How to reference objects with same name?

Probably another easy one, but again, couldn't find the answer in old discussions...
I have some objects with the same name on my form. Designer has made them unique by making an array out of them...object[0], object[1], object[2] etc. How can I reference the individual objects in javascript? I tried the obvious by referencing them as an array, but to no avail. I suppose it'd be just as easy, if not better, to just have unique names, but in this case, the objects are related and having them in an array would be handy.

You can try like below.
var oObject = xfa.resolveNode("Object[1]");
xfa.host.messageBox("" + oObject.rawValue);
Thanks
Srini

Similar Messages

Topic: How to refer columns with same name in jdbc

I have a join statement :
Select a.col1, a.col2, b.col3, b.col2 from TABLE1 a, TABLE2 b where a.col1 = b.col1
how do I refer with same column name suppose I want to get b.col2
I get error when I try rs.getString("b.col2") or
rs.getString("TABLE2.COL2")..
note I donot want positional retrieval i.e rs.getString(x) , where x is column number.
can you suggest how to refer the b.col2 uniquely.

Select a.col1, a.col2, b.col3, b.col2 from TABLE1 a,
TABLE2 b where a.col1 = b.col1You can use a column alias, like below. They "as" keyword isn't always necessary, depends on your database.
Select
    a.col1 as a_col1,
    a.col2 as a_col2,
    b.col3 as b_col3,
    b.col2 as b_col2
from
    TABLE1 a,
    TABLE2 b
where
    a.col1 = b.col1

How to create directories with same name in different schemas

I have two schemas on the same database.
I am trying to create directories with same name, but different paths in both the schemas.
When i created the directories in second schema, the directory paths of the first schema are automatically changed to the second path.
Is there any solution to create directories with same name, but different path in two different schemas on the same database.
Thanks,
Sridhar.

Hi,
>>When i created the directories in second schema, the directory paths of the first schema are automatically changed to the second path.
If you have removed the REPLACE clause of your create statement, then you would see that is not possible.
SYSTEM> connect scott/tiger
Connected.
SCOTT> create directory mydir as '/tmp';
Directory created.
SCOTT> connect legatti/pwd
Connected.
LEGATTI> create directory mydir as '/tmp';
create directory mydir as '/tmp'
ERROR at line 1:
ORA-00955: name is already used by an existing object
LEGATTI> select owner,object_name,object_type,created
2 from dba_objects where object_name='MYDIR';
OWNER OBJECT_NAME OBJECT_TYPE CREATED
SYS MYDIR DIRECTORY 19/12/2007Cheers
Legatti

How to send File with Same name to Receiver

HI Frnds,
In my peoject i have one scenario,
I have to access Orders is the name of file , available in FTP Server, i have to send same file to Receiver side with same name Orders
Is it possible with same name dynamically??
Regards,
Raj

hi,
You have to go for variable substitution option available in receiver file adapter,but for that you have to get the file name in receiver payload.
http://help.sap.com/saphelp_NW04/helpdata/en/e3/94007075cae04f930cc4c034e411e1/frameset.htm
these links are also helpful
/people/jayakrishnan.nair/blog/2005/06/20/dynamic-file-name-using-xi-30-sp12-part--i
/people/jayakrishnan.nair/blog/2005/06/28/dynamic-file-namexslt-mapping-with-java-enhancement-using-xi-30-sp12-part-ii
/people/sriram.vasudevan3/blog/2005/11/21/effective-xsl-for-multimapping-getting-source-filenames-in-legacy-legacy-scenarios
regards,
ujjwal kumar

