How to start a Java application

How do I start to a application?I have the SDK but where do I go to start it I cant seem to find it.
Thank you

Get a basic java programming book.
Maybe try something like JFrameBuilder which has a test version for free.
Available at
http://www.mars3000.com/
You will then be able to generate some code easly that you can look at and see some simple examples.
rykk

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How to start a java application from a website

hey does anyone know how i can start my java application, when a user clicks a button on my website. I dont want to convert to applet because it will be quite hard plus im gonna have to cut down alot of functionalities? thanks!

[http://java.sun.com/javase/technologies/desktop/javawebstart/index.jsp]
Kaj

How to start a java application as windows 2000 service?

Hi all,
I'm trying to start / stop a java application as a windows 2000 service. But nothing appens (I can see the screen that rapidly display the java help prompt and then disappear)
I've a working directory i.e C:\MyDir and it contains instsrv.exe, srvany.exe and my application jar MyApp.jar
I'm using instsrv.exe to register a java application as a service ( C:\MyDir\instsrv MyApp C:\MyDir\srvany.exe )
I've added a key in registry by running regedit
The key is under the tree HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Services\MyApp
the key value is Parameters
in the key I've added a string value "Application" with the value "C:\j2sdk1.4.2_01\bin\java.exe"
and a string value "AppParameters" with the value "-classpath C:\MyDir\MyApp.jar main" where main is the name of the main class application.
This seems to run correctly with Windows NT 4.0
But doesn't work with Windows 2000.
Can anyone help me?? pls.
Thanks.
Max

I'm replying to myself .... ;-) ahah
All we need for this purpose is JavaService, at link
http://www.alexandriasc.com/software/JavaService/index.html

How to start a java application by double clicking just like windows gui?

Hi,
I want to open the user-defined file in my java application. The way is like the notepad in windows:1.double click the file name 2.the file is opened in the java application 3.if this file has opened at the same time ,then the last opened will be read-only.
Could you tell me how to carry it out ? Thank you
from Maria

!!! Please give me a help! i am thirsty for itSo, to get this straight, you have a Java application in a jar. For some reason, you do not execute this directly. Are you aware that you can execute a jar directly without the need to write a C++ exe to do it?
Anyway, for some reason, instead you have a C++ application which launches the JVM with your jar main class.
Well, you want to do two things. First of all, on Windows level, you need to associate the file type of your user file with your application. Note that they have to have a specific file extension that you choose. To associate the file type with an executable, you open a windows explorer, go to View, Folder Options, File Types and add an entry for your file type and specify it to open with your application. If you do not know how to do this, google for "windows associate file type with program executable" or something alike.
Now, if you double-click one of your user files, the associated exe will open, and it will receive the file name as a command line argument. In your C++ application, you will need to pass this argument, a file name, to the Java application where you launch it.

How to start a Java application on Mac OS

Hello,
I am not sure whether this post would be appropriate to this community, but with the hope to find the answer to the question we have I'll try:
We are fairly new to Java Technology. We had the task to develop an application for Windows OS, and have successfully completed the job. BUT, we decided to go a bit further and see how our program would behave on Mac OS.
Unfortunately, we have never dealt with Macs before, thus don't have any idea on how to make the application run on Mac OS platform.
With Windows we have no problem, went by the most simple way by creating a .cmd file with "java name_of_file" string. Is there any similar simple way to start our small program on Mac OS?

There are many options:
From Terminal (similar to ms-dos prompt, if you didn't know it already):
If you have "java MyApp" in your myapp.cmd, you can execute it with:
sh myapp.cmd
Another option is to set myapp.cmd as executable:
chmod u+x myapp.cmd
and then from Terminal: ./myapp.cmd
Third and best option is to make an executable jar. Then you only have to double-click .jar -file to launch your application (and no need to go to Terminal).

How do starting/stopping of application services differ in R12 ??

How do starting/stopping of application services differ in R12 when compared to 11i ??
Can I start/stop services using opmnctl ??

