How to split a string - special character help need
hai all ,
i want to split a string
eg: this is the text file
dsgdsggdsgdsgds [dhana]
hsdhsdhdsh
sdhdshhdsh
sdjsdhdshdsh hdshsd hsahsh
hdfhhshs [sekaran]
dfhdhdh
i want to take only dhana & sekaran . which is in between the square bracket Special character "[ ] "
thanks
dhana
My now classical RegExp test class:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
* @author notivago 11/01/2005
* @version 1.0
public class RegTest {
public static void main(String[] args) {
RegTest test = new RegTest();
// test.classFind();
test.dharma();
test.kharma();
public void classFind() {
Pattern p = Pattern.compile( "class\\s+(\\w+)(?:\\s+extends\\s+(\\w+))?(?:\\s+implements\\s+(\\w+)(?:,\\s*(\\w+))*)?\\s*\\{");
Matcher m = p.matcher( "public class MyClass extends Esta implements Aquela, MaisUma { " );
m.find();
System.out.println("Match");
System.out.println( m.group() );
System.out.println( "Class name: " + m.group(1) );
System.out.println( "Extends: " + m.group(2) );
for( int i = 3; i < m.groupCount(); i++) {
System.out.println( "Implements: " + m.group(i) );
public void stringBreak() {
Pattern p = Pattern.compile( "([0-9]++\\s++)");
Matcher m = p.matcher( "1111 22222 333333 444 5 " );
for( int i = 0; m.find(); i++ ) {
System.out.println( "Match "+ i + ": [" + m.group(0) + "]" );
public void dharma() {
Pattern p = Pattern.compile( "(dhana|sekaran)");
Matcher m = p.matcher( "dsgdsggdsgdsgds [dhana]\nhsdhsdhdsh\nsdhdshhdsh\nsdjsdhdshdsh hdshsd hsahsh\nhdfhhshs [sekaran]\ndfhdhdh" );
for( int i = 0; m.find(); i++ ) {
System.out.println( "Match "+ i + ": " + m.group(0) );
public void kharma() {
Pattern p = Pattern.compile( "[\\[](dhana|sekaran)[\\]]");
Matcher m = p.matcher( "dsgdsggdsgdsgds [dhana]\nhsdhsdhdsh\nsdhdshhdsh\nsdjsdhdshdsh hdshsd hsahsh\nhdfhhshs [sekaran]\ndfhdhdh" );
for( int i = 0; m.find(); i++ ) {
System.out.println( "Match "+ i + ": \t" + m.group(0) );
System.out.println( "Sub-match "+ i + ": \t" + m.group(1) );
}May the code be with you.
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PunithString Subset is the function you are looking for.
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How To Split the String for "."
Hi Friends
I am Using Following Code to Split one String.
String str = "Jeetendra.choudhary";
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wdComponentApi.getMessageManager.reportSuccess(str[0]);
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How to split the string by datetime in sql
Hi,
How to split the string by datetime in sql, I've a table with comments column stores comments by datetime, while selecting I want to split and show as in rows by each jobref.
can anyone help me in this please.
