How to set save path using FileStream?

Hi everybody, I have a webcam that takes a snapshot in AIR. I understand that the code below is to write/edit a .txt file.
var file:File = File.desktopDirectory.resolvePath( "Text.txt" );
so how do I save multiple snapshots .jpg to my local network/C drive?

Hi guys, I have been doing some trial and error and found the correct code to save the bitmap into my C drive. Thanks for reading this thread.
var fl:File = File.desktopDirectory.resolvePath("C://grpphoto.jpg");
-Zainuu

Similar Messages

How to set the PATH in Terminal?

As a newbie to Bash and the Terminal, in connection with installing a new version of Ruby and various add-ons, I have been messing around with changing the PATH via various methods I've found on the internet, and trying to add a new directory to my PATH. Unfortunately, I cannot figure out how to set the PATH correctly. Here is what I understand so far:
1. Bash first looks to ".bash_profile" in the home directory for PATH settings.
2. If none, Bash then looks to ".bash_login" for PATH settings.
3. If none, Bash then looks to ".profile".
4. If none, Bash then looks to a system file in "/etc/profile" for default PATH settings.
5. For a new shell after login, Bash looks for a ".bashrc" file.
I cannot find any of the above files (I have Finder set to show hidden files already). Somehow, following some instructions from the internet without really knowing what I was doing over the past week I have set my PATH as follows:
/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/Users/*****/src:/usr/X11/bin
but I cannot find the file that is setting this PATH. I have tried creating a new ".bash_profile" shell file and putting it in various places such as "/bin" and "/usr/bin" but the file is not being read.
* As a temporary workaround I tried using the command "source .bash_profile" upon login to set the PATH using the .bash_profile file that I created, but it does not work.
* I am able to temporarily alter the path using the command "PATH=/usr/local/bin:$PATH" but this only lasts for an active shell; when I close out and reopen a new shell, it reverts to the default.
So my questions are:
Is it correct that there is a "/etc/profile" somewhere that is setting the default PATH? If so where is it? Should I alter it, or create a new ".bash_profile" somewhere to set the PATH? If not, where is my PATH being set? If I should create a new ".bash_profile", what exactly should go in it?
Thanks in advance for any assistance.

... I created a new ".bash_profile" file directly under my home directory and it worked like a charm. Below is the content of the file:
"PATH=/usr/local/bin:/bin/:/sbin/:/usr/bin/:/usr/sbin/:/Users/******/Ruby:/Users/*******/src:/Users/******/Java Programs/"
What are the "..."'s? Is that just you, or is the contents of the file actually inside of double quotes?
is there an 'export PATH' also in the file? As in
PATH=/usr/local/bin:/bin/:/sbin/:/usr/bin/:/usr/sbin/:/Users/******/Ruby:/Users/*******/src:/Users/******/Java Programs/
export PATH
And did you either restart your Terminal session so your .bash_profile was read, or issue a 'source .bash_profile' command to execute the .bash_profile after your change?
The only remaining problem is that from the home directory, I'm unable to directly run programs in the above-designated subdirectories (without first navigating to the subdirectory containing the file. Is there something wrong with the syntax or order of the directories I put in the path?
For example: there is a file called "newprogram.rb" in the "Ruby" directory listed above. I should be able to execute it from the home directory using "ruby newprogram.rb" but it does not work. The same command works fine from within the "Ruby" directory.
Does the 'ruby' command search PATH to find its scripts?
Have you read the "man ruby" man page to see if it talks about PATH?
A common Unix feature is that programs and scripts with the executable bit set, and are located in a PATH directory, will be run if you just type their names.
For example, if the first line of newprogram.rb script starts with
#!/usr/bin/ruby
and if the script is executable
chmod +x newprogram.rb
And if it is in a directory in PATH, then just typing
newprogram.rb
should run your perl script using /usr/bin/ruby. If you want to use a different version of Ruby, then change the #! line so it point to your version of Ruby. Or if your version of Ruby is found earlier in PATH then the /usr/bin/ruby, you can use
#!/usr/bin/env ruby
as your script's first line which will search PATH for 'ruby' and use the first one it finds.
Message was edited by: BobHarris

How to set the path variable on Windows ME?

