How to split a string in LabView?

Hello everyone,
I'm using the LabView to control a robot named SHRIMP |||. The robot gets commands in hexadecimal format. I need to process info from the command line and therefore I want to split the string of the command line.
In order to make myself clear this is the case: the command (in hex) is 040100 when 04 is the command itself (set velocity and steering angle), 01 is the velocity to set and 00 is the steering angle. When I read it in Labview I see - /04/01/00. I need to separate the velocity and angle from the string so I used the "search/split string" VI but it doesn't seem to help get rid of the "/" delimiter. I can get only the string before the delimiter or the string with the delimiter inside. When I tried to use offset, it seems that the LabView recognize each part of the command as one char in the string ("/04","/01","/00" are the 3 parts of the string) so I can't use it also. I tried to change the display of the string to hexadecimal format but still no luck- I couldn't convert the string to a number.
Any ideas?
Thanks,
Rap Master

RapMaster,
What you probably want in this case is Scan From String. This takes in an input string, a formatter string similar to the ones used in C (here is a refresher if you are not familiar with printf formatters: http://www.psych.upenn.edu/~saul/parasite/man/man3/printf.3.html), as well as some other parameters that are not as important to this project, and then outputs a number for each field that was represented by a formatter (i.e. %x). Double clicking on the VI brings up a window that will walk you through making the formatters, in case you feel more comfortable that way.
I'm attaching a VI that does exactly what you requested, using Scan From String. To expand the functionality of this VI, just modify the formatter, and more outputs will appear for each formatter.
David M.
Applications Engineer
National Instruments
Attachments:
ScanString.vi ‏8 KB

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How to split the string by datetime in sql

Hi,
How to split the string by datetime in sql, I've a table with comments column stores comments by datetime, while selecting I want to split and show as in rows by each jobref.
can anyone help me in this please.
Thanks,

declare @callcentre table (comments varchar(max),lbiref varchar(200))
insert into @callcentre
select '(28/10/2014 14:56:14) xyz ..... call logged (28/10/2014 14:56:58) xyz ..... call updated (28/10/2014 14:57:41)xyz ..... call updated','Vi2910201'
insert into @callcentre
select '(29/10/2014 14:56:14) xyz ..... call logged (29/10/2014 14:56:58) xyz ..... call updated (29/10/2014 14:57:41)xyz ..... call updated','Vi2910202'
insert into @callcentre
select '(30/10/2014 14:56:14) xyz ..... call logged (30/10/2014 14:56:58) xyz ..... call updated
output:
1) 28/10/2014 14:56:14, (28/10/2014 14:56:14) xyz ..... call logged ,'Vi2910201'
2) 28/10/2014 14:56:58 ,(28/10/2014 14:56:58) xyz ..... call updated ,'Vi2910201'
3) 28/10/2014 14:57:41, (28/10/2014 14:57:41)xyz ..... call updated,'Vi2910201'
4) 28/10/2014 14:56:14, (28/10/2014 14:56:14) xyz ..... call logged ,'Vi2910202'
5) 28/10/2014 14:56:58 ,(28/10/2014 14:56:58) xyz ..... call updated ,'Vi2910202'
6) 28/10/2014 14:57:41, (28/10/2014 14:57:41)xyz ..... call updated,'Vi2910202'
7) 28/10/2014 14:56:14, (28/10/2014 14:56:14) xyz ..... call logged ,'Vi2910203'
8) 28/10/2014 14:56:58 ,(28/10/2014 14:56:58) xyz ..... call updated ,'Vi2910203'
Thanks,
See this illustration
declare @callcentre table (comments varchar(max),lbiref varchar(200))
insert into @callcentre
select '(28/10/2014 14:56:14) xyz ..... call logged (28/10/2014 14:56:58) xyz ..... call updated (28/10/2014 14:57:41)xyz ..... call updated','Vi2910201'
insert into @callcentre
select '(29/10/2014 14:56:14) xyz ..... call logged (29/10/2014 14:56:58) xyz ..... call updated (29/10/2014 14:57:41)xyz ..... call updated','Vi2910202'
insert into @callcentre
select '(30/10/2014 14:56:14) xyz ..... call logged (30/10/2014 14:56:58) xyz ..... call updated','Vi2910203'
SELECT LEFT(p.u.value('.[1]','varchar(max)'),CHARINDEX(')',p.u.value('.[1]','varchar(max)'))-1) AS [Date],
'(' + p.u.value('.[1]','varchar(max)') AS comments,
lbiref
FROM
SELECT lbiref,CAST('<Root>' + STUFF(REPLACE(comments,'(','</Data><Data>'),1,7,'') + '</Data></Root>' AS XML) AS x
FROM @callcentre c
)t
CROSS APPLY x.nodes('/Root/Data')p(u)
and the output
Date comments lbiref
28/10/2014 14:56:14 (28/10/2014 14:56:14) xyz ..... call logged Vi2910201
28/10/2014 14:56:58 (28/10/2014 14:56:58) xyz ..... call updated Vi2910201
28/10/2014 14:57:41 (28/10/2014 14:57:41)xyz ..... call updated Vi2910201
29/10/2014 14:56:14 (29/10/2014 14:56:14) xyz ..... call logged Vi2910202
29/10/2014 14:56:58 (29/10/2014 14:56:58) xyz ..... call updated Vi2910202
29/10/2014 14:57:41 (29/10/2014 14:57:41)xyz ..... call updated Vi2910202
30/10/2014 14:56:14 (30/10/2014 14:56:14) xyz ..... call logged Vi2910203
30/10/2014 14:56:58 (30/10/2014 14:56:58) xyz ..... call updated Vi2910203
Please Mark This As Answer if it solved your issue
Please Mark This As Helpful if it helps to solve your issue
Visakh
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How To Split the String for "."

