How to subtract Time from Sysdate

Hello,
I want to subtract time from sysdate and get the sysdate with time.
Example : = (Sysdate with time)03-mar-2002 16:40:55 - 8 (hours). The result should be like :03-mar-2002 08:40:55
How to write a query for this?.
Please let me know as soon as possible.
Thanks,
Ravi.

Hi Ravi...
SYSDATE includes time, TRUNC(SYSDATE) does not include time.
If you subtract these two, you'll get a positive number of 1.00 or less which is the fraction of a day. For instance high noon would have a fraction of 0.50000. 12:01 p.m. would be 0.50000 + (1/(24*60)), or 0.50069444....
If you want to set the clock back, by calculating a "date" that is 8 hours less than the SYSDATE, then SYSDATE - (8/24) will do that. This will work even if SYSDATE was something like 2 a.m., because it will then set it to 6 p.m. of the day before the day in SYSDATE.
If you want to set a "date" to a specific time on the day of SYSDATE, then calculate the fraction for that time and add it to the TRUNC(SYSDATE). High noon would be TRUNC(SYSDATE) + 0.5.
SELECT TO_CHAR(TRUNC(SYSDATE)+0.5,'DD-MON-YY HH:MI:SS am') AS NOON FROM DUAL;Hope this helps...
Larry Johnson

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