I need help in finding ways to improve the speed of Firefox

Hello Everyone, A week ago after using 'system restore' an error message came up saying "XPCOM failed to load". Not really knowing what to do I rebooted my computer using the "Last know configuration to have worked" or something to that effect and then I had to install the latest version of Firefox, 29.0.1 and it cleared that error message. But now my computer is beyond being slow, it's worse than that. I went on to the Firefox start page, clicked on menu, then help, and then troubleshooting information and it advised me to reset Firefox which I did, but then a window appeared saying something to the effect of "Well this is embarrassing and Firefox can't be reset" because of an existing open page and something else, and at the bottom of that window it said to either restore or close. When I first brought up the page where it says to Reset Firefox, I noticed under the Graphics heading that there were three things that were blocked, Direct2D Enabled, GPU Accelerated Windows, and WebGL Renderer. Next to each of those headings to the right it said that "blocked for your graphics driver version, try updating your graphics driver to version 182.65 or newer". Not being a computer whiz I'm not sure if any of those things could be the cause of my computer operating at a snails pace. Any help would be greatly appreciated. Thank you.

That XPCOM error requires a ''Clean reinstall''. This means you remove Firefox program files and then reinstall Firefox. Please follow these steps:
'''Note:''' You might want to print these steps or view them in another browser.
#Download the latest Desktop version of Firefox from http://www.mozilla.org and save the setup file to your computer.
#After the download finishes, close all Firefox windows (click Exit from the Firefox or File menu).
#Delete the Firefox installation folder, which is located in one of these locations, by default (This will not delete important stuff like history, bookmarks, and addons!):
#*'''Windows:'''
#**C:\Program Files\Mozilla Firefox
#**C:\Program Files (x86)\Mozilla Firefox
#*'''Mac:''' Delete Firefox from the Applications folder.
#*'''Linux:''' If you installed Firefox with the distro-based package manager, you should use the same way to uninstall it - see [[Installing Firefox on Linux]]. If you downloaded and installed the binary package from the [http://www.mozilla.org/firefox#desktop Firefox download page], simply remove the folder ''firefox'' in your home directory.
#Now, go ahead and reinstall Firefox:
##Double-click the downloaded installation file and go through the steps of the installation wizard.
##Once the wizard is finished, choose to directly open Firefox after clicking the Finish button.
More information about reinstalling Firefox can be found [https://support.mozilla.org/en-US/kb/troubleshoot-and-diagnose-firefox-problems?esab=a&s=troubleshooting&r=3&as=s#w_5-reinstall-firefox here].
<b>WARNING:</b> Do not run Firefox's uninstaller or use a third party remover as part of this process, because that could permanently delete your Firefox data, including but not limited to, extensions, cache, cookies, bookmarks, personal settings and saved passwords. <u>These cannot be recovered unless they have been backed up to an external device!</u>
Please report back to see if this helped you!
Thank you.

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Need help in finding the number of occurrences of a pattern.

Hi All,
I need help in finding the number of occurrences of a pattern in a table's column's data.
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Edited by: Girish G on Jul 21, 2011 11:22 PM

I am sure there exists a better way then this one:
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3 SELECT SUM(Regexp_count(Regexp_substr(str, '(S\-?)+(A|P)+', 1,
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Need help in finding patterns and there counts

Hi All,
I need help in finding patterns as well as number of occurrences of those patterns in a table's column's data.
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for the above given data the patterns and counts are
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Hi, Girish,
Girish G wrote:
Hi All,
I need help in finding patterns as well as number of occurrences of those patterns in a table's column's data.
Consider sample data - one row's column from a table:
"S-S-S-P-S-B-S-S-C-S-P"
My requirement is:
I should get all the patterns that are followed by 'S'.Do you mean "I should get all patterns that *start with* 'S'"?
Example: for the above given data the patterns and counts are
SS - count is 3
SP - count is 2
SB - count is 1
SS - count is 1Why are there two rows of output for 'SS'? What does the second one, with count=1, mean?
There is one more condition for the above requirement:
If 'S' is followed by 'A', then 'SA' should not be considered as a pattern. The pattern should stretch until a non 'A' character is found.
Consider sample data for the above case:
"S-S-A-S-S-A-A-C-S-P-S-A"
for the above given data the patterns and counts are
SS - count is 2
SP - count is 1
SAS - count is 1
SAAC - count is 1
The data column is stored as VARCHAR2 type.
I have Oracle Database 11g Enterprise Edition Release 11.1.0.6.0 - 64bit ProductionThanks; the version information is very helpful.
Thanks in advance,
Girish GWhenever you have a question, please post a little sample data (CREATE TABLE and INSERT statements) and the results you want from that data.
For example, your sample data might be:
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(       x_id     NUMBER     PRIMARY KEY
,     txt     VARCHAR2 (30)
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FROM       got_pattern
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GROUP BY x_id
,            txt
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;At the heart of this query is the call to REGEXP_SUBSTR:
REGEXP_SUBSTR ( x
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S = the letter S
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