Can you plese refer me a document where role of OPMN and OC4J in R12 is mentioned ??? In short:-
OPMN - Oracle Process Manager & Notification Server is component in Oracle Application Server (10g) to manage (start/stop/status) Application Server components (HTTP, OC4J)
For more:-
http://download.oracle.com/docs/cd/B14099_19/core.1012/b13996/intro.htm
OC4J -- oracle container for java.
In R12 we have 3 groups of OC4J's.
oacore OC4J - framework based applications
forms OC4J - forms based applications
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For more, pls read
http://download.oracle.com/docs/cd/B10464_05/web.904/b10326/intro.htm
thanks,
JD

Could not start Sun Java Application Server

Hi ,
I have been using JSC for a while, now and then it reports an error " could not start sun java application server...". Does any one know why it s not able to start java application server..
Before you say anything, I have tried
1. use netstat to find any port conflicts.
2. Tried to start application server manually
3. shut down and start studio creator and then try running the project
4. shut down and start PC
unfortunately none of them helped
Only reinstalling resolved the problem. But I cant keep reinstalling very often.
Does any one know the permanent solution for this problem.
Cheers
kush

Sometimes it appears this is a timeout issue because it's taking too long to come up. As Jonathan says, undeploy can help with this (along with his other suggestions).
How many deployed projects do you see (in the server navigator you can open up the deployed server and see what's out there)?
I periodically undeploy "junk" projects that I'm not really using because they slow down the server startup (same thing happens I believe for tomcat... when the server starts it has to load them all and it takes awhile). You can undeploy from within the server navigator by drilling into the server nav and right clicking on the deployed app and choosing undeploy... or you can use the server admin tool.
hth,
v

How to schedule a java application via Windows Scheduler

I can't figure out how to schedule a java application using the Windows Scheduler. Do I schedule the java application with the .class file as a parameter? How do I pass arguments to it?
To execute FileCopy.class, my best guess was:
Start | Control Panel | Performance and Maintenance | Scheduled
Tasks | Add Scheduled Task | Browse | Program Files | Java |
jre1.5.0_06 | ... Advanced Properties
Under the Task tab:
Run: "C:\Program Files\Java\jre1.5.0_06\bin\java.exe"
Start In: "MyDocuments\Eclipse_Workspace\Java_File_Copy
FileCopy"
This does not work. How do I schedule the FileCopy.class java application, and how can I pass arguments to it? Can this be done without specifying a password?
TIA,
John

Suppose that your class is FileCopy (has no package name) and is located under MyDocuments\Eclipse_Workspace\Java_File_Copy folder, then you should have:
Run: "C:\Program Files\Java\jre1.5.0_06\bin\java.exe" FileCopy
Start In: "MyDocuments\Eclipse_Workspace\Java_File_Copy"
And yes you must provide a user password to execute the task.
Best way to do this is to create a special user (with password) for executing this task.
Regards

How can i run java application at system startup just liks as services

How we can run java application at the time of system
starts up just like as services.

Hi,
At first you have to create an exe of the class file.
for that go to the site www.duckware.com/java2exe.html
Click on the j2exe23c.exe(75k) download it and install in ur system. convert the class file to windows exe.
The put the exe in the startup folder in windows.
If ur not able to find that folder search for it and put that exe in that folder.

What is the recommended way to launch a web-start enabled Java application?

Hello,
I have a simple web-start enabled Java application, which I can launch from a brower by entering :
https://xx.xx.x.xxx/MyApp/launch.html
This method would show me a page. I then had to click on a link to run my application.
I noticed that I could also launch my program by entering :
https://xx.xx.x.xxx/MyApp/launch.jnlp
This method would run my application right away.
I wonder if there is a recommended way to launch/run a web-start enabled Java application?
Thank you,
Akino

user8708553 wrote:
..to directly launch my application and bypass the HTML page, why is there a need to
display the HTML page and make the user do a click?There are a number of advantages to using the web page. Including..
<li> An explanation to the end-user of what the application does (a 'sales pitch').
<li> Provision of screen shots of the app. (more 'sales pitch').
<li> A description of what security environment it requires, and why.
<li> Access to using the deployJava.js* to ensure the end-user actually has Java installed & has a suitable minimum version of Java, before they ever get access to the launch button/link.
* http://download.oracle.com/javase/6/docs/technotes/guides/jweb/deployment_advice.html#deployingApplications

How to Start / Stop Oracle Applications

How to Start / Stop Oracle Applications.
Oracle Applications Services (TCF, ConcManagers, Metric, Forms, Reports etc...) TnsListner & Oracle Service (DB) are started when the Server is started.
What is the sequential Order to Start / Shutdown services, Listener & DB.
Best regards,

hi
there is no hard coded rule on which service should be started first.
the basic thing is concurrent manager uses database for starting, so i advice you the following sequence:
1. start the database
2. start the database listener
3. Apache server
4. forms server
5. report server
6. concurrent manager
and shutdown in the reverse order
simple
regards
srinivas

How to make a Java application that will change the client box's IP address

HI how to make a Java application( that application would be run on the client ) that will change the client box's IP address ( IP address of itself )

If you can do that through the command line, then use Runtime.getRuntime().exec(...) to execute your command.

