How to insert new line in a text file

hi all,
i wnat to know how can i insert a new line in a text file using java.
for example i want the formate of the text like this
1 2 3
4 5 6
until now i know only how to insert data but not new line.
Thanks in advandce

Hi you can put a new line in a text file using System.getProperty("line.separator"). This implementation will work for every OS.
import java.io.*;
class Demo{
public static void main(String args[]) throws Exception {
FileWriter fr = new FileWriter("FileDemo.txt");
     fr.write("AAAAAAAAAA");
fr.write(System.getProperty("line.separator"));
fr.write("AAAAAAAAAAA");
fr.close();
}

Similar Messages

  • CLIENT_TEXT_IO : cannot insert new line into a text file

    Facts:
    Developer 10g
    AS 10g
    Web utility
    Problem:
    i am traying to
    Open a text file. using CLIENT_TEXT_IO.FOPEN
    insert a record in to a text file using CLIENT_TEXT_IO.PUTF
    insert a new line using chr(10) or CLIENT_TEXT_IO.NEW_LINE
    or CLIENT_TEXT_IO.put_line
    insert the next record
    Close the file.
    all work except insert a new line
    Why !!!
    it was Working fine in 6i, but now in 10g and Webutil is not working
    plz help

    Hi you can put a new line in a text file using System.getProperty("line.separator"). This implementation will work for every OS.
    import java.io.*;
    class Demo{
    public static void main(String args[]) throws Exception {
    FileWriter fr = new FileWriter("FileDemo.txt");
         fr.write("AAAAAAAAAA");
    fr.write(System.getProperty("line.separator"));
    fr.write("AAAAAAAAAAA");
    fr.close();
    }

  • Inserting new line to a text file at position #

    Hi,.
    Is it possible to do this in java?
    1. Open a new text File (woutFile)
    2. woutFile.write(" line #1\r\n"); // write new line
    3. woutFile.write(" line #2\r\n"); // write new line
    4.woutFile.write(" line #3\r\n"); // write new line
    5. Go to line #2 position on a text file
    6. Insert NEW LINE between line #2 and Line #3
    7. move to the end-of-file
    8.Close the file
    Please help

    Is it possible to do this? please look at question
    inside comments.Your question has already been answered. Beyond that,
    if you have some code and you want to know if it will
    work, then run it and see.The answer was no. It's one of the fundamental properties of files that you cannot insert content in the middle, just at the end. To insert content you first have to make room for it. In this respect a file works like an array and not like a linked list.

  • How to insert new line break in XSLT mapping

    Hi experts,
    I am doing file to mail scenario, i am sending the text file as an attachment using reciever mail adapter.
    I did everything, i can able to send the mail with text file attachment, but with in the file i got multiple rows, i need to put line break in XSLT mapping.
    I did use following statement but it is inserting small rectangle between the records, the records are not separating with new lines, all are in one line.
    <xsl:text>*#xA;</xsl:text>   
    note: in real coding replace * with &
    Can anyone suggest me how to insert new line in XSLT mapping.
    My XSLT mapping as look like:
    <?xml version='1.0'?>
    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:ns0="http://www.Coj.co.za/SapIsuToABSA/DirectDebitFile">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
    <xsl:variable name="break">&lt;br/&gt;</xsl:variable>
    <xsl:variable name="space"> </xsl:variable>
    <xsl:variable name="newline"><xsl:text></xsl:text></xsl:variable>
    <xsl:template match="/">
    <ns1:Mail xmlns:ns1="http://sap.com/xi/XI/Mail/30">
    <Subject>Please Check Attached Direct Debit File</Subject>
    <From>S@za</From>
    <To>P@za</To>
    <Content_Type>text/plain</Content_Type>
    <Content>
    <xsl:for-each select="MT_SapIsuToABSA_DirectDebitFile/DirectDebitRec/Body">
    <xsl:value-of select="Space1"/>
    <xsl:value-of select="Cust_AccNo"/>
    <xsl:value-of select="Reserve_1"/>
    <xsl:value-of select="Cust_Name"/>
    <xsl:value-of select="Cust_Name1"/>
    <xsl:value-of select="Cust_Bank_AccNo"/>
    <xsl:value-of select="Space2"/>
    <xsl:value-of select="Cust_Bank_BranchNo"/>
    <xsl:value-of select="Reserve_2"/>
    <xsl:value-of select="Space3"/>
    <xsl:value-of select="Cust_AccNo_1"/>
    <xsl:value-of select="Space4"/>
    <xsl:value-of select="Reserve_3"/>
    <xsl:value-of select="Deduction_Amnt"/>
    <xsl:value-of select="Space5"/>
    <xsl:value-of select="Reserve_4"/>
    <xsl:value-of select="Space6"/>
    <xsl:value-of select="Action_Date"/>
    <xsl:value-of select="Space7"/>
    <xsl:value-of select="Reserve_5"/>
    <xsl:text>*#xA;</xsl:text>   
    note: in real coding replace * with &
    </xsl:for-each>
    </Content>
      </ns1:Mail>
      </xsl:template>
      </xsl:stylesheet>
    Kind regards,
    Praveen

