How to save an image file

I am developing an applet which can manipulate an image,such as scale image,rotate image,subtract image...
then how can I save this manipulated image as generic .jpg format within applet environment.

Hi,
You can do this with JAI Java Advanced Imaging.
Here is the code you can use:
Image image =...
BufferedImage bufImage = (BufferedImage)image;
JPEGEncodeParam jep = new JPEGEncodeParam();
JPEGImageEncoder jencoder = JPEGCodec.createJPEGEncoder(out);
jencoder.encode(bufImage);
out.flush();
out.close();
Hope this helps,
Matt.
Java Developer Technical Support
Sun Microsystems.

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How to save uploaded image file to Apache Web Server from Tomcat

Hi guys,
Perhaps this is not an appropriate topic to ask under this forum but I really don't know where should I post my question. Hope you understand.
Ok, I need to know if my web application is running in Tomcat5 and user uploading some image file where I need to save these image files to the other server, which is running Apache Web Server. Should I ftp to there or other better method ?
Anyone got a better idea on doing this kind of process pls advice. Many Thanks !
regards,
Mark

if your Apache server is running in the same computer and if your servlet have write access to the folder in apache under which you want to save the file you can just write the file there but you will have to address concurrency issues.
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If you have Resorcerer from "ancient times" it of course can handle resource forks since that's was it's goal in life.
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How do i disable the open/save image dialog box in firefox? I want to directly save the image file to the drive without clicking on save option everytime when saving an image. I'm using firefox ver 35.0.1 for windows 7.

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How to insert a image file into oracle database

hi all
can anyone guide me how to insert a image file into oracle database now
i have created table using
create table imagestore(image blob);
but when inserting i totally lost don't know what to do how to write query to insert image file

Hi I don't have time to explain really, I did have to do this a while ago though so I will post a code snippet. This is using the commons file upload framework.
Firstly you need a multi part form data (if you are using a web page). If you are not using a web page ignore this bit.
out.println("<form name=\"imgFrm\" method=\"post\" enctype=\"multipart/form-data\" action=\"FileUploadServlet?thisPageAction=reloaded\" onSubmit=\"return submitForm();\"><input type=\"FILE\" name=\"imgSource\" size='60' class='smalltext' onKeyPress='return stopUserInput();' onKeyUp='stopUserInput();' onKeyDown='stopUserInput();' onMouseDown='noMouseDown(event);'>");
out.println("   <input type='submit' name='submit' value='Submit' class='smalltext'>");
out.println("</form>"); Import this once you have the jar file:
import org.apache.commons.fileupload.*;Now a method I wrote to upload the file. I am not saying that this is correct, or its the best way to do this. I am just saying it works for me.
private boolean uploadFile(HttpServletRequest request, HttpSession session) throws Exception {
        boolean result = true;
        String fileName = null;
        byte fileData[] = null;
        String fileUploadError = null;
        String imageType = "";
        String error = "";
        DiskFileUpload fb = new DiskFileUpload();
        List fileItems = fb.parseRequest(request);
        Iterator it = fileItems.iterator();
        while(it.hasNext()){
            FileItem fileItem = (FileItem)it.next();
            if (!fileItem.isFormField()) {
                fileName = fileItem.getName();
                fileData = fileItem.get();
                // Get the imageType from the filename extension
                if (fileName != null) {
                    int dotPos = fileName.indexOf('.');
                    if (dotPos >= 0 && dotPos != fileName.length()-1) {
                        imageType = fileName.substring(dotPos+1).toLowerCase();
                        if (imageType.equals("jpg")) {
                            imageType = "jpeg";
        String filePath = request.getParameter("FILE_PATH");
        session.setAttribute("filePath", filePath);
        session.setAttribute("fileData", fileData);
        session.setAttribute("fileName", fileName);
        session.setAttribute("imageType", imageType);
        return result;
     } And now finally the method to actually write the file to the database:
private int writeImageFile(byte[] fileData, String fileName, String imageType, String mode, Integer signatureIDIn, HttpServletRequest request) throws Exception {
        //If the previous code found a file that can be uploaded then
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        Connection con = null;
        int signatureID = 0;
        PreparedStatement pstmt = null;
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            udbq.setUsePreparedStatements(true);
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                sql = "SELECT SEQ_SIGNATURE_ID.nextval FROM DUAL";
                pstmt = con.prepareStatement(sql);
                ResultSet rs = pstmt.executeQuery();
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                if (fileName != null && imageType != null) {
                    sql = "INSERT INTO T_SIGNATURE (SIGNATURE_ID, SIGNATURE) values (?,?)";
                    InputStream is2 = new ByteArrayInputStream(fileData);
                    pstmt = con.prepareStatement(sql);
                    pstmt.setInt(1, signatureID);
                    pstmt.setBinaryStream(2, is2, (int)(fileData.length));
                    pstmt.executeUpdate();
                    pstmt.close();
                    con.commit();
                    con = null;
            if(mode.equals("U") && signatureIDIn != 0) {
                signatureID = signatureIDIn.intValue();
                if (fileName != null && imageType != null) {
                    sql = "UPDATE T_SIGNATURE SET SIGNATURE = ? WHERE SIGNATURE_ID = ?";
                    InputStream is2 = new ByteArrayInputStream(fileData);
                    pstmt = con.prepareStatement(sql);
                    pstmt.setBinaryStream(1, is2, (int)(fileData.length));
                    pstmt.setInt(2, signatureID);
                    pstmt.executeUpdate();
                    pstmt.close();
                    con.commit();
                    con = null;
        } catch (Exception e) {
            con = null;
            throw new Exception(e.toString());
        return signatureID;
   }