How to execute a java application once the server starts

I have created a java application which executes correctly. I want this application to execute everytime I start my server. I have modified my web.xml as shown below
<servlet>
<servlet-name>SendEmail</servlet-name>
<servlet-class>
com.allcorp.alliance.tdocs.servlets.SendEmail</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
<load-on-startup>1</load-on-startup>
</init-param>
</servlet>
I have extended the class with HttpServlet. When I start the server, I get the message saying the class is being initializing but it does not execute. I want the application to execute. Any idea what I need to do.

BalusC wrote:
Implement ServletContextListener and run the appplication on creation of the ServletContext.Well i understand implementation of ServletContextListener and by overiding contextInitialized(ServletContextEvent se) accordingly can solve the problem.
but you need to consider two cases here first
1).ServletContextListener is not supported by all container especially the minor onces which does not support Servlet 2.3 specification.
2).OP does not have any idea of how to use a Servlet first if you can see he had written his intialization code in the main method.Now how can you expect him to create a listener..... :)
I hope there are no hard issues on what i said this time.
*@OP*
My friend the bad news is that you need to spend bit of time learning about servlets.U'd not be writing intialization code inside a main rather you'd be doing it inside public void init(ServletConfig config) method.
by making <load-on-startup><!--value</load-on-startup> in web.xml enables Servlet container to call init method at the time of deployment of the web application else where it'd call the init method whenever servlet encounters first request from a client.
package com.allcorp.alliance.tdocs.servlets;
import java.util.*;
import javax.mail.*;
import javax.mail.internet.*;
import javax.servlet.http.*;
import javax.servlet.*;
import javax.activation.*;
* @author ssa3z
* TODO To change the template for this generated type comment go to
* Window - Preferences - Java - Code Style - Code Templates
public class SendEmail extends HttpServlet{
public void init(ServletConfig config) {
    // SUBSTITUTE YOUR EMAIL ADDRESSES HERE!!!
    String to = "[email protected]";
    String from = "[email protected]";
    // SUBSTITUTE YOUR ISP'S MAIL SERVER HERE!!!
    String host = "smtp.allstate.com";
    // Create properties, get Session
    Properties props = new Properties();
   // If using static Transport.send(),
// need to specify which host to send it to
props.put("mail.smtp.host", host);
// To see what is going on behind the scene
props.put("mail.debug", "true");
Session session = Session.getInstance(props);
try {
     // Instantiatee a message
     Message msg = new MimeMessage(session);
     //Set message attributes
     msg.setFrom(new InternetAddress(from));
     InternetAddress[] address = {new InternetAddress(to)};
     msg.setRecipients(Message.RecipientType.TO, address);
     msg.setSubject("Test E-Mail through Java");
     msg.setSentDate(new Date());
     // Set message content
     msg.setText("This is a test of sending a " +"plain text e-mail through Java.\n" +"Here is line 2.");
     //Send the message
     Transport.send(msg);
}catch (MessagingException mex) {
    mex.printStackTrace();
} Hope this might help :)
REGARDS,
RaHuL

How to disable my java application after a few days

I have a java application as a MyApplication.jar file. On clicking this .jar my application starts. I want to distribute this jar to my friends so that they can run the application and use it. However, I want my application to run only for a few days. The jar should become unusable after say 10 days and no one (including the people holding the jar) should be able to execute it.

>
...I want to distribute this jar to my friends so that they can run the application and use it. However, I want my application to run only for a few days. >Just a wild guess. You don't have many friends*, do you?
In any case, the usual way to approach this task is to write a key to the system that contains the first date the software was run, then check it each subsequent launch. If the 'first date' + 'allowable days' is before 'today', pop a message telling the user that the software has expired.
As to how/where to store this information..
You might use the Properties class to read/write the date property.
Problems with this approach are
a) Users adjusting their system clock to a previous date to get software to work again.
b) Users finding and deleting the file containing the 'first date' property.
c) Users leaving the software running for 173 consecutive days.
d) * Users hating the software so much that they come and burn your house down.
( That last one is the real worry. ;)

How to start a J2EE application in command line?

Dear all,
As known to all, in Visual Administrator we can start or stop an application in Deploy node easily.
my question is - Is there any command can we use in command line to start/stop an application like 'startapp.bat sap.com/app1' or 'java xxx.jar startApp sap.com/app1'?
Because we want to write a script to restart a certain application in schedule, any idea?
Thank you in advance.

Hi
How to programatically start j2ee application/service from command line
Regards
Sat
Edited by: Satya Narayana on Oct 11, 2009 9:25 AM

How to start a Java application

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