    Hi,
    I think <xsl:text>#xa;</xsl:text> should do the trick, but depending on which OS (ux or win), the "new line" chars sequence is different (win would require a CRLF like <xsl:text>#xd;*#xa;</xsl:text>)
    Chris
    -> &
    Edited by: Christophe PFERTZEL on Apr 14, 2010 2:16 PM

  • How to insert new line in the copied schema with transaction code PE01?

    Dear Experts,
             I have copied HKT0 to ZKT0 , i want to insert new line between  line 150 and line 160 in ZKT0, I don't know how to insert new line 160, who can tell me ?
             Looking forward to your reply.
    Best Regards,
    Merry

    Hi,
    1. Open your schema,
    2. In first colume "Line" select line where you want to add new line,
    3. Replace first value in the column field (that indicates number of line) with character I (means insert),
    4. Press enter
    The line will be added. The same way you can add lines to PCR.
    To delete use character D.
    Cheers

  • How to insert new line character?

    Hi all,
    I have two lines to print.
    out.println("Available number of columns="+cols);
    out.println("Number of columns must be present=10");My problem is:
    i want both the lines to be printed one below the other. But, it is displayed in one single line.....
    Can anyone please tell me how to insert new line character?
    I tried with \n, '\n' and \r\n but, in vain......
    Thanks for your time.
    Regards,
    Ashvini

    You should never use "\n" directly.
    The line separator character is different on different operating systems.
    And putting quotes around it in your string will make absolutely no difference in the JSP.
    To find out what the line separator is you should use System.getProperty("line.separator");
    The JSPWriter and PrintWriter classes will automatically use this property with a println statement, so a println will always finish with a line separator.
    The issue here was that HTML by default ignores all whitespace.
    The solutions provided
    - use a <br> tag instead of a carriage return
    - use <pre> tags, which tells the browser not to ignore whitespace. That can be troublesome in JSP which generates a lot of extraneous carriage returns into the code.
    Cheers,
    evnafets

  • How to insert new line char while writing bytes into file

    Hello Sir,
    Is it possible to insert the new line character in set of String variables and stored them into bytearray ,then finally write into File?
    This is the sample code which i tried:
                 File f = new File(messagesDir,"msg" + msgnum + ".txt");
                 FileOutputStream fout = new FileOutputStream(f);
                    String fromString = "From:    "+msg.getFrom()+"\n";
                    String toString = "To:     "+msg.getTo()+"\n";
                    String dateString = "Sent:    "+msg.getDate()+"\n";
                      String msgString =msg.getBody()+"\n";
                    String finalString=fromString+toString+dateString+msgString;
                    byte[] msgBytes = finalString.getBytes();
                    fout.write(msgBytes);
                 fout.close();in the above code , i tried to add the new line as "\n" in end of each string. but when i look into the generated files msg1.txt , it contains some junk char [] .
    please provide me the help
    regards
    venki

