How to pass some default values in all elements which are blank in xslt.

Question

Hi,
Help needed:
Scenario:
After .xslt transformation, there are some elements which are being mapped but left blank. I want to assign some default values to it like '0'. How to do that.
Thanks.

Answer 1

One solution would be something like this...
http://remysharp.com/2008/08/15/how-to-default-a-variable-in-xslt/
Or you can use a template like this...
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="node()|@*">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
</xsl:template>
<xsl:template match="Title">
    <xsl:choose>
        <xsl:when test="string-length(normalize-space(.)) = 0">
            <Title>default</Title>
        </xsl:when>
        <xsl:otherwise>
            <xsl:copy-of select="."/>
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>
</xsl:stylesheet>For every empty "Title" node, this template will add <Title>default</Title>... If the Title has value it won't be changed... You can change this to your fields/your defaults... If you need default for other field just add another template in the same transformation...
Cheers,
Vlad