How to save the image in the form?

As thread, how to save the image into a file from the pdf form - image box?
I have Adobe Acrobat 9 Pro extended.

Hi Sandy,
Sorry for Delay.Could you please provide script code for the Button and in which event we want to add the code
I want to Save the lot of images in the PDF. For that I kept Image field in the form.Here I am able to upload the images but those are not saved.
If possible please share the details document.
Please help me.
Thanks,
Ravi.

How to save an image as PDF?

Hi,
I need help o how to save an Image as PDF file?? is this possible?

Under Getting Started in the welcome window click Create PDF
Open your image
File>Save As...PDF
But I am finding that there are limitations on how big the image can be. I am trying to save a 20mb jpeg to pdf in acrobat and having issues. Good luck!

How can I assign image file name from Main() class

I am trying to create library class which will be accessed and used by different applications (with different image files to be assigned). So, what image file to call should be determined by and in the Main class.
Here is the Main class
import org.me.lib.MyJNIWindowClass;
public class Main {
public Main() {
public static void main(String[] args) {
MyJNIWindowClass mw = new MyJNIWindowClass();
mw.s = "clock.gif";
And here is the library class
package org.me.lib;
public class MyJNIWindowClass {
public String s;
ImageIcon image = new ImageIcon("C:/Documents and Settings/Administrator/Desktop/" + s);
public MyJNIWindowClass() {
JLabel jl = new JLabel(image);
JFrame jf = new JFrame();
jf.add(jl);
jf.setVisible(true);
jf.pack();
I do understand that when I am making reference from main() method to MyJNIWindowClass() s first initialized to null and that is why clock could not be seen but how can I assign image file name from Main() class for library class without creating reference to Main() from MyJNIWindowClass()? As I said, I want this library class being accessed from different applications (means different Main() classes).
Thank you.

Your problem is one of timing. Consider this simple example.
public class Example {
    public String s;
    private String message = "Hello, " + s;
    public String toString() {
        return message;
    public static void main(String[] args) {
        Example ex = new Example();
        ex.s = "world";
        System.out.println(ex.toString());
}When this code is executed, the following happens in order:
1. new Example() is executed, causing an object to constructed. In particular:
2. field s is given value null (since no value is explicitly assigned.
3. field message is given value "Hello, null"
4. Back in method main, field s is now given value "world", but that
doesn't change message.
5. Finally, "Hello, null" is output.
The following fixes the above example:
public class Example {
    private String message;
    public Example(String name) {
        message = "Hello, " + name;
    public String toString() {
        return message;
    public static void main(String[] args) {
        Example ex = new Example("world");
        System.out.println(ex.toString());
}

