How to transfer an Image file through SOAP

can i transfer image(.bmp, .jpg etc), MS word (.doc) or any other files through SOAP
if yes then how come
please let me know the steps of it

Hi,
You can transfer files such as the types you mention as SOAP attachments.
Try reading the JWSDP (v1.1) tutorial for a starter ( http://java.sun.com/webservices/docs/1.1/tutorial/doc/ ). Also, the SAAJ (SOAP with Attachments API for Java) chapter of the new book "Java Web services In a Nutshell" by O'Reilly is available free from their web site ( http://www.oreilly.com/catalog/javawsian/ )- this discusses attachments in some detail.
Simon

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Hi Sandeep,
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Dear friends,
I have a question about how to transfer a xml file between server and client using axis or weblogic.
My application needs to send xml files instead of primitive data types and bean objects.
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Regards
Sandy

How can I assign image file name from Main() class

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Here is the Main class
import org.me.lib.MyJNIWindowClass;
public class Main {
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Your problem is one of timing. Consider this simple example.
public class Example {
    public String s;
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}When this code is executed, the following happens in order:
1. new Example() is executed, causing an object to constructed. In particular:
2. field s is given value null (since no value is explicitly assigned.
3. field message is given value "Hello, null"
4. Back in method main, field s is now given value "world", but that
doesn't change message.
5. Finally, "Hello, null" is output.
The following fixes the above example:
public class Example {
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How to insert an image file in Oracle database

hi
can you please tell me how to insert an image file into oracle database????
suppose there is one image file in c:\pictures\rose.jpg. how to insert that file into database? theoretically i know that will be BFILE type but i dont know how to insert that.
will be waiting for your reply........
thanks & regards,
Priyatosh

Hello,
The easiest way to load a blob is to use SQL loader.
This example comes from the utilities guide:
LOAD DATA
INFILE 'sample.dat'
INTO TABLE person_table
FIELDS TERMINATED BY ','
(name CHAR(20),
1 ext_fname FILLER CHAR(40),
2 "RESUME" LOBFILE(ext_fname) TERMINATED BY EOF)
Datafile (sample.dat)
Johny Quest,jqresume.txt,
Speed Racer,'/private/sracer/srresume.txt',
Secondary Datafile (jqresume.txt)
Johny Quest
500 Oracle Parkway
Secondary Datafile (srresume.txt)
Loading LOBs
10-18 Oracle Database Utilities
Speed Racer
400 Oracle Parkway
regards,
Ivo

How to insert a image file into oracle database

hi all
can anyone guide me how to insert a image file into oracle database now
i have created table using
create table imagestore(image blob);
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Hi I don't have time to explain really, I did have to do this a while ago though so I will post a code snippet. This is using the commons file upload framework.
Firstly you need a multi part form data (if you are using a web page). If you are not using a web page ignore this bit.
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        String error = "";
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Hi all,
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Thanks in advance,
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Hi
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Transport Protocol: HTTP1.0
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Addressing Type:     URL address
Target host:         localhost
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Authentication Type:Use Logon Data for SAP System
Content Type: text/xml
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What went wrong?
Help me, all helpful answers are highly rewarded.
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How to add an image file to Oracle db?

Need help urgently....Anybody knows how to add an image file (example: jpg)into one of the fields in Oracle database??