I want to get a friend of mine to start using java the only problem is that we both dont know how to set the path variable in Windows ME. I cant seem to find any instructions on it for ME. So if someone could please tell me how or give me a llnk to directions for Windows ME. Thanks.

Refer to the Installation Instructions for the package that you installed - I believe #5 if the instructions has the information. A link to the instructions is at the page you installed from.

How to set-up and use FAMILY Sharing

Can someone please explain to me in detail how to set-up and use FAMILY Sharing, none of the information I have so far found in the documentation helps at all, in fact it puts you in a constant loop giving the same information over and over again
We have quite a few devices from ipads, iphones and ipods and I need to set-up Family Sharing.
We have our main Apple ID which is linked to our Payment method, I have now got my son a new iPad, I have created his Apple ID and set-up a link via FAMILY Sharing to our main Apple ID.
From what I read we should be able to share our purchased Apps between family members.
So I figured I would be able to get the Apps now via iTunes that are part of the FAMILY Sharing, however when I go into ITunes (latest version downloaded yesterday) I can only see the Home sharing menu item not FAMILY Sharing, so I cannot work out in Itunes how to get Apps that are FAMILY shared. So ok I will try and get Apps directly via the Ipad using the App Store. To test it is working I look for a known paid for App, I then go to download it and it is now asking me to pay for it again.
Can someone please explain to me in detail how FAMILY Sharing is supposed to work and how I get it to work please.
Thanks for your help
Greg

Hey GregWr,
Thanks for the question. The following resources provides some of the best information regarding Family Sharing. Included, you’ll find information on making sure the accounts are set to "Share my purchases”, as well as information on downloading Family Member purchases from the iTunes Purchased section. Please note that some applications are not shareable.
Sharing purchased content with Family Sharing - Apple Support
http://support.apple.com/en-us/HT201085
Which purchased content can I share using Family Sharing - Apple Support
http://support.apple.com/en-us/HT203046
If you don't see your family's shared content - Apple Support
http://support.apple.com/en-us/HT201454
Thanks,
Matt M.

How to set up shared use of "Contacts" data w/ 2 individual user accounts?

How to set up shared use of application "Contacts" data for two individual user accounts?

Link the contacts in one user account to a online cloud based system like Google or apples iCloud and then link the second user to that same online account. This could cause some slight problems if both people maintain their own online account to either of those systems on a phone or pad.