Please can someone tell me how to save a MP3 file from my email on my iPad so I can put in on Facebook? Thankyou

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Hi jscher200,
Thank you for your reply, sorry for the VERY late late response, but I have just figured out how to control this separate 'panel'. I find it really useful for monitoring Google Analytics in as it can just sit there running. It does have its limitations, as it's a limited size (you can't expand it to full screen view), so you can only ever see a vertical section of a website and need to scroll to look to the right or left, but I have the live view of people accessing my website running on there and if the numbers start racking up at any time, I can scroll to look and see what pages they are accessing, where they've been referred from, etc.
To get it to work, you save a website address in the Bookmarks Toolbar and when you can see it sitting on the toolbar at the top of the screen with its little icon, right click on it then click 'properties', then tick the box 'Load this bookmark in the sidebar'. The next time you click on this bookmark to open the website, it will load in this sidebar, which looks like a separate 'window' but is immovable. You can only have one sidebar application running at a time, but can change it by right clicking on the bookmark you want to load in there and it will then change to that one next time you click on that bookmark.
I hope this might be useful to others, as I asked for help with this on loads of forums and not one person knew that this existed - even really skilled techies!

Is there a way to save an image file as a jpeg and add -web or -print to the file name?

I am trying to find a way to save my image file as a jpeg and add -web or -print to the existing file name. This way I can easily see which files are lower resolution for web posting or high resolution for printing.

Jason,
I helped somebody do a very similar thing about a week ago.
The trick is to use the Batch command's ability to construct a file name.
Tell the batch to append, e.g. "-x" without quotes, to the name of each saved file.
The batch runs an Action which does a save as JPEG, resize image, add logo, save as JPEG, then close document.
The output is "<document name>-x.jpg" and "<document name>-x-x.jpeg".
Then use Windows Explorer to rename "*-x-x.jpg" to "*-print.jpg".
Then rename "*-x.jpg" to "*-web.jpg".
See http://forums.adobe.com/thread/1038992?start=32
The name construction that I used there was just an "x" appended to the document name. Use whatever you like. Also juliew subsequently referred to the method as a "double-batch" run, although it is not. One run of the batch will output two JPEGs for each input document.
I hope the disagreements in that thread don't cause too much disruption.
If you want, the Batch command itself can be recorded in another Action which would store the parameters of the batch, then you could run that Action anytime without having to set up the details of the batch each time. It would always output to one specific folder, though.

How to insert an image file in Oracle database

hi
can you please tell me how to insert an image file into oracle database????
suppose there is one image file in c:\pictures\rose.jpg. how to insert that file into database? theoretically i know that will be BFILE type but i dont know how to insert that.
will be waiting for your reply........
thanks & regards,
Priyatosh

Hello,
The easiest way to load a blob is to use SQL loader.
This example comes from the utilities guide:
LOAD DATA
INFILE 'sample.dat'
INTO TABLE person_table
FIELDS TERMINATED BY ','
(name CHAR(20),
1 ext_fname FILLER CHAR(40),
2 "RESUME" LOBFILE(ext_fname) TERMINATED BY EOF)
Datafile (sample.dat)
Johny Quest,jqresume.txt,
Speed Racer,'/private/sracer/srresume.txt',
Secondary Datafile (jqresume.txt)
Johny Quest
500 Oracle Parkway
Secondary Datafile (srresume.txt)
Loading LOBs
10-18 Oracle Database Utilities
Speed Racer
400 Oracle Parkway
regards,
Ivo

How to add an image file to Oracle db?

Need help urgently....Anybody knows how to add an image file (example: jpg)into one of the fields in Oracle database??