This will do the job..
package forum;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
import java.sql.*;
import oracle.jdbc.driver.*;
//import oracle.sql.*;
Wanneer een request.getInputStream wordt geconferteerd naar een "String" (zie later) dan ziet de output in tekstformaat er als volgt uit:
-----------------------------7d280152604f4 Content-Disposition: form-data; name="oploadfile"; filename="C:\WINNT\Profiles\mvo\Desktop\boodschap.txt" Content-Type: text/plain Deze boodschap dient te worden ge-insert in de database. -----------------------------7d280152604f4 Content-Disposition: form-data; name="StadID" 1234 -----------------------------7d280152604f4 Content-Disposition: form-data; name="SuccessPage" /forum/error.jsp -----------------------------7d280152604f4--
of opgesplitst
contentType........... multipart/form-data; boundary=---------------------------7d235ade00f0
filename.............. "C:\Documents and Settings\Administrator\Desktop\boodschap.txt"
MIME type............. text/plain
Wat in database moet.. Dit is de eigenlijke boodschap die moet worden ge-insert in de database.
Eind boundary......... -----------------------------7d235ade00f0 Content-Disposition: form-data; name="file1"; filename="" Content-Type: application/octet-stream -----------------------------7d235ade00f0--
We gaan achtereenvolgens:
1. Kijken of het van het "multipart/form-data" type is (uploaden) en strippen van eerste boundery.
1.a Geen "multipart/form-data" ? dan... error message
1.b Groter dan MAX_SIZE ?..dan .. error message
2. Filenaam van de te uploaden file uitlezen
3. Mimetype bepalen en bepalen in welke positie van de string het Mimetype ophoudt, cq waar te uploaden file begint
4. Bepalen waar eind boundery begint
5. De eigenlijke file uitlezen
6. Terug converteren naar bytes
public class WriteBlob extends HttpServlet {
public static final int MAX_SIZE = ParameterSettings.imageUpload;
String successMessage = "";
public void init(ServletConfig config) throws ServletException {
super.init(config);
* Process the HTTP Get request
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
DataInputStream in = null;
FileOutputStream fileOut= null;
PrintWriter out = response.getWriter();
int kb_size = 0;
boolean pass2 = true;
String message = "";
String responseRedirect = "/forum/uploaden.jsp?message="+" Uploaden geslaagd";
try
//get content type of client request
String contentType = request.getContentType();
// Start stap 1...content type is multipart/form-data
if(contentType != null && contentType.indexOf("multipart/form-data") != -1)
//open input stream
in = new DataInputStream(request.getInputStream());
//get length of content data
int formDataLength = request.getContentLength(); // totale lengte van de inputstream
//initieer een byte array om content data op te slaan
byte dataBytes[] = new byte[formDataLength];
//read file into byte array
int bytesRead = 0;
int totalBytesRead = 0;
int sizeCheck = 0;
while (totalBytesRead < formDataLength)
//kijken of de file niet te groot is
sizeCheck = totalBytesRead + in.available();
if (sizeCheck > MAX_SIZE)
pass2 = false;
message = "Sorry. U kunt slechts bestanden uploaden tot een grootte van 500KB";
responseRedirect = "/forum/uploaden.jsp?message="+message;
bytesRead = in.read(dataBytes, totalBytesRead,formDataLength);
totalBytesRead += bytesRead;
if (pass2==true)
kb_size = (int)(formDataLength/1024);
//create string from byte array for easy manipulation
String file = new String(dataBytes);
/*get boundary value (boundary is a unique string that separates content data)
contentType........... multipart/form-data; boundary=---------------------------7d235ade00f0
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex+1, contentType.length());
// Stap 2.....bepaal de naam van de upload file
// filename.............. "C:\Documents and Settings\Administrator\Desktop\boodschap.txt"
String saveFile = file.substring(file.indexOf("filename=\"")+10);
saveFile = saveFile.substring(0,saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+1,saveFile.indexOf("\"")); //naam van de file...boodschap.txt
String saveFileName = saveFile;
// Stap 3..Bepaal MIME Type en de positie van eind mime type in string
voorbeeld: -----------------------------7d23d21220524 Content-Disposition: form-data; name="file0"; filename="C:\WINNT\Profiles\mvo\Desktop\z clob.txt" Content-Type: text/plain
String restant = "";
int pos; //position in upload file
// bijv .. filename="C:\Documents and Settings\Administrator\Desktop\boodschap.txt"
pos = file.indexOf("filename=\"");
//find position of content-disposition line
pos = file.indexOf("\n",pos)+1; // eing file naam + spatie
// onderstaand geeft bijv Content-Type: text/plain
restant = file.substring(pos,file.indexOf("\n",pos)-1);
restant = restant.substring(restant.indexOf(":")+2,restant.length()); // MIME type
String mimeType = restant;
//find position of eind content-type line
pos = file.indexOf("\n",pos)+1;
//find position of blank line
pos = file.indexOf("\n",pos)+1;
int start = pos;
// Stap 4 eind boundary
/*find the location of the next boundary marker (marking the end of the upload file data)*/
int boundaryLocation = file.indexOf(boundary,pos)-4; //waarom -4 ..? ziet er uit als linebreak spatie--boundary=-----------------------------7d21c9ae00f0
// Stap 5 en 6..de eigelijke te uploaden file in nieuwe byte file inserten
byte dataBytes2[] = new byte[boundaryLocation-start]; //declareren
for (int i=0;i<(boundaryLocation-start);i++) // inserten BELANGRIJK !!
dataBytes2=dataBytes[start+i];
String next_id = "0";
Statement statement = null;
Connection conn = null;
boolean pass = true;
ResultSet rs = null;
Statement stmt_empty = null;
oracle.sql.BLOB blb = null;
try
int vendor = DriverUtilities.ORACLE;
String username = ConnectionParams.userName;
String password = ConnectionParams.passWord;
String connStr = DriverUtilities.makeURL(vendor);
DriverManager.registerDriver(new oracle.jdbc.driver.OracleDriver());
conn = DriverManager.getConnection(connStr,username, password);
if (conn==null){pass=false;}
} catch (Exception e){out.println("<P>" + "There was an error establishing a connection:");}
if (pass==true)
try
String seq_nextval ="select forum_blob_seq.nextval from dual";
statement = conn.createStatement();
ResultSet rset = statement.executeQuery(seq_nextval);
while (rset.next())
next_id = rset.getString(1);
if (next_id.equals("0"))
message = "Uploaden mislukt !...Er ging wat fout tijdens de interactie met de database";
responseRedirect = "/forum/uploaden.jsp?message="+message;
pass = false;
} catch (Exception e1) { out.println("Error blob1 : "+e1.toString()); };
} // end pass
if (pass==true)
try
Statement stmt2 = conn.createStatement();
String insert_empty_blob = "INSERT INTO test_blob(id "+
",filename "+
",mimetype "+
",kb) "+
"VALUES("+Integer.parseInt(next_id) +
",'"+saveFileName+"'"+
",'"+mimeType+"'"+
","+kb_size+")";
stmt2.executeQuery(insert_empty_blob);
conn.commit();
if (stmt2!= null) {stmt2.close();}else{stmt2.close();pass = false;}
} catch (Exception e2){
message = "Uploaden mislukt !...Er ging wat fout tijdens de interactie met de database";
responseRedirect = "/forum/uploaden.jsp?message="+message;
out.println("<P>" + "2. There was an error inserting mime type:");}
} //end pass
if (pass==true)
try
conn.setAutoCommit(false);
} catch (Exception e3) { pass = false; out.println("Error blob 3: "+e3.toString()); };
} //end pass
if (pass==true)
try
String Query_blob ="Select test_blob FROM test_blob where id="+next_id+" FOR UPDATE";
stmt_empty = conn.createStatement();
rs=stmt_empty.executeQuery(Query_blob);
} catch (Exception e4) {
pass = false;
out.println("Error blob 4: "+e4.toString());
message = "Uploaden mislukt !...Er ging wat fout tijdens de interactie met de database";
responseRedirect = "/forum/uploaden.jsp?message="+message;};
} //end pass
if (pass==true)
try
                         if (rs.next())
                         blb = ((OracleResultSet)rs).getBLOB(1);
                    OutputStream stmBlobStream = blb.getBinaryOutputStream();
                         try {
                              int iSize = blb.getBufferSize();
                         byte[] byBuffer = new byte[iSize];
                         int iLength = -1;
ByteArrayInputStream stmByteIn = new ByteArrayInputStream(dataBytes2);
                              try {
// while ( (iLength = in.read(byBuffer, 0,      iSize)) != -1 )
while ( (iLength = stmByteIn.read(byBuffer, 0,      iSize)) != -1 )
                                   stmBlobStream.write(byBuffer, 0, iLength);
                                   stmBlobStream.flush();
                                   } // end while
} catch (Exception e5) {
pass=false;
out.println("Error blob 5: "+e5.toString());
message = "Uploaden mislukt !...Er ging wat fout tijdens de interactie met de database";
responseRedirect = "/forum/uploaden.jsp?message="+message; }
                              finally { conn.commit();     }
} catch (Exception e6) { out.println("Error blob 6: "+e6.toString()); };
                         } //end if rs.next()
                         else {      throw new SQLException("Could not locate message record in database."); }
} catch (Exception e7) { out.println("Error blob : "+e7.toString()); };
} // end pass
} // end pass2
else //request is not multipart/form-data
message = "Uploaden mislukt !...Gegevens niet verstuurd via multipart/form-data.";
responseRedirect = "/forum/error.jsp?message="+message;
out.println("Request not multipart/form-data.");
catch(Exception e)
try
//print error message to standard out
out.println("Error in doPost: " + e);
//send error message to client
out.println("An unexpected error has occurred.");
out.println("Error description: " + e);
}catch (Exception f) {}
response.sendRedirect(responseRedirect);
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
doPost(request,response);
Regards
Martin