Thanks,declare @callcentre table (comments varchar(max),lbiref varchar(200))
insert into @callcentre
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2) 28/10/2014 14:56:58 ,(28/10/2014 14:56:58) xyz ..... call updated ,'Vi2910201'
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4) 28/10/2014 14:56:14, (28/10/2014 14:56:14) xyz ..... call logged ,'Vi2910202'
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6) 28/10/2014 14:57:41, (28/10/2014 14:57:41)xyz ..... call updated,'Vi2910202'
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Thanks,
See this illustration
declare @callcentre table (comments varchar(max),lbiref varchar(200))
insert into @callcentre
select '(28/10/2014 14:56:14) xyz ..... call logged (28/10/2014 14:56:58) xyz ..... call updated (28/10/2014 14:57:41)xyz ..... call updated','Vi2910201'
insert into @callcentre
select '(29/10/2014 14:56:14) xyz ..... call logged (29/10/2014 14:56:58) xyz ..... call updated (29/10/2014 14:57:41)xyz ..... call updated','Vi2910202'
insert into @callcentre
select '(30/10/2014 14:56:14) xyz ..... call logged (30/10/2014 14:56:58) xyz ..... call updated','Vi2910203'
SELECT LEFT(p.u.value('.[1]','varchar(max)'),CHARINDEX(')',p.u.value('.[1]','varchar(max)'))-1) AS [Date],
'(' + p.u.value('.[1]','varchar(max)') AS comments,
lbiref
FROM
SELECT lbiref,CAST('<Root>' + STUFF(REPLACE(comments,'(','</Data><Data>'),1,7,'') + '</Data></Root>' AS XML) AS x
FROM @callcentre c
)t
CROSS APPLY x.nodes('/Root/Data')p(u)
and the output
Date comments lbiref
28/10/2014 14:56:14 (28/10/2014 14:56:14) xyz ..... call logged Vi2910201
28/10/2014 14:56:58 (28/10/2014 14:56:58) xyz ..... call updated Vi2910201
28/10/2014 14:57:41 (28/10/2014 14:57:41)xyz ..... call updated Vi2910201
29/10/2014 14:56:14 (29/10/2014 14:56:14) xyz ..... call logged Vi2910202
29/10/2014 14:56:58 (29/10/2014 14:56:58) xyz ..... call updated Vi2910202
29/10/2014 14:57:41 (29/10/2014 14:57:41)xyz ..... call updated Vi2910202
30/10/2014 14:56:14 (30/10/2014 14:56:14) xyz ..... call logged Vi2910203
30/10/2014 14:56:58 (30/10/2014 14:56:58) xyz ..... call updated Vi2910203
Please Mark This As Answer if it solved your issue
Please Mark This As Helpful if it helps to solve your issue
Visakh
My MSDN Page
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how to split this string (char1)char2(char3)char4 into (char1)char2 , (char3)char4?
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result[0] = "(char1)char2" and
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I prefer String.split and Pattern.compile().split.
Edited by: iamjhkang on Feb 5, 2009 3:37 PM
Edited by: iamjhkang on Feb 5, 2009 3:41 PMiamjhkang wrote:
especially on
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Message was edited by:
billiejoewould it be better to use the first or the second?
int indexOf(int ch)
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AdeHi,
Welcome to the forum!
Whenever you ask a question, it helps if you post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) and the results you want from that data.
I think I understand the problemk well enough to attempt a solution, but if the query below isn't right, please post that information.
WITH cntr AS
SELECT LEVEL AS n
FROM dual
CONNECT BY LEVEL <= ( SELECT MAX (LENGTH (txt))
FROM table_x
, got_best_path AS
SELECT id
, txt
, MAX ( SYS_CONNECT_BY_PATH ( TO_CHAR (c.n, '99')
) AS best_path
FROM cntr c
JOIN table_x x ON c.n <= LENGTH (x.txt)
START WITH c.n = 1
CONNECT BY c.n - PRIOR c.n BETWEEN 1
AND :section_length
AND x.id = PRIOR x.id
AND SUBSTR ( x.txt
, c.n
, 1
) = '-'
AND LEVEL <= :section_cnt
GROUP BY id
, txt
, got_pos AS
SELECT id
, REPLACE ( txt
) || ';' AS txt
, best_path
, TO_NUMBER (REGEXP_SUBSTR (best_path, '[0-9]+', 1, 2)) AS pos_2
, TO_NUMBER (REGEXP_SUBSTR (best_path, '[0-9]+', 1, 3)) AS pos_3
, TO_NUMBER (REGEXP_SUBSTR (best_path, '[0-9]+', 1, 4)) AS pos_4
FROM got_best_path
SELECT id
, SUBSTR (txt, 1 , NVL ( pos_2 , :section_length)) AS section_1
, SUBSTR (txt, pos_2 + 1, NVL ((pos_3 - pos_2), :section_length)) AS section_2
, SUBSTR (txt, pos_3 + 1, NVL ((pos_4 - pos_3), :section_length)) AS section_3
, SUBSTR (txt, pos_4 + 1, :section_length ) AS section_4
FROM got_pos
;As written, this requires SQL*Plus 9 (or higher). You can have multiple versions or SQL*Plus on the same client, if you really need to keep the older version.
:section_length is the maximum length of each section (35, as you stated the problem).
:section_cnt is the number of sections. In the query above, this is 4. If you change it, you not only have to change the bind variable, but you have to change the hard-coded SELECT clauses of the main query and the last sub-query (that is, got_pos).