Hi Friends
I am Using Following Code to Split one String.
String str = "Jeetendra.choudhary";
String[] sp_str = str.split(".");
wdComponentApi.getMessageManager.reportSuccess(str[0]);
wdComponentApi.getMessageManager.reportSuccess(str[1]);
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when i am using following code its working fine.
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wdComponentApi.getMessageManager.reportSuccess(str[0]);
wdComponentApi.getMessageManager.reportSuccess(str[1]);
what may be the issue and how to split the string with "." ?
Thanks & Regards
Jeetendra

"." is a special character.
Use
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Regards
Benjamin
Edited by: Benjamin Hansen on Dec 29, 2009 7:52 AM

How to split this string(char1)char2(char3)char4 into (char1)char2 , .. etc

how to split this string (char1)char2(char3)char4 into (char1)char2 , (char3)char4?
String[] result = "(char1)char2(char3)char4".split("\\(");I want :
result[0] = "(char1)char2" and
result[0] = "(char3)char4"
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Edited by: iamjhkang on Feb 5, 2009 3:37 PM
Edited by: iamjhkang on Feb 5, 2009 3:41 PM

iamjhkang wrote:
especially on
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Thanks.The following:
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(?!...) // negative look ahead
(?<=...) // positive look behind
(?<!...) // negative look behindare all "look-arounds". See: [http://www.regular-expressions.info/lookaround.html]

How to split the string from character position.

HI ALL,
I need to split the string like this.
example:
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mid("HelloWorld", 2, 5);
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This one how to do in labview.
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String Subset is the function you are looking for.
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How would you split a string using indexOf and not using the .split method?
Any help is appreciated :D
Message was edited by:
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would it be better to use the first or the second?
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Returns the index within this string of the first occurrence of the specified character.
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I have below requirement.
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Edited by: user627525 on Dec 15, 2011 11:49 AM

Try this - may not be the best way but...:
create or replace type myTableType as table of varchar2(255)
declare
v_array mytabletype;
v_new_str varchar2(4000);
function str2tbl
         (p_str   in varchar2,
          p_delim in varchar2 default '.')
         return      myTableType
    as
        l_str        long default p_str || p_delim;
         l_n        number;
         l_data     myTableType := myTabletype();
    begin
        loop
            l_n := instr( l_str, p_delim );
            exit when (nvl(l_n,0) = 0);
            l_data.extend;
            l_data( l_data.count ) := ltrim(rtrim(substr(l_str,1,l_n-1)));
            l_str := substr( l_str, l_n+length(p_delim) );
        end loop;
        return l_data;
   end;
begin
v_array := str2tbl ('12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434', ',');
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end;
OUTPUT:
=======
'12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434'HTH
Edited by: user130038 on Dec 15, 2011 12:11 PM

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I got a function on this link,
http://www.orafaq.com/forum/t/11692/0/
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or
http://www.oracle-base.com/articles/8i/Collections8i.php

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Hello,
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Hi,
Welcome to the forum!
Whenever you ask a question, it helps if you post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) and the results you want from that data.
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WITH     cntr     AS
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     FROM     dual
     CONNECT BY     LEVEL     <= ( SELECT MAX (LENGTH (txt))
                         FROM    table_x
,     got_best_path     AS
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Hello Gurus,
I want to split the string and work on each split string.
The following code will do, but not exactly.
It's split into morethan three strings, where coma find.
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This forum is for VB.NET, please check the following resources
http://www.vbforums.com/forumdisplay.php?1-Visual-Basic-6-and-Earlier
http://social.msdn.microsoft.com/Forums/vstudio/en-US/6a0719fe-14af-47f7-9f51-a8ea2b9c8d6b/where-to-post-your-vb-6-questions?forum=vbgeneral
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Lots of articles:
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"If there's nothing wrong with me, maybe there's something wrong with the universe!"

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Hi
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Reward all helpfull answers
Regards
Pavan

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