How to store the File Name from a Unix Directory into a ODI variable?

Hi,
I have built a ODI package with the following steps:
1. ODI is polling for a flat file in a Unix directory. I have used OdiFileWait tool for this purpose. Here the file name is not fixed, so I am using wild character (*) to poll for file. Example: DF*ABC1*.DAT where the first wild character denotes 1 letter and the second wild character denotes 2 digits.
2. In the second step, if the file is found, I am moving the file to ODI file server path (../oracledi/demo/file). Here I have used ODIFileMove tool.
3. Then I am using an ODI Interface to Load the file data into a Oracle database table.
4. I am using a Process log table to keep the log for each step I am executing in ODI that is ODIFileWait, ODIFileMove, Interface etc. for each file. In this table a row needs to be inserted after ODIFileWait tool gets the file, with the File Name and File Date. Later on this row will be updated as the consequent steps are executed.
Here is my concern, I need to get the exact File Name of the file after ODIFileWait gets the file and I need to insert that in the Process Log table after the ODIFileWait step gets a file. So if I can store the File Name in a ODI Variable, I can insert it into the Process log table at this point. This I am not able to do.
The files are coming in a different directory (not in ODI file server path), So after getting the file it is moved to ODI file server path (../oracledi/demo/file)
The Files which I am processing are fixed length format. Also, the File name and File Date is stored in the 1st Record(Header record) of the files.
Kindly provide me suggestions to implement this in my code.
Thanks and Regards,
Anik
Edited by: 809820 on Nov 10, 2010 11:36 PM

Look at this link -http://odiexperts.com/getting-one-or-several-unknown-files-from-a-directory
change the command to fetch the ls command and write into File and then using either java or jython break the data and fetch the file name and date and insert into log table.
(or)
you can use the os.system command and get the complete ls command into string and then process and insert it.
Let us know if you need any other help.

Similar Messages

  • How to get the file name from Oracle B2B 10g

    Hi My requirement is I am getting a CSV file from Trading partner, I am using oracle 10g b2b to translate the data.
    In my BPEL 10g I am using AQ adapter to get the message from IP_IN_QUEUE.
    Now I want to get the file name Eg: SampleFile.dat of the CSV file in my BPEL process.
    I tried using the b2b.filename property in the receive activity and it is not getting the file name.
    <sequence name="main">
        <receive name="Receive_Note" partnerLink="GetB2BNote"
                 portType="ns1:Dequeue_ptt" operation="Dequeue"
                 variable="Receive_Note_Dequeue_InputVariable"
                 createInstance="yes">
                 <bpelx:property name="b2b.fileName" variable="WriteFileName"/>
        </receive>
      </sequence>
    Can you help me to get the file name from Oracle b2b 10g ?
    Thanks,
    b2b user

    Hi My requirement is I am getting a CSV file from Trading partner, I am using oracle 10g b2b to translate the data.
    In my BPEL 10g I am using AQ adapter to get the message from IP_IN_QUEUE.
    Now I want to get the file name Eg: SampleFile.dat of the CSV file in my BPEL process.
    I tried using the b2b.filename property in the receive activity and it is not getting the file name.
    <sequence name="main">
        <receive name="Receive_Note" partnerLink="GetB2BNote"
                 portType="ns1:Dequeue_ptt" operation="Dequeue"
                 variable="Receive_Note_Dequeue_InputVariable"
                 createInstance="yes">
                 <bpelx:property name="b2b.fileName" variable="WriteFileName"/>
        </receive>
      </sequence>
    Can you help me to get the file name from Oracle b2b 10g ?
    Thanks,
    b2b user

  • How to get the file name from directory

    Hi,
    I have a directory called test inside i have only one .txt file. i dont know that file name.
    Is it possible get the file name using PL/SQl code. ???
    Using that .txt file i have to create a dynamic table.
    If i have use *.txt also not working
    Anyone suggest me its possible to do or not????
    Cheers,
    Shan

    Hi Saubhik ,
    Wheni execute the function i am getting the following error
    Warning: compiled but with compilation errors
    Errors for FUNCTION LISTDIR
    LINE/COL                                                                       
    ERROR                                                                          
    7/3                                                                            
    PLS-00201: identifier 'DBMS_BACKUP_RESTORE.SEARCHFILES' must be declared       
    7/3                                                                            
    PL/SQL: Statement ignored                                                      
    8/54                                                                           
    PL/SQL: ORA-00942: table or view does not exist                                
    8/20                                                                           
    PL/SQL: SQL Statement ignored                                                  
    10/11                                                                          
    PLS-00364: loop index variable 'EACH_FILE' use is invalid                      
    10/2                                                                           
    PL/SQL: Statement ignored      Cheers,
    Shan

  • How to get the file name from downloads folder with the applescript??