    but it has still shown the the junk char, its not able
    to create the new line in the created file i am afraid
    how am i going to get the solution?:(Do not be afraid dear sir. You are obviously using a windows operating system or a mac operating system. On windows a newline is "\r\n" not '\n', and on a mac a newline is '\r', not '\n'. If you make that correction, dear sir, your program will work.
    However, there is a better way. First, you probably want to buffer your output if you are going to write more than one time to the file, which will make writing to the file more efficient. In addition, when you buffer your output, you can use the newLine() method of the BufferedWriter object to insert a newline. The newline will be appropriate for the operating system that the program is running on. Here is an example:
    File f = new File("C:/TestData/atest.txt");
    BufferedWriter out = new BufferedWriter(new FileWriter(f) );
    String fromString = "From: Jane";
    out.write(fromString);
    //Not written to the file until enough data accumulates.
    //The data is stored in a buffer until then.
    out.newLine();
    String toString = "To: Dick";
    out.write(toString);
    out.newLine();
    String dateString = "Sent: October 27, 2006";
    out.write(dateString);
    out.newLine();
    out.close(); 
    //Causes any unwritten data to be flushed from
    //the buffer and written to the file.

  • How to read every line from a text file???

    How can i read every line from my text file ("eka.txt")
    now it only reads the first line and prints it out.
    What is wrong with this?
    import java.io.*;
    import java.util.*;
    class Testi{
         public static void main(String []args)throws IOException {
         BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in));
    File inputFile = new File ("eka.txt");
    FileReader fis =new FileReader(inputFile);
    BufferedReader bis = new BufferedReader(fis);
    String test=bis.readLine();
    String tmp= "";
    while((bis.readLine().trim() != null)) {
    int spacefound=0;
    int l=test.indexOf(" ");
         for(int i=0;i<test.length();i++){
         char c=test.charAt(i);
         if(c!=' ') tmp+=""+c;
         if(c==' ' && (spacefound<1) && !(tmp.equals(""))){
         tmp+=""+c;
         spacefound++;
         if(tmp.length()==l) {
         System.out.println(tmp);
         tmp="";
         spacefound=0;
         if(tmp.length()<l){
         for(int i=0;i<=(l-tmp.length());i++)
         tmp+=""+' ';
         System.out.println(tmp);

    Try this code, Hope it servers your purpose.
    import java.io.*;
    import java.util.*;
    class Testi {
         public static void main(String []args)throws IOException {
              BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in));
              File inputFile = new File ("Eka.txt");
              FileReader fis =new FileReader(inputFile);
              BufferedReader bis = new BufferedReader(fis);
              String test=bis.readLine();
              while(test != null) {
                   StringTokenizer st = new StringTokenizer(test," ");
                   while(st.hasMoreTokens())
                        System.out.println(st.nextToken());
                   test = bis.readLine();
    }Sudha

  • How to read some lines from a text file using java.

    hi,
    i m new to java and i want to read some lines from a text file based on some string occurrence in the file. This file to be read in steps.
    we only want to read the file upto the first Occurrence of "TEXT" string.
    How to do it ,,,
    Kinldy give the code
    Regards,
    Sagar
    this is the text file
    dfgjdjj
    sfjhjkd
    ghjkdg
    hjkdgh TEXT
    ikeyt
    ujt
    jk
    tyk TEXT
    rukl
    r

    Hendawy wrote:
    Since the word "TEXT" is formed of 4 letters, you would read the text file 4 bytes by four bytes. Wrong on two counts. First, the file may not be encoded 1 byte per character. It could be utf-16 in which case it would be two byte per character. Second, even if it were 1 byte per character, the string "Text" may not start on a 4 byte boundary.
    Consider a FileInputStream object "fis" that points to your text file. use fis.read(byte[] array, int offset, int len) to read every four bytes. Convert the "TEXT" String into a byte array "TEXT".getBytes(), and yous the Arrays class to compare the equality of the read bytes with your "TEXT".getBytes()Wrong since it relies on my second point and will fail when fis.read(byte[] array, int offset, int len) does not read 4 bytes (as is no guaranteed to). Check the Javadoc. Also, the file may not be encoded with the default character encoding.
    The problem is easily solved by reading a line at a time using a BufferedReader wrapping an InputStreamReader wrapping a FileInputStream and specifying the correct character encoding.
    Edited by: sabre150 on Apr 29, 2009 2:13 PM

