);
    log.setMargin(new Insets(5,5,5,5));
    log.setEditable(false);
    JScrollPane logScrollPane = new JScrollPane(log);
    //Create a file chooser
    final JFileChooser fc = new JFileChooser();
    //Create the open button
    ImageIcon openIcon = new ImageIcon("images/open.gif");
    JButton openButton = new JButton("Open a File...", openIcon);
    openButton.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent e) {
    int returnVal = fc.showOpenDialog(FileChooserDemo.this);
    if (returnVal == JFileChooser.APPROVE_OPTION) {
    File file = fc.getSelectedFile();
    //this is where a real application would open the file.
    log.append("Opening: " + file.getName() + "." + newline);
    } else {
    log.append("Open command cancelled by user." + newline);
    //Create the save button
    ImageIcon saveIcon = new ImageIcon("images/save.gif");
    JButton saveButton = new JButton("Save a File...", saveIcon);
    saveButton.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent e) {
    int returnVal = fc.showSaveDialog(FileChooserDemo.this);
    if (returnVal == JFileChooser.APPROVE_OPTION) {
    File file = fc.getSelectedFile();
    //this is where a real application would save the file.
    log.append("Saving: " + file.getName() + "." + newline);
    } else {
    log.append("Save command cancelled by user." + newline);
    //For layout purposes, put the buttons in a separate panel
    JPanel buttonPanel = new JPanel();
    buttonPanel.add(openButton);
    buttonPanel.add(saveButton);
    //Explicitly set the focus sequence.
    openButton.setNextFocusableComponent(saveButton);
    saveButton.setNextFocusableComponent(openButton);
    //Add the buttons and the log to the frame
    Container contentPane = getContentPane();
    contentPane.add(buttonPanel, BorderLayout.NORTH);
    contentPane.add(logScrollPane, BorderLayout.CENTER);
    public static void main(String[] args) {
    JFrame frame = new FileChooserDemo();
    frame.addWindowListener(new WindowAdapter() {
    public void windowClosing(WindowEvent e) {
    System.exit(0);
    frame.pack();
    frame.setVisible(true);

    simply use file.getPath()
    That should do it!Thank you !
    It takes care of the problem !!

  • How to get customer number and name from the SD document

    Hi All,
    Can you please let me know how to get Customer Number and Name from the SD Document?
    Thanks a lot....
    Anil

    Hi,
    It will be displayed in the SD (BIlling document) itself,  you clikc on the VF03. The customer name and number will also appear in the SO document also Tcode VA03
    regards,
    radhika
    Edited by: kolipara radhika on Jul 10, 2009 5:32 AM

  • How to get the current schema name

    Hi,
    Can anybody please tell me how to get the current schema name, there is some inbuilt function for this,but i am not getting that. Please help me.
    Thanks
    Jogesh

    ok folks, I found the answer at Tom's as usual.
    http://asktom.oracle.com/tkyte/who_called_me/index.html
    I rewrote it into a function for kicks. just pass the results of DBMS_UTILITY.FORMAT_CALL_STACK to this function and you will get back the owner of the code making the call as well some extra goodies like the name of the code and the type of code depending on the parameter. This ignores the AUTHID CURRENT_USER issues which muddles the schemaid. Quick question, does the average user always have access to DBMS_UTILITY.FORMAT_CALL_STACK or does this get locked down on some systems?
    cheers,
    paul
    create or replace
    FUNCTION SELF_EXAM (
       p_call_stack VARCHAR2,
       p_type VARCHAR2 DEFAULT 'SCHEMA'
    ) RETURN VARCHAR2
    AS
       str_stack   VARCHAR2(4000);
       int_n       PLS_INTEGER;
       str_line    VARCHAR2(255);
       found_stack BOOLEAN DEFAULT FALSE;
       int_cnt     PLS_INTEGER := 0;
       str_caller  VARCHAR2(30);
       str_name    VARCHAR2(30);
       str_owner   VARCHAR2(30);
       str_type    VARCHAR2(30);
    BEGIN
       str_stack := p_call_stack;
       -- Loop through each line of the call stack
       LOOP
         int_n := INSTR( str_stack, chr(10) );
         EXIT WHEN int_cnt = 3 OR int_n IS NULL OR int_n = 0;
         -- get the line
         str_line := SUBSTR( str_stack, 1, int_n - 1 );
         -- remove the line from the stack str
         str_stack := substr( str_stack, int_n + 1 );
         IF NOT found_stack
         THEN
            IF str_line like '%handle%number%name%'
            THEN
               found_stack := TRUE;
            END IF;
         ELSE
            int_cnt := int_cnt + 1;
             -- cnt = 1 is ME
             -- cnt = 2 is MY Caller
             -- cnt = 3 is Their Caller
             IF int_cnt = 1
             THEN
                str_line := SUBSTR( str_line, 22 );
                dbms_output.put_line('->' || str_line);
                IF str_line LIKE 'pr%'
                THEN
                   int_n := LENGTH('procedure ');
                ELSIF str_line LIKE 'fun%'
                THEN
                   int_n := LENGTH('function ');
                ELSIF str_line LIKE 'package body%'
                THEN
                   int_n := LENGTH('package body ');
                ELSIF str_line LIKE 'pack%'
                THEN
                   int_n := LENGTH('package ');
                ELSIF str_line LIKE 'anonymous%'
                THEN
                   int_n := LENGTH('anonymous block ');
                ELSE
                   int_n := null;
                END IF;
                IF int_n IS NOT NULL
                THEN
                   str_type := LTRIM(RTRIM(UPPER(SUBSTR( str_line, 1, int_n - 1 ))));
                 ELSE
                   str_type := 'TRIGGER';
                 END IF;
                 str_line  := SUBSTR( str_line, NVL(int_n,1) );
                 int_n     := INSTR( str_line, '.' );
                 str_owner := LTRIM(RTRIM(SUBSTR( str_line, 1, int_n - 1 )));
                 str_name  := LTRIM(RTRIM(SUBSTR( str_line, int_n + 1 )));
              END IF;
           END IF;
       END LOOP;
       IF UPPER(p_type) = 'NAME'
       THEN
          RETURN str_name;
       ELSIF UPPER(p_type) = 'SCHEMA.NAME'
       OR    UPPER(p_type) = 'OWNER.NAME'
       THEN
          RETURN str_owner || '.' || str_name;
       ELSIF UPPER(p_type) = 'TYPE'
       THEN
          RETURN str_type;
       ELSE
          RETURN str_owner;
       END IF;
    END SELF_EXAM;

