How to insert varchar2 40000 englist char to database.

How to insert varchar2 40000 englist char to database use jdbc.
My table is ut(varchar2(4000));]
oracle version is 9.0

Are you using the thin driver or the OCI driver? The Oracle Globalization Guide documents that the thin driver imposes more restrictive size limitations on character data than the Oracle database http://download-west.oracle.com/docs/cd/B10501_01/server.920/a96529/ch9.htm#14068 You would need to ensure that you're using the OCI driver to work around these restrictions.
Justin
Distributed Database Consulting, Inc.
http://www.ddbcinc.com/askDDBC

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How to insert an image file in Oracle database

hi
can you please tell me how to insert an image file into oracle database????
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will be waiting for your reply........
thanks & regards,
Priyatosh

Hello,
The easiest way to load a blob is to use SQL loader.
This example comes from the utilities guide:
LOAD DATA
INFILE 'sample.dat'
INTO TABLE person_table
FIELDS TERMINATED BY ','
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1 ext_fname FILLER CHAR(40),
2 "RESUME" LOBFILE(ext_fname) TERMINATED BY EOF)
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hi all
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Hi I don't have time to explain really, I did have to do this a while ago though so I will post a code snippet. This is using the commons file upload framework.
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Hi all,
Hope doing well,
sir i am using one stored procedure and storing time in varchar2 variable in this format: 08:00:00
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thanks

952646 wrote:
Hi all,
Hope doing well,
sir i am using one stored procedure and storing time in varchar2 variable A "Very Bad Idea"(tm)
When you do this, there is no fundamental difference between "08:00:00" and "here's your sign".
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thanks

How To Insert List of Record To the Database Using Linq

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gives the Numbers below...
6131
5241
3978
6824
3842//To Save to the database
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2 5241
3 3978
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Hello,
>>Now i want to insert those Numbers to the database
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Regards.
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Hi,
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Hi,
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when i execute the following query,
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I do not understand as to why you are using the to_date function on sysdate since sysdate is already in date format.
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i did one program similar to this requirement. when the rows and columns are fixed then what is the problem.
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Hi ,
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Poornima

If you can write the text in Notepad, then enter the text and save the file with the encoding "Unicode big endian". Then, open the file in a hex editor. The first two bytes will be 0xFE and 0xFF (this is the Byte Order Mark). This code should be skipped for database storage as it is relevant to flat files only. What follows are two-byte character codes that you can put into UNISTR calls. The file with the word "Patra" will show up in the hex editor as:
FE FF 09 2a 09 24 09 4d 09 30
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-- Sergiusz

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I looking for some help SHUTTLE. The scenario is given below. Appreciate your urgent help/steps how to use UIX SHUTTLE for this example.
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User
====
Fields=>(uid,uname)
Dept
====
Fields=>(deptno,uid)
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Hi, there,
I want to insert date information to oracle database in a jsp page using JSTL. but always got wrong message:
javax.servlet.jsp.JspException:
INSERT INTO DATE_TEST
(date_default,date_short,date_medium)
values(?,?,?)
: Invalid column type
I don't know how to convert java date type to oracle date type or vice versa. the following is the source code(all the fields of DATE_DEFAULT,DATE_SHORT,DATE_MEDIUM are oracle date type. and even I want to insert d instead d1, I got the same wrong message)
<%@ page contentType="text/html;charset=windows-1252"%>
<%@ page import="java.util.*" %>
<%@ taglib prefix="c" uri="http://java.sun.com/jstl/core" %>
<%@ taglib prefix="sql" uri="http://java.sun.com/jstl/sql" %>
<%@ taglib prefix="fmt" uri="http://java.sun.com/jstl/fmt" %>
<%
Calendar now;
Calendar rightNow = Calendar.getInstance();
%>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
<title>
Hello World
</title>
</head>
<body>
<h2>
The current time is:
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<p>
<%= new java.util.Date() %></p>
<%
java.util.Date d=new java.util.Date();
java.sql.Date d1=new java.sql.Date(d.getYear(),d.getMonth(),d.getDate());
out.print(d1.toString());
%>
<sql:update>
INSERT INTO DATE_TEST
(DATE_DEFAULT,DATE_SHORT,DATE_MEDIUM)
VALUES(?,?,?)
<sql:dateParam value="${d}" type="date" />
<sql:dateParam value="${d}" type="date" />
<sql:dateParam value="${d}" type="date" />
</sql:update>
</body>
</html>
thank you very much for the great help!!

