How to see the contents of jar file?

Hi
is there any way we can see the contents of jar file.(Since it is similar to zip file can we unzip it and see the contents)

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How to get the contents of jar file?

Hi
is there any way we can see the contents of jar file.(Since it is similar to zip file can we unzip it and see the contents)

You can use:
this->getClass().getResourceAsStream("/something.txt")
where 'something.txt' is a file inside your .jar

How to Display the content of Excel file into Webdynpro Table

Hi Experts
I am following the Blog to upload a file in to the webdynpro context,but my problem is after uploading a excel file i need to extract the content from that Excel file and that content should be displayed in the webdynpro table.Can any body please guide me how to read the content from excel and to Display in the Table.
Thanks and Regards
Kalyan

HI,
Take for example, if Excel file contains 4 fields,
Add jxl.jar to JavaBuild path and Use this snippet
File f=new File("sample.xls");
Workbook w=Workbook.getWorkbook(f);
Sheet sh=w.getSheet(0);
int cols=sh.getColumns();
int rows=sh.getRows();
Cell c=null;
String s1=null;
String s2=null;
String s3=null;
String s4=null;
ArrayList al=new ArrayList();
int j=0;
for(int i=1;i<rows;i++)
ITableElement table=wdContext.createTableElementz
     s1=sh.getCell(0,i).getContents();
     s2=sh.getCell(1,i).getContents();
     s3=sh.getCell(2,i).getContents();
     s4=sh.getCell(3,i).getContents();
                         table.setName(s1);
     table.setAddress(s2);
     table.setDesignation(s3);
     table.setDummy(s4);
     al.add(j,table);
     j++;
wdContext.nodeTable().bind(al);
Regards
LakshmiNarayana

How to get the content of text file to write in JTextArea?

Hello,
I have text area and File chooser..
i wanna the content of choosed file to be written into text area..
I have this code:
import java.awt.Container;
import java.awt.FlowLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.File;
import javax.swing.JButton;
import javax.swing.JFileChooser;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.*;
public class Test_Stemmer extends JFrame {
public Test_Stemmer() {
super("Arabic Stemmer..");
setSize(350, 470);
setDefaultCloseOperation(EXIT_ON_CLOSE);
setResizable(false);
Container c = getContentPane();
c.setLayout(new FlowLayout());
JButton openButton = new JButton("Open");
JButton saveButton = new JButton("Save");
JButton dirButton = new JButton("Pick Dir");
JTextArea ta=new JTextArea("File will be written here", 10, 25);
JTextArea ta2=new JTextArea("Stemmed File will be written here", 10, 25);
final JLabel statusbar =
              new JLabel("Output of your selection will go here");
// Create a file chooser that opens up as an Open dialog
openButton.addActionListener(new ActionListener() {
   public void actionPerformed(ActionEvent ae) {
     JFileChooser chooser = new JFileChooser();
     chooser.setMultiSelectionEnabled(true);
     int option = chooser.showOpenDialog(Test_Stemmer.this);
     if (option == JFileChooser.APPROVE_OPTION) {
       File[] sf = chooser.getSelectedFiles();
       String filelist = "nothing";
       if (sf.length > 0) filelist = sf[0].getName();
       for (int i = 1; i < sf.length; i++) {
         filelist += ", " + sf.getName();
statusbar.setText("You chose " + filelist);
else {
statusbar.setText("You canceled.");
// Create a file chooser that opens up as a Save dialog
saveButton.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae) {
JFileChooser chooser = new JFileChooser();
int option = chooser.showSaveDialog(Test_Stemmer.this);
if (option == JFileChooser.APPROVE_OPTION) {
statusbar.setText("You saved " + ((chooser.getSelectedFile()!=null)?
chooser.getSelectedFile().getName():"nothing"));
else {
statusbar.setText("You canceled.");
// Create a file chooser that allows you to pick a directory
// rather than a file
dirButton.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae) {
JFileChooser chooser = new JFileChooser();
chooser.setFileSelectionMode(JFileChooser.DIRECTORIES_ONLY);
int option = chooser.showOpenDialog(Test_Stemmer.this);
if (option == JFileChooser.APPROVE_OPTION) {
statusbar.setText("You opened " + ((chooser.getSelectedFile()!=null)?
chooser.getSelectedFile().getName():"nothing"));
else {
statusbar.setText("You canceled.");
c.add(openButton);
c.add(saveButton);
c.add(dirButton);
c.add(statusbar);
c.add(ta);
c.add(ta2);
public static void main(String args[]) {
Test_Stemmer sfc = new Test_Stemmer();
sfc.setVisible(true);
}could you please help me, and tell me what to add or to modify,,
Thank you..

realahmed8 wrote:
thanks masijade,
i have filter the file chooser for only text files,
but i still don't know how to use FileReader to put text file content to the text area (ta) ..
please tell me how and where to use it..How? -- See the IO Tutorials on Sun for the FileReader (and I assume you know how to call setText and append in the JTextArea).
Where? -- In the actionPerformed method (better would be a separate thread that is triggered through the actionPerformed method, but that is probably beyond you at the moment), of course.
Give it a try.