    Hi All..
    I am downloading an application to downloads folder, I need to install the same application after downloading programatically.
    So how do I get the filename in runtime while downloading or after downloading from downloads folder with Applescript or Java?
    Also my download URL link doesnot contain full name of the download file.
    Pls suggest.

    Hi,
    The best method is to use curl.
    Other methods are not reliable, but can work, it depends on several factors (what the script does, what the user does).
    Here is an example with the curl command:
    set tUrl to "http://sourceforge.net/projects/vlc/files/2.0.4/macosx/vlc-2.0.4.dmg/download?ac cel_key=60%3A1350656196%3Ahttp%253A//www.videolan.org/vlc/download-macosx.html%3 A7233e4e9%245818d66f39b0576e1e9c4a0f3b46b1991180bfdd&click_id=976a88ee-19f7-11e2 -9a21-0200ac1d1d8e&source=accel"
    set dFolder to path to downloads folder
    tell application "Finder" to set newFolder to (make new folder at dFolder) as string
    set f to quoted form of POSIX path of newFolder
    do shell script "cd " & f & " && curl -L " & tUrl & " -o 'vlc.dmg'" -- download  to file "vlc.dmg"
    set downloadedFile to newFolder & "vlc.dmg" --<-- HFS path
    --do something with the downloadedFile

  • How to hide the file name (the bizarre number assigned by the camera) when exporting an image version in aperture from an album. Pl understand I want to keep the file name in the project library version.

    how to hide the file name (the bizarre number assigned by the camera) when exporting an image version in aperture from an album. Pl understand I want to keep the file name in the project library version.

    Within Aperture you have Images, which are constructed on-the-fly from two files (the Master and the Version).  You get an image-format file _only_ when you export an Image.  You select the file name (usually a scheme) when you create an image-format file (that is, when you export).  Look under "Aperture→Presets→File Naming" for built-in Presets.  You can, of course, create your own or customize any provided.
    The Preset is applied to only the file newly created by your "export" command.  It is not applied to the Image in Aperture (unless you rename your Versions or your Masters).

  • How to find the dsn name from an *.rpd file provided?

    How to find the dsn name from an *.rpd file provided? All the ODBC details which would require to run your dashboard.

    Hi
    DSN name is not a part of .rpd file. So There is no information about DSN name in .rpd file.
    Thanks
    Siddhartha P

  • How to print the file name in sap

    Hi All,
    I have requirment like,
    there is a folder in my local system, inside that folder there are 10 Excel file like file1.xls,file2.xls..............file10.xls
    how to print the file name of all these file in SAp like
    file1.xls
    file2.xls
    file3.xls
    file4.xls
    file10.xls
    Appropriate points will be rewarded.
    Thanks in Advance
    Arun kumar

