How to know the current VI is aborted ?

i hv three VI A.vi is opening B.vi and it opens C.vi,,,,,,, now at one time only 1 VI is opening at the task bar,,, and even i can go back.
i have made that program,,,,,, but the problem is ,,, while i m starting from A.vi and ,,, go to C.vi via B.VI,.,,, and,, after stoping C.vi,..... if i open A.vi from the folder it is still running(in the running stage),,,, so...........
i want to add the fuctionality,,, in which, i want to find the event..... when my current VI is aborted i want the A.vi to be aborted....
HOW ITS POSSIBLE...
Waiging for reply,,,
Manisha
Attachments:
C.vi ‏20 KB
A.vi ‏19 KB
B.vi ‏27 KB

Maybe you can tell us what you are trying to achieve. I simply cannot make much sense out of your code.
At least try to put a small wait in each loop, right now they all spin millions of times doing nothing. Maybe you could use an event structure? You should also set your buttons to latch when released. Currently, e.g. the "Go back to B" button inside c.vi is set to switch until released, meaning you'll probably run the TRUE case a few thousand times whenever you press the button. Also familiarize yourself with dataflow. You seem to think that you set the boolean flag value before the while loop starts, however LabVIEW does not guarantee that this happens in this order because there is no data dependency.
What are you trying to do? I am sure there are better ways.
LabVIEW Champion . Do more with less code and in less time .

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How to know the current VI is aborted ?

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