How to check the contents of Control file, Log file & Parameter file

Can anybody help me how i can check the contents of Control file, Log file & Parameter file.
Arif

OK ...
Parameter file:
It will normally be in the $ORACLE_HOME/dbs directopry. It could be aan init{sid}.ora or a spfile{sid}.ora ... do not edit an SPFILE as yu could corrupt it.
http://download-east.oracle.com/docs/cd/B19306_01/server.102/b14231/create.htm#sthref434
If it's an init{sid}.ora, use any editor to see the actual content.
If it's a spfile{sid}.ora, use one of V$PARAMETER, V$PARAMETER2, V$SYSTEM_PARAMETER, V$SYSTEM_PARAMETER2 as aappropriate (read the Reference manual to get an idea about when each is appropriate)
Control File:
You should not edit a control file. It consists of many areas, as described here http://download-east.oracle.com/docs/cd/B19306_01/server.102/b14220/physical.htm#i10135 and each are is interrogated by V$views as given in the reference manual. The following V$views all deal with some aspect of the control file or provide info about the control files or the contents of control files:
V$ARCHIVE_DEST
V$ARCHIVED_LOG
V$BACKUP_ARCHIVELOG_DETAILS
V$BACKUP_CONTROLFILE_DETAILS
V$BACKUP_CONTROLFILE_SUMMARY
V$BACKUP_COPY_DETAILS
V$BACKUP_COPY_SUMMARY
V$BACKUP_CORRUPTION
V$BACKUP_DATAFILE
V$BACKUP_DATAFILE_DETAILS
V$BACKUP_FILES
V$BACKUP_PIECE
V$BACKUP_REDOLOG
V$BACKUP_SET
V$BACKUP_SET_DETAILS
V$BACKUP_SPFILE
V$CONTROLFILE
V$CONTROLFILE_RECORD_SECTION
V$COPY_CORRUPTION
V$DATABASE
V$DATABASE_INCARNATION
V$DATAFILE
V$DATAFILE_COPY
V$DATAFILE_HEADER
V$DELETED_OBJECT
V$LOCK
V$LOG
V$LOG_HISTORY
V$LOGHIST
V$OBSOLETE_BACKUP_FILES
V$OFFLINE_RANGE
V$PROXY_COPY_DETAILS
V$PROXY_COPY_SUMMARY
V$PROXY_DATAFILE
V$RMAN_BACKUP_JOB_DETAILS
V$RMAN_BACKUP_SUBJOB_DETAILS
V$RMAN_CONFIGURATION
V$SESSION
V$TABLESPACE
V$THREAD
V$UNUSABLE_BACKUPFILE_DETAILS
3) Log Files
The contents of the log files are viewed using LogMiner - read Chapter 11 of the Oracle Utilities manual

How to read the contents of XML file from my java code

All,
I created an rtf report for one of my EBS reports. Now I want to email this report to several people. Using Tim's blog I implemented the email part. I am sending emails to myself based on the USERID logic.
However I want to email to different people other then me. My email addresses are in the XML file.
From the java program which sends the email, how can I read the fields from XML file. If any one has done this, Please point me to the right examples.
Please let me know if there are any exmaples/BLOG's which explain how to do this(basically read the contents of XML file in the Java program).
Thank You,
Padma

Ike,
Do you have a sample. I am searched so much in this forum for samples. I looked on SAX Parser. I did not find any samples.
Please help me.
Thank you for your posting.
Padma.

How to read the contents of attached files

Hi,
I am designing a Form using LiveCycle Designer 8.0
Scenario:
User can attach the file through "Attachments" facility provided on Adobe Reader.
The requirement is to attach 3 documents and post it to SAP system using Web services.
I am using the following code(which i got from this forum only) to find the number of files user has attached.
d = event.target.dataObjects;
n = d.length;
xfa.host.messageBox("Number of Attachments: "+n);
//Displaying the names of the Attached files
for( i = 0; i < n; i++ )
xfa.host.messageBox("Name of the file: "+d[i].name);
My problem: is how to read the contents of the attached files so that I post it to SAP using Web services
Thanks in advance!!
Taha Ahmed

In order to read the content of the Redo Log files, you should use Logminer Utility
Please refer to the documentation for more information:
[Using LogMiner to Analyze Redo Log Files|http://download.oracle.com/docs/cd/B19306_01/server.102/b14215/logminer.htm#SUTIL019]
Kamran Agayev A. (10g OCP)
http://kamranagayev.wordpress.com
[Step by Step install Oracle on Linux and Automate the installation using Shell Script |http://kamranagayev.wordpress.com/2009/05/01/step-by-step-installing-oracle-database-10g-release-2-on-linux-centos-and-automate-the-installation-using-linux-shell-script/]

How To Fetch the Content of a File from Client's PC?