  • Want to know how to check for new line character in text file

    Hi All,
    I`m trying to read data from text file. However I`m not sure whether the data is in 1st line or nth line. Now I`m trying to read the text from the readline. But if text is "" and not NULL then my code fails. So I want to know how to check for new line character and go to next line to find the data. Please help.
    Thanks
    static int readandwriteFile(Logger logger,String filepath){
              BufferedWriter out = null;
              BufferedReader in = null;
              File fr = null;
              int get_count = 0;
              try     {
              if(new File(filepath).exists())
              fr= new File(filepath);
                        System.out.println("FileName: "+fr);
                   if(fr != null){
    in = new BufferedReader(new FileReader(fr));
                             String text = in.readLine();
                             if(text != null){
                             get_count = Integer.parseInt(text);
                             in.close();
                             else{
                                  get_count = 0;
         else{                    
    out = new BufferedWriter(new FileWriter(filepath));
         out.write("0");
                out.close();
                   }          //Reading of the row count file ended.
              catch(Exception e) {
                   e.printStackTrace();
              finally {
                   try{               if (in != null) {
                             in.close();
              if (out != null) {
                             out.close();
              catch(Exception e) {
                        e.printStackTrace();
              return get_count;
         }

    You are calling the readline() only once which means you are reading only the first line from the file...
    Use a loop (Do-While preferably)
    do{
    //your code
    }while(text == "")

  • af:validateLongRange displaying message: How to insert 'new line' ?

    Hello,
    While using <af:validateLongRange> tag we need to display message in a well formatted way, we have to display each statement in a new line.For eg. : message as displayed by property 'messageDetailNotInRange' must come in three different new lines not as a continuous statement.I tried inserting '\n' escape sequence for new line, but it dint work.I tried spacing the statements but that also is not working out.
    Any idea how can we get this message displayed separately in three rows rather than in a continuous statement ?
    ++messageDetailNotInRange="You have entered a value more than is available. Value entered must be in the range of {2} to {3}.To delete this line, clear the value and click Delete"++
    +<af:validateLongRange id="xyz_VC1" minimum="1"+
    maximum="100"
    messageDetailNotInRange="You have entered a value more than is available. Value entered must be in the range of {2} to {3}.To delete this line, clear the value and click Delete"
    messageDetailMinimum="Minimum {0} allowed is {2}"
    messageDetailMaximum="Maximum {0} allowed is {2}"
    hintNotInRange="#{'xyz'}"/>

    Thx..Done that!! but dint get the desired result ,I put it as :-
    messageDetailNotInRange="You have entered a value more than is available.&lt;br&gt; Quantity entered must be in the range of {2} to {3}.&lt;br&gt; To delete this order line, clear the quantity and click DELETE."
    On corresponding page this message was displayed as :
    You have entered a value more than is available.<br> Quantity entered must be in the range of 1 to 100.<br> To delete this order line, clear the quantity and click DELETE.
    It dint insert line breaks in the message.Do i need to write it differently?
    Above html code is modified once i posted it, it has inserted line breaks here for the br tag i added , but in my actual .jsff page it did not . I can only see br tag displayed as part of message and no new line got inserted.
    I dont see an option to attach a file with the post so that I can show the code to you.
    Edited by: user13439821 on Aug 15, 2011 2:58 PM

  • ADF: how to insert new line character in column of VO?

    Hi Everyone,
    Im using Jdev 11G.
    i have a VO with 5 columns displayed on the ADF page.(VO has total 8 columns)
    1 column is the combination of 3 columns. i concatenated the 3 columns and added new line character after each column chr(13).
    VO query is working very fine in Toad. the columnn displays each concatenated column value after a new line character but the same query is not working in ADF.
    The column which is concatenating 3 columns and has to display with new line character is not displaying new line character its just concatenating the 3 values and displaying it on the page.
    wat can be the solution for this in ADF?
    Thank you.