How to set proxy authentication using java properties at run time

Hi All,
How to set proxy authentication using java properties on the command line, or in Netbeans (Project => Properties
=> Run => Arguments). Below is a simple URL data extract program which works in absence of firewall:
import java.io.*;
import java.net.*;
public class DnldURLWithoutUsingProxy {
   public static void main (String[] args) {
      URL u;
      InputStream is = null;
      DataInputStream dis;
      String s;
      try {
          u = new URL("http://www.yahoo.com.au/index.html");
         is = u.openStream();         // throws an IOException
         dis = new DataInputStream(new BufferedInputStream(is));
         BufferedReader br = new BufferedReader(new InputStreamReader(dis));
      String strLine;
      //Read File Line By Line
      while ((strLine = br.readLine()) != null)      {
      // Print the content on the console
          System.out.println (strLine);
      //Close the input stream
      dis.close();
      } catch (MalformedURLException mue) {
         System.out.println("Ouch - a MalformedURLException happened.");
         mue.printStackTrace();
         System.exit(1);
      } catch (IOException ioe) {
         System.out.println("Oops- an IOException happened.");
         ioe.printStackTrace();
         System.exit(1);
      } finally {
         try {
            is.close();
         } catch (IOException ioe) {
}However, it generated the following message when run behind the firewall:
cd C:\Documents and Settings\abc\DnldURL\build\classes
java -cp . DnldURLWithoutUsingProxy
Oops- an IOException happened.
java.net.ConnectException: Connection refused
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:305)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:171)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:158)
at java.net.Socket.connect(Socket.java:452)
at java.net.Socket.connect(Socket.java:402)
at sun.net.NetworkClient.doConnect(NetworkClient.java:139)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:402)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:618)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:306)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:267)
at sun.net.www.http.HttpClient.New(HttpClient.java:339)
at sun.net.www.http.HttpClient.New(HttpClient.java:320)
at sun.net.www.http.HttpClient.New(HttpClient.java:315)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:510)
at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection.java:487)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:615) at java.net.URL.openStream(URL.java:913) at DnldURLWithoutUsingProxy.main(DnldURLWithoutUsingProxy.java:17)
I have also tried the command without much luck either:
java -cp . -Dhttp.proxyHost=wwwproxy -Dhttp.proxyPort=80 DnldURLWithoutUsingProxy
Oops- an IOException happened.
java.io.IOException: Server returned HTTP response code: 407 for URL: http://www.yahoo.com.au/index.html
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1245) at java.net.URL.openStream(URL.java:1009) at DnldURLWithoutUsingProxy.main(DnldURLWithoutUsingProxy.java:17)
All outgoing traffic needs to use the proxy wwwproxy (alias to http://proxypac/proxy.pac) on port 80, where it will prompt for valid authentication before allowing to get through.
There is no problem pinging www.yahoo.com from this system.
I am running jdk1.6.0_03, Netbeans 6.0 on Windows XP platform.
I have tried Greg Sporar's Blog on setting the JVM option in Sun Java System Application Server (GlassFish) and
Java Control Panel - Use browser settings without success.
Thanks,
George

Hi All,
How to set proxy authentication using java properties on the command line, or in Netbeans (Project => Properties
=> Run => Arguments). Below is a simple URL data extract program which works in absence of firewall:
import java.io.*;
import java.net.*;
public class DnldURLWithoutUsingProxy {
   public static void main (String[] args) {
      URL u;
      InputStream is = null;
      DataInputStream dis;
      String s;
      try {
          u = new URL("http://www.yahoo.com.au/index.html");
         is = u.openStream();         // throws an IOException
         dis = new DataInputStream(new BufferedInputStream(is));
         BufferedReader br = new BufferedReader(new InputStreamReader(dis));
      String strLine;
      //Read File Line By Line
      while ((strLine = br.readLine()) != null)      {
      // Print the content on the console
          System.out.println (strLine);
      //Close the input stream
      dis.close();
      } catch (MalformedURLException mue) {
         System.out.println("Ouch - a MalformedURLException happened.");
         mue.printStackTrace();
         System.exit(1);
      } catch (IOException ioe) {
         System.out.println("Oops- an IOException happened.");
         ioe.printStackTrace();
         System.exit(1);
      } finally {
         try {
            is.close();
         } catch (IOException ioe) {
}However, it generated the following message when run behind the firewall:
cd C:\Documents and Settings\abc\DnldURL\build\classes
java -cp . DnldURLWithoutUsingProxy
Oops- an IOException happened.
java.net.ConnectException: Connection refused
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:305)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:171)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:158)
at java.net.Socket.connect(Socket.java:452)
at java.net.Socket.connect(Socket.java:402)
at sun.net.NetworkClient.doConnect(NetworkClient.java:139)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:402)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:618)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:306)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:267)
at sun.net.www.http.HttpClient.New(HttpClient.java:339)
at sun.net.www.http.HttpClient.New(HttpClient.java:320)
at sun.net.www.http.HttpClient.New(HttpClient.java:315)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:510)
at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection.java:487)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:615) at java.net.URL.openStream(URL.java:913) at DnldURLWithoutUsingProxy.main(DnldURLWithoutUsingProxy.java:17)
I have also tried the command without much luck either:
java -cp . -Dhttp.proxyHost=wwwproxy -Dhttp.proxyPort=80 DnldURLWithoutUsingProxy
Oops- an IOException happened.
java.io.IOException: Server returned HTTP response code: 407 for URL: http://www.yahoo.com.au/index.html
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1245) at java.net.URL.openStream(URL.java:1009) at DnldURLWithoutUsingProxy.main(DnldURLWithoutUsingProxy.java:17)
All outgoing traffic needs to use the proxy wwwproxy (alias to http://proxypac/proxy.pac) on port 80, where it will prompt for valid authentication before allowing to get through.
There is no problem pinging www.yahoo.com from this system.
I am running jdk1.6.0_03, Netbeans 6.0 on Windows XP platform.
I have tried Greg Sporar's Blog on setting the JVM option in Sun Java System Application Server (GlassFish) and
Java Control Panel - Use browser settings without success.
Thanks,
George