    Hi,
    Still you are facing any problem with this code expalin the problem with details , otherwise close this thread.
    Use Method <b>cl_gui_frontend_services=>directory_list_files</b> to read file names for a given directory
    after reading the files then Use FM : <b>RSPO_SX_OUTPUT_TEXTDATA</b> to create spool from internal table data and print the data.
    <b>sample code :</b>
    data: desktop_dir type string.
    data: ifiles type table of string.
    data: xfiles type string.
    data: count type i.
    data: filepath type string.
    call method cl_gui_frontend_services=>get_desktop_directory
      changing
        desktop_directory    = desktop_dir .
    call method cl_gui_cfw=>flush.
    call method cl_gui_frontend_services=>directory_list_files
      exporting
        directory                   = desktop_dir
    *    filter                      = '*.xls'
         files_only                  = 'X'
    *        DIRECTORIES_ONLY            =
      changing
        file_table                  = ifiles
        count                       = count.
      DATA : x_name       LIKE tsp03d-name,
             x_dest       LIKE tsp03d-padest VALUE 'LOCL',
             x_rows       LIKE sxpcklsti1-body_num VALUE 0,
             x_startrow   LIKE sxpcklsti1-body_start VALUE 1,
             x_pages      LIKE rspotype-pages VALUE 1,
             x_pages_1    TYPE p DECIMALS 2,
             x_rqtitle    LIKE sxpcklsti1-obj_descr,
             x_rqcopies   TYPE i VALUE 1,
             x_rqowner    LIKE trdyse01cm-username,
             x_immediate  LIKE pri_params-primm VALUE ' ',
             x_rqid       LIKE tsp01-rqident,
             i_contents    LIKE  solisti1 OCCURS 0 WITH HEADER LINE,
          x_pages   = 1.
          x_rqowner = sy-uname.
          x_dest     = 'LOCL'.
          x_startrow = 1.
          x_rqcopies = 1.
          x_immediate = 'X' .
          CALL FUNCTION 'RSPO_SX_OUTPUT_TEXTDATA'
           EXPORTING
    *       name                 =   x_name
             dest                 =  x_dest
             rows                 =  x_rows
             startrow             =  x_startrow
             pages                =  x_pages
             rqtitle              =  x_rqtitle
             rqcopies             =  x_rqcopies
             rqowner              =  x_rqowner
             immediately          =  x_immediate
           IMPORTING
             rqid                 =  x_rqid
           TABLES
             text_data            = i_contents
           EXCEPTIONS
             name_missing         = 1
             name_twice           = 2
             not_found            = 3
             illegal_layout       = 4
             internal_error       = 5
             size_mismatch        = 6
             OTHERS               = 7.
          IF sy-subrc <> 0.
    ** MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
    **         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
          ENDIF.
    Regards
    Appana
    *Reward Points for helpful answers
    Message was edited by: L Appana

  • Retreiving the file names from directory inside another directory from application server

    Hi,
    I had a problem in retreiving the file names from a directory inside another directory.
    I tried using the FM's  SUBST_GET_FILE_LIST, RZL_READ_DIR_LOCAL and EPS_GET_DIRECTORY_LISTING
    But here I am getting only one directory details.
    Actually my file is located a directory inside one more directory and one more directory and inside the files are located.
    i.e total 3 directories inside the 3rd one my files are there.
    I need to read the latest file name in the directory.
    So that i can do some manipulation after getting the file name.
    Is there option like OPEN DATASET , READ DATASET and CLOSE DATASET?
    Can anyone please let me know How can i acheive this one.
    Regards
    Ram

    Hi Ram,
        Following thread can be helpful for you, were it shows in the tables structure rsfillst a field RSFILLST-TYPE whether its a directory or file..........
    http://scn.sap.com/thread/865272
    thanks and regards,
    narayan

  • How to retrieve the parameter names from a JSP page ? Urgent Please

    Hello,
    Can anybody tell me how to retrieve the parameter names from the JSP
    page. (without using getParameterNames() method.)
    The problem with the getParameterNames() method is I get the Jumbled output.
    I need it very badly
    With regards
    Ananth R
    email:[email protected]
    [email protected]

    Dear duffymo,
    My primary intention is to convert the JSP form information into a XML file.
    If I do not get the Parameter names in the correct order how can I maintain
    tag order in XML file.
    For ex: (JSP PAGE VIEW)
    Name--
    FirstName
    MiddleName
    LastName
    Address--
    Street1
    Street2
    City
    Country
    &so on
    (XML File to be generated)
    <Name>
    <FirstName>Value</FirstName>
    </Name>
    <Address>
    <street1>value</street1>
    </Address>
    & so on
    If I use getParameterNames() to get all the parameter names(Which form the tag names in the XML file ) the Enumeration object it returns will not be in the same order as the text fields in JSP.From this I can not construct a meaningful XML file.
    order means: Order of entry on the page, from top to bottom
    That's it
    Waiting for your responses

  • How to insert the file name to column

    When user upload the file, in order to avoid the double file name conflict, so I need to  change the file name to something else, but I still need save the former file name to some column to download the file with correct file name, I know how to rename and upload file, but I don't know how to catch the file name and save it to some column when using addt insert transaction?

