How to write a shell script to execute a procedure with out parameter

Question

Hi,
How to write a shell script to execute a procedure with out parameter.
here is my procedure
PROCEDURE sample(invar1 VARCHAR2,
invar2 VARCHAR2,
invar3 VARCHAR2,
invar4 VARCHAR2,
ecode out number);
Any example really helpfull
Thanks in advance

Answer 1

Or if we're passing values in, maybe something like:
Test procedure:
CREATE OR REPLACE PROCEDURE p (myin IN VARCHAR2, myout OUT VARCHAR2)
AS
BEGIN
    myout :=
        CASE myin
            WHEN 'A' THEN 'APPLE'
            WHEN 'B' THEN 'BANANA'
            ELSE 'STARFRUIT'
        END;
END;Shell script:
#!/bin/bash
my_shell_variable=$1
unset ORACLE_PATH
sqlplus -s un/pw@db <<-EOF
set feedback off pause off
set pagesize 0
set autoprint off
VAR out varchar2(30)
VAR myin varchar2(30)
exec :myin := '${my_shell_variable}'
BEGIN
  p(:myin, :out);
END;
print out
exit
EOFTest:
/Users/williamr: xx A
APPLE
/Users/williamr: xx B
BANANA
/Users/williamr: xx
STARFRUITObviously in a real script you would not hardcode the password or let it show in a "ps" listing.
Message was edited by:
William Robertson