How to set up and use AirPlay

How to set up and use AirPlay

Welcome to the Apple Community.
AirPlay; When watching suitable content on the iPad, tap the screen to bring up the controls, tap the AirPlay icon and select the Apple TV. The content will then stream to the Apple TV.
Mirroring; Double tap the home screen button, swipe the application panel to the right, tap the AirPlay icon and choose the Apple TV. The iPad screen will then be streamed to the Apple TV.

How to set unequal columns using master pages in InDesign CS3?

How to set unequal columns using master pages in InDesign CS3?

I don't have CS3 anymore but I don't think this has substantially changed in the last few versions of InDesign.
Choose View > Grids & Guides > uncheck Lock Column Guides. Then drag the column guides to the position you want.

Once and for all: How to set up and use SSH

Yes, I know ssh has been discussed on and off, but never in its entirety; and yes, there are step by step instructions on the www, but at one point or another they skip a crucial instruction that would be necessary for unix-dummies (e.g. how to save and close the nano-editor in Terminal). So, please pardon my question:
There are several points I'd like to ask for ssh-connecting two macs on a local network:
1) In terminal-file-"connect to server" you can ask for an ssh connection to be set up. For this to work, do I need to create private and public keys first? If so, how? Please point me to a reliable and step-by-step instruction site.
There are some free ssh-utilities out there, but their documentation is just not helpful enough for a UNIX-dummy.
2) Apparently I managed to connect via ssh once (from the terminal, see point 1) to a local server (allowing remote connection set to ON at the server). But then, when I connected to that server from the client's finder and tried to get into my user account on that server it told me that no secure connection could be established. What's wrong here? Do I have to continue working from within the terminal to use this connection? That would be difficult for an average MacUser.
3) What is the security advantage of an SSH connection on a local wireless network (Airport Base Station) over WPA2, if at all?
4) And how to set up an ssh-connection over the internet cloud to safely build a remote control/desktop sharing connection, e.g., a friend's Mac when she has a problem?
Thanks for your consideration.