Multiple objects with same name when rebuilding index online

I am looking for advice on how to handle a race-condition in sql server, related to reading metadata while an online index rebuild is being performed.
The problem is as follows:
At some point we execute the following statement:
SELECT
obj.object_id AS id,
scm.name AS scm,
obj.name AS name,
obj.type AS type,
ds.name AS dataspace_name,
prop.value AS description,
part.data_compression_desc as compression_desc
FROM sys.objects AS obj
INNER JOIN sys.schemas AS scm ON obj.schema_id = scm.schema_id
INNER JOIN sys.indexes AS idx ON obj.object_id = idx.object_id AND idx.type IN (0,1)
INNER JOIN sys.data_spaces AS ds ON idx.data_space_id = ds.data_space_id
INNER JOIN (SELECT object_id, data_compression_desc FROM sys.partitions WHERE index_id IN (0,1) /*Heap, Clustered*/) AS part ON part.object_id = obj.object_id
LEFT OUTER JOIN sys.extended_properties AS prop ON obj.object_id = prop.major_id AND prop.minor_id = 0 AND prop.class = 1 AND prop.name = 'Description'
WHERE obj.type = 'U' OR obj.type = 'S'";
The statement returns some metadata for indexes (indices?), the purpose of wich is not the subject.
When executed while an online index rebuild is running, a race condition occurs: When the rebuilding enters the final phase, the new index, which have the same name, becomes visible and thus results in two rows with the same name (from sys.object). I am unaware
if this only occurs for clustered index (which is what we have observed).
We became aware of this behaviour, as we added the metadata to a .Net Dictionary using name as key, and received a duplicate key exception. We have, hoewever, not been able to reproduce the situation, due to the nature of the race condition, and we found very
little documentation on the subject.
What we would like to do now, is to differentiate between the two. We see two options:
1) We could just use the first of the rows and ignore the second. This solution would require that the metadata for both rows are identical.
2) We could discern the "real" index from the "rebuilding" index. This requires some kind of extension of the Where-part.
We have not been able to determine if the requirements for either option is present, as we havent found any documentation, nor have we been able to test for differences, as we cannot reproduce the situation.
We would also like some way of reproducing the situation, so ideas as to how to do that is welcome.
Can anyone direct me to relevant documentation, or alternate solutions.
HRP

1. Use the index with the lower fragmentation to identify the newly rebuilt index (as it almost always will have lower fragmentation)
2. To reproduce, block the online index rebuild process by trying to alter the table's definition in a transaction (and don't commit, which will place schema lock on the table)
Satish Kartan http://www.sqlfood.com/

How to import XSD with same name

Hi,
I have a Parent XSD which imports 3 XSD's.
The parents XSD name and one of the imported XSD name is same in the XSD.
Say for Ex: 1.xsd is a parent
which import 2.xsd , 3.xsd & 1.xsd ( from different directory - import path in the XSD is different - <xsd:import namespace="www.localdomain.com/1.xsd" schemaLocation="C:/container/path/1.xsd"/>
where as the parent 1.xsd is in c:/jms/path/1.xsd
So whenever i import into the workshop it is giving me compilation error.
How to fix this ? pls help.
Thanks,
-Raj..

You can try like below.
var oObject = xfa.resolveNode("Object[1]");
xfa.host.messageBox("" + oObject.rawValue);
Thanks
Srini

How to differentiate tags with same name/different attributes using JDOM?

Hello,
If I have the following xml file:
<level1>
<level2 att="a1">first</level2>
<level2 att="a2">second</level2>
<level2 att="a3">third</level2>
</level1>
how do I distinguish them from each other and add another attribute to each element?
<level1>
<level2 att="a1" insert="s1">first</level2>
<level2 att="a2" insert="s2">second</level2>
<level2 att="a3" insert="s3">third</level2>
</level1>
regrads,
Happy New Year!

Document document;
NodeList nodeList=document.getElementsByTagName("level2");
        for(int i=0; i<nodeList.getLength(); i++){
          if(((Element)(nodeList.item(i)).getAttribute("att")).equals("a1"))
            ((Element)(nodeList.item(i))).setAttribute("insert","s1");
          if(((Element)(nodeList.item(i)).getAttribute("att")).equals("a2"))
            ((Element)(nodeList.item(i))).setAttribute("insert","s2");
          if(((Element)(nodeList.item(i)).getAttribute("att")).equals("a3"))
            ((Element)(nodeList.item(i))).setAttribute("insert","s3");

How to create device IDs with same name

i am using SE 3310 and its creating different device ids for each node sharing it . since I will be building a RAC enviornment I need these IDs/name to be same .
for example on one node the lun id is /dev/rdsk/c3t0d0s6 but the same lun id on node 2 is /dev/rdsk/c2t0d0s6.
In past with an old storage array I fixed this issue by creating links in /dev/rdsk for c3t0d0s6 ---> c2t0d0s6.
my question is : is there a way in SE3310 that device ids get created with same name or do i still have to rely on creating these soft links ?
thanks
Note: since i need the answer to this quickly i will wait a while and then post this question in other forums and i will update the question here with the answer .