    Hi,
    As I said earlier, you have to maintain the list of filename's "itemdescr" in different temp file and load it an and when required table instead of checking for round robin functionality. If you are looking forward that oracle sqlldr can able to access the filename as one of the parameter then - it might not possible AFAIK.
    else perform the direct insert on the table from sqlclient.
    - Pavan Kumar N

  • How to Capture the File Names of any extension using ssis

    Hello,
    Can you please let me know on how to Capture the File Names of any extension(EG : xls,text,.csv etc) at a time  and stores in excel file  using SSIS?
    Any help would be appreciated.
    Thanks,
    Vinay s

    If you need to act differently on each file type separately or if not all types of files are wanted, i.e. the Filespecifier cannot be *.* in the Foreach loop:
    In the ssis package
    make 3 variables:
    to store the file extension, e.g. User::CurrentExtension of type string
    to store the filename found in the directory: @CurrentFilename
    to store the name of the directory where the files reside e.g. User::CurrentDirectory
    make a foreach loop of type Foreach Item enumerator:
    in the items list you add each file extension that you need
    txt
    csv
    xls
    xlsx
    As Variable mappings map the CurrentExtension to Index 0
    Inside this foreach loop add another foreach loop of type Foreach File enumerator, in the collection Expressions
    add Expression Directory , set to @[User::CurrentDirecotry]
    add Expression FileSpec, set to "*." + @[User::CurrentFileExtension]
    In the Variable mappings, map Variable user::CurrentFilename to Index 0
    Inside this loop use Execute SQL Task to insert the filename in a Excel connection.
    Jan D'Hondt - SQL server BI development

  • MessageFileUpload how to retrive the file name?

    Hi there guys,
    maybe it's a stupid question but i cannot find the answer :_( any of you knows how to retrive the file name i am going to upload from the messageFIleUpload item?
    Thank You, Pier Paolo.
    Edit: Found in another post!! eeheh LAZY ME!! :_)
    Message was edited by:
    PandreoL

    Nice to know that you found the solution. You could have as well used the javadoc for the same.
    --Shiv                                                                                                                                                                                                                   

  • How to put the file name in notepad file

    dear frank,
    how to put the file name in notepad file via power shell. I mean i want to put the file name in that notepad file
    for example,
    my file name is ABL and in this file data is
    02/06/2015,180.00,182.00,176.01,180.50,1575500
    02/06/2015,4.20,4.20,4.20,4.20,500
    02/06/2015,113.50,113.70,112.91,113.09,157800
    02/06/2015,682.01,695.90,682.00,683.19,4250
    02/06/2015,213.98,215.00,213.00,214.87,326200
    02/06/2015,21.52,21.65,21.52,21.60,4000
    02/06/2015,111.00,111.25,108.25,108.91,17100
    02/06/2015,52.00,52.00,52.00,52.00,500
    and i want to data in this form
    ABL,02/06/2015,180.00,182.00,176.01,180.50,1575500
    ABL,02/06/2015,4.20,4.20,4.20,4.20,500
    ABL,02/06/2015,113.50,113.70,112.91,113.09,157800
    ABL,02/06/2015,682.01,695.90,682.00,683.19,4250
    ABL,02/06/2015,213.98,215.00,213.00,214.87,326200
    ABL,02/06/2015,21.52,21.65,21.52,21.60,4000
    ABL,02/06/2015,111.00,111.25,108.25,108.91,17100
    ABL,02/06/2015,52.00,52.00,52.00,52.00,500
    There are many file like this that i want to be edit
    plese tell me how can i do it, i think it is possible via windows power shell.
    thanks in advance.