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How to Split the string using Substr and instr using loop condition
Hi every body,
I have below requirement.
I need to split the string and append with single quotes('') followed by , (comma) and reassign entire values into another variable. so that i can use it where clause of update statement
for example I am reciveing value as follows
ALN varchar2(2000):=(12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434);
Note: In the above variable i see 8 transactions, where as in real scenario i donot how many transaction i may recive.
after modification i need above transactions should in below format
ALTR Varchar2(2000):=('12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434');
kindly help how to use substr and instr in normal loop or for loop or while loop while modifying the above transactions.
Please help me to sort out this issue.
Many Thanks.
Edited by: user627525 on Dec 15, 2011 11:49 AMTry this - may not be the best way but...:
create or replace type myTableType as table of varchar2(255)
declare
v_array mytabletype;
v_new_str varchar2(4000);
function str2tbl
(p_str in varchar2,
p_delim in varchar2 default '.')
return myTableType
as
l_str long default p_str || p_delim;
l_n number;
l_data myTableType := myTabletype();
begin
loop
l_n := instr( l_str, p_delim );
exit when (nvl(l_n,0) = 0);
l_data.extend;
l_data( l_data.count ) := ltrim(rtrim(substr(l_str,1,l_n-1)));
l_str := substr( l_str, l_n+length(p_delim) );
end loop;
return l_data;
end;
begin
v_array := str2tbl ('12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434', ',');
FOR i IN 1 .. v_array.COUNT LOOP
v_new_str := v_new_str || ''''||v_array(i)||'''' || ',';
END LOOP;
dbms_output.put_line(RTRIM(v_new_str, ','));
end;
OUTPUT:
=======
'12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434'HTH
Edited by: user130038 on Dec 15, 2011 12:11 PM -
How to split a string into tokens and iterate through the tokens
Guys,
I want to split a string like 'Value1#Value2' using the delimiter #.
I want the tokens to be populated in a array-like (or any other convenient structure) so that I can iterate through them in a stored procedure. (and not just print them out)
I got a function on this link,
http://www.orafaq.com/forum/t/11692/0/
which returns a VARRAY. Can anybody help me how to iterate over the VARRAY, or suggest a different alternative to the split please ?
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or
http://www.oracle-base.com/articles/8i/Collections8i.php -
How to split a string around "." expression
My code is:
public String removeExtn(String resource){
String[] splittedName = resource.split(".");
System.out.println("LENGHT IS: "+ splittedName.length);
if(splittedName.length >= 3)
resource = splittedName[0]+ "." + splittedName[1];
return resourceName;
* @param args
public static void main(String[] args) {
Test obj = new Test();
System.out.println(obj.removeExtn("myfile.xml.sample"));
But it doesn't split the string around "." and given the arraylength 0. But if I try to use any another character (e.g. "," or ";") it works perfectly fine.
Please help me.
Thanks in advance.
MansiHi mansi,
I had a same kind of problem a few days back.
What I learned was the split() method has a string expression in it, which is usually noted as regex .
'Regex' is just a short form for 'regular expression'
You may directly use the string variable you would split around in some cases or may want to use a '\\' before some of the characters.
I can't place whole information here .So, let me give you that sun site link I read it from.
This link deals with the whole string class.
You may want to ctrl+F and split to read on split method.
http://java.sun.com/j2se/1.4.2/docs/api/java/lang/String.htmlThis link talks about the regular expressions
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html#sumI got his for you from that link :
\p{Punct} Punctuation: For One of !"#$%&'()*+,-./:;<=>?@[\]^_`{|}~ This is for your knowledge.
And if you want a quick fix just for your code...
that'ld be using a
split(\p{.}) in place where u used a split(.)I have not tried that ...but u may want to!
Hope that helps.
Message was edited by:
Kishorei20
Message was edited by:
Kishorei20 -
How to split a string with a space in between?
Hi ABAP Guru's,
Can you please help me out? How can I split a string into two which has a space in between?
For example: lets suppose the string is 'LA CA USA'. How can I split this string? I have to dynamically determine the number of characters before the space therefore I cannot use number constant such as 2 or 3.
With best regards,
KetanHi
Try like this
DATA : opbal TYPE p DECIMALS 2 VALUE 0.