In my JSP I have this:
<input type="file" name="filename">for visitors of the web page to browse their PCs' directories to select a file to upload (when the Submit button is clicked).
What appears in the text field will be a file name. How do I get both the file name and the content of that file to be saved in the database?

From http://www.htmlhelp.com/reference/html40/forms/input.html:
A form that includes a file INPUT must specify METHOD=post and ENCTYPE="multipart/form-data" in the <FORM> tag. CGI libraries such as CGI.pm allow simple handling of such forms.
Form-based file upload is unsupported by many currently deployed browsers. Authors should provide alternative methods of input where possible.
The following example allows the user to upload an HTML document for validation:
<FORM METHOD=post ACTION="/cgi-bin/validate.cgi" ENCTYPE="multipart/form-data">
<P>Select an HTML document to upload and validate. If your browser does not support form-based file upload, use one of our alternate methods of validation.</P>
<P><INPUT TYPE=file NAME="html_file" ACCEPT="text/html"></P>
<P><INPUT TYPE=submit VALUE="Validate it!"></P>
</FORM>
Your servlet would then have to process whatever data is put into that parameter. You can look at O'Reilly's servlet utilities, or one of the other other links here:
http://www.google.com/search?q=java+servlet+file+upload&sourceid=opera&num=0&ie=utf-8&oe=utf-8

How to store the contents of a file

Hi,
I'm using forms6i and database 10g.
Through forms if a user selects a filename , and clicks a button or something,
the contents of the file should be saved in the database.
The file can be of any type, like .doc,.pdf,.xml,.html etc...
and the contents filed will be of type varchar
Please help me do this..
Thanks

Do you really want to save the "Content" of a file or the file itself? If you try to save the contents of a .doc or .pdf in a column with a VARCHAR2 datatype, you are going to corrupt the contents of the file since these file types have binary data in them as well as text. I think you would have greater success storing the actual file in a BLOB column.
Here are a few Oracle Support documents that discuss how to store and retrieve files stored as BLOBs in the database.
Doc ID: 168277.1 - How to Upload Binary Documents Back to Database BLOB Column from Forms
Doc ID: 330146.1 - How to write BLOBs Stored Inside the Database Out to Files.
Hope this helps,
Craig B-)
If someone's response is helpful or correct, please mark it accordingly.

How to save the contents of a file(not a text file)

Hi all, I want to save the contents of a file(,png file, not a text file) as a field in a class. Shall I have it as a string or byte array or something?
I have tried saving a file in a string but there were some problems with loading the file from a different platform. Following is my code.
        String string;
        try {
            StringBuffer sb = new StringBuffer(1024);
            char[] characterArray = new char[1024];
            BufferedReader br = new BufferedReader(new FileReader(file));
            while(br.read(characterArray) != -1){
                sb.append(String.valueOf(characterArray));
            br.close();
            string= sb.toString();
        } catch (IOException ex) {
            ex.printStackTrace();
        }and I use the following code to recover the string back to a stream, and save that stream back to a time later.
    ByteArrayInputStream bais = new ByteArrayInputStream(map.getBytes());I realized that because this file is not a text file, the string could cause some problems. But anyone could tell me if I should use a byte array or someting? and how?
Any help would be appreciated!
Cheers,
Jing

You should use a byte array, and the binary streams (InputStream a& OutputStream). Never use Strings and Reader/Writer if you have binary data.
Kaj

How to store the content of a file in oracle table.

Hello,
I have a .xml file in unix , how can i upload the content of that file into a column of a table in oracle?

Did you look at the link posted in response to the OP? At a quick look, it seems fairly reasonable to me.
John

Not able to see the content of opened files (.jpg or .psd) in Photoshop CS6

I recently downloaded Adobe Design and Web Premium CS6. I am not able to see the content of any of the file I open (.psd or .jpg). I do see the file has been opened as the file name appears on the open file tabs, I also see the preview of the file in the Navigator Window and list of layers in the layers window. I am relatively new to this so might be missing on some option that needs to be turned on or something.
I am using Window 7 Professional, Service Pack 1, with 8GB RAM.
Any suggesstion/help is greatly appreciated.