This could be a Solaris (I presumed) O.S. question rather than SE3310 or storage question.
The logical device (/dev/[r]dsk/*) is the work of the O.S. when it first configures the device, in this case the LUN from your SE3310.   I can go in depth on how the cX number happens (due to device probe order, driver differences, history of device discovery due to need of persistent device naming, etc...) but ... it's a really long story and is really quite irrelevant and most people should not be interested...
If you have COMPLETELY identical servers, i.e. identical hardware down to specific HBA in specific slot are the same,   and if you make sure that luns are presented to all servers exactly the same way, same order, and any changes are seen by all servers in the same sequence, in theory, all /dev/rdsk/* devices will be consistent across servers.
But that's still rather irrelevant.    Application that is designed to work in a redundant environment should not be dependent on logical devices like /dev/rdsk being the same.
So ... in effect this is also not a question for the Solaris forum, but rather a question for those familiar with RAC, how to configure such that device access is done "safely" through actually identifying the lun rather than assuming /dev/rdsk are consistent.

How to create two employees with same name as supplier record?

Dear all,
We need to create a supplier record for an employee so that we can issue invoice for pretty cash payment. If there are 2 employees with same name, how can we create supplier records for these 2 employees? The system does not allow duplicate supplier name.
Please advise.
Regards,
HY

Hello,
In R12 it is possible to create 2 employee with same name but different employee number.
And also possible to create these 2 employees as suppliers in Payables.
HTH,
Vik

How to get Unique calid for users with same name in multiple domain env..

I found we need to use "-k legacy" option for creating users in non-hosted setup..
I had two domains default as xxxx.com and the one that I created as yyyy.com
When I have users with same name in two of the domains as user1..
The calid for both of them is... user1 ....so they share the same calendar
When Im in valid SSO of yyyy.com I get the mail account for user1 as [email protected] .....but the calid .. common as user1
How I can get unique calid for users under two domains..
whether I need to set Hosted domain support...Then how the mailid's differ with out using hosted domain support..
And I need to login UWC without using @domain.com...
Help me on this...
Ashik

Do you have UWC and Cal configured at least for virtual domain support?
basically.. for discussion.. let's say you have three domains on your server.. 1st domain is the default domain. other 2 domains are virtual domains.
if all domains were created with mail and cal support (-S mail,cal).. you would use the following options when creating users:
1) for the default domain.. you must use the "-k legacy" option when adding users.
2) for the other two domains.. when you create the user.. do NOT use a "-k" option.
If you do not use the "-k" option.. it defaults to "hosted" which will cause the user's calid to be [email protected]
If you Do use the "-k legacy" option.. it will create the calid as just "userid"
With regard to logging into UWC without the @domain.com part of a username in a hosted domain.. the easiest way to avoid this.. is to point a host name under the hosted domain to the server.
if you point webmail.xxxx.com to the server... and then access it via:
http://webmail.xxxx.com/uwc/
any users in the xxxx.com hosted domain will NOT need to use @xxxx.com when logging in... they can just use "userid"
This feature does not take any special configuration (aside from adding a DNS entry for the hosted domain)
Hopefully that helps.

How to delete one existing file before uploading a file with same name?

Hello everybody.
I am uploading a file to Tomcat server. But, the problem is:
i want to delete an existing file in the server, if i upload a fresh file with same name. In other words, "First check for the file with the same name in the server. If it exists, then delete existing file in the server and upload fresh one". If such file doesnot exist, then upload the file to server.
I have given deleteonExit()
but, for the first time when user is uploading, i want to check for the file with same name in the server.
i am pasting the code here. please help:

<%
String contentType = request.getContentType();
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0))
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength)
byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
totalBytesRead += byteRead;
String contextRootPath = this.getServletContext().getRealPath("/");
contextRootPath=contextRootPath.concat("uploaded");
String file = new String(dataBytes);
String saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
// Create a directory; all ancestor directories must exist
File outputFile = new File(contextRootPath, saveFile);
var=outputFile.getPath();
outputFile.createNewFile();
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,contentType.length());
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
FileOutputStream fileOut = new FileOutputStream(outputFile);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
outputFile.deleteOnExit();
%>Please help. Thanks for taking time.
Regards,
Ashvini

Thank you MartinHilpert,
I have one more doubt,
I am uploading the file to one folder called "uploaded". Before uploading a fresh file, i want to delete all existing files in that folder. IS that possible ?? If yes, can you please tell me how to do that ??
Regards, Thanks for your time.
Ashlvini

How to separate two contact with same name

Hi, anyone knows how to separate two contacts with same name in Contacts? Actually they are two persons from two gmail contacts with same name but different contact numbers, different emails....etc, but Contacts assume they are same person and merge them as one!