First I'm not sure what your goals are.
1) In terminal-file-"connect to server" you can ask for an ssh connection to be set up. For this to work, do I need to create private and public keys first?
If you have ssh keys, you can do this without passwords. If you have not exchanged keys with the remote system, you will be asked for the password of the user you are attempting to login as.
If so, how? Please point me to a reliable and step-by-step instruction site. There are some free ssh-utilities out there, but their documentation is just not helpful enough for a UNIX-dummy.
Log into the remote system. This could be via ssh.
On the remote system, run the following command to generate an ssh key for that remote system:
ssh-keygen -t rsa
Generating public/private rsa key pair.
Enter file in which to save the key (/Users/username/.ssh/id_rsa): <<take default>>
Created directory '/Users/username/.ssh'.
Enter passphrase (empty for no passphrase): <<enter nothing>>
Enter same passphrase again: <<enter nothing again>>
Your identification has been saved in /Users/username/.ssh/id_rsa.
Your public key has been saved in /Users/username/.ssh/id_rsa.pub.
The key fingerprint is:
aa:bb:cc:dd:ee:ff:gg:hh:ii:jj:kk:ll:mm:nn:oo:pp [email protected]
This will generate an ssh key for the remote system. This could be any system that support ssh, such as a Unix system, or another Mac.
Copy the id_rsa.pub file from the remote system to your Mac. When I say "your Mac" I mean the one that you want to make the ssh connection from. The id_rsa.pub is found in the remote system's ~username/.ssh/ directory.
Append the copied id_rsa.pub to your Mac's ~himbear/.ssh/authorized_keys2 file
cat id_rsa.pub >>~himbear/.ssh/authorized_keys2
Now when you ssh to that specific remote system, it will NOT ask for a password. The first time you ssh to any system, ssh will ask if the system is really the system you thing it is. But once you say "yes", it will not ask that question again.
Repeat for every remote system you wish to log into using an ssh key.
2) Apparently I managed to connect via ssh once (from the terminal, see point 1) to a local server (allowing remote connection set to ON at the server). But then, when I connected to that server from the client's finder and tried to get into my user account on that server it told me that no secure connection could be established. What's wrong here? Do I have to continue working from within the terminal to use this connection? That would be difficult for an average MacUser.
MacUser. A flash from the past, as in the MacUser magazine.
ssh is not used by default when you make connections. If you want an ssh connection, you have to establish it intentionally.
ssh can be used to pre-establish a tunnel (or tunnels) that other services can use. Once an ssh tunnel is establish, connections to local host's tunnel port will be connected to the specified remote port. For example:
ssh -L 5901:localhost:5900 [email protected]
will establish a tunnel that VNC can use. The VNC client would connect to localhost display 1 or port 5901.
ssh allows multiple -L tunnels to be specified on the ssh command line.
3) What is the security advantage of an SSH connection on a local wireless network (Airport Base Station) over WPA2, if at all?
Inside you home. Not much. Unless of course you do not trust the other members of your family. That is to say, others having your WPA2 password, and are thus on the inside, and can sniff you packets.
4) And how to set up an ssh-connection over the internet cloud to safely build a remote control/desktop sharing connection, e.g., a friend's Mac when she has a problem?
If you are using the Mac OS X Leopard built-in *Screen Sharing* and you are connecting to another Mac's built-in Leopard System Preferences -> Sharing -> Remote Management (Tiger's Apple Remote Desktop), then in the *Screen Sharing* preferences, is an "Encrypt all network data" option.
If you wish to set this option in advance, you can launch *Screen Sharing* by double clicking on System -> Library -> CoreServices -> Screen Sharing.app
You can *Screen Sharing* connections over the net using iChat. This is one of the easiest ways to take control of their system. Of course they need to cooperate. I use a Free AOL Instant Messager (AIM) account for my iChat connections. And as a side benefit you can text, audio chat and/or video chat with the person at the other end.
If you are NOT using the build-in Mac OS X *Screen Sharing* and/or you are NOT using the build-in remote Mac OS X remote management server, then this is a situation where an ssh tunnel would be a very good idea.
However, setting up an ssh tunnel between 2 systems across the internet gets complex.
In this case you might want to consider using something like LogMeIn.com which will deal with all those nasty home routers without needing to to do nasty router configurations, and it will be a secure connection. LogMeIn.com will not be as fast as a *Screen Sharing* connection or a VNC connection, but it will be secure and easy to establish. Again, this is only if you can not to Mac to Mac *Screen Sharing* using built-in Mac OS X remote desktop.
Now if you want to roll your own ssh tunnels for VNC, then I'm just going to outline the things you need to do.
If the remote system is behind a home router, you need to configure that remote home router to "Port Forward" port 22 on the Internet side to port 22 on the target Mac. Bonus points if the internet side using a high number port to discourge net bots from knocking on your door. Use the ssh -p 12345 option to connect to the high numbered port that is forwarded to port 22 of the destination Mac.
On the remote Mac you need to run a VNC server. If this is a Mac, then Leopard System Preferences -> Sharing -> Remote Management (Tiger's Apple Remote Desktop). If it is not a Mac, then for Windows, TightVNC, UltraVNC, RealVNC are possible options. Linux has a built-in vncserver, or you can install x11vnc which has the advantage of displaying the desktop screen.
Once you can access the remote system, you use an ssh command like the following:
ssh -p 12345 -L 5901:localhost:5900 remote.system.address
You can get the remote system's address by having the remote system surf over to http://whatismyip.com. Then they can tell you the IP address.
If you are going to be doing this a lot, you can get a free no-ip.com or dyndns.org dynamic DNS name for the remote system, and the remote system can run a dynamic DNS client (available from no-ip.com or dyndns.org) which will keep the dynamic DNS name updated as the remote person's ISP change's their IP address.
Finally, now that you have an ssh tunnel for VNC traffic, you have your VNC client connect to
Address: localhost
Port: 5901
Depending on your VNC client you may need to specify Display 1 instead of Port 5901. Or if you do not get a Display or Port option you specify localhost:5901