  • How to get the report server name in Forms 10g.

    How to get the report server name in Forms 10g.
    I'm using the Application Server 10g 10.1.2.

    Hello,
    I do not think that you can get this value from anywhere. A solution is to put the Reports server name in an environment variable stored in the /forms/server/default.env file, then to query it at Forms runtime with the TOOL_ENV.Getvar() built-in.
    Francois

  • How to retrieve the all user name from system domain(including login user)?

    Hi, I am trying to get the system domain all users name. But I unable to get the all user name except domain login user name. I used the below code. What I want to do to get the all user name from system domain. Kindly any one help me.
    Properties envVars = new Properties();
    Runtime r = Runtime.getRuntime();
    String OS = System.getProperty("os.name").toLowerCase();
         if ((OS.indexOf("nt") > -1) || (OS.indexOf("windows 2000") > -1 ) || (OS.indexOf("windows xp") > -1) )
              p = r.exec( "cmd.exe /c set" );
         BufferedReader br = new BufferedReader ( new InputStreamReader( p.getInputStream() ) );
         String line;
         while( (line = br.readLine()) != null )
              int idx = line.indexOf( '=' );
              String key = line.substring( 0, idx );
              String value = line.substring( idx+1 );
              envVars.setProperty( key, value );
         String domainDNSName = envVars.getProperty("USERDNSDOMAIN");
         String userName = envVars.getProperty("USERNAME");
         System.out.println("\n\n\n DOMAIN NAME == "+domainDNSName +" USERNAME == "+userName);
    Thanks & Regards
    Palani

    Thanks kajbj,
    I don't know, How many users in domain. I neet to get all the user names from my domain. User like A, B,C,D, E,F. I need to get this users name.
    public class Env {
         public static void main(String[] args) {
              System.out.println("USERDOMAIN: " + System.getenv("USERDOMAIN"));
              System.out.println("USERNAME: " + System.getenv("USERNAME"));
    Here , I am getting the login user name only. So i needs all user name. How to retrive or get this.
    Regards
    Palani

Maybe you are looking for

  • SSO password push to another database

    We are about to enforce password expiration times at our company, which as of now we do not use. Currently, when a user chooses to change their password, we have modified the link to point ot a procedure which first updates the SSO password using cal

  • How many screws are supposed to be install in a G4 Quicksilver 1GHz DP CPU?

    Hi. I got a new (used, lol) Quicksilver 1GHz DP which is having problems "using" the first RAM bank (DIMM 0/J21 - closest to the processor). When I first got the machine (in the mail, well protected), I did a quick internal inspection, making sure th

  • How to execute several ROUNDS in a single transformation file?

    Hi everybody, I've put several transformation files into one transformation file but I have the following problems: - when I look at the log after validating the transformation file, it only shows values for the last combination of OPTIONS / MAPPING

  • IChat AV progress but no cigar

    I've been trying to troubleshoot the problem with iChat AV video chat for about 2 months. With the help of many posters to this forum I've made some progress and would like to share that information in the hope that someone may have additional insigh

  • DAQmx Error 88709

    I'm running TestStand in conjunction with LabVIEW on a PXI/SCXI system.  I experience DAQmx Error 88709 only when running my TestStand sequence file the first time after all equipment has been powered down.  For all subsequent executions of the TestS