FG,
In Lion, you have the File > Duplicate option. You will then have two copies of your document open, and the one on top will have the temporary filename "OriginalFileName copy", and your next responsibility is to File > Save (or Command-S) and rename the duplicate. At this point, you edit the copy's name, to perhaps ...copy 1, or whatever you wish. The document you had open when you initiated the File > Duplicate will still be there on your screen, waiting for you to Close it or continue editing.
Jerry

How to create logical directories with same name on two databases

Hi,
OS: Windows
Oracle Version : 10g
I have to databases in one oracle home. I have created some logical directories in one database. When I am trying to create logical directories with same name in another database, it is overwriting the first database directory paths with the second one
Can't we create directories with same name but different path in two databases on one machine?
Pls suggest me on this
Regards,
Vijay

I am trying to create logical directory using CREATE
DIRECTORY statement. I am very much aware that the
create directory statement doesn't create directory
on OS. But we can attach the physical directory on OS
to logical directory in oracle
My requirement is to create logical directories in
oracle mapping the OS directories. Both the
databases, wil have same logical directory names but
different OS directory mappingsIf I understand you correctly, you can do this:
On DB 1
CREATE OR REPLACE DIRECTORY same_dir_name as 'C:\myoracle\mydir1';
On DB 2
CREATE OR REPLACE DIRECTORY same_dir_name as 'D:\myoracle\mydir2';
What stops you from doing that ?
Note: If what you have is one database but different connections, then you are connecting to one database. The above second statement will drop and replace with the first one

Can I run 2 different domains with same name but on 2 different machines?

I am trying to setup 2 domains with same name (sharedcds1) on 2 different machines (Machine1 and Machine2).
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          Here is the error in the log -
          <Jun 14, 2005 10:53:29 AM EDT> <Error> <Cluster> <BEA-000123> <Conflict start: You tried to bind an
          object under the name weblogic.transaction.coordinators.sharedcds1managedserver1 in the JNDI tree.
          The object from 4596206652609838848S:130.170.61.153:[9505,9505,-1,-1,9505,-1,-1,0,0]:sharedcds1:s
          haredcds1managedserver1 is non-clusterable, and you have tried to bind more than once from two or m
          ore servers. Such objects can only be deployed from one server.>
          <Jun 14, 2005 10:53:29 AM EDT> <Error> <Cluster> <BEA-000123> <Conflict start: You tried to bind an
          object under the name weblogic.transaction.coordinators.sharedcds1managedserver1 in the JNDI tree.
          The object from 8842351474821025197S:130.170.61.154:[9505,9505,-1,-1,9505,-1,-1,0,0]:sharedcds1:s
          haredcds1managedserver1 is non-clusterable, and you have tried to bind more than once from two or m
          ore servers. Such objects can only be deployed from one server.>
          Thanks
          Satish

Yes you can. Make sure that domains configured to use different multicast address. WLS uses multicast for communications between nodes in domain.
          although your configuration will work, you could have troubles if you going to execute inter-domain calls between domains/servers with the same names.

BI Platform: Parameter object with the name "URL_PARAM"... does not exist

Hi,
I'm facing this issue with only one dashboard in BI4 Platform. When trying to view it through the BI Launch Pad, I get the following error:
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I've seen this thread where a similar thing was reported with NetWeaver platform.
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Also, although some of the pictures referenced in the dashboard are not in the Public Folders on BI4. Could it be that it's not able to reference the images and hence not be displaying the whole dashboard?
Please let me know if anyone has a solution to this.
Thanks!
- Sakshi Dhakad

Hi,
So here are the versions we currently have:
SAP BO Design Studio (64 bit) - 14.1.0
SAP BO Design Studio 1.4 for BI Platform - 14.1.0.349
And on checking on Central Management Console, I get this:
SAP BO BI Platform 4.1 Support Pack 5 Patch 2
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Thanks!

How to reference objects with same name?

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