    Hi
    Just for completeness, what version of VB.NET are you using?
    Here is a complete project to copy all the files with the added "ABL," at the start of each line.  You need to start a new Project with a BLANK default Form1, and replace all of Form1 code with the code below. When you run this project, you
    need to use the 2 buttons to set up the ORIGINAL file folder and a folder to place the copies. You need to check if the file EXTENSION is correct (I assumed txt), and check the text to add to each line is correct.  Once all is set up you should have a
    big red button to start the operation.
    NOTE: it is important that you try this out on a copy of some of the files to verify accuracy BEFORE trying on original files. Make sure you have a good back up of the original files before doing anything else.
    ' new project with default BLANK Form1
    ' replace all Form1 code with this code
    ' WARNING: make sure you have a backup of
    ' any files you use this application to
    ' operate on.
    Option Strict On
    Option Infer Off
    Option Explicit On
    Public Class Form1
    Dim OrigFileFolderPath As String = Nothing
    Dim CopyToFolderPath As String = Nothing
    Dim lab1, lab2, lab3 As New Label
    Dim tb1, tb2, tb3 As New TextBox
    Dim b1, b2, b3, b4 As New Button
    Dim fb As New FolderBrowserDialog
    Dim bgw As New System.ComponentModel.BackgroundWorker
    Private Sub Form1_Load(sender As Object, e As EventArgs) Handles Me.Load
    Me.Size = New Size(731, 300)
    With lab1
    .Text = "Original Files Folder Path"
    .Location = New Point(15, 5)
    End With
    With tb1
    .Width = 560
    .Location = New Point(10, 30)
    .BackColor = Color.Khaki
    .ForeColor = Color.Maroon
    .Font = New Font(Me.Font.FontFamily, 12)
    .BorderStyle = BorderStyle.FixedSingle
    .Anchor = AnchorStyles.Top Or AnchorStyles.Left Or AnchorStyles.Right
    End With
    With lab2
    .Text = "Copy Files to Folder Path"
    .Location = New Point(15, 125)
    End With
    With tb2
    .Width = 665
    .Location = New Point(10, 150)
    .BackColor = Color.Khaki
    .ForeColor = Color.Maroon
    .Font = New Font(Me.Font.FontFamily, 12)
    .BorderStyle = BorderStyle.FixedSingle
    .Anchor = AnchorStyles.Top Or AnchorStyles.Left Or AnchorStyles.Right
    End With
    With lab3
    .Text = "File Ext"
    .Location = New Point(600, 5)
    .Anchor = AnchorStyles.Top Or AnchorStyles.Right
    End With
    With tb3
    .Text = ".txt"
    .Width = 80
    .Location = New Point(590, 30)
    .BackColor = Color.Khaki
    .ForeColor = Color.Maroon
    .TextAlign = HorizontalAlignment.Center
    .Font = New Font(Me.Font.FontFamily, 12)
    .BorderStyle = BorderStyle.FixedSingle
    .Anchor = AnchorStyles.Top Or AnchorStyles.Right
    End With
    With b1
    .Text = "Choose Original Files Folder Path"
    .AutoSize = True
    .Location = New Point(10, 65)
    End With
    With b2
    .Text = "Choose Copy Files to Folder Path"
    .AutoSize = True
    .Location = New Point(10, 185)
    End With
    With b3
    .Text = "DO THE COPY"
    .AutoSize = False
    .Size = New Size(240, 50)
    .BackColor = Color.Red
    .ForeColor = Color.White
    .Font = New Font(Me.Font.FontFamily, 20, FontStyle.Bold)
    .Location = New Point(420, 80)
    .Anchor = AnchorStyles.Top Or AnchorStyles.Right
    .Visible = False
    End With
    With b4
    .Text = "CANCEL JOB"
    .AutoSize = False
    .Size = New Size(240, 50)
    .BackColor = Color.Red
    .ForeColor = Color.White
    .Font = New Font(Me.Font.FontFamily, 20, FontStyle.Bold)
    .Location = New Point(420, 80)
    .Anchor = AnchorStyles.Top Or AnchorStyles.Right
    .Visible = False
    End With
    Me.Controls.AddRange({lab1, lab2, lab3, tb1, tb2, tb3, b1, b2, b3, b4})
    With bgw
    .WorkerReportsProgress = True
    .WorkerSupportsCancellation = True
    End With
    AddHandler bgw.DoWork, AddressOf bgw_DoWork
    AddHandler bgw.RunWorkerCompleted, AddressOf bgw_Completed
    AddHandler b1.Click, AddressOf b1_Click
    AddHandler b2.Click, AddressOf b2_Click
    AddHandler b3.Click, AddressOf b3_Click
    AddHandler b4.Click, AddressOf b4_Click
    End Sub
    Private Sub b1_Click(sender As Object, e As EventArgs)
    fb.SelectedPath = My.Computer.FileSystem.SpecialDirectories.MyDocuments
    fb.ShowNewFolderButton = False
    Dim r As DialogResult = fb.ShowDialog
    If r = Windows.Forms.DialogResult.OK Then
    tb1.Text = fb.SelectedPath
    If IO.Directory.Exists(tb1.Text) AndAlso IO.Directory.Exists(tb2.Text) AndAlso Not (tb1.Text = tb2.Text) Then
    If tb3.Text = Nothing Then
    redo: tb3.Text = InputBox("Enter the file extension that you want to copy/change", "FILE EXTENSION")
    If tb3.Text = Nothing Then GoTo redo
    End If
    b3.Visible = True
    Else
    b3.Visible = False
    End If
    End If
    End Sub
    Private Sub b2_Click(sender As Object, e As EventArgs)
    fb.SelectedPath = My.Computer.FileSystem.SpecialDirectories.MyDocuments
    fb.ShowNewFolderButton = True
    Dim r As DialogResult = fb.ShowDialog
    If r = Windows.Forms.DialogResult.OK Then
    tb2.Text = fb.SelectedPath
    If IO.Directory.Exists(tb1.Text) AndAlso IO.Directory.Exists(tb2.Text) AndAlso Not (tb1.Text = tb2.Text) Then
    If tb3.Text = Nothing Then
    redo: tb3.Text = InputBox("Enter the file extension that you want to copy/change", "FILE EXTENSION")
    If tb3.Text = Nothing Then GoTo redo
    End If
    b3.Visible = True
    Else
    b3.Visible = False
    End If
    End If
    End Sub
    Private Sub b3_Click(sender As Object, e As EventArgs)
    b3.Visible = False
    b4.Visible = True
    If Not tb3.Text.StartsWith(".") Then tb3.Text = "." & tb3.Text
    bgw.RunWorkerAsync()
    End Sub
    Private Sub b4_Click(sender As Object, e As EventArgs)
    bgw.CancelAsync()
    End Sub
    Private Sub ReadPWFile(fn As String)
    Dim filename As String = My.Computer.FileSystem.GetName(fn)
    Dim barename As String = IO.Path.GetFileNameWithoutExtension(fn)
    Dim copyto As String = tb2.Text & "\" & filename
    Dim line As String = Nothing
    Dim lines As New List(Of String)
    Using sr As IO.StreamReader = New IO.StreamReader(fn)
    Do
    line = sr.ReadLine()
    If Not line = Nothing Then
    lines.Add(barename & "," & line)
    End If
    Loop Until line = Nothing
    End Using
    Using sw As IO.StreamWriter = New IO.StreamWriter(copyto)
    For Each s As String In lines
    sw.WriteLine(s)
    Next
    End Using
    End Sub
    Private Sub bgw_DoWork(sender As Object, e As System.ComponentModel.DoWorkEventArgs)
    Dim ftc As Collections.ObjectModel.ReadOnlyCollection(Of String) = My.Computer.FileSystem.GetFiles(tb1.Text)
    For Each f As String In ftc
    If bgw.CancellationPending Then
    e.Cancel = True
    Exit For
    End If
    Dim ex As String = My.Computer.FileSystem.GetFileInfo(f).Extension.ToLower
    If My.Computer.FileSystem.GetFileInfo(f).Extension.ToLower = tb3.Text.ToLower Then
    ReadPWFile(f)
    End If
    Next
    End Sub
    Public Sub bgw_Completed(sender As Object, e As System.ComponentModel.RunWorkerCompletedEventArgs)
    tb1.Text = Nothing
    tb2.Text = Nothing
    b3.Visible = False
    b4.Visible = False
    MessageBox.Show("Finished copying files", "Job Completed")
    End Sub
    End Class
    Regards Les, Livingston, Scotland

