I have these non english words on the startup screen just below the tab

4 different words, 3 in blue & underliined

Can you attach a screenshot?
* http://en.wikipedia.org/wiki/Screenshot
Use a compressed image type like PNG or JPG to save the screenshot and make sure that you do not exceed the maximum file size (1 MB).
Start Firefox in <u>[[Safe Mode]]</u> to check if one of the extensions is causing the problem (switch to the DEFAULT theme: Firefox (Tools) > Add-ons > Appearance/Themes).
* Don't make any changes on the Safe mode start window.
* https://support.mozilla.com/kb/Safe+Mode
* https://support.mozilla.com/kb/Troubleshooting+extensions+and+themes

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    chris227 wrote:
    Works well for meNo, it does not. It will fail if table has duplicate strings of two digit length but, what is even worse, it will produce wrong results if table has small duplicate strings:
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      3                    select  '19 character string' str from dual
      4                   )
      5  select distinct
      6    listagg(substr(str,level,1))within group ( order by level desc) over (partition by str) r
      7  from testdata
      8  connect by
      9  level <= length(str)
    10  and str = prior str
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    SQL> with testdata as (
      2                    select  'ABC' str from dual union all
      3                    select  'ABC' str from dual
      4                   )
      5  select distinct
      6    listagg(substr(str,level,1))within group ( order by level desc) over (partition by str) r
      7  from testdata
      8  connect by
      9  level <= length(str)
    10  and str = prior str
    11  and prior sys_guid() is not null
    12  /
    R
    CCCCCCCCBBBBAA
    Elapsed: 00:00:00.00You need to identify rows uniquely. With real table it is easy - rowid. With subquery factoring we need another view with, for example, ROW_NUMBER. However here we use subquery factoring to create sample table on-the-fly and assume OP will have real table. So I'd leave your example as is, but would let OP know to use:
    select distinct
      listagg(substr(str,level,1))within group ( order by level desc) over (partition by str) r
    from testdata
    connect by
    level <= length(str)
    and rowid = prior rowid
    and prior sys_guid() is not null
    /But this still will not work. Why? Same answer - duplicates:
    SQL> create table testdata as (
      2      select  'ABC' str from dual union all
      3      select  'ABC' str from dual
      4     );
    Table created.
    Elapsed: 00:00:00.42
    SQL> select distinct
      2    listagg(substr(str,level,1))within group ( order by level desc) over (partition by str) r
      3  from testdata
      4  connect by
      5  level <= length(str)
      6  and rowid = prior rowid
      7  and prior sys_guid() is not null
      8  /
    R
    CCBBAA
    Elapsed: 00:00:00.01
    SQL>Again, partition by str doesn't identify rows uniquery. We need to partition by rowid. But even this will not help:
    SQL> select distinct
      2    listagg(substr(str,level,1))within group ( order by level desc) over (partition by rowid) r
      3  from testdata
      4  connect by
      5  level <= length(str)
      6  and rowid = prior rowid
      7  and prior sys_guid() is not null
      8  /
    R
    CBA
    Elapsed: 00:00:00.00
    SQL>We got one row back instead of two. You probably put DISTINCT trying to resolve all these issues caused by building hierarchy and partitions on a non-unique bases. So now, when we identify rows uniquely by rowid, DISTINCT is not needed and should be replaced by GROUP BY (along with using aggregate LISTAGG instead of analytic LISTAGG). So final solution would be:
    select listagg(substr(str,level,1))within group ( order by level desc) r
    from testdata
    connect by
    level <= length(str)
    and rowid = prior rowid
    and prior sys_guid() is not null
    group by rowid
    R
    CBA
    CBA
    Elapsed: 00:00:00.00
    SQL>And with 19 character string:
    SQL> insert
      2    into testdata
      3  select  '19 character string' str from dual union all
      4                    select  '19 character string' str from dual;
    2 rows created.
    Elapsed: 00:00:00.00
    SQL> select listagg(substr(str,level,1))within group ( order by level desc) r
      2  from testdata
      3  connect by
      4  level <= length(str)
      5  and rowid = prior rowid
      6  and prior sys_guid() is not null
      7  group by rowid
      8  /
    R
    CBA
    CBA
    gnirts retcarahc 91
    gnirts retcarahc 91
    Elapsed: 00:00:00.00
    SQL>SY.

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