    Setting escape="false" will allow putting html <BR> in the column and it will display ok however if your table allows export to excel the <BR> gets exported and displays as text in your exported file. Also & will export as &amp; To prevent that, use your original text without the escape=false setting and insert LF or CR (10 or 13 character), then add inline style of white-space: pre-line; to column or to style class in your skin. That will cause all line feeds to wrap but will export to excel without mixing html in the export.
    http://www.w3schools.com/cssref/pr_text_white-space.asp
    Edited by: Don Kleppinger on Jan 14, 2013 4:06 PM

  • How to insert new line in textarea

    I try programatiaclly to add for example three strings in <textarea>
    the final result should be something like this:
    --TEXTAREA TAG BEGIN
    line1
    line2
    line3
    --TEXTAREA TAG END
    I tried the hack described here;
    http://www.mail-archive.com/[email protected]/msg08294.html
    <c:set var="temp" value="one
    two"/>
    <c:set var="newline" value="${fn:substring(temp,4,5)}"/>after that I used it like this:
    <textarea>
      // forEach begin (write some output)
        <c:out value="${newline}"></c:out> //try to add new line
      // forEach end
    </textarea>Sorry about the wrong comment style, I'm just pointing out whta I expect as a result.
    I was surprised when I found out that "newline" value is "t" instead of special character "\n" or "\r". Anyway, I didn't receive the desired result.
    I use XML JSP files and UTF-8.
    Can anyone help me?

    I think I remember using a pre tag in between.
    <pre>
    // ur text area tags here.
    </pre>

  • Writing to a new line in a text files

    I have a servlet that collects results from a questionnaire by getting the parameter values of the radio buttons on a questionnaire page. I am trying to store the results of the questionnaire by writing them to a text file. I can get it to write to the files fine but cannot seem to get it to write the next set of results to a new line. I have many different ways but cannot seem to get it to work. Any ideas?
    Heres the part of the code that writes to a text file
    String lineRead = "";
                int lineCount = 0;
                while((lineRead = input.readLine()) != null)
                    lineCount ++;
                    String result = request.getParameter("question" + lineCount);
                    output.write(result + ",");       
                    output.write("\n");

    Heres the part of the code that writes to a text
    file
    String lineRead = "";
    int lineCount = 0;
    while((lineRead = input.readLine()) !=
    adLine()) != null)
    lineCount ++;
    String result =
    String result = request.getParameter("question" +
    lineCount);
    output.write(result + ",");       
    output.write("\n");
    Can you do output.writeln(result + ",");?
    Failing that, putting output.write("\n") inside the while loop should do the trick.

  • How to write new line character to a file from textarea

    Hi ,
    I want to save the contents of textarea in a file.The textarea may contain new line characters,
    I am getting the contents from the textarea using getText() method but after writing the contents to the file
    it stores the entire text in a single line.But I want the text as it apperars in the textarea.
    Please provide me a good solution.
    -mani

    maybe this code samples are useful to your problem
    File datatext = new File(fileName);
    try {BufferedWriter writer =new BufferedWriter(new OutputStreamWriter(new FileOutputStream(datatext)));
    writer.write(.......);
    writer.newLine();
    writer.close();                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

Maybe you are looking for

  • Can XML files be used for data?

    We have an XML file that contains all of the data we want to use for a model.  Is there any way that this can be used instead of a database query?

  • How to design data load process chain?

    Hello, I am designing data load process chains for the first time and would like to get some general information on best practicies in that area. My situation is as follows: I have 3 source systems (R3 and two for which I use flat files). How do you

  • PO number getting generated but PO doesnt get save in the system

    Hi, System creating a PO number, and soon after a terminate message comes and no PO found in the system. What will be the reason, can any one please help? Regards, Sattuj

  • 709/709 Source Settings and Export

    I'm working with Sony RAW Lite 4k footage in Premiere, and I keep getting the default 709 LUT applied in my sequence causing unusable blown out looking footage. If I right click the clip and select Source Settings, I can select S-Log in the drop down

  • Error in syncing iPhone 5

    Getting an error message when i am trying to sync my Iphone 5 with mac?