How to go to the link ip:port/forms90/f90servlet directly

Hi everybody,
I am using oracle Forms and reports Server. What I want is to open my application (http://<ip>:<http listner port>/forms90/f90servlet?config=mytest) instead of the default page when one types the URL: http://<ip>:<http listner port> in browser.
I come to know that the default html page that gets downloaded is index.html. If I edit the body of the index.html and redirect it to my application, it shows my appliction. But it is extremely slow.
If anybody has any ideas related to this issue, then please help.
Thanking u in advance.

Different solutions:
1. Change index.html (different versions under $OH/Apache/Apache/httdoc)
2. Add a rewrite rule in httpd.conf
3. Add an alias in httpd.conf
Regards,
Martin

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How to go to the link ip:port/forms90/f90servlet directly

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