How to parse xml file, containing image, generaged from JAX-RS connector?

Hi,
We are using JAX-RS connector and just want to call getBusinessObjects() directly using JerseyMe (basically bypassing sync engine). We have used sync engine so far and want to try as how to bypass it. The method produces the text/xml and verified the xml file in the web by giving the full url. The plan is to call the same URL from the Java Me Client using JerseyMe. When I print the bytes at the client I receive the same xml that I have seen in the web. Actually, I am passing an image that I can see in a different character format in xml (assuming this is bcos of UTF-8 encoding). I am wondering as how to parse this xml file and how to decode the "UTF-8" format? Do we need to use SGMP for this or use kxml or java me webservices spec.
I would really appreciate if somebody can answer this one.
I have been observing in this forum that SGMP team is not at all active in answering the questions. Please let us know whether Oracle is keeping this product and we can continue using SGMP1.1. Please let us know so that we can plan accordingly as we are building a product based on SGMP.

Hi Rajiv,
The client library is using org.apache.commons.codec.binary.Base64 internally. We don't have the full Commons Codec library bundled, but you can look up the javadoc for the Base64 class online. All you need to do is call Base64.decode(obj.getBytes()) on the objects you get out of the XML.
In general it isn't a good idea to depend on implementation details of the client library, but in this case, I think it is pretty safe to expect org.apache.commons.codec.binary.Base64 to remain in our library.
--Ryan

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          <completed></completed>
     </Game>
</Database>I have been trying for ages and just can't get the content handler class to extract a gameID and instantiate a Game to add to my ArrayList! How do I extract the information from my file?
I have tried so many things in the startElement() method that I can't actually remember what I've tried and what I haven't! If you need to know, the Game class instantiates with asnew Game(int gameID)and the rest of the variables are public.
Please help someone...

OK, how's this?
public void startElement(String namespaceURI, String localName, String qualifiedName, Attributes atts) throws SAXException
          current = "";
     public void endElement(String namespaceURI, String localName, String qualifiedName) throws SAXException
          try
               if(qualifiedName.equals("Game") || qualifiedName.equals("Database"))
                    {return;}
               else if(qualifiedName.equals("gameID"))
                    {games.add(new Game(Integer.parseInt(current)));}
               else if(qualifiedName.equals("name"))
                    {games.get(games.size()-1).name = current;}
               else if(qualifiedName.equals("publisher"))
                    {games.get(games.size()-1).publisher = current;}
               etc...
               else
                    {System.out.println("ERROR - Qualified Name found in xml that does not exist as databse field: " + qualifiedName);}
          catch (Exception e) {} //Ignore
     public void characters(char[] ch, int start, int length) throws SAXException
          current += new String(ch, start, length);
     }

How to parse xml string

Hi! I'm having problems parsing an xml string. I've done DOM and SAX parsing before. But both of them either parse a file or data from an input source. I don't think they handle strings. I also don't want to write the string into a file just so I can use DOM or SAX.
I'm looking for something where I could simply do:
Document doc = documentBuilder.parse( myXMLString );
So the heirarchy is automatically established for me. Then I could just do
Element elem = doc.getElement();
String name = elem.getTagName();
These aren't the only methods I would want to use. Again, my main problem is how to parse xml if it is stored in a string, not a file, nor comming from a stream.
thanks!

But both of them either parse a file or data from an input source. I don't think they handle strings.An InputSource can be constructed with a Reader as input. One useful subclass of Reader is StringReader, so you'd use something likeDocument doc = documentBuilder.parse(new InputSource(new StringReader(myXMLString)));

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