This will do the job..
package forum;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
import java.sql.*;
import oracle.jdbc.driver.*;
//import oracle.sql.*;
Wanneer een request.getInputStream wordt geconferteerd naar een "String" (zie later) dan ziet de output in tekstformaat er als volgt uit:
-----------------------------7d280152604f4 Content-Disposition: form-data; name="oploadfile"; filename="C:\WINNT\Profiles\mvo\Desktop\boodschap.txt" Content-Type: text/plain Deze boodschap dient te worden ge-insert in de database. -----------------------------7d280152604f4 Content-Disposition: form-data; name="StadID" 1234 -----------------------------7d280152604f4 Content-Disposition: form-data; name="SuccessPage" /forum/error.jsp -----------------------------7d280152604f4--
of opgesplitst
contentType........... multipart/form-data; boundary=---------------------------7d235ade00f0
filename.............. "C:\Documents and Settings\Administrator\Desktop\boodschap.txt"
MIME type............. text/plain
Wat in database moet.. Dit is de eigenlijke boodschap die moet worden ge-insert in de database.
Eind boundary......... -----------------------------7d235ade00f0 Content-Disposition: form-data; name="file1"; filename="" Content-Type: application/octet-stream -----------------------------7d235ade00f0--
We gaan achtereenvolgens:
1. Kijken of het van het "multipart/form-data" type is (uploaden) en strippen van eerste boundery.
1.a Geen "multipart/form-data" ? dan... error message
1.b Groter dan MAX_SIZE ?..dan .. error message
2. Filenaam van de te uploaden file uitlezen
3. Mimetype bepalen en bepalen in welke positie van de string het Mimetype ophoudt, cq waar te uploaden file begint
4. Bepalen waar eind boundery begint
5. De eigenlijke file uitlezen
6. Terug converteren naar bytes
public class WriteBlob extends HttpServlet {
public static final int MAX_SIZE = ParameterSettings.imageUpload;
String successMessage = "";
public void init(ServletConfig config) throws ServletException {
super.init(config);
* Process the HTTP Get request
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
DataInputStream in = null;
FileOutputStream fileOut= null;
PrintWriter out = response.getWriter();
int kb_size = 0;
boolean pass2 = true;
String message = "";
String responseRedirect = "/forum/uploaden.jsp?message="+" Uploaden geslaagd";
try
//get content type of client request
String contentType = request.getContentType();
// Start stap 1...content type is multipart/form-data
if(contentType != null && contentType.indexOf("multipart/form-data") != -1)
//open input stream
in = new DataInputStream(request.getInputStream());
//get length of content data
int formDataLength = request.getContentLength(); // totale lengte van de inputstream
//initieer een byte array om content data op te slaan
byte dataBytes[] = new byte[formDataLength];
//read file into byte array
int bytesRead = 0;
int totalBytesRead = 0;
int sizeCheck = 0;
while (totalBytesRead < formDataLength)
//kijken of de file niet te groot is
sizeCheck = totalBytesRead + in.available();
if (sizeCheck > MAX_SIZE)
pass2 = false;
message = "Sorry. U kunt slechts bestanden uploaden tot een grootte van 500KB";
responseRedirect = "/forum/uploaden.jsp?message="+message;
bytesRead = in.read(dataBytes, totalBytesRead,formDataLength);
totalBytesRead += bytesRead;
if (pass2==true)
kb_size = (int)(formDataLength/1024);
//create string from byte array for easy manipulation
String file = new String(dataBytes);
/*get boundary value (boundary is a unique string that separates content data)
contentType........... multipart/form-data; boundary=---------------------------7d235ade00f0
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex+1, contentType.length());
// Stap 2.....bepaal de naam van de upload file
// filename.............. "C:\Documents and Settings\Administrator\Desktop\boodschap.txt"
String saveFile = file.substring(file.indexOf("filename=\"")+10);
saveFile = saveFile.substring(0,saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+1,saveFile.indexOf("\"")); //naam van de file...boodschap.txt
String saveFileName = saveFile;
// Stap 3..Bepaal MIME Type en de positie van eind mime type in string
voorbeeld: -----------------------------7d23d21220524 Content-Disposition: form-data; name="file0"; filename="C:\WINNT\Profiles\mvo\Desktop\z clob.txt" Content-Type: text/plain
String restant = "";
int pos; //position in upload file
// bijv .. filename="C:\Documents and Settings\Administrator\Desktop\boodschap.txt"
pos = file.indexOf("filename=\"");
//find position of content-disposition line
pos = file.indexOf("\n",pos)+1; // eing file naam + spatie
// onderstaand geeft bijv Content-Type: text/plain
restant = file.substring(pos,file.indexOf("\n",pos)-1);
restant = restant.substring(restant.indexOf(":")+2,restant.length()); // MIME type
String mimeType = restant;
//find position of eind content-type line
pos = file.indexOf("\n",pos)+1;