I don't have time to read thru all your code, but I hope this information will help you.
It depends on how the Oracle database was set up. Usually, the date format is something like this: '27-MAY-2003 22:10:00'. A quick check will be to run this SQL script in SQLPlus:
select sysdate from dual;
You have to convert the date from textbox or whatever to this exact Oracle format. Otherwise, Oracle will not accept it. It is very picky on that. I found the best way is to do the conversion inside the SQL statement. It makes life so much easier.
Hope this helps.

How to Insert a record into a MySql database.

Hi,
In an earlier question I was advised to use the Adobe extension to get access to database connectivity and server behaviours.
That extension is now installed. Whether it is functional is another question.
To chewck it out I follwed exactly the steps set out in Lessons 5 and 6 of Dreamweaver CS5 with PHP
When trying to make a database connection I am still getting the 404 error I mentioned in an earlier email. However if I type the database name (phpcs5) into the “select database” box and test it says I connected successfully and I can see the user’s table in the database panel.
So far apparently so good.
I have created the cs5wtite and cs5read connections to the phpcs5 database
I set up the insert record behaviour using “Form1!, “cs5write”, “users”,
Everything went as per the manual, the file turned aqua in Live view.
I entered data and ctrl/clicked “Sign me up” button and nothing happened.
No data was entered into the database and I was not passed to login.php.
I deleted everything from the computer, restarted the pc and started again from scratch.
The result was the same. Nothing
My one concern was line 49 $insertGoTo = " login.php";
The file is in registration so I changed to $insertGoTo = "registration/login.php";
but that made no difference.
Is there any logging or error reporting I can use to see where it is going wrong?
This is the add user page generated
<?php require_once('../Connections/cs5write.php'); ?>
<?php
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
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$theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);
switch ($theType) {
    case "text":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;
    case "long":
    case "int":
      $theValue = ($theValue != "") ? intval($theValue) : "NULL";
      break;
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      $theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
      break;
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      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
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return $theValue;
$editFormAction = $_SERVER['PHP_SELF'];
if (isset($_SERVER['QUERY_STRING'])) {
$editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']);
if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) {
$insertSQL = sprintf("INSERT INTO users (first_name, family_name, username, password) VALUES (%s, %s, %s, %s)",
                       GetSQLValueString($_POST['first_name'], "text"),
                       GetSQLValueString($_POST['surname'], "text"),
                       GetSQLValueString($_POST['username'], "text"),
                       GetSQLValueString($_POST['password'], "text"));
mysql_select_db($database_cs5write, $cs5write);
$Result1 = mysql_query($insertSQL, $cs5write) or die(mysql_error());
$insertGoTo = "login.php";
if (isset($_SERVER['QUERY_STRING'])) {
    $insertGoTo .= (strpos($insertGoTo, '?')) ? "&" : "?";
    $insertGoTo .= $_SERVER['QUERY_STRING'];
header(sprintf("Location: %s", $insertGoTo));
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Add new user</title>
<link href="../../styles/users.css" rel="stylesheet" type="text/css" />
</head>
<body>
<h1>Sign Up Now</h1>
<form id="form1" name="form1" method="POST" action="<?php echo $editFormAction; ?>">
<fieldset>
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    <p>
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      <input type="text" name="first_name" id="first_name" />
    </p>
    <p>
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    </p>
    <p>
      <label for="username">Username:</label>
      <input type="text" name="username" id="username" />
    </p>
    <p>
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      <input type="password" name="password" id="password" />
    </p>
    <p>
      <label for="conf_password">Confirm password:</label>
      <input type="password" name="conf_password" id="conf_password" />
    </p>
    <p>
      <input type="submit" name="add_user" id="add_user" value="Sign me up!" />
    </p>
</fieldset>
<input type="hidden" name="MM_insert" value="form1" />
</form>
</body>
</html>
This is the connection page
<?php
# FileName="Connection_php_mysql.htm"
# Type="MYSQL"
# HTTP="true"
$hostname_cs5write = "localhost";
$database_cs5write = "phpcs5";
$username_cs5write = "cs5write";
$password_cs5write = "Smp??2014";
$cs5write = mysql_pconnect($hostname_cs5write, $username_cs5write, $password_cs5write) or trigger_error(mysql_error(),E_USER_ERROR);
?>
I understand this solution is a wokraround Adobe privided whist deprecating its use.
In the earlier question I asked if there was another way to work with a database. Someone posted a link to an Object orientated solution but It was way beyond my coding abilities. I wonder are there any other solutions out there?
Thanks for any input