  • How to find the File name using the FTP Adapter

    hi all,
    how to find the File name using the FTP Adapter with BPEL.
    Regards

    Found the solution for this.
    First In the mediator's routing rule use assign property $in.property.jca.file.FileName to $out.property.jca.file.FileName
    In the BPEL's receive activity go to the properties tab and get the property to a BPEL variable. That should do it.
    Thanks for the posts

  • How to include the file name as an XML field

    Hi,
    I'm using a file adapter for process a flat file and convert it into an XML. Does anybody knows how to include the file name into an XML field.
    Ex.
    I process the file named <b>XXIMN21022007.txt</b> and I need an XML like:
    <MT_FILE>
    <field1></field1>
    <field2></field2>
    <field3></field3>
    <filename><b>XXIMN21022007.txt</b></filename>
    </MT_FILE>
    Regards
    Gonzalo

    Just go for dynamic configuration.
    Check the sender file adapter to write the filename in the header (as explained in Michal's blog) and then read that header in some mapping.
    U can use that even in simple message mappings.
    http://help.sap.com/saphelp_nw2004s/helpdata/en/43/03612cdecc6e76e10000000a422035/frameset.htm
    Your code for the filename tag would be something like:
    <i>DynamicConfiguration conf = (DynamicConfiguration) container
        .getTransformationParameters()
        .get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
    DynamicConfigurationKey key = DynamicConfigurationKey.create(
        “http://sap.com/xi/XI/System/File”,
        “FileName”);
    return conf.get(key);</i>
    Regards,
    Henrique.

Maybe you are looking for