I have an "unexpected error" on my iPad for my VPN.

I have an "unexpected error" on my iPad for my VPN. I removed my old certificate because it said "not trusted" and received and installed a new certificate (now it shows trusted) but get the same message. Worked find before I installed iOS7.

Could be a "bug".
Send feedback to Apple.
http://www.apple.com/feedback/ipad.html
 Cheers, Tom

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If connect iPad to my TV every time the clip is finished I have to disconnect and reconnect the iPad for new clip playing.

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1. Why don't you purchase it from Apple? I'd be wary with eBay sellers - and, after all, Apple posts their stuff everywhere, even if you live in a country without a localized Apple store webpage or local (physical) Apple stores.
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Here are the links:
http://store.apple.com/us/product/MD098ZM/A
http://store.apple.com/us/product/MC552ZM/B

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The error is coming on line 39:
* Program: MathProgramExtra
* Author: Michael Stewart
* Date: August 22, 2010
* Program Purpose: This program is intended to display selection and iterative statements.
import javax.swing.*;
public class MathProgramExtra
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        Object[] firstintegerPossibilities = {"0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "10"};
        Object[] secondintegerPossibilities = {"1", "2", "3", "4", "5", "6", "7", "8", "9", "10"};
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        String f;
        String s;
        int firstint;
        int secondint;
        int answer;
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            secondint = secondNumConversion(s);
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                break;
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            firstint = 1;
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            firstint = 5;
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            firstint = 6;
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        int secondint = 0;
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            secondint = 2;
        else if(s.equals("3"))
            secondint = 3;
        else if(s.equals("4"))
            secondint = 4;
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            secondint = 5;
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            secondint = 6;
        else if(s.equals("7"))
            secondint =7;
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            secondint = 8;
        else if(s.equals("9"))
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        int answer = 0;
        if (m.equals("+"))
        answer = add(m,firstint, secondint);
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        answer = multiply(m,firstint, secondint);
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        answer = divide(m,firstint, secondint);
        if (m.equals ("%"))
        answer = modulus(m, firstint, secondint);
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        int answer;
        answer = (firstint + secondint);
        return answer;
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        int answer;
        answer = (firstint - secondint);
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        int answer;
        answer = (firstint * secondint);
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        int answer;
        answer = (firstint / secondint);
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        int answer;
        answer = (firstint % secondint);
        return answer;
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        String message = "Your answer is:" + answer;
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                ans = 'Y'; break;
            case 1:
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mstew1979 wrote:
Thank you! I actually just got it working :)Cool. Here's a bit of advice, just in case you "fixed" it by making a common mistake: Don't just initialize a variable to a dummy value to make the compiler happy. Those "not initialized" errors usually point to a logic error. But just initializing the variable to 0, null, etc. at declaration, usually you're just masking the logic error so the compiler doesn't see it. You haven't fixed anything.
public String signum (int x) {
String result;
if (x > 0) {
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else if (x < 0) {
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return result;
}Here we have a compiler error, brought on by my logic error of forgetting to account for x being 0. The wrong way to fix it would be to blindly change the declaration of result to String result = ""; or == null;. The logic error is still there, but now it's hidden from the compiler. So we have an error at runtime instead--we don't get a valid response if we pass in 0. Runtime errors are much harder to debug than compile-time errors.
The correct response to the compiler's "not initialized" error is to look at our code more carefully and see what we might have missed. In this case, we would add and else clause that returns "zero".

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http://support.apple.com/kb/TS1398
iOS and OS X: Recommended settings for Wi-Fi routers and access points
http://support.apple.com/kb/HT4199
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