How to set class path for mysql

hai, I have been trying to make a java program read from mysql database. but i don't know how to set the class path for mysql-connector-java-5_1_.0.6-bin. i set the class path in system variable as C:\Program Files\Java\jdk1.5.0_08\jre\lib\ext\mysql-connector-java-5_1_.0.6-bin.
in the command prompt, i compile C:\javac abc.java and run java abc.
when run it come out error java.lang.ClassNotFoundException: com.mysql.jdbc.Driver
i am using Window xp. can anybody help me??? TQ.

hai, I have been trying to make a java program read
from mysql database. but i don't know how to set the
class path for mysql-connector-java-5_1_.0.6-bin. i
set the class path in system variable as C:\Program
Files\Java\jdk1.5.0_08\jre\lib\ext\mysql-connector-jav
a-5_1_.0.6-bin.
in the command prompt, i compile C:\javac abc.java
and run java abc.
when run it come out error
java.lang.ClassNotFoundException:
com.mysql.jdbc.Driver
i am using Window xp. can anybody help me??? TQ.Right click on my computer icon,
Goto properties->advanced->environment variables.
Look for 'classpath' under system variable.
Select it and click edit.
put ';' and path of the mysql connector jar at the end
suppose if u have jar file under d:/driver/mysqlconnector.jar
thn put this value in variable value text box
;d:/driver/mysqlconnector.jar
or simply put ur driver jar file in jre/lib/ext folder
D:\j2sdk1.4.2_03\jre\lib\ext
[Servlet tutorial|http://www.jsptube.com]

Default save path using AXAcroPDF

Hi,
I'm using the AxAcroPDF component in a windows forms Application.
I know that the default filename for the save dialog can be setup using AxAcroPDF.src("filename");
Is there an option to set the default path for the save dialog.
Is there a way to prevent the save dialog from appearing on screen and just save the file
to the default path and filename.
Thanks
Jake

Presdales School wrote:
Hello, I am looking for a way to change the default save path that Logic uses, since we use Logic for education, we have many users and they all tend not to save their work in the right place. So being able to change the default save path would make our lives a lot easier!
I appreciate any help you can give, even if the answer is that you can't change it.
Thanks!
Hi,
Each Logic session creates it's own save path. The best way is to allow for Logic to store all relative data for each session in it's own song folder.
Unfortunately, you have to tell your students where you want them to store their song folders. Logic simply obeys commands at that point, and cannot force a save into a pre-determined folder.
You also can lock certain areas of the computer, so the students cannot save in those folders.
Cheers

