How to Update and XML file

Hi,
I'm reading an XML file using SAX api, now based on some calculations, i want to add a new Element inside the same XML file.
<?xml version="1.0" encoding="UTF-8"?>
<types>
<type super = "City">
<t>Faro</t>
<t>Porto</t>
<t>Helsinki</t>
</type> 
</types>Now in the above XML snippet, i want to add an new sub element <t> Islamabad </t>, inside types.
Following is the point in the code where i'm stuck:
for (int typeID = 0; typeID < typeList.size(); typeID++) {
                    Element type = (Element) typeList.get(typeID);
                    String superTypeStr = type.getAttributeValue("super").toString();
                    if (superTypeStr.equalsIgnoreCase(comboValue)) {
                         Element t = new Element("t");
                         t.addContent(typeValue);
                         //NOW HOW TO ADD THIS <t>, inside a matched type element (in this case "city"), and write it into the xml file
                         break;
typeList is a List object, which i get using : typeList = types.getChildren("type");Hope i have explained the problem clearly, writing an XML fime from scratch is easy. but in my case i want to update an existing xml file with a new element entry.
The XML file should need to be updated like this:
<?xml version="1.0" encoding="UTF-8"?>
<types>
<type super = "City">
<t>Faro</t>
<t>Porto</t>
<t>Helsinki</t>
<t>Islamabad</t>
</type> 
</types>--
Regards Suleman

hey mate, i remember when i had a similar issue before. I ended up using parsing the document using DOM instead of SAX. The reason being that i wanted to update the XML file and if i parsed the document using DOM i had a handle on the document object so i could subsequently update it. But the drawback is that the entire xml structure is parsed into memory, as opposed to SAX which im sure you know is event driven and memory friendly. I would use SAX for the simple process of parsing the xml file to either examine, or print out the content or both.Perhaps consider DOM?

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    import org.xml.sax.SAXParseException;
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