//find position of blank line
pos = file.indexOf("\n",pos)+1;
int start = pos;
// Stap 4 eind boundary
/*find the location of the next boundary marker (marking the end of the upload file data)*/
int boundaryLocation = file.indexOf(boundary,pos)-4; //waarom -4 ..? ziet er uit als linebreak spatie--boundary=-----------------------------7d21c9ae00f0
// Stap 5 en 6..de eigelijke te uploaden file in nieuwe byte file inserten
byte dataBytes2[] = new byte[boundaryLocation-start]; //declareren
for (int i=0;i<(boundaryLocation-start);i++) // inserten BELANGRIJK !!
dataBytes2=dataBytes[start+i];
String next_id = "0";
Statement statement = null;
Connection conn = null;
boolean pass = true;
ResultSet rs = null;
Statement stmt_empty = null;
oracle.sql.BLOB blb = null;
try
int vendor = DriverUtilities.ORACLE;
String username = ConnectionParams.userName;
String password = ConnectionParams.passWord;
String connStr = DriverUtilities.makeURL(vendor);
DriverManager.registerDriver(new oracle.jdbc.driver.OracleDriver());
conn = DriverManager.getConnection(connStr,username, password);
if (conn==null){pass=false;}
} catch (Exception e){out.println("<P>" + "There was an error establishing a connection:");}
if (pass==true)
try
String seq_nextval ="select forum_blob_seq.nextval from dual";
statement = conn.createStatement();
ResultSet rset = statement.executeQuery(seq_nextval);
while (rset.next())
next_id = rset.getString(1);
if (next_id.equals("0"))
message = "Uploaden mislukt !...Er ging wat fout tijdens de interactie met de database";
responseRedirect = "/forum/uploaden.jsp?message="+message;
pass = false;
} catch (Exception e1) { out.println("Error blob1 : "+e1.toString()); };
} // end pass
if (pass==true)
try
Statement stmt2 = conn.createStatement();
String insert_empty_blob = "INSERT INTO test_blob(id "+
",filename "+
",mimetype "+
",kb) "+
"VALUES("+Integer.parseInt(next_id) +
",'"+saveFileName+"'"+
",'"+mimeType+"'"+
","+kb_size+")";
stmt2.executeQuery(insert_empty_blob);
conn.commit();
if (stmt2!= null) {stmt2.close();}else{stmt2.close();pass = false;}
} catch (Exception e2){
message = "Uploaden mislukt !...Er ging wat fout tijdens de interactie met de database";
responseRedirect = "/forum/uploaden.jsp?message="+message;
out.println("<P>" + "2. There was an error inserting mime type:");}
} //end pass
if (pass==true)
try
conn.setAutoCommit(false);
} catch (Exception e3) { pass = false; out.println("Error blob 3: "+e3.toString()); };
} //end pass
if (pass==true)
try
String Query_blob ="Select test_blob FROM test_blob where id="+next_id+" FOR UPDATE";
stmt_empty = conn.createStatement();
rs=stmt_empty.executeQuery(Query_blob);
} catch (Exception e4) {
pass = false;
out.println("Error blob 4: "+e4.toString());
message = "Uploaden mislukt !...Er ging wat fout tijdens de interactie met de database";
responseRedirect = "/forum/uploaden.jsp?message="+message;};
} //end pass
if (pass==true)
try
                         if (rs.next())
                         blb = ((OracleResultSet)rs).getBLOB(1);
                    OutputStream stmBlobStream = blb.getBinaryOutputStream();
                         try {
                              int iSize = blb.getBufferSize();
                         byte[] byBuffer = new byte[iSize];
                         int iLength = -1;
ByteArrayInputStream stmByteIn = new ByteArrayInputStream(dataBytes2);
                              try {
// while ( (iLength = in.read(byBuffer, 0,      iSize)) != -1 )
while ( (iLength = stmByteIn.read(byBuffer, 0,      iSize)) != -1 )
                                   stmBlobStream.write(byBuffer, 0, iLength);
                                   stmBlobStream.flush();
                                   } // end while
} catch (Exception e5) {
pass=false;
out.println("Error blob 5: "+e5.toString());
message = "Uploaden mislukt !...Er ging wat fout tijdens de interactie met de database";
responseRedirect = "/forum/uploaden.jsp?message="+message; }
                              finally { conn.commit();     }
} catch (Exception e6) { out.println("Error blob 6: "+e6.toString()); };
                         } //end if rs.next()
                         else {      throw new SQLException("Could not locate message record in database."); }
} catch (Exception e7) { out.println("Error blob : "+e7.toString()); };
} // end pass
} // end pass2
else //request is not multipart/form-data
message = "Uploaden mislukt !...Gegevens niet verstuurd via multipart/form-data.";
responseRedirect = "/forum/error.jsp?message="+message;
out.println("Request not multipart/form-data.");
catch(Exception e)
try
//print error message to standard out
out.println("Error in doPost: " + e);
//send error message to client
out.println("An unexpected error has occurred.");
out.println("Error description: " + e);
}catch (Exception f) {}
response.sendRedirect(responseRedirect);
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
doPost(request,response);
Regards
Martin

