How to set the root path of XML document when calling Inserting procedure

Question

Hi,
I was create a procedure to insert XML Document in to DBMS Tables, but i am not able to set the Start root element in calling procedure.
My calling procedure is
exec insXmldoc('pmc_sample.xml', 'pmc')
When i am calling this procedure i got this error
11:23:54 Error: ORA-29532: Java call terminated by uncaught Java exception: oracle.xml.sql.OracleXMLSQLException: Start of root element expected.
ORA-06512: at "SYS.DBMS_XMLSAVE", line 65
ORA-06512: at "SCOTT.INSPROC", line 8
ORA-06512: at line 2
I am checking my XML file using XML Validator. My XML file was parsed with out errors.
Please give the solution,and tell me where i did wrong in my calling procedure.
suppose i have this XML file in local E drive ,how to set the path for that XML file in my calling procedure.

Answer 1

Hi, I am doing the code likthis,please give the solution.
SQL> create or replace procedure insProc(xmlDoc IN CLOB, tableName IN VARCHAR2) is
2 insCtx DBMS_XMLSave.ctxType;
3 l_ctx dbms_xmlsave.ctxtype;
4 rows number;
5 begin
6 insCtx := DBMS_XMLSave.newContext(tableName); -- get the context handle
7 rows := DBMS_XMLSave.insertXML(insCtx,xmlDoc); -- this inserts the document
8 DBMS_XMLSave.closeContext(insCtx); -- this closes the handle
9 end;
10 /
Procedure created.
SQL> begin
2 insProc('/usr/tmp/ROWSET.xml', 'emp');
3 end;
4 /
begin
ERROR at line 1:
ORA-29532: Java call terminated by uncaught Java exception: oracle.xml.sql.OracleXMLSQLException:
Start of root element expected.
ORA-06512: at "SYS.DBMS_XMLSAVE", line 65
ORA-06512: at "SCOTT.INSPROC", line 7
ORA-06512: at line 2
Kishore B