I'm using safari 5.1.7, on opening the popup whatever values i enter it's getting doubled(i.e "q" means "qq"). Main page is working properly. Please help me to solve this.

Question

Entering text in popup

Answer 1

Hi,
Apart from Connection objects and Prepared Statment closure declarations
the Constructors
public CandidateMgr() {
this.nicno = nicno;
this.title = title;
this.firstName = firstName;
this.civilStatus = civilStatus;
this.tele = tele;
this.eduQua = eduQua;
will give problem as all the String in java are initialize to null by default when they are memeber variable of a classs.Hence you get null pointer Exception
even if you exchange 652,653 with corresponding change in u r )functionSQL) (i.e)nicno and title
do sometihing like
public CandidateMgr(String nicno,Stirng title,String firstName,String civilStatus,String tele,String eduQua) {
this.nicno = nicno;
this.title = title;
this.firstName = firstName;
this.civilStatus = civilStatus;
this.tele = tele;
this.eduQua = eduQua;
}