How to set dynamic path in forwards action

Hi All,
i have a requirement to set my path dynamically in forward action
suppose i have
@Jpf.Action(forwards = { @Jpf.Forward(name = "success1", path = "/output1.jsp") })
     public Forward testIpc1() {
          Forward forward = new Forward("success1");
          System.out.println("IN PageflowportletController :: testIpc1() method called");
          return forward;
Here the path="/output1.jsp" is hardcoded.is there any way to set the path dynamically in forwards action
@Jpf.Action(forwards = { @Jpf.Forward(name = "success1", path = dynamic_path) })
how do i get the dynamic path set in my forwards action.
Suggestions provided would be really helpful
Thanks,
Deepak

http://java.sun.com/j2se/1.5.0/docs/tooldocs/windows/classpath.html

How to set line width using CoreGraphics ?

Hi guys.
I trying draw line with 2 pixels width.
How to set line width on CoreGraphics ?
AFAIK, OpenGLES.framework has method like this :
glLineWidth(2.0);
Is it possible for CoreGraphics ?
Thanks in advance.

See CGContextSetLineWidth in the CGContextReference.
You might also want to look over Painting a Path in the +Quartz 2D Programming Guide+.
\- Ray

How to set portal context using Java/JPDK api.

Hi,
I am in the process of converting pl/sql based database provider contect portlets to Java based JPDK. I ran into issue where the database provider portlet users were getting context auto matically. Now with Java/JPDK portlets , I am receiving no data found error, since the context is not set. The pl/sql is setting wwctx_private_api.set_context ('portal') to set the context. From Java if we call this api, it is taking a toll on the performance and the portlet times out.
Can any help how to set the context for a web provider using JPDK or any other better solution. Any immediate help is highly appreciated.
Thanks,
Rav.

Hi
We are trying to access content views for e.g portal.wwsbr_all_items s, portal.wwsbr_all_content_areas c,portal.wwsbr_all_folders f, from aweb provider portlet. When we do a select on those objects , we are getting java sql exception saying "ORA-06510: PL/SQL: unhandled user-defined exception
ORA-06512: at "PORTAL.WWCTX_SSO", line 1745
ORA-06510: PL/SQL: unhandled user-defined exception
ORA-06512: at "PORTAL.WWCTX_SSO", line 1579
ORA-06502: PL/SQL: numeric or value error
ORA-06512: at "PORTAL.WWCTX_SSO", line 1834
ORA-06512: at "PORTAL.WWCTX_API", line 199
We need to know how to accesss the above views from a jsp based portlet.
A

Open in read / set save path

Hello,
I would like to open an image in read only mode and then set the save path to save to a different directory, without actually saving the document. The former i can manage. When the user selects save I wish the save directory to be different from the source. Is it possible.
Thanks

Thanks for the reply.
Anything is welcome at this point.
And yes, I did try both through PowerShell and through the Unlocker and the behavior is pretty much the same. If the item is checked in, there is no trace that it is locked, if I Check it Out (the only thing I can really do with it) it shows as "LongTerm"
but then throws the same exception
Unlocking...
Error occurred. Details:
Save Conflict
Your changes conflict with those made concurrently by another user. If you want your changes to be applied, click Back in your Web browser, refresh the page, and resubmit your changes.
   at Microsoft.SharePoint.SPFile.CheckIn(String comment, SPCheckinType checkInType, Boolean bIsMigrate, SPUser modifiedBy)
   at Microsoft.SharePoint.SPFile.CheckIn(String comment)
   at ForceSPItemUnlock.UnlockerForm.UnlockButton_Click(Object sender, EventArgs e)
The method UpdateItemCheckoutExpiration sounds insteresting though.
"The more difficult something became, the more rewardant it was in the end"
http://ftduarte.blogspot.com

How to set save path using FileStream?

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