This is going to be the weak point:
Intel(R) HD Graphics card
While the Intel HD chip is fine for general computer work, it is weak for programs, like Photoshop and Adobe Premiere. The driver support is usually very bad, as well. If Lenovo does not have updated drivers, that work better, about the only choice that one has with a laptop is to turn OFF graphics accleration, and wait for a new driver. That will probably be very slow in coming.
Good luck,
Hunt
PS - Noel's link will list what you are missing.

How to see the content of an attachment in sxmb_moni

Hi all,
Does someone know how to see the actual content of an attachment in sxmb_moni?
If I look under Inbound Message (CENTRAL)/Payloads, I would see one node for MainDocument and another node with the name of the attachment.
When I click on the attachment name, a word document shows with one line in it. That line is just the name of the attachment and nothing else.
How can I see the actual content of that attachment?
Thank you. Points will be awarded to helpful answers.
Regards,
-Michelle

I checked my coding again in debug mode. I cannot find anything wrong.
I duplicate here my coding again.
   DATA lo_attachment TYPE REF TO if_ai_attachment.
lo_attachment = lo_attachment_protocol->get_attachment_from_binary(
                      data = iv_attachment_content
                      type = iv_attachment_mime_type
                      name = iv_attachment_name
* set the attachment
DATA lt_attachments TYPE prx_attach.
APPEND lo_attachment TO lt_attachments.
lo_attachment_protocol->set_attachments( lt_attachments ).
The local variable LT_ATTACHMENTS has field payload-resource with the following expected values --
KIND : B
TYPE : application/msword
BINDATA : 00530068006F00740073005F0073007700630076002E0064006F00630020002000
The BINDATA correctly contains the dummy data I assigned.
I must have missed something. Can someone help?
Best regards,
-Michelle

How to search the content of TPL files?

Hi. I have a folder with hundreds of template "tpl" files that I'm needing to search the file contents of but using the regular search of that folder is unable to search the content of the tpl files, is it possible to do so?
Thanks!,
Wesley

I assume there's not a "scan all files" with Spotlight?
I don't think that would be possible in the specific case of content searches. Here's my understanding:
EasyFind searches the files themselves when it looks for content, which makes it slow but very flexible.
In contrast, Spotlight searches a pre-existing index when it looks for things - it can be instructed to search the index in various ways, but if the desired information is not in the index in the first place, it won't be found. Indexing the content of every file in the system is not feasible, so only the contents of certain file types get indexed. I found the following in [this Wikipedia article|http://en.wikipedia.org/wiki/Spotlight_%28software%29]:
Aside from basic information about each file like its name, size and timestamps, the mdimport daemon can also index the content of some files, when it has an Importer plug-in that tells it how the file content is formatted. Spotlight comes with importers for certain types of files, such as Microsoft Word, MP3, and PDF documents. Apple publishes APIs that allow developers to write Spotlight Importer plug-ins for their own file formats.[3]
So unless you'd care to write your own Spotlight Importer plug-in for tpl files, I think you are out of luck!

How to see the contents of a directory?

ok, here is my problem. I need to see the contents of a directory (ie. like doing a dir in DOS or ls in Linux) and then process each of the files in the directory.
Is there a way in java to see the contents of a directory? Please help...

hi,
well you can see the contents of a directory, a directory in turn could have files and subdirectories, so you could use the following snippet of code.
import java.io.File;
import java.io.IOException;
public class FileBrowser
     private File mFile;
     public void listDirectory(String fileName)
          mFile = new File(fileName);
          if (mFile.exists()) //check if File or Directory with given name exists
               if (mFile.isDirectory())
                    File mTempFile[] = mFile.listFiles();
                    if (mTempFile.length > 0)
                         for (int i=0; i < mTempFile.length; i++)
                              listDirectory(mTempFile.getAbsolutePath()); //recursive call
               else if (mFile.isFile())
                    printFilePath(mFile);
          else
               throw new IllegalArgumentException("File or Directory does not exist");
     public void printFilePath(File file)
          System.out.println("File path :" + file.getAbsolutePath());
     public static void main(String args[])
          try
               FileBrowser fb = new FileBrowser();
               fb.listDirectory("c://temp//");
          catch(IllegalArgumentException ex)
the above code snippet first figures out if a File object is representing a File or a Directory, if it represents a File it just call a method which prints out the Absolute path of the file which contains the file name also, else if it is a directory it just recursively scans through all sub-directories and files within the directory, also if the String arguement passed to listDirectory is incorrect, it throws a IllegalArguementException, hope this was useful.
Cheerz

How to see the contents of jar file?

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