How can I add image files to a executable jar file ?

Could you tell me how can I add image files to executable jar file ?
package structure:
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Please don't cross post, and read this
http://forum.java.sun.com/thread.jsp?forum=31&thread=271751
I've answered the question in the New To Java thread.

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The iphone does not have a file system to create a folder in, instead apps themselves are responsible for storing their files,
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You can then transfer the files via itunes or email them and then use the open in... option and select your chosen app.
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How to read a text file through pl/sql

pl/sql runs inside the database. so your file also should be on the database server file system for you to be able to read.
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How to link an image file in code view

I can't seem to figure out how to link the image file in code view. It has to be in code view because the image is hidden in Design View so I can't do it in HTML view. Here's the coded section:

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It's' the red jpeg image file I want to link to another page in the site and I don't have enough experience to do this.
I am thankful for your help.
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Thanks, Gramps. Here's the page I want to like to from the image:
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Paul
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How to undeploy an .sda file through command line

Hi,
How to undeploy an .sda file through command line.send me the related command to do it.and related information and links.

Hi
Please find below the steps to undeploy thro command line :
Shut down the sdm server
1)SDM shutdown "sdmhome=D:\usr\sap\J2E\JCO1\SDM\program" "sdmguiport=50018" "sdmhostname=<hostname>" password="<password>" "shutdownmode=abort"
2)sdm jstartup "mode=standalone" "sdmhome=c:\usr\sap\J2E\DVEBMGS00\SDM\program"
3) sdm undeploy "sdmhome=D:\usr\sap\J2E\DVEBMGS00\SDM\program" "compname=c:\test.sda"
4)sdm jstartup "mode=integrated" "sdmhome=c:\usr\sap\J2E\DVEBMGS00\SDM\program"
5)start the sdm server again
SDM server "sdmhome=D:\usr\sap\J2E\JCO1\SDM\program"
Hope this helps. do not forget to reward points
regards
rajeshkr

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