How can I add image files to a executable jar file ?

Could you tell me how can I add image files to executable jar file ?
package structure:
../com/Main.class
../images/..

Please don't cross post, and read this
http://forum.java.sun.com/thread.jsp?forum=31&thread=271751
I've answered the question in the New To Java thread.

How to link an image file in code view

I can't seem to figure out how to link the image file in code view. It has to be in code view because the image is hidden in Design View so I can't do it in HTML view. Here's the coded section:

                <div id="tab3" class="tabsGeneral">
                  <div class="tabsFeatureImageContainer asyncImgLoad" title="img/index/tabs/tab3/DonateNow-168x112.jpg"></div>
                  <h3 class="tabsHeader">Partner With Us</h3>
                  <p class="tabsDesc">Get involved with all the exciting things God is doing at Provision House. Partner with us to help others find true and lasting freedom from addiction in Christ. <a href="http://provisionhouse.org/giving.html" class="commonLink">Click here</a></p>
It's' the red jpeg image file I want to link to another page in the site and I don't have enough experience to do this.
I am thankful for your help.
Paul

Thanks, Gramps. Here's the page I want to like to from the image:
http://provisionhouse.org/giving.html
Paul
Here's the whole section where the problem exists:

            <div id="tabsContainer">
                <div id="tabsWrapper">
                    
                    <div id="tab1" class="tabsGeneral">
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                    </div> 
                    
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                        <div class="tabsFeatureImageContainer asyncImgLoad" title="img/index/tabs/tab2/FreedomFromAddiction168x112.jpg"></div>
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                        <p class="tabsDesc">Is it possible for the Christian to find true and lasting freedom from addiction? This session explains how all addictions are also sin, and it is sin that Jesus has set us free from. Anticipated release: November, 2011. <span class="commonLink"><a href="curriculum.html">Read about Session 2</a></span>
 
                  </div> 
                    
                    <div id="tab3" class="tabsGeneral">
                    <div class="tabsFeatureImageContainer asyncImgLoad" title="img/index/tabs/tab3/DonateNow-168x112.jpg"></div>
                        <h3 class="tabsHeader">Partner With Us</h3>
                        <p class="tabsDesc">Get involved with all the exciting things God is doing at Provision House. Partner with us to help others find true and lasting freedom from addiction in Christ. <a href="http://provisionhouse.org/giving.html" class="commonLink">Click here</a></span>
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How I can store Image file in a database

Can any one how i can stored image file in a database and then by using same database how i can show in HTML page...(in a browser)

This is not something that can be answered easily. There is quite alot of code involved....
To get started I suggest you read up on the built-in package 'DBMS_LOB' from Oracle . Most of what you need you should find there.
regards Dave.

How to save an image file

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