How to get value from list of string

Question

Hi All,
I have list of values (11,16,18) I need to get 16 i.e mid value . This string can go long .. How Will I do this . Is ther any function in Oracle 10g which supports this .
Any assistance will help
Thanks in advance .
Sachin

Answer 1

Or...
SQL> ed
Wrote file afiedt.buf
  1  With T
  2   AS
  3   (SELECT '11,16,18,50,60,70' str FROM DUAL UNION ALL
  4    SELECT '11,16,18,50,60,70,90,40,30' str FROM DUAL UNION ALL
  5    SELECT '11,16,18' str FROM DUAL
  6    )
  7  --
  8  select regexp_substr(str, '[^,]+', 1, lvl)
  9  from t, (select level lvl from dual connect by rownum <= (select max(length(regexp_replace(str,'[^,]')))+1 from t))
10  where regexp_substr(str, '[^,]+', 1, lvl) is not null
11* order by t.str, lvl
SQL> /
REGEXP_SUBSTR(STR,'[^,]+',
11
16
18
11
16
18
50
60
70
11
16
18
50
60
70
90
40
30
18 rows selected.
SQL>(assumes there are no empty values in the strings)