Hi,
Thanks for the test.
I used your amendment but still got nothing, no record in database and not sent to login page..
I also tried this code below. It returns "Record added to database" but it was not.
Something strange going on.
<?PHP
$user_name = "cs5write";
$password = "Smp??2014";
$database = "phpcs5";
$server = "127.0.0.1";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
$SQL = "INSERT INTO users (first_name, surame, username, password) VALUES) VALUES ('Albert', 'Dent', 'hitchiker', 'space')";
$result = mysql_query($SQL);
mysql_close($db_handle);
print "Records added to the database";
else {
print "Database NOT Found ";
mysql_close($db_handle);
?>

How to insert a java object int derby database

hi,
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Thanks

Or you would design a table where the columns of the table correspond to attributes of the object. Then you would make a row by writing out the attributes to the columns they correspond to.

How to insert message style text columns in database tables

Hi All,
i have two pages.
in first page segment1 lov is their.once u select the segment1 and click on the create button its navigate to next page.
and display the releted segment1 details(these columns are message text input fields but read only columns).
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its very urgent
Thanks
Latha.

Hi Anil,
plz help me still i am faceing the problem
so plz help me because i dont know java.
i wrote below code and i got the below error.
if(pageContext.getParameter("Submit")!=null)
String projnumber=pageContext.getParameter("ProjectNO");
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String oldoperationid=pageContext.getParameter("EmployeeNumber");
String newManagerName=pageContext.getParameter("NewManagerName");
String ProjectID=pageContext.getParameter("ProjectID");
String OldOperationName=pageContext.getParameter("OperationsManager");
String OldOperationID=pageContext.getParameter("OldOperationID");
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String projnumber=null;
if(bean!=null)
projnumber = (String)projnumberbean.getValue(pageContext);
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am.invokeMethod("xxinsertpagelogic",params);
and i wrote import also.
import oracle.apps.fnd.framework.webui.beans.message.OAMessageTextInputBean;
my errors are
Error(64,78): incompatible types; found: oracle.apps.fnd.framework.webui.beans.OAWebBean, required: oracle.apps.fnd.framework.webui.beans.message.OAMessageTextInputBean
Error(65,13): duplicate definition of variable projnumber in method processFormRequest(oracle.apps.fnd.framework.webui.OAPageContext, oracle.apps.fnd.framework.webui.beans.OAWebBean)
Error(66,9): variable bean not found in class wnsgs.oracle.apps.pa.projectinfo.webui.ProjectInfoCreateCO
plz help me.
its very urgent
Thanks
Edited by: Latha on Jan 4, 2012 9:57 PM
Edited by: Latha on Jan 4, 2012 10:00 PM

How to insert varchar2 40000 englist char to database.

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