SELECT * FROM zs_mkpf_mseg
into corresponding fields of table it_opbal
WHERE werks = itmat-werks
AND matnr = itmat-matnr
AND budat = s_budat-low.
* sort it_opbal by budat.
loop at it_opbal.
read table it_opbal.
IF it_opbal-shkzg = 'S'.
opbal = opbal + it_opbal-menge.
ELSEIF it_opbal-shkzg = 'H'.
opbal = opbal + it_opbal-menge * -1.
ENDIF.
endloop.
append opbal TO itab-opbal.
ENDFORM. " opbal_data
you can also use thi s
DATA: NAMES(30) TYPE C VALUE 'Charly, John , Peter',
NAMES2 TYPE STRING,
ONE(10) TYPE C,
TWO(10) TYPE C,
THREE TYPE STRING,
FOUR(4) TYPE C VALUE 'FOUR',
DELIMITER(2) VALUE ','.
SPLIT NAMES AT DELIMITER INTO ONE TWO.
* ONE contains 'Charly' and TWO contains 'John , Pet'.
* SY-SUBRC is 4, because TWO was not large enough to
* accommodate the whole of the remaining string
SPLIT NAMES AT ',' INTO ONE TWO THREE.
* ONE contains 'Charly', TWO contains ' John',
* THREE contains ' Peter'.
SPLIT NAMES AT ', ' INTO ONE THREE TWO.
* ONE contains 'Charly', THREE contains 'John',
* TWO contains 'Peter'.
CONCATENATE NAMES '' INTO NAMES2 SEPARATED BY SPACE.
SPLIT NAMES2 AT DELIMITER INTO ONE TWO THREE FOUR.
* ONE contains 'Charly', TWO contains 'John',
* THREE contains 'Peter ', FOUR is empty.
SPLIT NAMES2 AT DELIMITER INTO ONE FOUR THREE.
* ONE contains 'Charly', FOUR contains 'John',
* THREE contains 'Peter', SY-SUBRC is 4, since
* FOUR was not large enough (spaces are significant
* characters!)
Reward all helpfull answers
Regards
Pavan -
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I have a set of strings or names in ${form.temp.name}Is there anyway I can split a string in jsp or jstl by a newline "\n" or space "\\s" character and print them separately. Or Do i have to do something in my controller as I am using spring with jsp and jstl for my web application?
Thanks.Yes I did the work as below. When I use some delimiters like ";", the code works. But for the newline character of carriage return it does nto work.
<c:set var="str" value="${form.temp.name}"/>
<c:set var="delim" value=" \r\n|\\n"/>
<c:set var="array" value="${fn:split(str, delim)}"/>
<c:forEach var="token" items="${array}">
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Hello everyone,
I'm using the LabView to control a robot named SHRIMP |||. The robot gets commands in hexadecimal format. I need to process info from the command line and therefore I want to split the string of the command line.
In order to make myself clear this is the case: the command (in hex) is 040100 when 04 is the command itself (set velocity and steering angle), 01 is the velocity to set and 00 is the steering angle. When I read it in Labview I see - /04/01/00. I need to separate the velocity and angle from the string so I used the "search/split string" VI but it doesn't seem to help get rid of the "/" delimiter. I can get only the string before the delimiter or the string with the delimiter inside. When I tried to use offset, it seems that the LabView recognize each part of the command as one char in the string ("/04","/01","/00" are the 3 parts of the string) so I can't use it also. I tried to change the display of the string to hexadecimal format but still no luck- I couldn't convert the string to a number.
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Thanks,
Rap MasterRapMaster,
What you probably want in this case is Scan From String. This takes in an input string, a formatter string similar to the ones used in C (here is a refresher if you are not familiar with printf formatters: http://www.psych.upenn.edu/~saul/parasite/man/man3/printf.3.html), as well as some other parameters that are not as important to this project, and then outputs a number for each field that was represented by a formatter (i.e. %x). Double clicking on the VI brings up a window that will walk you through making the formatters, in case you feel more comfortable that way.
I'm attaching a VI that does exactly what you requested, using Scan From String. To expand the functionality of this VI, just modify the formatter, and more outputs will appear for each formatter.
David M.
Applications Engineer
National Instruments
Attachments:
ScanString.vi 8 KB
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