How to obtain the current panel name

Hi
Is there a way to get, with a function or something, the name of the current Panel I am on?
Thanks,
Daniel

Hi
Is there a way to get, with a function or something,
the name of the current Panel I am on?
Thanks,
DanielYes there is a way.
A far quicker way of getting an answer to such a basic question is to consult the API documentation at http://java.sun.com/j2se/1.5.0/docs/api/
If you have already looked and couldnt fin the answer then have a look at the methods inherited.

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http://asktom.oracle.com/tkyte/who_called_me/index.html
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create or replace
FUNCTION SELF_EXAM (
   p_call_stack VARCHAR2,
   p_type VARCHAR2 DEFAULT 'SCHEMA'
) RETURN VARCHAR2
AS
   str_stack   VARCHAR2(4000);
   int_n       PLS_INTEGER;
   str_line    VARCHAR2(255);
   found_stack BOOLEAN DEFAULT FALSE;
   int_cnt     PLS_INTEGER := 0;
   str_caller VARCHAR2(30);
   str_name    VARCHAR2(30);
   str_owner   VARCHAR2(30);
   str_type    VARCHAR2(30);
BEGIN
   str_stack := p_call_stack;
   -- Loop through each line of the call stack
   LOOP
     int_n := INSTR( str_stack, chr(10) );
     EXIT WHEN int_cnt = 3 OR int_n IS NULL OR int_n = 0;
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     str_line := SUBSTR( str_stack, 1, int_n - 1 );
     -- remove the line from the stack str
     str_stack := substr( str_stack, int_n + 1 );
     IF NOT found_stack
     THEN
        IF str_line like '%handle%number%name%'
        THEN
           found_stack := TRUE;
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            THEN
               int_n := LENGTH('package ');
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            THEN
               int_n := LENGTH('anonymous block ');
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            THEN
               str_type := LTRIM(RTRIM(UPPER(SUBSTR( str_line, 1, int_n - 1 ))));
             ELSE
               str_type := 'TRIGGER';
             END IF;
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          END IF;
       END IF;
   END LOOP;
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   THEN
      RETURN str_name;
   ELSIF UPPER(p_type) = 'SCHEMA.NAME'
   OR    UPPER(p_type) = 'OWNER.NAME'
   THEN
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Thanx in advance.

j0o wrote:
System.out.println("Class Name: " + new Exception().getStackTrace()[0].getClassName() +
"/n Method Name : " + new Exception().getStackTrace()[0].getMethodName() +
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
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%>
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